Answer:
Dilating the pupils.
Answer:
the retina of the eye contains photoreceptor cells that detect the light intensity, whether it is dim or bright, changing shape of iris.
Explanation:
in dim light, the receptors detect the light intensity, and in order to allow us to see more clearly, the radial muscles in iris contract, making the pupil widen(dilate), so more light enters eye.
in case of bright light, he receptors detect the light intensity, and in order to allow us to see more clearly, the circular muscles in iris contract, making the pupil narrow(constrict), so less light enters eye
A man pushes a 49 kg mower with a force of 650 N at a downward angle of 35° as shown in the picture to the right. If the mower experiences a frictional force of 493.249 N, find:
The acceleration of the mower.
The normal force acting on the mower.
Answer:
a = 0.8m/s^2
F = 39.28 N
Explanation:
Sum of forces in X direction = 650cos(35)N-493.249N
Sum of forces in X direction= 39.28 N
F = m*a
a = F/m
a = 39.28N/49kg
a = 0.8 m/s^2
A coastline on Earth experiences tides according to the graph below.
A graph showing a high tide at approximately 12 hours and 24 hours with a low tide occurring 6 hours before each high tide.
What type of tide is cycling in this location?
AWNSER CHOICES:
A: Diurnal tides
B: Mixed dinural tides
C: Mixed semidiurnal tides
D: Semidiurnal tides
If I can figure out how to mark brainliest I will if the awnser provided is correct
Answer:
Most coastal areas, with some exceptions, experience two high tides and two low tides every lunar day (Ross, D.A., 1995). Almost everyone is familiar with the concept of a 24-hour solar day, which is the time that it takes for a specific site on the Earth to rotate from an exact point under the sun to the same point under the sun. Similarly, a lunar day is the time it takes for a specific site on the Earth to rotate from an exact point under the moon to the same point under the moon. Unlike a solar day, however, a lunar day is 24 hours and 50 minutes. The lunar day is 50 minutes longer than a solar day because the moon revolves around the Earth in the same direction that the Earth rotates around its axis. So, it takes the Earth an extra 50 minutes to “catch up” to the moon (Sumich, J.L., 1996; Thurman, H.V., 1994).
the answer is C
Mixed semidiurnal tides is the type of wave that coastline on Earth experiences.
What is meant by Mixed semidiurnal tides?An area has a mixed semidiurnal tidal cycle if it experiences two high and two low tides of different size every lunar day. Some areas, such as the Gulf of Mexico, have only one high and one low tide each day.Many areas on the western coast of North America experience these tidal cycles.Mixed semidiurnal tides is the type of wave that coastline on Earth experiences.
To learn more about Mixed semidiurnal tides refer:https://brainly.com/question/14681092
#SPJ2
if the bill is vetoed
Answer:
Explanation:
A vote is maybe a vote
a sealed bottle of water was taken from a refrigerator and left in a warm kitchen. explain in the terms of its molecules what happened to the thermal energy and temperature of the water in a few minutes
Answer:
Explanation:
The sealed bottle serves as an open system for the water molecules, thus heat energy can be exchanged with its surroundings. When the bottle is placed in a warm environment, there would be a gradual increase in the thermal energy of the molecules of water due to a change in the temperature of its surroundings.
Thus, the molecules of water closer to the boundary of the bottle absorbs heat, becomes lighter and changes position. This gradual process continues until all molecules attains an average temperature which equals that of the surroundings of the bottle.
Therefore, both the thermal energy and temperature of the water increases.
1. Ex. Weight lifted above your head, piston in an engine
(1 Point)
Mechanical Energy
Nuclear Energy
Sound Energy
Chemical Energy
Answer:
I think it is mechanical energy
Which planet in our solar system is considered the most thoroughly studied?
1. Mars
2. Pluto
3. Venus
4. Jupiter
I feel death among us
same but who knows how 2021 might go
Answer:
same....
Explanation:
Wanna be friends?
Why is it important for cornea of the eye to be transparent?
Answer:
More than 60% of the total refractive power of the eye is attributed to the cornea making it vital to focusing light onto the retina for visual processing 115.
Explanation:
For optimal vision, the cornea must efficiently transmit incident light by maintaining its transparency.
Glaciers begin with snowfall building up and __________________ the ice. (Choose the best answer)
Group of answer choices
compacting
exposing
freezing
Answer:
compacting
Explanation:
i don't think there is very much explanation, the snow falls and compacts the ice to become giant lol
Which of the following is an example of Kinetic to Electrical energy
conversion?
A. Toaster
B. Bicycle
C. Ceiling fan
D. Generator
What direction does tangential velocity point?
inward
outward in a straight line tangent to the circle
around the circle
Answer:b.outward in a straight line tangent to the circle!
