14. Each leg is [tex]21\sqrt{2}[/tex] units long.
15 (a). The longer leg is [tex]7\sqrt{3}[/tex] units long
15 (b). The hypotenuse is [tex]14[/tex] units long
=====================================================
Explanations:
For a 45 degree right triangle, aka 45-45-90 triangle, the hypotenuse is equal to sqrt(2) times the short leg. Algebraically we can say
[tex]y = x\sqrt{2}[/tex] where x is the leg and y is the hypotenuse
Let's solve for x
[tex]y = x\sqrt{2}\\\\x\sqrt{2} = y\\\\x = \frac{y}{\sqrt{2}}\\\\x = \frac{y\sqrt{2}}{\sqrt{2}*\sqrt{2}} \ \text{rationalizing denominator}\\\\x = \frac{y\sqrt{2}}{2}\\\\[/tex]
Now plug in the given hypotenuse y = 42, this leads to,
[tex]x = \frac{y\sqrt{2}}{2}\\\\x = \frac{42\sqrt{2}}{2}\\\\x = \frac{42}{2}\sqrt{2}\\\\x = 21\sqrt{2}\\\\[/tex]
---------------------------
For a 30-60-90 triangle, the hypotenuse is double that of the short leg. So the hypotenuse is 2*7 = 14.
The longer leg is equal to sqrt(3) times the short leg. The longer leg is [tex]7\sqrt{3}[/tex]
The diameter of a sphere is 4 centimeters. Which represents the volume of the sphere? StartFraction 32 Over 3 EndFractionπ cm3 8π cm3 StartFraction 64 Over 3 EndFractionπ cm3 16π cm3
Answer:
The volume of the sphere is 32 π /3 cm^3
Step-by-step explanation:
Mathematically, the volume of a sphere can be calculated using the formula below;
V = 4/3 * pi * r^3
Now since we have the radius and diameter = 2 * radius
radius = diameter/2 = 4/2 = 2
Substituting this value into the volume equation;
V = 4/3 * pi * 2^3 = 32pi/3
Answer:
The correct answer is A
Step-by-step explanation:
If you expand and simplify. -(y+2)(y-8)
Answer:
[tex]-y^2+6y+16[/tex]
Step-by-step explanation:
[tex]-(y+2)(y-8)[/tex]
[tex]-1(y+2) \times (y-8)[/tex]
[tex](-y-2)\times (y-8)[/tex]
[tex]-y(y-8)-2(y-8)[/tex]
[tex]-y^2+8y-2y+16[/tex]
[tex]-y^2+6y+16[/tex]
HELP ASAP!!
Determine the surface area of the figure built out of blocks.
A) 30 sq. Units
B) 26 sq. Units
C) 22 sq. Units
D) 19 sq. Units
Answer:
i think it's s d because that's how many sq. there are
find the initial value of the function x + 3y = 18
simplify (a+b)^3 + (a-b)^3 + 6a(a^2-b^2)
Answer:
8a^3.
Step-by-step explanation:
(a+b)^3=a^3+b^3+3a^2b+3ab^2
(a-b)^3=a^3-b^3-3a^2b+3ab^2
(a+b)^3+(a-b)^3=2a^3+6ab^2
According to the question
(a+b)^3+(a-b)^3+6a(a^2-b^2)
Put in the value
=2a^3+6ab^2 +6a^3–6ab^2
=8a^3
In the simplest form expression (a + b)³ + (a - b)³ + 6a(a² - b²) can be written as, 8a³
What are algebraic identities?Algebraic identities are algebraic equations that are true regardless of the value of each variable. Additionally, they are employed in the factorization of polynomials. Algebraic identities are employed in this manner for the computation of algebraic expressions and the solution of various polynomials.
Given that,
A algebraic identity,
(a + b)³ + (a - b)³ + 6a(a² - b²)
It is known that,
(a + b)³ = a³ + b³ + 3ab(a + b)
(a - b)³ = a³ - b³ - 3ab(a - b)
So, now we can substitute expressions
(a + b)³ + (a - b)³ + 6a(a² - b²)
a³ + b³ + 3ab(a + b) + a³ - b³ - 3ab(a - b) + 6a(a² - b²)
a³ + b³ + 3a²b + 3ab² + a³ - b³ -3a²b + 3ab² + 6a³ - 6ab²
8a³
Hence, the simplest form is 8a³
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To eliminate the y-terms and solve for x in the fewest steps, by which constants should the equations be multiplied by before
adding the equations together?
