How many atoms are in 12.9 mol Au?

Group of answer choices

a. 7.77x1024 atoms

b. 2.14x10-23 atoms

c. 6.02x1023 atoms

d. 1.38x1023 atoms

Answers

Answer 1

Given :

12.9 mol of Au.

To Find :

How many atoms are in 12.9 moles Au.

Solution :

We know, 1 mol of any element/molecules contains [tex]6.022\times 10^{23}\ atoms/mol[/tex].

Number of atoms in 12.9 moles of Au is :

[tex]n = 12.9 \times 6.022\times 10^{23}\ atoms\\\\n = 7.77\times 10^{24}\ atoms[/tex]

Therefore, number of atoms in 12.9 moles of Au is [tex]7.77\times 10^{24}\ atoms[/tex].

Hence, this is the required solution.

Answer 2

Answer:

amy what happen to your old account and the answer is c

Explanation:


Related Questions

A strong electrolyte is one that ________ completely in solution. a) reacts.b) decomposes.c) disappears.d) ionizes.

Answers

Answer:

A.

Explanation:

elctrolytes decomposes

Answer:

D. ionizes

Explanation:

What is the temperature 0 Kelvin called?

What happens at that temperature?

Answers

Answer:

0 Kelvin is called Absolute Zero. Particles will stop moving, and lose all energy.

Please help on the image below.

Answers

Heat capacity of Calorimeter = 10.7 J/°c

Further explanation

Heat lost=Heat gained

Q in = Q out

-Q lost(hot water)=Q gained (cold water+calorimeter)

-m.c.Δt=m.c.Δt+C.Δt

[tex]\tt \rightarrow -50\times 4.18\times (32.7-43)=50\times 4.18\times (32.7-22.9)+(32.7-22.9)\times C_{cal}\\\\\rightarrow 2152.7=2048.2+9.8\times C_{cal}\\\\104.5~J=9.8\times C_{cal}\\\\C_{cal}=\dfrac{104.5}{9.8}=10.7~J/^oC[/tex]

Perform the arithmic shown AND round your answers to the correct number of significant digits.

56.5in + 95.3in + 15 in

(Fill in the blank)

Answers

Answer:

167in

Explanation:

Given arithmetic;

        56.5in + 95.3in + 15in

To determine the correct significant digits, the sum cannot be more precise than the least precise value in the addition;

 The least precise is 15in and it is in 2significant places;

      56.5in

      95.3in

 +    15    in

......................

      166.8in

......................

The value is 167in

What is the mass, in grams, of 2.3 moles of gold?

Answers

Answer:

453.031g

Explanation:

atomic mass (molar mass)- 196.97g/m

2.3(196.97)=453.031

an ionic bond is a force of _____between anions and ______when combined make _____compounds that are electrically_____

Answers

Ionic bonds are formed between cations and anions. A cation is formed when a metal ion loses a valence electron while an anion is formed when a non-metal gains a valence electron. They both achieve a more stable electronic configuration through this exchange.


What elements make up water?

Answers

Water molecules are made of hydrogen atoms and one oxygen atom.

Hope this helped!

Answer:

1 oxygen and 2 hydrogen

Nitrogen gas at 300 k and 200 kpa is throttled adiabatically to a pressure of 100 kpa if the change in kinetic energy is negligble the temperature of the nitrogen after throttling will be:_________

Answers

Answer:

The temperature of the Nitrogen after throttling is  [tex]T_2 = 300 \ K[/tex]

Explanation:

From the question we are told that

   The  temperature is  [tex]T_1 = 300 \ K[/tex]

    The pressure is  [tex]P = 200 \ kPa = 200 * 10^{3} \ Pa[/tex]

    The pressure after being  [tex]P_1 = 100 \ kPa = 100 * 10^{3} \ Pa[/tex]

   

Generally from the first law of thermodynamics we have that

      [tex]Q - W = \Delta U + \Delta K[/tex]

Here [tex]\Delta U[/tex]  is the change internal  energy which is mathematically represented as

            [tex]\Delta U = C_p (T_2 - T_1)[/tex]

