Given that both liquid A and B exert the same amount of pressure .What would be the height of column of liquid A if the density of liquid A is twice the density of liquid B and the height of column of liquid B is 10cm ?show you are work?​

Answers

Answer 1

Answer:

ans 5

Explanation:

hope it's help It seems to me


Related Questions

A merry-go-round of radius 2 m is rotating at one revolution every 5 s. A
child is located at 1 m from the axis. A teenager is located at 2 m from the
axis.
What is the angular speed of the child?
What is the angular speed of the teenager?
What is tangential speed of the child?
What is the tangential speed of the teenager?

Answers

Answer:

a) The angular speed of the child is approximately 1.257 rad/s

b) The angular speed of the teenager is approximately 1.257 rad/s

c) The tangential speed of the child is approximately 1.257 m/s

d) For the child, r = 2 m

The tangential speed of the teenager is approximately 2.513 m/s

Explanation:

The revolutions per minute, r.p.m. of the merry-go-round = 1 revolution/(5 s)

The radius of the merry-go-round = 2 m

The location of the child = 1 m from the axis

The location of the teenager = 2 m from the axis

1 revolution = 2·π radians

Therefore, we have;

The angular speed, ω = (Angle turned)/(Time elapsed) = (2·π radians)/(5 s)

∴ The angular speed of the merry-go-round, ω = 2·π/5 radians/second

a) The angular speed of the child = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s

b) The angular speed of the teenager = The angular speed of the merry-go-round = 2·π/5 radians/second ≈ 1.257 rad/s

c) The tangential speed, v = r × The angular speed, ω

Where;

r = The radius of rotation of the object

For the child, r = 1 m

The tangential speed of the child = 1 m × 2·π/5 radians/second = 2·π/5 m/s ≈ 1.257 m/s

d) For the child, r = 2 m

The tangential speed of the teenager = 2 m × 2·π/5 radians/second = 4·π/5 m/s ≈ 2.513 m/s

Din Djarin pushes on a crate of frog eggs (with a mass of 88) with a force of 240 N, if µs= .4 and µk= .133 what is the net force acting on the crate?

I'll give brainliest to anyone who can answer this, too.

Answers

Answer:

R = mg

F = µsR

Fs= 0.4 × ( 88 × 10)

Fs = 772 N

Fk= µk R

Fs= 1.33 × 880 N

Net force = (772+(1.33×880))-240 N

Soccer is technically know as what ?

a - Futbol

b - Association football

c - Association soccer

Answers

Answer:

c - Association soccer

because there is football in form of American football, hence it's soccer

Answer:

B.

Explanation:

Soccer was the only football-type game in the United States until American-style football became popular in the 1870s

The blades of a metal cutter are shorter than the blades of paper cutter scissor. Give reason​

Answers

Answer:

Metal is a tougher material to cut though, so the blades must be shorter to create more pressure to break through the metal. Paper on the other hand is easier to cut through so the blades can be longer in order to cut more in each snip.

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