First Equation: 5x - 4y = 28
Second equation: 3x - 3y = 30
The first equation should be multiplied by 3 and the second equation by 5.
The first equation should be multiplied by 3 and the Second equation by -5.
The first equation should be multiplied by 9 and the second equation by 4
The first equation should be multiplied by 9 and the second equation by -4.
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Answer:
To eliminate y- terms
Multiply equ(1) by 3 and equ(2) by -4
To eliminate y- terms
Multiply (1) by 3 and (2) by -5
Step-by-step explanation:
5x - 4y = 28 (1)
3x - 3y = 30 (2)
To eliminate y- terms
Multiply equ(1) by 3 and equ(2) by -4
15x-12y=84
-12x+12y= -120
Add equ (3) and (4)
3x=84-120
3x=-36
x=-36/3
= -12
x=-12
To eliminate x- terms
5x-4y=28
3x-3y=30
Multiply (1) by 3 and (2) by -5
15x-12y=84
-15x+15y=-150
Add the new equation
3y= -66
y= -22
Mateo's wage is £420 per week.
He spends 1/3 of his wage on food.
35% goes on the household bills and the rest is saved.
How much does Mateo save each week?
Answer:
He saves £133 every week
Given: 3x < -6. Choose the solution set.
A. {x | x < -2}
B. {x | x > -2}
C. {x | x < 2}
D. {x | x > 2}
Answer:
When we divide the inequality by 3 we get x < -2 so the answer is A.
The volume of a rectangular tank is 20 000 cm3 . Given that the length is 40 cm and width is 25 cm, find its height
[tex]answer \\ 20 \: cm \\ solution \\ volume = 20000 \: {cm}^{3} \\ length = 40 \: cm \\ breadth = 25 \: cm \\ height = \\ now \\ v = l \times b \times h \\ \: \: \: \: \: \: or \: 20000 = 40 \times 25 \times h \\ or \: 20000 = 1000 \times h \\ or \: h = \frac{20000}{1000} \\ h = 20 \: cm \\ hope \: it \: helps[/tex]
Answer:
[tex]20cm[/tex]
Step-by-step explanation:
[tex]volume = length \times width \times height \\ 20000= 40 \times 25 \times h \\ 2000 0= 1000h \\ \frac{20000}{1000} = \frac{1000h}{1000} \\ h = 20[/tex]
hope this helps
brainliest appreciated
good luck! have a nice day!
(PLZ NEED HELP) The doubling time of a bacterial population is 10 minutes. After 80 minutes, the bacterial population was 80000. _____
Using your rounded answer for the initial population above (do not round your growth rate), find the size of the bacterial population after 5 hours.____
Answer:
Initial population = 313
Population after 5 hours = [tex]3.36 \times 10^{11}[/tex]
Step-by-step explanation:
Let initial population = [tex]x[/tex]
It is given that population gets doubled every 10 minutes.
Population after 10 minutes = [tex]2x[/tex]
Population after 20 minutes = [tex]2^{2} x[/tex]
:
:
Population after 80 minutes = [tex]2^{8} x[/tex] and it is given as 80000.
[tex]\Rightarrow 2^{8} x = 80000\\\Rightarrow x = \dfrac{80000}{256}\\\Rightarrow x = 313[/tex]
So, initial population is 312.5 = ~313
To find, population after 5 hours i.e. 5 [tex]\times[/tex] 60 = 300 minutes
Population after 300 minutes =
[tex]2^{30} x\\\Rightarrow 2^{30} \times 313\\\Rightarrow 3.36 \times 10^{11}[/tex]
So, the answers are:
Initial population = 313
Population after 5 hours = [tex]3.36 \times 10^{11}[/tex]
The area of a circle is 18pi square inches. If the area of a sector of this circle is 6pi square inches, then which of the following must be the sector's central angle?
Please help I’ll give you brainliest promise !
Answer:
240 degrees
Step-by-step explanation:
Mathematically, the area of a circle is
A = 2 * pi * r^2
we need to calculate the radius of the circle first
18pi = 2pi * r^2
divide both sides by 2pi
r^2 = 9
r = 3 inches
Area of sector = angle/360 * pi * r^2
6pi = angle/360 * pi * 3^2
6pi = angle/360 * 9pi
(360 * 6pi)/9pi = angle
40 * 6 = 240 degrees
Need help ASAP! Need help ASAP will mark you as brainiest!