Explanation:at any given point on the circle is always along the tangent line.
12.Two masses are arranged as shown on a ramp that makes an angle of 36° with the horizontal. Mass m1 is twice mass m2
. What is the minimum coefficient of static friction required between mass m1 and the ramp to ensure equilibrium?
Force M2 exerts on tension T
T = M2 g
T = M1 g sin theta - M1 g u cos theta
Note that M1 g is exerted down the plane while the frictional force opposes this motion and will be directed in the opposite direction of M1 g
M2 g = M1 g sin theta - u M1 g cos theta
1 = 2 sin 36 - u 2 cos 36
.5 = sin 36 - u cos 36
u = (sin 36 - .5) / cos 36 = .108
Any friction less that this will result in sliding
"1.7456" would be the minimum coefficient of static friction required.
Given:
Angle,
[tex]\Theta = 30^{\circ}[/tex]Mass,
[tex]m_2 =2 m_1[/tex]To keep the system in equilibrium forces acting on mass "[tex]m_1[/tex]" must balance forces acting on "[tex]m_2[/tex]".
That's,
→ [tex]Forces \ on \ m_1 \ downward \ along \ ramp = Forces \ on \ m_2 \ downwards[/tex]
or,
→ [tex]m_1 g Sin \Theta + \mu_s m_1 g Cos \Theta =m_2 g[/tex]
Thus,
→ [tex]\mu_s = \frac{m_2 g - m_1 g Sin \Theta}{m_1 g Cos \Theta}[/tex]
[tex]= \frac{m_2-m_1 Sin \ 36^{\circ}}{m_1 Cos \Theta}[/tex]
hence,
→ [tex]\mu_s = \frac{2 m_1 - m_1 Sin \ 36^{\circ}}{m_1 Cos \ 36^{\circ}}[/tex]
[tex]= 1.7456[/tex]
Thus the above answer is right.
Learn more:
https://brainly.com/question/14747133
Someone please help me I’m begging you
[tex] \large{ \text{Hii, Hope \: you \: are \: fine!}}[/tex]
4321 is the answer
On Earth, friction can be _____ but not removed.
Answer:
reduced
Explanation:
The use of bearing surfaces that are themselves sacrificial, such as low shear materials, of which lead/copper journal bearings are an example
If the air pressure measures is 3 atm. How many mb of pressure is in the air?
Answer:
3
Explanation:
If there is 3 at the moment (atm) is the same as might be (mb) in the air.
What year was soccer added to the Olympic games ?
a - 1996
b - 1904
c - 1900
Answer:
a - 1996
Explanation:
Answer:
1900
Explanation:
It's football but for the U.S terms, they call it Soccer, and it was in 1900
To boil water it requires heat , what happens to the heat when the water cools down as energy can neither be destroyed nor be created ?
Answer:
Explanation:
The water particles just flow through each other. They cannot be destroyed nor created.
Answer:
The water cooling down is due to evaporation, the heat is simply changing the state of matter of the water. Energy is being used to change it's state. Evaporation causes the cooling down of something. Think of sweat?
Explanation:
14. The design for a rotating spacecraft below consists of two rings. The outer ring with a radius of 30 m holds the living quarters and mimics the surface gravity of Earth, approximately 9.80 m/s'. The inner ring is designed to help the astronauts become accustom to the surface gravity of a new planet: 5.35 m/s. Calculate the spacecraft's period of rotation for the outer ring.
Answer:
[tex]T= 11.0003[/tex]s
Explanation:
From the question we are told that
The outer ring with a radius of 30 m
inner Gravity Approximately 9.80 m/s'
Outer Gravity Approximately 5.35 m/s.
Generally the equation for centripetal force is given mathematically as
Centripetal acceleration enables Rotation therefore?
[tex]\omega ^2 r =Angular\ acc[/tex]
Considering the outer ring,
[tex]\omega ^2 r = 9.8[/tex]
[tex]\omega ^2= \frac{9.8}{30}[/tex]
[tex]\omega = \sqrt{\frac{9.8}{30}}[/tex]
[tex]\omega= 0.571 rad/s[/tex]
Therefore solving for Period T
Generally the equation for solving Period T is mathematically given as
[tex]T= \frac{2\pi}{\omega}[/tex]
[tex]T= \frac{2\pi}{0.571 rad/s}[/tex]
[tex]T= 11.0003[/tex]s
Godric and Savos are a few meters apart, at one end of the football field. Peter is at the other end of the field. Godric and Savos starts moving towards Peter at a speed of 4m/s. From Savos point of view how is Godric moving?