Here      [tex]C_p[/tex] is the specific heat of the gas at constant pressure

        [tex]\Delta K[/tex]  is the change kinetic energy which is negligible

         Q  is the thermal  energy  which is Zero for an adiabatic process

         W  is the work done and the value is zero given that the gas was throttled adiabatically

So

      [tex]0= \Delta U +0[/tex]

=>   [tex]\Delta U = 0[/tex]

=>  [tex](T_2 - 300) = 0[/tex]

=>   [tex]T_2 = 300 \ K[/tex]

     

An Sulfur tetrafluoride gas is collected at 23.0 °C in an evacuated flask with a measured volume of 20.0 L. When all the gas has been collected, the pressure in the flask is measured to be 0.230 atm . Calculate the mass and number of moles of sulfur tetrafluoride gas that were collected. Be sure your answer has the correct number of significant digits. mass: 1 g N10 mole: mol X & ? Explanation Check​

Answers

mass = 20.48 g

moles=0.1895

Further explanation

In general, the gas equation can be written  

Pv=nRT  

where  

P = pressure, atm  

V = volume, liter  

n = number of moles  

R = gas constant = 0.08205 L.atm / mol K  

T = temperature, Kelvin  

P=0.23 atm

V=20 L

T=23+273=296 K

[tex]\tt n=\dfrac{PV}{RT}=\dfrac{0.23\times 20}{0.082\times 296}=0.1895[/tex]

mass SF₄ (MW=108,07 g/mol) :

[tex]\tt 0.1895\times 108,07 g/mol=20.48~g[/tex]

PLZ HELP ME NO WRONG ANSWERS

Answers

Answer:

okay I will help you just message me johnpatrick on messenger

Write the thermochemical equation for the combustion of acetylene, C2H2 (g), in oxygen, for which the standard enthalpy of reaction is -1300 kJ per mole of acetylene.

Answers

Answer:

C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l)   ΔH° = -1300 kJ/mol

Explanation:

In the combustion of acetylene, it reacts with oxygen to produce carbon dioxide and water. The corresponding chemical equation is:

C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l)

The thermochemical equation includes the balanced chemical equation, stating the states of aggregation and the enthalpy of the reaction.

C₂H₂(g) + 2.5 O₂(g) ⇒ 2 CO₂(g) + H₂O(l)   ΔH° = -1300 kJ/mol

Which of the following has a nonpolar bond? *
02
HCI
NH3
CH4

Answers

Answer: CH4

Explanation:

BRAINLESS PLEASE

Answer:

O₂

Explanation:

The example of the compound or the molecule that forms a non-polar bond is oxygen gas.

Oxygen gas has a formula of O₂

Since this is a homonuclear molecule, the two bonding atoms have the same kind of electronegativity. The difference is therefore zero. In such a molecule, there is equal sharing of the electron pair between the atoms and no electrostatic charge on the molecule.

Are transition metals reactive?

Answers

Answer: Yes

Explanation:

unit factor method
convert a)26 cm in to meter​

Answers

1m= 100cm
26cm /100 = 0.26m

what is filtration??​

Answers

Answer:

the action or process of filtering something.

Explanation:

Filtration is a physical, biological or chemical operation that separates solid matter and fluid from a mixture with a filter medium that has a complex structure through which only the fluid can pass.

Helium is a....

a. metalloid
b. nonmetal
c. metal

Answers

B be ace it’s not mealy

Answer:

Nonmetal

Explanation:

Arrange the following compounds in order of increasing acidity, and explain the reasons for your choice of order. Enter your answer in the answer box below. a. 4-nitrophenol b. cyclohexanol c. 2,6-difluorocyclohexanol d. 4-bromophenol

Answers

Answer:

(a) > (d) > (c) > (b)

Explanation:

Acidic character is based upon inductive effect of the functional group that are attached to parent chain.

