help please #16 already found x can’t figure out y

Answer:

To the nearest tenth of a meter, this is 3,309.4 m

Step-by-step explanation:

Here, we want to convert the jogging distance to meters only

we have 2 miles 120.3 yards

5,280 ft = 1 mile

2 miles will be 5,280 * 2 = 10,560 ft

3 ft = 1 yard

x ft = 120.3 yards

x = 120.3 * 3 = 360.9 ft

Adding both together to give ft only, we have

360.9 + 10,560 = 10,920.9 ft

1 m = 3.3 ft

x m = 10,920.9 ft

x = 10,920.9/3.3

x = 3,309.363636363636

To the nearest tenth of a meter, this is 3,309.4 m

Answer:

D

Step-by-step explanation:

Answer:

100,000m

Step-by-step explanation:

find the square root of 100 squared +1,000squared

Answer:

5x + 22=

Step-by-step explanation:

8x+13-3x+9

Combine like terms.

8x-3x=5x

13+9=22

Piece it back together.

5x+22

And there you have it. Hope it helps! :3

Answer:

C

Step-by-step explanation:

Answer:

C) A car can travel 80 miles on 2 gallons of gasoline.

Step-by-step explanation:

They gave us the unit rate which is 40 mile/1 gallon of gasoline. With the unit rate, we can then simplify each answer choice.

Simplified version of answer a: 1 mile/40 gallon of gasoline (we know it is wrong because it doesn't match with the unit rate.)

Simplified version of answer b: 41 mile/ 1 gallon of gasoline (we know it is wrong because it doesn't match with the unit rate.)

Simplified version of answer c: 40 miles/1 gallon of gasoline (this one is the correct answer since it matched the unit rate.

Simplified version of answer d: 40 miles/ 20 gallon of gasoline  (we know it is wrong because it doesn't match with the unit rate.)

Hope this helped you : )

Answer:

10

Step-by-step explanation:

Answer:

10

Step-by-step explanation:

Since the triangles are similar then the ratios of corresponding sides are equal, that is

scale factor = [tex]\frac{PQ}{XY}[/tex] = [tex]\frac{3}{6}[/tex] = [tex]\frac{1}{2}[/tex]

That is the sides of Δ PQR are half those of Δ XYZ, thus

The perimeter of Δ PQR is half Δ XYZ, that is

perimeter of Δ PQR = [tex]\frac{1}{2}[/tex] × 20 = 10

Answer:

104$

Step-by-step explanation:

520/10*2

Answer:

$104

Step-by-step explanation:

cool person said it so

Answer:

6d-3

Step-by-step explanation:

Answer:

[tex]m-n=2[/tex]

Step-by-step explanation:

Instead of using the standard form, we can use the vertex form of a quadratic equation:

[tex]f(x)=a(x-h)^2+k[/tex]

Where a is the leading coefficient, and (h, k) is our vertex.

Our vertex point is at (2, -4). So, let’s substitute 2 for h and -4 for k:

[tex]f(x)=a(x-2)^2-4[/tex]

Now, we need to determine a.

We know that it passes through the point (4, 12). So, when x is 4, y must be 12. In other words:

[tex]12=a((4)-2)^2-4[/tex]

Solve for a. Subtract within the parentheses:

[tex]12=a(2)^2-4[/tex]

Add 4 to both sides:

[tex]16=a(2)^2[/tex]

Square:

[tex]16=4a[/tex]

Solve:

[tex]a=4[/tex]

Thererfore, the value of a is 4.

So, our function is:

[tex]f(x)=4(x-2)^2-4[/tex]

Now, let’s find our roots. Set the equation to 0 and solve for x:

[tex]0=4(x-2)^2-4[/tex]

[tex]4=4(x-2)^2\\1=(x-2)^2\\x-2=\pm1 \\ x=2\pm1 \\ x=3\text{ or } 1[/tex]

So, our roots are 1 and 3.

The greater root is 3 and the lesser root is 1.

Therefore, m-n, where m>n, is 3-1 or 2.

Our final answer is 2.

Answer:

2

Step-by-step explanation:

Source: AOPS

Answer: HL, SAS, LL, SSS

Step-by-step explanation:

its that easy

ΔJKL and ΔQRS are congruent by HL, SAS, SSS, and LL postulates.

Options A, B, C, and F are the correct answer.

There are ways to prove that two triangles are congruent.

- Side-Side-Side (SSS) Congruence.

The three sides of one triangle are equal to the corresponding three sides of another triangle.

- Side-Angle-Side (SAS) Congruence.

The two sides and the included angle of one triangle are equal to the corresponding two sides and included angle of another triangle.

- Angle-Side-Angle (ASA) Congruence.

The two angles and the included side of one triangle are equal to the corresponding two angles and included side of another triangle.