Answer:
From Savos point of view, Gadros appear not to be moving
Explanation:
The given parameters are;
The distance between Godric and Savos = A few meters
The location of Godric and Savos = One end of the field
The location pf Peter = The other end pf the field
The speed with which Godric and Savos are moving towards Peter = 4 m/s
Let the positive x-direction be the direction in which Godric and Savos are moving
Therefore;
The speed and direction with which Godric is moving = The speed and direction with which Savos is moving = 4·i m/s
From Savos point of view, the relative speed with which Godric is moving = (The speed and direction in which Godric is moving) - (The speed and direction in which Savos is moving) = 4·i m/s - 4·i m/s = 0 m/s
Therefore, from Savos point of view, the relative speed with which Godric is moving = 0 m/s or Gadros appears stationary or not to moving.
write the terms involved in s=ut+1\2
s = displacement; u = initial velocity; t = time of motion
PLEASE HELP Due Today!
When the motion energy of an object changes, energy is being transferred. How do you know that's true?
Answer: The statement when the motion energy of an object changes, energy is being transferred is true.
Explanation:
Motion energy is also called mechanical energy and it is the summation of kinetic energy and potential energy stored in an object required for work.
As kinetic energy is the energy acquired due to motion of an object and potential energy is the energy acquired by an object due to its position.
For example, when a moving ball strikes another ball causing it to move then energy is being transferred from one ball to another.
Therefore, the statement when the motion energy of an object changes, energy is being transferred is true.
The human body can store excess animo acids as a protein source ?
Answer:
The thermic effect (TEF) is greater for protein compared to carbohydrate and fat. The body can store excess amino acids for later use. The protein-sparing effect spares the utilization of protein as an energy source and allows it to be used for more important metabolic functions.
Which of these is one of six most common elements found in the human body??
Answer: Oxygen
Explanation: Oxygen is the most common element in the human body. It makes up 65% of the body.
Why cloth and leather are used to make safety clothing for people who work with heat. A.they are both good sources of heat. B they both can produce electrical energy C they both can absorb light energy. D they are both poor conductors of heat
Answer: D
Explanation:
During a goal-line stand, a 112-kg fullback moving eastward with a speed of 6 m/s
collides head-on with a 120-kg lineman moving westward with a speed of 8 m/s.
The two players collide and stick together, moving at the same velocity after the
collision. Determine the post-collision velocity of the two players.
Answer:
-1.24 m/s
Explanation:
Total momentum before collision = total momentum after collision
Total momentum before collision = (mass of full back * velocity of fullback) + (mass of lineman * velocity of line man).
Mass of full back = 112 kg, mass of line bag = 120 kg, velocity of full back 6 m/s (east), velocity of line back = -8 m/s (west). Hence:
Total momentum before collision = (112 * 6) + (120 * -8) = 672 - 960 = -288 kgm/s
The total momentum after collision = (mass of full back + mass of line back) * velocity after collision.
Let velocity after collision be v, hence:
The total momentum after collision = (112 + 120)v = 232v
Total momentum before collision = total momentum after collision
-288 = 232v
v = -288 / 232
v = -1.24 m/s
Therefore after collision, the two players would move at a velocity 1.24 m/s west (the same direction as the lineman).
How would the gravitational force between the earth and the moon change if the moon had half the mass?
The moon's gravity, combined with the waltz of Earth and the moon around their center of mass, forces the oceans into an oval shape, with two simultaneous high tides. ... If the moon were half its mass, then the ocean tides would have been correspondingly smaller and imparted less energy to it.
Which of the following are not correctly balanced reactions?
Check all that apply.
A. C + Cl2 → CC14
OB. 2K + Br2 + 2KBr
O C. Mg + FeO →2Fe + Mgo
D. C + 02 → CO2
Answer:
B. 2K + Br2 + 2KBr
D. C + 02 → CO2
Explanation:
In balancing a chemical reaction, the number of atoms on both sides of the expression must be the same in order to obey the law of conservation of mass.
According to the law of conservation of mass, in a chemical reaction, matter is neither created nor destroyed.
So, let us investigate:
Number of atoms
Reactants Products
K 2 2
Br 2 2
C + 0₂ → CO₂
C 1 1
O₂ 2 2
We see that for both equations, the number of atoms on both sides of the expression is the same.
8 A small smooth object slides from rest down a smooth inclined plane inclined at
30° to the horizontal. What is (i) the acceleration down the plane, (ii) the time
to reach the bottom if the plane is 5 m long?
The object is now thrown up the plane with an initial velocity of 15 ms -1.
(iii) How long does the object take to come to rest? (iv) How far up the plane has
the object then travelled?
