How many grams are in 1.30 x 10^24 formula units of Ca(NO3)2?
A. 151 g
B. 354 g
C. 294 g
D. 416 g

How Many Grams Are In 1.30 X 10^24 Formula Units Of Ca(NO3)2?A. 151 GB. 354 GC. 294 GD. 416 G

Answers

Answer 1

Answer:

354 gram

Explanation:

No of formula units = no of moles × Avogadro's number

Number of moles = no of formula units/ Avogadro's number

No of moles = 1.30×10^24/60.02×10^23

No of moles = 2.159 moles

Mo of moles = mass in gram/ molar mass

Mass in gram = no of moles× molar mass

Mass in gram =2.159×164

Mass in gram = 354.15 gram

Answer 2

The grams that are present in [tex]1.30 * 10^{24}[/tex] formula units of [tex]Ca(NO_3)_2[/tex] is 354 gram that can be calculated using number of moles.

(B) 354 g

One mole:

A mole is defined as [tex]6.02214076 * 10^{23}[/tex] of some chemical unit, be it atoms, molecules, ions, or others.

No. of formula units = no of moles × Avogadro's number

Number of moles = no of formula units/ Avogadro's number

No. of moles = [tex]1.30*10^{24}/6.022*10^{23}[/tex]

No. of moles = 2.159 moles

The Number of moles is defined as the given mass over molar mass.

No. of moles = Mass / Molar mass

Mass = no. of moles× molar mass

Mass =2.159×164

Mass = 354.15 gram

Thus, option B is correct.

Find more information about Moles here:

brainly.com/question/1358482


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Answers

Answer:

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have a great day


XD​

Answers

Answer:

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Explanation:

[tex]\huge{\mathfrak{\purple{Answer}}}[/tex]

The boiling point and freezing point of the given liquid comes out to be 100°C or 373 K and 0°C or 273 K respectively under one atmospheric pressure, it confirms that the given liquid is pure water

[tex]\huge{\mathfrak{\purple{Explanation}}}[/tex]

#HopeItHelps

what does 'potable water' mean?

Answers

Answer:

Potable water, also known as drinking water, comes from surface and ground sources and is treated to levels that that meet state and federal standards for consumption.

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Answers

Answer:

24.06 g of CO₂

Explanation:

The balanced equation for the reaction is given below:

CH₄ + 2O₂ —> 2H₂O + CO₂

Next, we shall determine the mass of O₂ that reacted and the mass of CO₂ produced from the balanced equation. This can be obtained as follow:

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Mass of O₂ from the balanced equation = 2 × 32 = 64 g

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= 12 + 32

= 44 g/mol

Mass of CO₂ from the balanced equation = 1 × 44 = 44 g

SUMMARY:

From the balanced equation above,

64 g of O₂ reacted to produce 44 g of CO₂.

Finally, we shall determine the mass of CO₂ produced by the reaction of 35 g of O₂. This can be obtained as follow:

From the balanced equation above,

64 g of O₂ reacted to produce 44 g of CO₂.

Therefore, 35 g of O₂ will react to produce = (35 × 44)/64 = 24.06 g of CO₂.

Thus, 24.06 g of CO₂ were produced from the reaction.

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Answers

Answer:

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Answer:

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Answers

Answer:

[tex]\boxed {\boxed {\sf 301.325 \ Joules }}[/tex]

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Answers

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https://www.cdc.gov/handwashing/pdf/wash-your-hands-fact-sheet-508.pdf

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Answers

Answer:

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Explanation:

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partial pressure of oxygen  = 29.3kPa

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partial pressure of methane  = ?

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The total pressure of mixture is equal to the sum of their particles pressures;

 

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