Answer: Ca(NO3)2(aq) + 2NaOH(aq) —> Ca(OH)2(s) + 2NaNO3(aq)
Substitution
Explanation:
The given reaction is a substitution reaction in which hydroxil group is exchanged between compounds.
Substitution Reaction:
It is a reaction in which functional group of a compound replaced by the another functional group.
For example-
[tex]\bold {Ca(NO3)_2(aq) + 2NaOH(aq) \rightarrow Ca(OH)_2(s) + 2NaNO_3(aq)}[/tex]
In the reaction hydroxil group is exchanged between compounds.
1 mole of aqueous calcium nitrate react with 2 moles aqueous sodium hydroxide to produce 1 mole of solid precipitate calcium hydroxide and 2 moles aqueous sodium nitrate.
Therefore, the given reaction is a substitution reaction in which hydroxil group is exchanged between compounds.
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5.6 g of Iron reacts with excess fluorine gas.
The mass of iron fluoride produced is 11.3 g
What is the formula of the iron fluoride?
Answer: FeF3 Iron(III) fluoride
Explanation: 5.6 g = 1/10 mole Fe
11.3-5.6g F = 5.7 = 3/10 mole F
I'll give brainliest to whoever gives me the answer to all of this.
a golf ball is hit at a distance of 300 yards in 10 seconds what is the speed of the golf ball
Answer:
30 yard per second
Explanation:
300/10 = 30
What is the concentration of lithium ions in 0.400 M Li₂HPO₄?
Answer: 0.800 M
Basically, the ratio is 2:1, so when you have 1 M of Li2HPO4 it means you have 2 M in the concentration of lithium ions. So knowing the ratio, we know we just need to multiply 0.400 x 2.
I'm bad at explaining it, but got it right on chem101 sooo
The concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄ is 0.8 M.
The concentration of a substance is simply the amount of the substance in 1 L of water.
To obtain the concentration of lithium ion, Li⁺ in Li₂HPO₄, we'll begin by writing the dissociation equation of Li₂HPO₄. This is illustrated below:
Li₂HPO₄ (aq) <=> 2Li⁺(aq) + HPO₄²¯(aq)From the balanced equation above,
1 mole of Li₂HPO₄ produced 2 moles of Li²⁺.
Finally, we shall determine the concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄. This can be obtained as follow:
From the balanced equation above,
1 mole of Li₂HPO₄ produced 2 mole of Li⁺.
Therefore, 0.4 M Li₂HPO₄ will produce = 2 × 0.4 = 0.8M Li²⁺
Thus, 0.8 M lithium ion, Li⁺ is present in the solution.
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Define the following Vocabulary words
1. Archae Bacteria
2. Bacteria
3. Eukarya Kingdom
4. Domain
235U92 + 1N0 + 135Cs55 + 99Rb37 + x1n0
As human populations grow, it becomes more important to use renewable sources of energy Which of the following objects uses energy from a renewable source?
a stove that is powered by natural gas
a refrigerator that runs on solar power
a lantern that burns oil from beneath Earth's surface
a foaster that uses electricity from a coal-burning power plant
Explanation:
Moreover, increasing use of fossil fuels also causes serious environmental problems. Hence, there is a pressing need to use renewable energy sources like solar energy, wind, tide, biomass and energy from waste material. (i) it reduces the dependence on fossil fuels for energy. (ii) they donot produces pollution.
Helppppp pleaseeee xxxxxx
Answer:
2812.6 g of H₂SO₄
Explanation:
From the question given above, the following data were obtained:
Mole of H₂SO₄ = 28.7 moles
Mass of H₂SO₄ =?
Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:
Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)
= 2 + 32 + 64
= 98 g/mol
Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:
Mole of H₂SO₄ = 28.7 moles
Molar mass of H₂SO₄ =
Mass of H₂SO₄ =?
