find the measure of the acute angles pls help

Find The Measure Of The Acute Angles Pls Help

Answers

Answer 1

Answer:

60 degrees

and

52 degrees


Related Questions

What is 2x-47+(4-1)?

Answers

Answer:

x = 280/17 = 16.471

Step-by-step explanation:

4 ÷ (-6) =

please write the answer as a fraction

Answers

4 and 6 have 2 in common
-2/3

Answer:

[tex] \frac{ - 2}{3} [/tex]

Step-by-step explanation:

if it is right mark me brainliest

Help pls and thank you!!

Answers

Answer:

it's 8x

hope i could help :)

7x + 2y + x + 10y=180

Answers

The answer is x=-3/2y+45/2

To manufacture scooters, the manufacturer has a fixed cost of 34,400$$ plus a variable cost of n $$ per scooter. Find 100$$, the number of scooters that need to be produced so that the average cost per scooter is 180$$.

Answers

Answer:

The number of scooters that need to be produced so that the average cost per scooter is $180 is 430 scooters.

Step-by-step explanation:

Note: This question is not properly structured/written. The question is therefore rewritten properly before answering the question as follows:

To manufacture scooters, the manufacturer has a fixed cost of $34,400 plus a variable cost of $100 per scooter. Find n, the number of scooters, that need to be produced so that the average cost per scooter is $180.

The explanation of the answer is now provided as follows:

The number of scooters can be calculated as follows:

Variable cost per scooter = $100

n = number of scooter = ?

Total variable cost = Variable cost per scooter * n = $100 * n = $100n

Total cost = Fixed cost + Total variable cost = $34,400 + $100n

Average cost per scooter = Total cost / n = $180 ................ (1)

Substituting the value for Total cost into equation (1) and solve for n, we have:

($34,400 + $100n) / n = $180

$34,400 + $100n = $180n

$34,400 = $180n - $100n

$34,400 = $80n

n = $34,400 / $80

n = 430

Therefore, the number of scooters that need to be produced so that the average cost per scooter is $180 is 430 scooters.

Do all numbers have a prime factorization

Answers

Answer:

It depends on the numbers

Step-by-step explanation:

Give some examples

Select the correct answer.
A parabola has an x-intercept of -1, a y-intercept of -3, and a minimum of -4 at x = 1.

Which graph matches this description? ( in the screenshots)

Answers

Step-by-step explanation:

answer A should be correct

Line r is parallel to line t. Find m<5.

Answers

Answer:

B. 135

Step-by-step explanation:

According to corresponding angles answer is b

135 is congruent to angle 1 and angle 1 is congruent to angle 5

so if angle 1 is 135 then angle 5 is 135

Brainliest please

Hope this helps

Answer:

d.

Step-by-step explanation:

straight angle = 180 degress

135+45=180

In order to prove △ABC ≅ △DBC by SAS, what additional information must be given?

Answers

SAS: if two pairs of corresponding sides and the included angles are congruent, then the 2 triangles are congruent.

Two triangles are congruent if two pairs of corresponding angles and included sides are congruent.

What is the triangle?

Triangle is a polygon that has three sides and three angles. The sum of the angle of the triangle is 180 degrees.

In order to prove △ABC ≅ △DBC by SAS. Then the additional information must be given will be

SAS: Two triangles are congruent if two pairs of corresponding sides and included angles are congruent.

More about the triangle link is given below.

https://brainly.com/question/25813512

The endpoints of CD are (-2,-4) and D (6,2). What are the coordinates of the midpoint of CD?

Answers

The midpoint of the line segment CD whose coordinates (-2,-4) and D (6,2) will be (2, -1).

What is the mid-point of the line segment?

Let AB be the line segment and C be the mid-point of line segment AB. Let the coordinate of point A (x₁, y₁), the coordinate of point B (x₂, y₂), and the coordinate of the mid-point (x, y).

Then the coordinate of the mid-point of the line segment is given as,

(x, y) = [(x₁ + x₂) / 2, (y₁ + y₂) / 2]

The endpoint of the segment CD is given as C(-2, -4) and D(6, 2). Then the mid-point of the line segment CD will be

(x, y) = [(-2 + 6) / 2, (-4 + 2) / 2]

(x, y) = (4/2, -2/2)

(x, y) = (2, -1)

The midpoint of the line segment CD whose coordinates (-2,-4) and D (6,2) will be (2, -1).

More about the Mid-point link is given below.