1. Nitro is a -I group which makes phenol acidic due to increased resonance,  2. bromine is a -I group but it is weaker than nitro group

3. phenol is more acidic than cyclohexanol due to resonance stabilization of resonance and among halogen F>Cl>Br>I is the order of acidity

4. cyclohexanol will be weakest as  it is not associated with any -I groups here.

so the order of acidity will be

(a). 4-nitropheno >  (d). 4-bromophenol > (c). 2,6-difluorocyclohexanol  >               (b). cyclohexanol

A gas sample has a gas density of 5.95 g/L at 100°C and 755 mmHg. Determine the molar mass of the gas.​

Answers

Answer:

M = 184.1 g/mol

Explanation:

Given data:

Density = 5.95 g/L

Temperature = 100°C (100+273 = 373 K)

Pressure = 755 mmHg = (755/760 = 0.99 atm )

Molar mass of gas = ?

Formula:

d = PM/RT

Solution:

M = dRT / P

M = 5.95 g/L × 0.0821 atm.L/mol.K  × 373 K/ 0.99 atm

M = 182.21atm.g/mol / 0.99 atm

M = 184.1 g/mol

2. Which of the following is NOT a necessary input for the process of photosynthesis?
A. CO2 (carbon dioxide)
B. Sunlight
C. H20 (water)
D. O2 (oxygen)

Answers

The answer would be option A. This is because CO2 or carbon dioxide is an output rather than an input. I hope this helped!

The answer option which is not a necessary input for the process of photosynthesis is: D. [tex]O_2[/tex] (oxygen)

Photosynthesis can be defined as a biological and chemical process through which living organisms such as green plants, transform light energy (sunlight) into chemical energy.

Basically, both sunlight, carbon dioxide ([tex]C0_2[/tex]) and water ([tex]H_2O[/tex]) contained in the Earth's atmosphere plays a significant role in photosynthesis because they serve as an input.

Hence, the necessary input for the process of photosynthesis to take place include the following:

Water ([tex]H_2O[/tex]) Sunlight (light energy).Carbon dioxide ([tex]C0_2[/tex]).

In conclusion, [tex]O_2[/tex] (oxygen) is an end product (output) of photosynthesis rather being an input.

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The temperature at which a particular liquid becomes a gas
5 points
A melting point
B boiling point
C freezing point
D sublimation point
5 points
a substance made of at least two atoms that are chemically combined
Apure substance
B element
C compound
D mixture

Answers

Answer:

A: melting point and the other one is i think element

1. B: boiling point 2. Is either B or C

Calculate Kb for a 0.1 M solution of cyanide ion, given that Ka for hydrocyanic acid is 6.2 x 10â10.a) 8.4 x 10â9b) 7.87 x 10â3c) 1.34 x 10â3d) 1.8 x 105e) 7.87 x 10â6f) 1.61 x 10â5g) 7.4 x 10â8

Answers

Answer:

Kb = 1.6 × 10⁻⁵

Explanation:

Step 1: Given data

Acid dissociation constant of hydrocyanic acid (Ka): 6.2 × 10⁻¹⁰

Concentration of cyanide ion (Cb): 0.1 M

Step 2: Calculate the basic dissociation constant (Kb) of cyanide ion

We have the Ka of HCN. We can calculate the Kb of its conjugate base using the following expression.

Ka × Kb = Kw = 1.0 × 10⁻¹⁴

Kb = 1.0 × 10⁻¹⁴/Ka

Kb = 1.0 × 10⁻¹⁴/6.2 × 10⁻¹⁰

Kb = 1.6 × 10⁻⁵

The  Kb for a 0.1 M solution of cyanide ion is :

- 1.6 × 10⁻⁵

Base dissociation constant

Given:

Acid dissociation constant of hydrocyanic acid (Ka)= 6.2 × 10⁻¹⁰

Concentration of cyanide ion (Cb)= 0.1 M

Base dissociation constant (kb)=?

Ka × Kb = Kw = 1.0 × 10⁻¹⁴

Kb = 1.0 × 10⁻¹⁴/Ka

Kb = 1.0 × 10⁻¹⁴/6.2 × 10⁻¹⁰

Kb = 1.6 × 10⁻⁵

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branches of sicence​

Answers

Answer:

Natural science can be divided into two main branches

Explanation:

life science and physical science. Life science is alternatively known as biology, and physical science is subdivided into branches: physics, chemistry, astronomy and Earth science.