Answer:
[tex]r=\frac{44}{\pi }[/tex]
Step-by-step explanation:
[tex]88=2\pi r[/tex]
[tex]\mathrm{Switch\:sides}\\2\pi r=88\\\frac{2\pi r}{2\pi }=\frac{88}{2\pi }\\r=\frac{44}{\pi }\\or\\r=14.00563[/tex]
Answer:
2 metres
Step-by-step explanation:
Circumference = 2 × π × r
→ Substitute in the values
88 = 2 × [tex]\frac{22}{7}[/tex] × r
→ Divide both sides by 2 to isolate [tex]\frac{22}{7}[/tex] and r
44 = [tex]\frac{22}{7}[/tex] × r
→ Multiply everything by 7 to get rid of the fraction
308 = 22 × 7r
→ Divide the equation by 22 to isolate 7r
14 = 7r
→ Divide the equation by 7 to isolate r
2 = r
The radius of the circle with a circumference of 88 meters is 2 metres
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Answer:
18 square meters
Step-by-step explanation:
Answer:
7.5 square meterssolution,
The given figure if a Trapezium whose parallel sides are of 3 m and 2 m respectively.
Distance between the parallels sides
i.e. height is 3 m
Now,
[tex]area = \frac{1}{2} \times sum \: of \: parallel \: sides \times height \\ = \frac{1}{2} \times (3 + 2) \times 3 \\ = \frac{1}{2} \times 5 \times 3 \\ = \frac{15}{2} \\ = 7.5 \: {m}^{2} [/tex]
Hope this helps...
Good luck on your assignment...
(6x^2+5x-3)+(x^2-9) find the sum please
Answer:
7x^2+5x-12
Step-by-step explanation:
(6x^2+5x-3)+(x^2-9)
Combine like terms
(6x^2+ x^2+5x-3-9)
7x^2+5x-12
I need help please!! Identify the solution for the system of equations graphed here.
A. (1,1)
B. (-1,1)
C. (1,-1)
D. (-1,-1)
Answer:
C. (1,-1)
Step-by-step explanation:
Lines are intersecting each other at point (1, - 1).
Hence, the system of equations graphed here would be (1, - 1)
Which of the following is not a case of direct variation?a Number of sheets of some kind and increased when their total weight its inceased. b More quantity of petrol is required to travel more distance with a fixed speed. c More fees would be collected if number of students increased in a class. d Time taken will be less if number of workors are increased to complete the same work.
Answer:
Step-by-step explanation:
If two variables, x and y have a direct variation, it means that an increase in x would lead to a corresponding increase in y. A decrease on x would lead to a corresponding decrease in y.
Therefore, we would compare the scenarios to determine which is not a direct variation. The correct option is
d) Time taken will be less if number of workers are increased to complete the same work.
The rest are direct variation scenarios
Solve the following equation 4×6x−7=1 x= log8log6 x= log2log6 x= log6log8 x= log6log2
Answer:
The value of x is [tex]x=\frac{\log(2)}{\log(6)}[/tex].
Step-by-step explanation:
Solve the equation as follows:
[tex]4\times 6^{x}-7=1[/tex]
[tex]4\times 6^{x}=7+1[/tex]
[tex]6^{x}=\frac{8}{4}[/tex]
[tex]6^{x}=2[/tex]
Take log on both sides.
[tex]\log(6^{x})=\log(2)[/tex]
[tex]x\log (6)=\log(2)[/tex]
[tex]x=\frac{\log(2)}{\log(6)}[/tex]
Thus, the value of x is [tex]x=\frac{\log(2)}{\log(6)}[/tex].
(3x+8) (4x+10) what is the length
Factor this polynomial completely over the set of complex numbers: f(x)=x^3-x^2-4x+4 Pleaseee answer asap! Thanks!
f(x)=(x-1)(x+2)(x-2) over all it equals to zero
Answer:
(x-1) (x-2) (x+2)
Step-by-step explanation:
1. Factorice x^2 y -4 de la expresion.
x^2(x-1) -4(x-1)
2. Luego, debemos de factorizar x-1 de la expresion.
(x-1)(x^2 -4)
3. Usando a^2 - b^2= (a-b)(a+b) factorice la expresion.
(x-1) (x-2) (x+2)
A car travels 0.75 miles every minute.explain how you could use proportional reasoning too find how far the car travels in a hour
Answer:
The car travels 45 miles in one hour.
Step-by-step explanation:
Knowing that one hour is 60 minutes and that the car travels 0.75 miles every minute, you can multiply 60 and 0.75 which gives you 45 miles per hour meaning in one hour the car travels 45 miles.
Let f(x) = .............
Answer:
4
Step-by-step explanation:
g(3) = -2(3)^2 -4 = 2(9) -4 = 18-4 = 14
|f(2)| = | 2^2 -3| = | 4-3| = 1
(g(3) +2) = (14+2) = 16
4* |f(2)| = 4*1 = 4
16/4 = 4
Help please!
How does the function f(x)=x^2−4x−21 illustrate the Fundamental Theorem of Algebra?
Fill in the blanks. (Hint: Your answers are numbers.)
The degree of f(x) is _____. The Fundamental Theorem of Algebra guarantees that a polynomial equation has the same number of complex roots as its degree. This means that f(x) has exactly _____ zeros. Those zeros are 7 and _____.
f(x)=x²−4x−21
The degree is the biggest power of x. That's a polynomial of degree 2, also called a quadratic function. Let's find its zeros.
0 = x²−4x−21 = (x - 7)(x+3)
x=7 or x=-3
The fundamental theorem guarantees every non-constant polynomial with complex coefficients has a complex zero, let's call it r. If we divide the polynomial by x-r there won't be any remainder and we'll get a new polynomial, one degree less. The fundamental theorem again applies and (if it's not a constant polynomial) we are assured of another zero, s. We divide by x-s and get a new polynomial of degree one less. We repeat all this until we get a constant polynomial (degree zero). So we get a zero for every degree. They're not necessarily all different.
Answer:
The degree of f(x) is 2. The Fundamental Theorem of Algebra guarantees that a polynomial equation has the same number of complex roots as its degree. This means that f(x) has exactly 2 zeros. Those zeros are 7 and -3.
Find the slope of the line that passes through (5, 9) and (2, 2). will mark brain
Simplify your answer and write it as a proper fraction, improper fraction, or integer.
The right answer is 7/3
please see the attached picture for full solution
hope it helps..
Good luck on your assignment
Answer:
[tex]slope = \frac{7}{3} [/tex]
Step-by-step explanation:
[tex](5 \: \: , \: \: 9) = > (x1 \: \: \:, \: y1) \\ (2 \: \: , \: \: 2) = > (x2 \: \: \:, \: \: y2)[/tex]
[tex] slope \\ = \frac{y1 - y2}{x1 - x2} \\ = \frac{9 - 2}{5 - 2} \\ = \frac{7}{3} [/tex]
hope this helps
brainliest appreciated
good luck! have a nice day!
In the diagram of circle O, what is the measure of ? 27° 54° 108° 120°
Answer:
Option (2).
Step-by-step explanation:
This question is incomplete; here is the complete question and find the figure attached.
In the diagram of a circle O, what is the measure of ∠ABC?
27°
54°
108°
120°
m(minor arc [tex]\widehat {AC}[/tex]) = 126°
m(major arc [tex]\widehat {AC}[/tex]) = 234°
By the intersecting tangents theorem,
If the two tangents of a circle intersect each other outside the circle, measure of angle formed between them is half the difference of the measures of the intercepted arcs.
m∠ABC = [tex]\frac{1}{2}[m(\text {major arc{AC})}-m(\text{minor arc} {AC})][/tex]
= [tex]\frac{1}{2}(234-126)[/tex]
= 54°
Therefore, Option (2) will be the answer.
Answer:
B.
Step-by-step explanation:
solve tan x - cot x = -2cos 2x cosec 2x
Answer:
Step-by-step explanation:
tan x-cot x
[tex]=\frac{sin~x}{cos~x} -\frac{cos~x}{sin ~x} \\=\frac{sin^2x-cos^2 x}{sin ~x~cos~x} \\=\frac{-2(cos^2x-sin^2x)}{2 sin ~x~cos~x} \\=\frac{-2 cos~2x}{sin~2x} \\=-2 cos ~2x~cosec~2x[/tex]
1 Point
Which statement best describes the end behavior of the following function?
F(x) = 3x +4x3 - X+11
A. The graph of the function starts low and ends high.
B. The graph of the function starts high and ends high.
C. The graph of the function starts low and ends low.
D. The graph of the function starts high and ends low.
Answer:
The graph of the function starts high ends low
Step-by-step explanation:
I put the equation into Desmos
2/3 - 4x + 7/2 = -9x + 5/6 apply the properties.. step by step
Answer:
x=5/13
Step-by-step explanation:
2/3+7/2=9x+5/6+4x
2/3+7/2-5/6=9x+4x
lcm of 2,3,6=6
2/3=4/6 7/2=21/6 5/6=5/6
4/6+21/6-5/6=9x+4x
30/6=13x
5=13x
x=5/13
Steps:
Step 1: Simplify both sides of the equation.