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Find the length of the third side to the nearest tenth.
3
9

Answers

Answer:

8.5

Step-by-step explanation:

X^2 = 9^2 - 3^2

x^2 = 81 - 9

x^2 = 72

x = √72

x = 8.485

Here you go. Hope this helped :)

Could anybody help me with this i will cashapp u $5 if its right

Answers

Answer:

a. Correct

b. Incorrect

c. Correct

d. Incorrect

e. Incorrect

Step-by-step explanation:

b. Incorrect because negative hours do not make sense

d. 80 is achieved only with more than 3.89 hours of study, so 3.5 is not enough

e. No, the score is the dependent, it comes out of the formula.

Blake practices the piano 420 minutes in 4 weeks. assuming he practices the same amount every week, how many minutes would he practice in 1 weeks?

Answers

Answer: 105 minutes in 1 week


Explanation: 420min / 4 weeks = 105min/week

2. (05.02 LC) Which equation does the graph below represent? (5 polnts) 8 2 .2 O y = 2x Y = 2 x y = 2 + x​

Answers

Answer:

b

Step-by-step explanation:

Samantha puts $800.00 into an account to use for school expenses. The account earns 11% interest, compounded annually. How much will be in the account after 10 years? Round your answer to the nearest cent.

Answers

Answer:

$2271.54

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Algebra I

Compounded Interest Formula: [tex]A=P(1+\frac{r}{n} )^{nt}[/tex]

A is final amountP is principle amountr is raten is compoundt is time in years

Step-by-step explanation:

Step 1: Define

P = 800.00

r = 0.11

n = 1

t = 10

Step 2: Find A

Substitute [Formula]:                    [tex]A=800(1+\frac{0.11}{1} )^{1(10)}[/tex]Divide/Multiply:                             [tex]A=800(1+0.11 )^{10}[/tex]Add:                                               [tex]A=800(1.11 )^{10}[/tex]Exponents:                                    [tex]A=800(2.83942)[/tex]Multiply:                                         [tex]A=2271.54[/tex]

Will the standard form of 8.5 × 10–3 be more or less than 1? Explain what effect the negative exponent has.

Answers

The value is less than 1 and the impact of the negative exponent is that it moves the decimal point to the left

What is standard form?

Standard form can be defined as a mathematical way of writing large or too small numbers in a defined manner.

Given the standard form;

8.5 × 10–3

The negative exponent (-3) indicates an addition of three zeros ruled out from the start.

It could be written as;

0. 0085

This is 0. 9915 less than the value of 1

The impact of the negative value is that it moves the decimal point to the left.

Thus, the value is less than 1 and the impact of the negative exponent is that it moves the decimal point to the left

Learn more about standard form here:

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What are the solutions of the quadratic equation?
3x? - 23x + 40 = 0

Answers

The correct answer would be 2

HELP ASAPPP!!!! Please dude

Answers

Answer:

A

Step-by-step explanation:

That's the only one that makes sense

Answer:

It's either A or C

Step-by-step explanation:

Can you help me I have no idea how to do this

Answers

Answer:

[tex](f + g)(x) = 7 - 6x[/tex] --- (1)

[tex](f - g)(x) = 6x - 1[/tex] -- (2)

[tex](f . g)(x) =4(5^x)[/tex] ---- (3)

[tex](f / g)(x) = \frac{4}{5^x}[/tex] ----- (4)

[tex](f + g)(x) = -7x-7[/tex] --- (5)

[tex](f - g)(x) = 9x+ 9[/tex] --- (6)

[tex](f . g)(x) = (-8)(x+1)^2[/tex] --- (7)

[tex](f / g)(x) = -\frac{1}{8}[/tex] ----- (8)

[tex]F(t) = \frac{9}{5}t^2 + 32[/tex] ---- (9)

[tex]T(t) = (t - 2)^2 - 4[/tex] --- (10)

Step-by-step explanation:

Given

[tex]f(x) = 3[/tex]

[tex]g(x) = 4 - 6x[/tex]

Solving (1): (f + g)(x)

[tex](f + g)(x) = f(x) + g(x)[/tex]

So, we have:

[tex](f + g)(x) = 3 + 4 - 6x[/tex]

[tex](f + g)(x) = 7 - 6x[/tex]

Solving (2): (f - g)(x)

[tex](f - g)(x) =f(x) - g(x)[/tex]

So, we have:

[tex](f - g)(x) =3 - (4 - 6x)[/tex]

[tex](f - g)(x) =3 - 4 + 6x[/tex]

[tex](f - g)(x) =-1 + 6x[/tex]

[tex](f - g)(x) = 6x - 1[/tex]

Given

[tex]f(x) = 4[/tex]

[tex]g(x) = 5^x[/tex]

Solving (3): (f . g)(x)

[tex](f . g)(x) =f(x) * g(x)[/tex]

So, we have:

[tex](f . g)(x) =4 * 5^x[/tex]

[tex](f . g)(x) =4(5^x)[/tex]

Solving (4): (f / g)(x)

[tex](f / g)(x) = \frac{f(x)}{g(x)}[/tex]

So, we have:

[tex](f / g)(x) = \frac{4}{5^x}[/tex]

Given

f(x) = x + 1

g(x) = -8 - 8x

Solving (5): (f + g)(x)

[tex](f + g)(x) = f(x) + g(x)[/tex]

So, we have:

[tex](f + g)(x) = x + 1 -8-8x[/tex]

Collect Like Terms

[tex](f + g)(x) = x -8x+ 1 -8[/tex]

[tex](f + g)(x) = -7x-7[/tex]

Solving (6): (f - g)(x)

[tex](f - g)(x) = f(x) - g(x)[/tex]

So, we have:

[tex](f - g)(x) = x + 1 -( -8-8x)[/tex]

[tex](f - g)(x) = x + 1 +8+8x[/tex]

Collect Like Terms

[tex](f - g)(x) = x +8x+ 1 +8[/tex]

[tex](f - g)(x) = 9x+ 9[/tex]

Solving (7): (f . g)(x)

[tex](f . g)(x) = f(x) . g(x)[/tex]

So, we have:

[tex](f . g)(x) = (x+1) . (-8 - 8x)[/tex]

Factorize

[tex](f . g)(x) = (x+1) .(-8) (1 + x)[/tex]

Rewrite as:

[tex](f . g)(x) = (x+1) .(-8) (x+1)[/tex]

[tex](f . g)(x) = (-8)(x+1) (x+1)[/tex]

[tex](f . g)(x) = (-8)(x+1)^2[/tex]

Solving (8): (f / g)(x)

[tex](f / g)(x) = \frac{f(x)}{g(x)}[/tex]

So, we have:

[tex](f / g)(x) = \frac{(x+1)}{(-8-8x)}[/tex]

Factorize

[tex](f / g)(x) = \frac{(x+1)}{-8(1+x)}[/tex]

[tex](f / g)(x) = \frac{1}{-8}[/tex]

[tex](f / g)(x) = -\frac{1}{8}[/tex]

Solving (9):

From the question, we have that:

[tex]F(c) = \frac{9}{5}c + 32[/tex]

[tex]C(t) = t^2[/tex]

Required

Determine function F in terms of c

The implication of this question is to solve for [tex]F(c(t))[/tex]

If [tex]F(c) = \frac{9}{5}c + 32[/tex] and [tex]C(t) = t^2[/tex],

Then

[tex]F(c(t)) = \frac{9}{5}*t^2 + 32[/tex]

[tex]F(c(t)) = \frac{9}{5}t^2 + 32[/tex]

This can be rewritten as:

[tex]F(t) = \frac{9}{5}t^2 + 32[/tex]

Solving (10):

[tex]T(h) = h^2 - 4[/tex]

[tex]h(t) = t - 2[/tex]

Required

Find [tex]T(h(t))[/tex]

If [tex]T(h) = h^2 - 4[/tex]  and   [tex]h(t) = t - 2[/tex], then

[tex]T(h(t)) = (t - 2)^2 - 4[/tex]

This is gotten by substituting t -2 for h

The solution can be rewritten as:

[tex]T(t) = (t - 2)^2 - 4[/tex]

Which function has only one x-intercept at (-6, 0)?
O fx) =x(x -6)
O fx) = (x-6)(x -6)
O f() = (x+ 6)(x - 6)
O f)= (x+ 6)(x + 6)
Please help

Answers

Answer: O f)= (x+ 6)(x + 6)

Hope this helps :)

The correct answer is D

I need to graph y=−2.5, please help!?!

Answers

Answer:

Step-by-step explanation:

(a) Work out the value of (16/81)^3/4

Answers

Answer: 8/27

Step-by-step explanation:

Just evaluate the equation.

Do it in this order: Parenthesis, Exponents, Multiply/Divide, Add/Subtract.

So:

16/81 = 16/81

16/81 To the Power of 3/4 = 0.2^0.75 = 8/27

who is good at math?! IM GIVING BRAINLIEST! comment or answer on the question so we can talk cuz i need help!!

Answers

Answer:

Wheres the question then i'll help

Step-by-step explanation:

I’m not the brightest but I can help with math

For their history project, students case to either write a report or give a presentation. Two fifth of the students wrote a report and 0.6 of the students gave a presentation. Dominic said that more students gave a presentation. Do you agree with Dominic? Use numbers and words to support your answer. *

Answers

Answer: Yes. Dominic is correct

Step-by-step explanation:

We are informed that Two fifth of the students wrote a report. This also means that (2/5 × 100) = 40% = 0.4 wrote a report and 0.6 of the students gave a presentation.

From the decimals gotten, we can see that 0.6 is more than 0.4. Therefore, more students gave a presentation. This implies that Dominic is correct.

Lee won 30 tickets at the carnival. He then gave each of his friends 2 tickets. He has 4 tickets left. How many friends does Lee have?

Answers

Answer: 30-4=x  4+x=30 x=26

Step-by-step explanation: So he has 30 tickets and he gives 2 to each of his friends which means that lee has 26 friends with 4 tickets left over.


Between 7 and 8 o'clock, there were 56 vehicles in the zoo parking lot. There were 3 times as many vans as cars.
How many vans and how many cars were counted?

Answers

Answer:

14 cars, 42 vans

Step-by-step explanation:

can divide the total by 4, since the number of cars is just 3x the number of vans

x+3x=56

4x=56

56/4

14 cars times 3 plus the original 14

There are 14 cars times 3 plus the original 14.

What is the unitary method?

The unitary method is a method for solving a problem by the first value of a single unit and then finding the value by multiplying the single value.

Given Between 7 and 8 o'clock, there were 56 vehicles in the zoo parking lot. There were 3 times as many vans as cars.

Then it can divide the total by 4, since the number of cars is just 3x the number of vans.

x+3x=56

4x=56

56/4

Therefore, there are 14 cars times 3 plus the original 14.

Learn more about the unitary method here;

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Find the ratio of the speed of a cycle 15km per hour to the speed of scooter 30km per hour​

Answers

Step-by-step explanation:

15:30

Divide by 5

3:6

1:2

Answer:

3:4

Step-by-step explanation:

speed of cycle=15 km pers

speed of scooter=30 km per s

Now,

Ratio of speed= distance travelled ÷time taken

= (15+30)÷60 (1 hour=60 min)

= 45÷60

= 3÷4

= 3:4

:: The answer is 3:4.

If CM=15, Find DC and DM

Answers

image ????? please attach image and try again

find the 24th term of the arithmetic
sequence whose common difference is d=4
and whose first term is a1=1
what is the answer?

Answers

Answer:93

Step-by-step explanation:

an island has three towns located at points with the coordinates a (15,3) b (25,10) and c (0,20) where the coordinates have units of Km the government wants to locate a toxic waste dump at a position as far as possible away from each town you may assume that this location is not on the edge of the island find the coordinates at the point where the toxic waste dump should be located

Answers

9514 1404 393

Answer:

  (13.06, 16.41)

Step-by-step explanation:

Any point not on a perpendicular bisector of the line between towns will be closer to one town than the other. So, the intersection of perpendicular bisectors will be the equidistant from all towns. That point is the circumcenter of the circle circumscribing the triangle with the towns as its vertices. This can be found as the intersection of two perpendicular bisectors of the segments between the towns.

The midpoint of AB is ...

  (A +B)/2 = ((15, 3) +(25, 10))/2 = (40, 13)/2 = (20, 6.5)

The midpoint of AC is ...

  (A +C)/2 = ((15, 3) +(0, 20))/2 = (15, 23)/2 = (7.5, 11.5)

__

The differences between points are ...

  B -A = (25, 10) -(15, 3) = (10, 7)

  C -A = (0, 20) -(15, 3) = (-15, 17)

Then the perpendicular bisector equations can be written as ...

  bisector of AB  ⇒  10(x -20) +7(y -6.5) = 0

     10x +7x -245.5 = 0

  bisector of AC  ⇒  -15(x -7.5) +17(y -11.5) = 0

     -15x +17y -83 = 0

These have coefficients that aren't particularly nice, so a method similar to Cramer's Rule is suitable for solving this pair of equations. Using the "cross multiplication method", we have ...

  x = (7(-83) -17(-245.5))/(10(17) -(-15)(7)) = 3592.5/275 = 13 7/110 ≈ 13.06

  y = (-245.5(-15) -(-83)(10))/275 = 4512.5/275 = 16 9/22 ≈ 16.41

The point as far as possible from each town within the boundary of the island has coordinates (13.06, 16.41).

_____

Further detail regarding the solution

Here, we have written the equation for the perpendicular bisector this way. The difference in coordinates between points R and S can be called ...

  R -S = (∆x, ∆y)

The midpoint of segment RS can be called ...

  (R +S)/2 = (h, k)

Then the line that is a perpendicular bisector of RS can be written as ...

  ∆x(x -h) +∆y(y -k) = 0

This is the form that is used above.

__

The "cross multiplication method" for solving a pair of general-form linear equations ...

  ax +by +c = 0

  dx +ey +g = 0

will give the solution as ...

  1/(ae -db) = x/(bg -ec) = y/(cd -ga)

If you write the coefficients in two rows of four, the pattern of products and differences is easy to see.

  [tex]\left[\begin{array}{cccc}a&b&c&a\\d&e&g&d\end{array}\right][/tex]

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