Answer:

Astronomy  

Biology

Geology

Chemistry

Please Mark Brainliest and rate me 5

Thank You Good Night / Good Day  to you

element that is the "best" at removing electrons from other atoms.

Answers

Answer:

Fluorine

Explanation:

Fluorine is the "best" at removing electrons because it has 5 electrons on its second shell. The 5 electrons are really close and are trying to drag in another electron to complete the shell and have all 6 electrons to complete the valence shell.

Calculate the concentration (M) of arsenic acid (H3AsO4) in a solution if 25.00 mL of that solution required 35.21 mL of 0.1894 M KOH for neutralization.

Answers

Answer:

[tex]M_{acid}=0.08892M[/tex]

Explanation:

Hello!

In this case, since the reaction between arsenic acid and potassium hydroxide is:

[tex]H_3AsO_4+3KOH\rightarrow K_3AsO_4+3H_2O[/tex]

Thus, since the mole ratio between the acid and the base is 1:3, at the equivalence point we can write:

[tex]3n_{acid}=n_{base}[/tex]

That in terms of molarities and volumes is:

[tex]3M_{acid}V_{acid}=M_{base}V_{base}[/tex]

Thus, the concentration of the arsenic acid is:

[tex]M_{acid}=\frac{M_{base}V_{base}}{3V_{acid}}=\frac{0.1894M*35.21mL}{3*25.00mL} \\\\M_{acid}=0.08892M[/tex]

Best regards!

The concentration (M) of arsenic acid in a solution of 25.00 mL is 0.088M.

How we calculate the molarity?

Molarity of any solution will be calculated as:

M = n/V, where

V = volume

n is the moles and it will be calculated as:
n = W/M, where

W = given mass

M = molar mass

Given chemical reaction is:

H₃AsO₄ + 3KOH → K₃AsO₄ + 3H₂O

Moles of 35.21 mL of 0.1894 M KOH will be calculated as:

n = (0.1894)(0.035) = 0.0066 moles

From the stoichiometry of the reaction it is clear that:

1 mole of H₃AsO₄ = react with 3 moles of KOH

0.0066 moles of KOH = react with 1/3×0.0066= 0.0022 moles of H₃AsO₄

Now we calculate the molarity of H₃AsO₄ in 25mL of solution as:

M = 0.0022/0.025 = 0.088 M

Hence, required molarity is 0.088 M.

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QUESTION 24
Calculate [H 30+] of a solution with a pH of 2.14.

Answers

Answer:

The hydronium ion concentration can be found from the pH by the reverse of the mathematical operation employed to find the pH. [H3O+] = 10-pH or [H3O+] = antilog (- pH).

I hope what I just explained is enough .

What electrically neutral atom has 30 neutrons and 25 electrons?

Answers

Answer:

Manganese (Mn)

Explanation:

We know it's manganese because we are told it is an electrically neutral atom. This means it has the same number of protons and electrons. If it has 25 electrons, it has 25 protons. Protons tell us the atomic number of the atom, which also tells us the name of the element. Manganese is element 25 on the periodic table.

Compare and contrast the applications and benefits of circle graphs and bar charts. Explain

Answers

Answer:

A circle graph, or a pie chart, is used to visualize information and data. A circle graph is usually used to easily show the results of an investigation in a proportional manner. Bar graphs are used to compare things between different groups or to track changes over time. However, when trying to measure change over time, bar graphs are best when the changes are larger.

Explanation:

In short, bar graphs are better to keep track of data over long periods of time, and circle graphs are better when you are trying to visualize a specific set of data.

Circle graph and Bar charts are mainly differentiated by their shapes. Circle and bars respectively.

Circle graph can be also be called pie chart, which  is more widely used. It is usually made up of a circle, divided into parts or pies. In the divided parts, it is used to differentiate between different data.

Bar charts on the other hand are like graphs having both x and y axis. It is used to represent data with respect to the height of the graph. Each data is divided into different smaller parts on the graph.

Example of what they look like is attached below.

First one is bar chart while the second is a circle graph

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a solution is dilute when?

A. it has a lot of solute
B. has little solvent
C. it has a lot of solvent
D. has maximum solute

Answers

The answer to your equation is C. Hope this Helps!
C. It has more solvent
To dilute a solution means to add more solvent without the addition of more solute

Nitrogen dioxide (NO2) gas and liquid water (H2O) react to form aqueous nitric acid(HNO3) and nitrogen monoxide gas. Suppose you have 2.0 mol of NO2 and 7.0 mol of H20 in a reactor. Calculate the largest amount of NHO3 that could be produced. Round your answer to the nearest 0.1 mol.

Answers

Answer:

1.3 moles of HNO₃ will be produced

Explanation:

Equation for the reaction:

3NO₂ + H₂O ----> 2HNO₃ + NO

From the equation of the reaction, 3 moles of NO₂ reacts with 1 mole of H₂O to produce 2 moles of HNO₃

Suppose there are 2 moles of NO₂  and 7.0 moles of H₂O in a reactor, the limiting reactant will be NO₂ and H₂O will be in excess since 3 moles of NO₂ reacts with every 1 mole of H₂O.

Since 3 moles of NO₂ reacts to produce  2 moles of HNO₃;

2 moles of NO₂ will react to produce 2/3 * 2 moles HNO₃ = 1.3 moles of HNO₃

Therefore, 1.3 moles of HNO₃ will be produced

The largest amount of HNO₃ produced from the reaction between 2 mole of NO₂ and 7.0 mole of H₂O in a reactor is 1.3 mole

We'll begin by determining the limiting reactant. This can be obtained as follow:

3NO₂ + H₂O —> 2HNO₃ + NO

From the balanced equation above,

3 moles of NO₂ reacted with 1 mole of H₂O.

Therefore,

2 moles of NO₂ will react with = [tex]\frac{2}{3}\\\\[/tex] = 0.67 mole of H₂O.

From the calculation made above, we can see that only 0.67 mole of H₂O out of 7 moles given, reacted completely with 2 moles of NO₂. Thus, NO₂ is the limiting reactant and H₂O is the excess reactant.

Finally, we shall determine the largest amount of HNO₃ produced from the reaction. This can be obtained by using the limiting reactant as illustrated below:

From the balanced equation above,

3 moles of NO₂ reacted to produce 2 moles of HNO₃.

Therefore,

2 moles of NO₂ will react to produce = [tex]\frac{2 *2 }{3} \\\\[/tex] = 1.3 mole of HNO₃.

Thus, the largest amount of HNO₃ produced from the reaction is 1.3 mole

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(a) Given that the path length of the cuvette is 1 cm, what is the extinction coefficient of the 0.020 mM Yellow 5 dye at lambda max?(b) Given the data in the table below, what is the concentration of the diluted solution?Stock solution concentration 0.075 MStock solution absorbance 1.84Diluted solution absorbance 0.78

Answers

Answer:

(a). Kindly check the explanation section.

(b). 24.5 M^-1 cm^-

(c). 0.0318 M

Explanation:

So, we are given the following data parameters which is going to aid us in solving the above Question;

The path length = 1cm, extinction coefficient = unknown, absorbance is unknown and concentration= 0.02mM.

Using the formula below; we can determine the extinction coefficient as;

Absorbance = extinction coefficient × concentration × path length. -----------(1).

(a). Since, the absorbance is not given in the Question it won't be possible to determine the value of the extinction coefficient. Thus, say the value of absorbance = A.

Then, extinction coefficient = A/ 0.02 × 1 cm.

(b). Making use of the formula above, the extinction coefficient can be Determine as follows;

extinction coefficient = 1.84/0.075 × 1 = 24.5 M^-1 cm^-1.

(c). The concentration can be Determine by also making use of the formula above and making the concentration the subject of the formula;

Concentration = absorbance/ extinction coefficient × path length.

Concentration = 0.78/24.5 M^-1 cm^-1. × 1cm = 0.0318 M.

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