Explain how to get the answer please.
Two points defining a linear function are shown in the table below.
[tex]\left[\begin{array}{ccc}&x&y\\&-14&-18\\&-10&-12\end{array}\right][/tex]
How do u get the slope?

Slope in fraction form = 3/2

Slope in decimal form = 1.5

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Explanation:

That table shows the two points (x1,y1) = (-14,-18) and (x2,y2) = (-10,-12).

Each row is a different point.

To find the slope, we subtract the y values to get y2-y1 = -12-(-18) = -12+18 = 6

Then we subtract the x values to get x2-x1 = -10-(-14) = -10+14 = 4

Lastly, we divide the two differences: ydiff/xdiff = 6/4 = 3/2

The slope in fraction form is 3/2, which is equivalent to the decimal form 1.5

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If you want, you can apply the slope formula like so

m = slope

m = rise/run

m = (change in y)/(change in x)

m = (y2-y1)/(x2-x1)

m = (-12-(-18))/(-10-(-14))

m = (-12+18)/(-10+14)

m = 6/4

m = 3/2

m = 1.5

We effectively are following the same as steps as before, but in this format, it's more of what you might have on your homework if you were to show the step-by-step process. You could also do a visual graph approach as a different option. Often in math there are multiple ways to get the answer.

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