Answer:
(i) The acceleration of the object down the plane is approximately 4.9 m/s²
(ii) The time it takes for the object to reach the bottom is approximately [tex]1.\overline{428571}[/tex] seconds
(iii) The time it takes the object to come to rest is approximately 1.030636 seconds
(iv) The object has travelled past the top of the plane by time it comes to rest
Explanation:
(i) The given parameter for the objects motion are;
The angle of inclination of the plane with the horizontal, θ = 30°
The length of the plane, s = 5 m
Let "a" represent the acceleration down an inclined plane, due to the acceleration under gravity "g" we have;
a = g × sin(θ)
Where;
g = The acceleration due to gravity ≈ 9.8 m/s²
∴ a ≈ 9.8 m/s² × sin(30°) = 9.8 m/s² × 0.5 = 4.9 m/s²
The acceleration of the object down the plane, a ≈ 4.9 m/s²
(ii) The time it takes for the object to reach the bottom, can be found from the following kinematic equation of motion;
s = u·t + 1/2·a·t²
Where;
s = The length of the inclined plane = 5 m
u = The initial velocity of the object = 0 m/s
t = The time of motion of the object (Here the time to reach the bottom of the plane)
a = The acceleration of the object = 4.9 m/s²
Therefore, we have;
5 = 0 × t + 1/2 × 4.9 × t² = 2.45·t²
t² = 5/2.45 = 100/49
t = √(100/49) = 10/7 = [tex]1.\overline{428571}[/tex]
The time to reach the bottom of the plane = t = [tex]1.\overline{428571}[/tex] seconds
(iii) When the object is thrown up the plane with an initial velocity of 15 m/s, the time, "t", it takes the object to come to rest is found by the following kinematic equation of motion;
v² = u² - 2·a·s
Therefore, we have;
v² = 15² - 2 × 4.9 × 5 = 176
v = √176 = 4·√11
The velocity of the object at the top of the plane = v = 4·√11 m/s
The time it takes the object to come to rest after reaching the top of the plane = The time it takes the object (projectile) to reach maximum height
[tex]t_m = \dfrac{v_i \cdot sin(\theta _i )}{g}[/tex]
Where;
[tex]t_m[/tex] = The time it takes the object to reach maximum height
[tex]v_i[/tex] = The initial velocity of the object at the top of the inclined plane = 4·√11 m/s
[tex]\theta _i[/tex] = The initial angle of inclination of the path of the object with the horizontal = 30°
Therefore, we have;
[tex]t_m = \dfrac{4 \times \sqrt{11} \times sin(30^{\circ} )}{9.8} = \dfrac{10 \cdot \sqrt{11} }{49} \approx 0.67686[/tex]
The time it takes the object to come to rest after reaching the top of the plane = The time it takes the object to reach maximum height = [tex]t_m[/tex] ≈ 0.67686 seconds
The time it takes the object to reach the top of the plane, [tex]t_{top}[/tex], is given from the kinematic equation of motion, v = u - a·t, as follows
v = u - a·t
∴ t = (u - v)/a
[tex]t_{top}[/tex] = (15 - 4·√11)/4.9 ≈ 0.353776
The time it takes the object to reach the top of the plane = [tex]t_{top}[/tex] ≈ 0.353776 s
The total time it takes the object to come to rest, ∑t = [tex]t_m[/tex] + [tex]t_{top}[/tex]
∴ ∑t ≈ 0.67686 + 0.353776 = 1.030636
The time it takes the object to come to rest = ∑t ≈ 1.030636 seconds
(iv) The distance up the plane the object reaches, "s", is given by the following kinematic equation;
s = u·t - 1/2·a·t²
Therefore, we have;
s = 15 × 15/4.9 - 1/2 × 4.9 × (15/4.9)² ≈ 22.959 m
However, the plane is 5 meters long, therefore, the object goes further than the top of the plane.
Determine the acceleration of the block
if the coefficient of static friction is 0.343.
Answer:
a = 1.49m/s²
Explanation:
Find the diagram attached
According to Newton's second law of motion
\sum Fx = ma
Fm - Ff = ma
Fm is the moving force
Ff is the frictional force
Fm = Wsin theta
Ff = μR = μWcos theta
Wsin theta - μWcos theta = ma
W is the weight = 50.1 * 9.8 = 490.98N
theta is the angle of inclination = 27.2°
μ is the coefficient of friction = 0.343
m is the mass = 50.1kg
a is the acceleration
Substitute into the formula as shown;
Wsin theta - μWcos theta = ma
490.98sin27.2° - 0.343(490.98)cos 27.2° = 50.1a
224.423 - 149.78 = 50.1a
74.64 = 50.1a
a = 74.64/50.1
a = 1.49m/s²
Hence the acceleration of the block is a = 1.49m/s²
How many DAYS occur between a new moon and a first quarter moon?
Answer:
About 29.5
Explanation:
Answer:
7 days or a week
Explanation: