Find the distance ab give your answer correct to 1. Decimal place

Answer:

AB=10

AB=7.2

Step-by-step explanation:

AB= √{(9-1)²+(8-2)²} = √{8²+6²}=√{64+36}=√100 =10

AB= √{(6-2)²+(2-8)²} = √{4²+(-6)²}=√{16+36}=√52 =7.2

The distance between points A(1, 2) and B(9,8) is 10 and the distance between points A(2, 6) and B(8, 2) is 7.2.

A coordinate plane is a plane in which a set of two number lines are represented, horizontal line is called x-axis and vertical line is called y-axis.

In the first coordinate plane,

The coordinate of point A is (1, 2) and coordinate of point B is (9,8),

To find distance, use distance formula between two points (x₁, y₁) and (x₂, y₂) is [tex]\sqrt{(x_2 - x_1)^2+ (y_2 -y_1)^2)}[/tex]

Thd distance between A(1, 2) and B(9,8),

AB= [tex]\sqrt{{(9-1)^2+(8-2)^2}}[/tex] = [tex]\sqrt{{8^2+6^2}}[/tex]=[tex]\sqrt{{64+36}}[/tex]=[tex]\sqrt{100}[/tex] =10

In the second coordinate plane,

The coordinate of point A is (2, 6) and coordinate of point B is (8, 2),

To find distance, use distance formula between two points (x₁, y₁) and (x₂, y₂) is [tex]\sqrt{(x_2 - x_1)^2+ (y_2 -y_1)^2)}[/tex]

The distance between A(2, 6) and B(8, 2),

AB= [tex]\sqrt{{(8-2)^2+(2-6)^2} }[/tex]= [tex]\sqrt{6^2+(-4)^2}}[/tex]=[tex]\sqrt{{36+16}}[/tex]=[tex]\sqrt{52}[/tex] =7.2

To know more about Coordinate plane on:

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