2/3−4x+7/2=−9x+5/6
2/3+−4x+7/2=−9x+5/6
(−4x)+( 2/3 + 7/2 )=−9x+ 5/6 (Combine Like Terms)
−4x+25/6=−9x+5/6
−4x+25/6=−9x+5/6
Step 2: Add 9x to both sides.
−4x+25/6+9x=−9x+5/6+9x
5x+25/6=5/6
Step 3: Subtract 25/6 from both sides.
5x+25/6−25/6=5/6−25/6
5x=−10/3
Step 4: Divide both sides by 5.
5x/5=−10/3/5
= x=-2/3
Answer: x=-2/3
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Hope this helps.
[tex]R = \sqrt{ \frac{ax - P}{Q + bx} } [/tex]
solve for x. Please can someone help me ASAP. I need to hand it on today.
Step-by-step explanation:
[tex]r = \sqrt{ \frac{ax - p}{q + bx} } \\ {r}^{2} = \frac{ax - p}{q + bx} [/tex]
r² (q + bx) = ax - p
qr² + bxr² = ax - p
qr² + p = ax - bxr²
qr² + p = x (a - br²)
[tex]x = \frac{q {r}^{2} + p}{a - b {r}^{2} } [/tex]
Answer:
[tex]\displaystyle x=\frac{-P-\math{R}^2Q}{\math{R}^2b-a}[/tex]
Step-by-step explanation:
[tex]R=\sqrt{\frac{ax-P}{Q+bx}}[/tex]
[tex]\mathrm{Square\:both\:sides}[/tex]
[tex]R^2=\left(\sqrt{\frac{ax-P}{Q+bx}}\right)^2[/tex]
[tex]R^2=\frac{ax-P}{Q+bx}[/tex]
[tex]\mathrm{Multiply\:both\:sides\:by\:}Q+bx[/tex]
[tex]\math{R}^2\left(Q+bx\right)=\frac{ax-P}{Q+bx}\left(Q+bx\right)[/tex]
[tex]\math{R}^2\left(Q+bx\right)=ax-P[/tex]
[tex]\math{R}^2Q+\math{R}^2bx=ax-P[/tex]
[tex]\mathrm{Subtract\:}\math{R}^2Q\mathrm{\:from\:both\:sides}[/tex]
[tex]\math{R}^2Q+\math{R}^2bx-\math{R}^2Q=ax-P-\math{R}^2Q[/tex]
[tex]\math{R}^2bx=ax-P-\math{R}^2Q[/tex]
[tex]\mathrm{Subtract\:}ax\mathrm{\:from\:both\:sides}[/tex]
[tex]\math{R}^2bx-ax=ax-P-\math{R}^2Q-ax[/tex]
[tex]\math{R}^2bx-ax=-P-\math{R}^2Q[/tex]
[tex]\mathrm{Factor}\:\math{R}^2bx-ax[/tex]
[tex]x\left(\math{R}^2b-a\right)=-P-\math{R}^2Q[/tex]
[tex]\mathrm{Divide\:both\:sides\:by\:}\math{R}^2b-a[/tex]
[tex]\frac{x\left(\math{R}^2b-a\right)}{\math{R}^2b-a}=-\frac{P}{\math{R}^2b-a}-\frac{\math{R}^2Q}{\math{R}^2b-a}[/tex]
[tex]x=\frac{-P-\math{R}^2Q}{\math{R}^2b-a}[/tex]
A weather station reports that there is a 40% chance of rain today. What is the probability that it will not rain today?
Answer:
Since the full percentage of something is 100% thats because 1*100 = 100.
So since it has 40% chance of rain what would 100-40 be? Well it would be 60. So the probability that it will not rain is
60%Which expressions have a positive product? *
–(5)(–0.2)(–1.9)(9)
–(2.14)(1.6)(14)
(6.3)(–8.7)(0.7)
(8.5)(–0.4)(–2.7)
Answer:
The fourth choice is the correct one.
Step-by-step explanation:
If the count of negative signs is even, the product is even (positive).
This does not apply to the first choice; this expression is odd.
Same for the second choice.
Same for the third choice. The expression is odd.
The fourth choice is POSITIVE because there are an even number (2) of negative signs.