Mole = mass / Molar mass
28.7 = Mass of H₂SO₄ / 98
Cross multiply
Mass of H₂SO₄ = 28.7 × 98
Mass of H₂SO₄ = 2812.6 g
Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄
Menstruation occurs on a ______ interval from puberty until menopause
A. Three months
B. Two months
C. Half month
D. One month
PLEASE HURRY ILL GIVE 95 POINTS!
A student dissolved 5g of table salt in 100 mL of water in a beaker. When you compare the total mass of the salt and water before mixing to the mass of the solution after mixing, which is true?
A. The total mass of the solution after mixing, Will increase by a large amount
B. The total mass of the solution after mixing, Will increase by a small amount
C. The total mass of the solution after mixing will neither increase nor decrease
D. The total mass of the solution after mixing, Will decrease by a small amount
Answer:
B.
Explanation:
Answer:
B is the correct answer
Explanation:
Choose the correct statement regarding the behavior of water.Group of answer choicesThe heat capacity of liquid water is greater than the heat capacity of solid ice.The water phase with the smallest temperature increase when adding 10 kcal of heat is solid ice.Ice has a higher density than liquid water and therefore sinks.The water phase with the smallest temperature increase when adding 10 kcal of heat is gas vapor.The heat capacity of gas vapor is greater than the heat capacity of liquid water.
Answer:
The water phase with the smallest temperature increase when adding 10 kcal of heat is solid ice.
Explanation:
The rest of the statements are incorrect. The density of ice is lower than the density of water. The heat capacity of solid ice is greater almost twice the heat capacity of the liquid water. The heat capacity of vapors is less than heat capacity of liquid.
Calculate the solubility at of in pure water and in a solution. You'll find data in the ALEKS Data tab lead chromate.
Answer:
1.34 * 10^-7 M
Explanation:
The Ksp of lead II chromate is 1.8 x 10^-14
So, we have that;
PbCrO4(s) -----> Pb^2+(aq) + CrO4^2-(aq)
s s
Where s = molar concentration of Pb^2+(aq) and CrO4^2-(aq)
and;
[Pb^2+] = [CrO4^2-]
This implies that Ksp = s^2
s = √Ksp
s = √1.8 x 10^-14
s = 1.34 * 10^-7 M
Which of these describes the essential conclusion of the Rutherford experiment? The atom contains a very small nucleus that contains most of its mass. The proton is positively charged and the neutron has no charge? Atoms are solid spheres with electrons suspended in them like chocolate chips in a cookie. Mass is neither made nor consumed in a chemical reaction.
Answer:
The atom contains a vey small small nucleus that contains most of its mass.
Explanation:
The Rutherford gold leaf experiment concluded that most (99%) of all the mass of an atom is in the nucleus of the atom, that the nucleus is very small (105 times small than the size of the atom) and that is is positively charged.
A banana has 0.42 g of potassium. How many moles of potassium are in a banana ?
Answer:
0.011mole
Explanation:
Given parameters:
Mass of potassium in the banana = 0.42g
Unknown:
Number of moles of potassium in the banana = ?
Solution:
To solve this problem, we use the expression below:
Number of moles = [tex]\frac{mass}{molar mass}[/tex]
Molar mass of K = 39g/mol
Number of moles = [tex]\frac{0.42}{39}[/tex] = 0.011mole
what does the roman numeral stand for in copper(1) oxide should it not be copper(II) oxide
Answer:
The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.
Explanation:
Roman numeral is used to indicate the oxidation number of an element in a compound.
The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.
This can be seen from the following illustration:
copper(I) oxide => Cu₂O
Oxidation number of O = –2
Oxidation number of Cu₂O = 0
Oxidation number of Cu =?
Cu₂O = 0
2Cu + O = 0
2Cu – 2 = 0
Collect like terms
2Cu = 0 + 2
2Cu = 2
Divide both side by 2
Cu = 2/2
Cu = 1
Thus, we can see that the oxidation number of Cu in Cu₂O is 1. Hence the name of Cu₂O is copper(I) oxide indicating that the oxidation number of of copper (Cu) in the compound is 1.
For copper(II) oxide, we shall determine the oxidation number of Cu. This can be obtained as follow:
copper(II) oxide, CuO => CuO
Oxidation number of O = –2
Oxidation number of CuO = 0
Oxidation number of Cu =?
CuO = 0
Cu + O = 0
Cu – 2 = 0
Collect like terms
Cu = 0 + 2
Cu = 2
Thus, the oxidation number of Cu in CuO is 2. Hence the name of CuO is copper(II) oxide indicating that the oxidation number of of copper (Cu) in the compound is 2.
From the above illustrations,
We can see that the roman numeral in both copper(I) oxide, Cu₂O and copper(II) oxide, CuO are different because the oxidation number of Cu in both cases are different.
2. Methyl dichloroacetate (Cl2CHCO2CH3) decays into methanol (CH3OH) and dichloroacetic acid (Cl2CHCO2H) on reaction with water. Given a rate constant of 2.7 x 10-4/sec and an initial concentration of 1-ppm methyl dichloroacetate in the water, how much methanol will be present in the water after 30 min
Answer:
2.69 * 10^-6 Mol/L
Explanation:
The equation of the reaction is;
Cl2CHCO2CH3 -------------------> Cl2CHCO2H + CH3OH
To convert from ppm concentration to Mol/L, we have
M = ppm/MM * 1000
Where;
M = mol/l
MM= Molar mass
M = 1/142.97 g/mol * 1000 =
M= 6.99 * 10^-6 Mol/L
For first order reaction;
ln[A] = ln[A]o -kt
Given that
[A]o = 6.99 * 10^-6 Mol/L
[A]=??
k= 2.7 x 10-4/sec
t= 30 mins * 60 = 1800 s
ln[A] = ln[6.99 * 10^-6] - (2.7 x 10-4 * 1800)
ln[A] = -11.87 - 0.486
ln[A] = -12.356
[A] = e^(-12.356)
[A] = 4.3 * 10^-6 Mol/L
Concentration of methanol present after 30 mins= 6.99 * 10^-6 - 4.3 * 10^-6 = 2.69 * 10^-6 Mol/L
One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal
and one mole of water. 5.00 g of the metallic oxide produces 2.32 g of the metal. What is the metallic
oxide?
Answer:
Lithium oxide, Li₂O.
Explanation:
Hello!
In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:
[tex]M_2O+H_2 \rightarrow 2M+H_2O[/tex]
Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:
[tex]5.00gM_2O*\frac{1molM_2O}{(2x+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{xgM}{1molM} = 2.32gM[/tex]
Thus, we perform the operations in order to obtain:
[tex]\frac{10x}{2x+16}=2.32[/tex]
So we solve for x as shown below:
[tex]10x = 2.32(2x+16)\\\\10x = 4.64x+37.12\\\\x = \frac{37.12}{10-4.64}\\\\x= 6.93 g/mol[/tex]
Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.
Best regards!
How many moles are in 3.01 x 10^23 atoms of zinc?
Answer:
What is ^ for?
Explanation:
PLEASE HELP it’s due in 30 minutes
Answer:
1-6
3 1 3 3 2 2
Explanation:
What is the name of the sugar that is created
through photosynthesis?
Nopetose
Glucose
Sucrose
Blooptose
:D
Answer:
Glucose!!
Explanation:
Also keep in mind that the actual sugar produced from photosynthesis is C6H12O6, which is the basis for glucose as well as other complex molecules
Answer:
Glucose
Explanation:
photosynthesis uses the energy from the light to convert carbon dioxide molecules which makes glucose
Help solve please, it’s due in less than an hour or so.
sorry i can only figure out 1 but the answer is
------------------------------------------------------------------
124
hope you do good on your test :D
pertain to the following class, Point:
public class Point {
private double x;
private double y;
public Point() {
this (0, 0);
}
public Point(double a, double b) {
/* missing code */
}
// ... other methods not shown
}
Which of the following correctly implements the equals method?
public boolean equals(Point p) {
return (x == p.x && y == p.y );
}
public void equals(Point p) {
System.out.println(x == p.x && y == p.y);
}
public void equals(Point p) {
return (x == p.x && y == p.y );
}
public boolean equals(Point p) {
return (x == Point.x && y == Point.y);
}
public boolean equals(Point p) {
System.out.println(x == p.x && y == p.y);
}
_______________________
The default constructor sets x and y to (0, 0) by calling the second constructor. What could be used to replace /* missing code */ so that this works as intended?
a = 0;
b = 0;
this (x, y);
this(0, 0);
x = a;
y = b;
a = x;
b = y;
_____________________
Which of the following correctly implements a mutator method for Point?
public double getX() {
return x;
}
public void setCoordinates (double a, double b) {
x = a;
y = b;
}
None of the items listed.
public double getX() {
return a;
}
public void setCoordinates (double a, double b) {
Point p = new Point(a,b);
}
b = 0;
this (x, y);
this(0, 0);
x = a;
y = b;
a =x
This above solution is just according to the public boolean equals(Point p) { return (x == p.x && y == p.y ); and public void equals(Point p) { System.out.println(x == p.x && y == p.y);}
What is public void?An abstract class contains a pure virtual function. Pure virtual class cannot be instantiated but it can be subclassed and the subclass can provide an implementation of the function.
A virtual function declaration in the class is preceded by the virtual keyword. For example, virtual void print();
A pure virtual function declaration is followed by '=0;'
public: virtual void print()=0;
The main method header is written as public static void main(String[] args). A main method is something that is required in Java. You must have at least one class with a method named main. In Java, main is a static method, which means that it is part of its class but not parts of objects.
Therefore, This above solution is just according to the public boolean equals(Point p) { return (x == p.x && y == p.y ); and public void equals(Point p) { System.out.println(x == p.x && y == p.y);}
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Calculate what will be the volume of 10.0 grams of
gaseous ammonia at STP?
Answer:
13.22 L
Explanation:
Given data:
Volume of ammonia = ?
Mass of ammonia = 10.0 g
Temperature = standard = 273.15 K
Pressure = standard = standard = 1 atm
Solution:
First of all we will calculate the number of moles of ammonia.
Number of moles = mass/molar mass
Number of moles = 10.0 g/ 17 g/mol
Number of moles = 0.59 mol
one mole of any substance at standard temperature and pressure occupy 22.41 L . Thus, 0.59 moles of ammonia will occupy,
0.59 mol × 22.4 L / 1 mol
13.22 L
Answer: 12.4L
Explanation:
mw NH3 18
1 mole = 22.4L
10g = 10/18 moles
A gas stream contains 18.0 mole% hexane and the remainder nitrogen. The stream flows to a condenser, where its temperature is reduced and some of the hexane is liquefied. The hexane mole fraction in the gas stream leaving the condenser is 0.0500. Liquid hexane condensate is recovered at a rate of 1.50 L/min. N2 C6H14(v) (5.00 mole%) N2 C6H14(v) (18.0 mole%) Liquid condensate 1.50 L C6H14 (l)/min CONDENSER (a) What is the flow rate of the gas stream leaving the condenser in mol/min
Answer:
the flow rate of the gas stream leaving the condenser is 71.9 moles/min
Explanation:
Given the data in the question and the figure below;
N2 BALANCE
(100% - 18%) × ( mole rate in ) = ( 100% - 5%) × ( mole rate out)
0.82 × ( mole rate in ) = 0.95 × ( mole rate out)
mole rate in = 0.95 × ( mole rate out) / 0.82
mole rate in = 1.1585365853 × ( mole rate out)
now;
HEXANE BALANCE
0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate --- equ 1
but condensate = 1.5 L/min × ( density of hexane ) × 1/molar mass of hexane
we know that;
density of hexane is 0.6548 g/mL
and molar mass of hexane is 86.18 g/mol
so,
condensate = 1.5 L/min × ( 0.6548 g/mL × 1000 mL/L ) × ( 1/86.18 g/mol)
condensate = 11.3970758876
now lets substitute into equation 1
0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate
⇒ 0.18 × ( 1.1585365853 × ( mole rate out) ) = 0.0500 × ( mole rate out) + 11.3970758876
⇒ 0.208536585354(mole rate out) = 0.0500( mole rate out) + 11.3970758876
⇒ 0.208536585354(mole rate out) - 0.0500( mole rate out) = 11.3970758876
⇒ 0.158536585354(mole rate out) = 11.3970758876
mole rate out = 11.3970758876 / 0.158536585354
mole rate out = 71.889247 ≈ 71.9 moles/min
Therefore, the flow rate of the gas stream leaving the condenser is 71.9 moles/min
what is the substance? cdH) (Η) (Η
(H)C
cco
Ή) (Η
Η
Η
Answer:
A substance is a pure single form of matter. It cannot be separated into other kinds of matter by any physical process.
14.86 ml + 15.0 ml + 14.980 ml =
Answer:
44.84 ml
Explanation:
14.86
+
15.0
+
14.980
_______
44.84
Write the molecular equation for the reaction that occurs, if any, when solutions of the following substances are mixed: nitric acid and potassium carbonate. Make sure that you have properly identified all of the phases in your answer.
Answer:
The balanced molecular equation for the reaction is:
[tex]2HNO_{3_{(aq)} }[/tex] + [tex]K_{2} CO_{3} _{(s)}[/tex] → [tex]2KNO_{3} _{(s)}[/tex] + [tex]H_{2} O_{(l)[/tex] + [tex]CO_{2} _{(g)}[/tex]↑
Explanation:
The weak nitric acid reacts with the strong potassium base to produce salt, water and carbon dioxide which is given off.
Molecular ratio of reactants is 2 : 1.
All phases are represented in the equation: aq for aqueous, l for liquid and g for gas (notice how they are written in subscript).
I hope this was helpful.
What is the name of the process happening in the picture? How do you know it’s that process? Explain your answer in 2 to 3 sentences complete help please
Answer:
The name of the process happening in the picture is explained below in details.
Explanation:
The process in the picture is photosynthesis. The plant is taking CO2 and H2O and using light to form glucose which would be the sugars and creating a byproduct of oxygen that is being released into the atmosphere. How did you know this is photosynthesis? A big thing clearly is the plant and how it’s taking H2O and CO2 and making glucose so it isn’t cellular respiration (if you don’t know what that is don’t worry, if you are learning about this you are bound to come across that later) and it’s releasing oxygen into the atmosphere and light has a function in this process according to the image.
(1) Solution A and B are separated by a membrane that is permeable to Mg2 and impermeable to Cl-. Solution A contains 0.1 mM MgCl2, solution B contains 100 mM MgCl2. Mg2 will be at electrochemical equilibrium when solution A is around ____________ mV. 180 mV - 180 mV 90 mV - 90 mV 60 mV - 60 mV
Answer:
90 mV
Explanation:
Faraday constant, F = 96487
Gas constant, R = 8.314
Number of mole of electron transferred, Z = 2
MgCl in solution A, = 0.1 mm
MgCl in solution A, = 100 mm
Using the relation :
E=(RT/ZF) In(Mg out/Mgin)
E = (8.314*298) / (2*96485) * In(100/0.1)
E = (2477.572 / 192970) * 6.9077552
E = 0.0128391 * 6.9077552
E = 0.0886897 V
E = 88.68 mV (approximately 90 mV)
How to Balance __MgF2 + __Li2CO3 + __ LiF