Answers
F = 6.0 x 10⁻⁸ N
Further explanationGiven
mass of 2 dump trucks = 1500 kg
distance = 50 m
Required
Gravitational force
Solution
Newton's Gravity Law:
[tex]\rm F=G.\dfrac{m_1.m_2}{r^2}[/tex]
with F = gravitational force,
G = gravitational constant,
m1, m2 = mass of object,
r = distance between two objects.
Input the value :
F = (6.67.10⁻¹¹N.m² / kg² x 1500²) : 50²
F = 6.0 x 10⁻⁸ N
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Identify and define Four causes of infections diseases
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Answer:
Bacteria
Fungi
Viruses
Parasites
A car accelerates from 20.0 m/s to 28.0 m/s over a distance of 50.0 m. What is the car’s acceleration?
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Answer:
Explanation:
[tex]V^2=V^2_o+2a(x_f-x_i)[/tex]
[tex]28^2=20^2+2a(50)\\784=400+100a\\384=100a\\a=3.84m/s^2[/tex]
A 50 kg bumper car with a 40 kg child and it is at rest when a 60 kg child in her own bumper car slams into it the collision last point1 seconds and the rubber bumpers are perfectly bouncy with no heating from the collision what is the force experienced by the first car
Answers
Answer:
F = 99 v₂₀
v₂₀ = 1 m / s, F = 99 N
Explanation:
In this exercise it is asked to find the force during the collision, for this we use the relationship between the momentum and the momentum of car 1
I = Δp
F t = p_f- p₀
F t = m (v_f -v₀) (1)
We must find the final speed of car 1, for this we define a system formed by the two cars, in this case the forces during the collision are internal and the moment is conserved
initial instant. Before the crash
p₀ = 0 + m₂ v₂₀
final instant. After the crash
p_f = m₁ v₁ + m₂ v_{2f}
the moment is preserved
p₀ = p_f
m₂ v₂₀ = m₁ v_{1f} + m₂ v_{2f} (2)
m₂ (v₂₀ - v_2f}) = m₁ v_{1f}
as the collision is elastic the kinetic energy is also conserved
K₀ = K_f
½ m₂ v₂₀² = ½ m₁ v_{1f}² + ½ m₂ v_{2f}²
m₂ (v₂₀² -v_{2f}²) = m₁ v_{1f}²
let's write our system of equations, using
a² - b² = (a + b) (a-b)
m₂ (v₂₀ - v_{2f}) = m₁ v_{1f}
m₂ (v₂₀ -v_{2f}) (v₂₀ + v_{2f}) = m₁ v_{1f}²
to solve we divide the equations
v₂₀ + v_{2f} = v_{1f}
with this we substitute in equation 2 and find the speed of each car, in this case we need the speed of car 1
m₂ v₂₀ = m₁ v_{1f} + m₂ (v_{1f}-v₂₀)
2m₂ v₂₀ = (m₁ + m₂) v_{1f}
v_{1f} = [tex]\frac{2m_2}{m_1+m_2} v_{2o}[/tex]
We substitute in the drive ratio of car 1
F t = m (v_f -v₀)
F = m₁ (\frac{2m_2}{m_1+m_2} v_{2o} - 0) / t
F = [tex]\frac{2m_1 m_2 }{m_1+m_2} \ \frac{v_{2o}}{t}[/tex]
the mass of each car is the mass of the car plus the mass of the boy
m₁ = 50 +40 = 90 kg
m₂ = 50 +60 = 110 kg
time is t = 1
we substitute the values
F = [tex]\frac{ 2\ 90 \ 110}{90+110} \ \frac{v_{2o}}{1}[/tex]2 90 100/90 + 110 vo2 / 1
F = 99 v₂₀
The value of the initial velocity of car 2 is not indicated in the problem, if this velocity is known it can be included and the force value is obtained, suppose that the initial velocity v₂₀ = 1 m / s
F = 99 N
Who may perform a post-exposure medical evaluation?
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B) An LPN
C) A physician's assistant
D) Your employer
Answers
Answer:a licensed physician
Explanation: taking the osha test now.
A licensed physician is the one to carry out a post-exposure medical evaluation. (Option A)
Post-Exposure Medical EvaluationPost-exposure Medical Evaluation is any medical evaluation started after exposure to a pathogen in order to prevent the infection from occurring.
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Force (N) = 250
Mass (kg) = 221
Acceleration (m/s^2) = ?
Answers
Answer:
The required acceleration is [tex]a=1.1[/tex] m/s²
Explanation:
Given
Force F = 250 NMass m = 221 kgTo determine
Acceleration a = ?
We know that acceleration is produced when a force is applied to a body.
The acceleration can be determined using the formula
[tex]F = ma[/tex]
where
F is the force m is the mass a is the accelerationnow substituting F = 250 , and m = 221 in the formula
[tex]F = ma[/tex]
[tex]250 = 221 (a)[/tex]
switch the equation
[tex]221(a) = 250[/tex]
Divide both sides by 221
[tex]\frac{221a}{221}=\frac{250}{221}[/tex]
simplify
[tex]a=\frac{250}{221}[/tex]
[tex]a=1.1[/tex] m/s²
Therefore, the required acceleration is [tex]a=1.1[/tex] m/s²
What does the potential energy of an object depend on?
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Answer:
The amount of gravitational potential energy an object has depends on its height and mass. The heavier the object and the higher it is above the ground, the more gravitational potential energy it holds.
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Answer:
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What is passive continental margin?Where there is no plate border to mark the transition from land to sea, this is known as a passive continental margin.
A good example is the east coast of the United States, where the plate boundary is a distance from the shore along the mid-Atlantic ridge. Little geological activity occurs along passive borders.
Volcanoes, mountain belts, and earthquakes all identify active margins. They lack a continental uplift and an abyssal plain, in contrast to passive margins.
The Pacific and North American Plate boundaries are visible along the west coast of the United States, which is an example of an active margin. Where there is no plate border to mark the transition from land to sea, this is known as a passive continental margin.
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B. To weave together different fictional elements in a specific pattern
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D. An event that a reader probably wouldn't have been able to predict
SUBMIT
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Answer:
D
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please find attached pdf
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yes
.......................
Answer:
C + 2H2 -----> CH4