- Angle-Angle-Side (AAS) Congruence.

We have,

LL congruency

Two triangles are said to be congruent under LL congruence if they have two pairs of corresponding sides that are equal in length and the included angles between these pairs of sides are also equal.

HL congruency

If two right triangles have the same hypotenuse and one corresponding leg, then the two triangles are congruent (have the same shape and size).

Now,

The two triangles are right triangles.

So,

From the definition of congruency, we can say,

ΔJKL and ΔQRS are congruent by:

HL, SAS, SSS, and LL.

Thus,

ΔJKL and ΔQRS are congruent by HL, SAS, SSS, and LL postulates.

Learn more about triangle congruency here:

https://brainly.com/question/12413243

#SPJ7

Answer:

[tex]f(x)=-4(x-2)(x+7)[/tex]

Or, in standard form:

[tex]f(x)=-4x^2-20x+56[/tex]

Step-by-step explanation:

We can use the factored form of a quadratic equation:

[tex]f(x)=a(x-p)(x-q)[/tex]

Where a is the leading coefficient and p and q are the zeros of the quadratic.

We know that the x-intercepts are at (2, 0) and (-7, 0).

So, let's substitute 2 for p and -7 for q. This yields:

[tex]f(x)=a(x-2)(x+7)[/tex]

Now, we need to determine a.

We know that it passes through the point (1, 32). In other words, if we substitute 1 for x, we should get 32 for f(x). Therefore:

[tex]32=a(1-2)(1+7)[/tex]

We can now solve for a. First, compute:

[tex]32=a(-1)(8)[/tex]

Multiply:

[tex]32=-8a[/tex]

Divide both sides by -8:

[tex]a=-4[/tex]

So, the value of a is -4.

Therefore, our entire equation is:

[tex]f(x)=-4(x-2)(x+7)[/tex]

Notes:

We can expand this into standard form:

[tex]f(x)=-4(x-2)(x+7) \\ f(x)=-4(x^2+5x-14) \\ f(x)=-4x^2-20x+56[/tex]

Answer:

Search it up on utube

Step-by-step explanation:

Answer:

I

Step-by-step explanation:

3x-5+7x+5+90=180

x=9

Answer:

A

Step-by-step explanation:

√23 is 4.795

So point A

Answer:

Step-by-step explanation:

Complete question :

Cheddar Cheese

$3/lb

Swiss Cheese

$5/lb

Keisha is catering a luncheon. She has $30 to spend on a mixture of Cheddar cheese and Swiss cheese. How many pounds of cheese can Keisha get if she buys only Cheddar cheese? Only Swiss cheese? A mixture of both cheeses?

What linear equation in standard form can she use to model the situation?

Answer:

10 lbs of cheddar cheese

6 lbs of Swiss cheese

$3a + $5b = $30

Step-by-step explanation:

Given that :

Cheddar cheese = $3/lb

Swiss cheese = $5/lb

Total amount budgeted for cheese = $30

How many pounds of cheese can Keisha get if she buys only Cheddar cheese?

Pounds of cheedar cheese obtainable with $30

Total budget / cost per pound of cheddar cheese

$30 / 3 = 10 pounds of cheedar cheese

Only Swiss cheese?

Pounds of cheedar cheese obtainable with $30

Total budget / cost per pound of Swiss cheese

$30 / 5 = 6 pounds of Swiss cheese

A mixture of both cheeses?

What linear equation in standard form can she use to model the situation?

Let amount of cheddar cheese she can get = a

Let amount of Swiss cheese she can get = b

Hence,

(Cost per pound of cheddar cheese * number of pounds of cheddar) + (Cost per pound of Swiss cheese * number of pounds of Swiss cheese) = total budgeted amount

(3 * a) + (5 * b) = $30

$3a + $5b = $30

Answer:

Factors of 18 are 1, 2, 3, 6, 9, 18

Answer:

1)  if Line AB is parallel to line CD then value of a is: a=3

2) if Line AB is perpendicular to line CD then value of a is: a=1

Step-by-step explanation:

We are given A(3,5), B(7, 10), C(0, 2), and D(1, a) we need to find value of a for which:

We can use slope formula: [tex]Slope=\frac{y_2-y_1}{x_2-x_1}[/tex] to find value of a according to conditions given.

We are given:

[tex]x_1=3, y_1=5, x_2=7, y_2=10 \ for \ line \ AB \ and \\\x_1=0, y_1=2, x_2=1, y_2=a \ for \ line \ CD \[/tex]

a) Line AB is parallel to line CD.

When 2 lines are parallel there slope is same so, using this we can find value of a

[tex]Slope \ of \ line \ AB = Slope \ of \ line \ CD[/tex]

[tex]\frac{y_2-y_1}{x_2-x_1}= \frac{y_2-y_1}{x_2-x_1}\\\frac{10-5}{7-3}=\frac{a-2}{1-0} \\\frac{5}{5}=\frac{a-2}{1}\\1=a-2\\a=1+2\\a=3[/tex]

So, if Line AB is parallel to line CD then value of a is: a=3

b) Line AB is perpendicular to line CD.

When 2 lines are perpendicular there slopes are opposite of each other so, using this we can find value of a

[tex]Slope \ of \ line \ AB =-\frac{1}{Slope \ of \ line \ CD}[/tex]

[tex]\frac{y_2-y_1}{x_2-x_1}=-\frac{1}{ \frac{y_2-y_1}{x_2-x_1}} \\\frac{y_2-y_1}{x_2-x_1}=-\frac{x_2-x_1}{y_2-y_1}\\\frac{10-5}{7-3}=-\frac{1-0}{a-2} \\\frac{5}{5}=-\frac{1}{a-2}\\1=-\frac{1}{a-2}\\a-2=-1\\a=-1+2\\a=1[/tex]

So, if Line AB is perpendicular to line CD then value of a is: a=1

Answer:

B

Step-by-step explanation:

absolute value is 2½

hope it helped

Answer:

Number 8 is going to be 5/2

Number 9 is going to be 31/8

Number 10 is going to be 7/4

Number 11 is going to be 29/6

Number 12 is going to be 67/13

Step-by-step explanation:

Hope this helped

Answer:

25 percent

Step-by-step explanation:

percent=1/100

16 times x=4

16 times 1/4=4

Answer:

.06 % (6%)

Step-by-step explanation:

I'm not good at explaining but,

Using baseball method I:

1. Wrote it out as a fraction

2. multiplied numerator (4) by the denominator of (16)

3. Then I divided the product of that, 64, by 100 and got .04

Which is 4% (:

Answer:

a0.50 + b0.30 ≤ $3.00

Step-by-step explanation:

From the question, we have:

Gumballs cost per unit = $0.50

Jawbreakers cost = $0.30

Total budget of Bob = $3.00

Let a represents the number of Gumballs Bob can buy.

Let b represents the number of jawbreakers Bob can buy.

Therefore, inequality that represents the number of gumballs and jawbreakers Bob can buy can be given as follows:

a0.50 + b0.30 ≤ $3.00

The inequality implies that total amount Bob can spend on both gumballs and jawbreakers can be less or equal to $3.00 but cannot be greater than $3.00.

Answer:

It would be the 2nd one

Step-by-step explanation:

Answer:

Answer

3.0/5

10

FluttershyK22

x(4-k)=p

[x(4-k)=p]/x

4-k=p/x

-4 = -4

-k=p/x-4

k=4-p/x

Step-by-step explanation:

Answer:

k = - 4 + p

Step-by-step explanation:

p = x ( 4 - k )

p = 4x - kx

-4x    -4x

4x - p = - kx

divide by -x

-k = 4 - p

divide by -

k = - 4 + p

Hope this helps!!!

Answer:

Step-by-step explanation:

to get the slope, we use the fotmula y2-y1/x2-x1

so that would be

7-3 over -4-(-2)

7-3=4 and -4-(2)=-2

so the slope is -4/2x, or simply -2x

Answer:

He uses 23 balloons for each of the 28 events.

Step-by-step explanation:

Answer:

23

Step-by-step explanation:

I divided 644 by 28. There are 644 balloons and you want to split

(divide) into the same number of balloons with none left over. Look for those key words to tell you what type of math your doing. Hope this helps!

Answer:

The answer is D

The equation that can be used to determine the number of years at which the trees will be an equal height is -

14x + 12 = 16x + 2

The general equation of a straight line is -

[y] = [m]x + [c]

where -

[m] → is slope of line which tells the unit rate of change of [y] with respect to [x].

[c] → is the y - intercept i.e. the point where the graph cuts the [y] axis.

We have Sara owns a tree farm. Variety A of a pine tree is shipped to her at 12 inches tall and grows at a rate of 14 inches per year. Variety B of a pine tree is shipped to her at 2 inches tall and grows at a rate of 16 inches per year.

Variety [A] = 14x + 12

Variety [B] = 16x + 2

The equation that can be used to determine the number of years at which the trees will be an equal height is -

14x + 12 = 16x + 2

Therefore, the equation that can be used to determine the number of years at which the trees will be an equal height is -

14x + 12 = 16x + 2

To solve more questions on straight lines, visit the link below-

brainly.com/question/20400984

#SPJ5

Answer:

The answer is 2nd one

2nd pair of triangle is congruent by ASA(angle side angle)

Answer:

2nd option is correct.