How many significant figures does 5.750 have?

C.heat the solution

Answer:

I think its D sorry if im wrong

Answer:i think its D

Explanation:

Answer:

they should have a number that can completely transfer and fill the other atom

Explanation:

example:

sodium(2.8.1)and Chlorine(2.8.7)the sodium will give chlorine the 1 valence electrobo so they both become stable(2.8)±and(2.8.8)–

magnesium(2.8.2)and oxygen(2.6)same way as above to abtain mg(2.8)±²and oxygen(2.8)–²

[H+]=3.98x10^-9

[H+]=10^-pH=10^-8.4

[H+]=10^-11, base

[H+]=10^-pH=10^-11

A solution with a pH of more than 7 is basic.

Lemon juice because it is more acidic

pH of lemon juice: 2.5

pH of vinegar: 3.3

Since the pH of lemon juice is lower, it is more acidic and will be more effective at removing the basic deposits.

What Connie could have used to detect when the chemical reaction was complete is an: acid-base indicator.

A chemical reaction is a chemical process that involves the continuous rearrangement (transformation) of either the ionic, atomic or molecular structure of a chemical element through the breakdown and formation of chemical bonds, in order to produce a chemical compound.

When a strong acid such as Hydrogen chloride (HCl) react with a strong alkali such as Sodium hydroxide (NaOH), it gives rise to the formation of Sodium chloride (NaCl) and Water ([tex]H_2O[/tex]);

                       [tex]HCl + NaOH[/tex] ----> [tex]NaCl + H_2O[/tex]

The progress of the above chemical reaction can be followed by using a pH sensor and the final pH of a strong acid and strong base is seven (7), meaning it is neutral.

However, Connie could make use of an acid-base indicator to detect when the chemical reaction is complete.

An acid-base indicator can be defined as a chemical substance that changes color with respect to the pH (hydrogen ion concentration) of a solution or chemical reaction. Some examples of an acid-base indicator are:

In conclusion, an acid-base indicator is typically used for detecting when a chemical reaction between an acid and an alkali is complete.

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Answer:When a strong acid such as Hydrogen chloride (HCl) react with a strong alkali such as Sodium hydroxide (NaOH), it gives rise to the formation of Sodium chloride (NaCl) and Water ();

---->

Explanation:

Gases, liquids and solids are all made up of atoms, molecules, and/or ions, but the way the particles inside them differ.

In a gas, the molecules are spread wide apart and moves freely at high speeds

In a liquid, the more closer to each other and will vibrate or slip past each other

In a solid, the molecules are tightly packed, making no room for each other and harder to move. These molecules vibrate and jiggle but, don't move

Answer:

The answer is animals

Explanation:

Plants and fungi have a cell wall, and although most bacteria lack a cell wall, the question is asking in which kingdom do ALL organisms lack a cell wall. Hope this helps.

Answer:Bacteria

Explanation:

Answer:

X= -Y + 2/2     Y=-X + 3/2

Explanation:

I don't know how to simplify it anymore. You would get x=-y+3/2 and y=-x+3/2

Answer:

Explanation:

(-1/2,1)

Answer:

3.34x10¹⁶ molecules of aspirin are in a drop of blood

Explanation:

The recomended dose of aspirin in blood is 100.0μg/mL =

1x10⁻⁴g aspirin / mL of blood.

In a drop (0.100mL) there are:

0.100mL ₓ (1x10⁻⁴g aspirin / mL of blood) = 1x10⁻⁵g aspirin.

Molecular mass of aspirin is:

9C = 12.01g/mol ₓ 9 = 108.09g/mol

8H = 1.01g/mol ₓ 8 = 8.08g/mol

4O = 16g/mol ₓ 4 = 64g/mol

108.09 + 8.08 + 64 = 180.17g/mol

Thus, moles of aspirin in 1x10⁻⁵g are:

1x10⁻⁵g ₓ (1mol / 180.17g) = 5.55x10⁻⁸ moles of aspirin

In 1 mole, you have 6.022x10²³ molecules, thus:

5.55x10⁻⁸ moles of aspirin ₓ (6.022x10²³ molecules / 1 mole ) =

Answer:

Basis and basic​ are two different words.

In English, Basis is used as a noun while basic is used as an adjective. Basis term refers as the base or starting point of any discussion.

For example: Bread is a basic ingredient of cake.

                      On the basis of Mendel's hypothesis.

In chemistry, Basis set is used as a set of functions that represent the electronic wave function in the density-functional theory which forms an  algebraic equations that can be easily implemented on a computer.

While Basic term is used for substances that can accept a hydrogen ion (H+) from another substance and have pH above 7. such as sodium.

So, It is not important that both the terms, basis and basic change their English meaning if used in chemistry, they both can be used with English meaning in chemistry as well. Bases and basic,​ both the terms can be used as either English or Chemistry without affecting the meaning.

A chemical  reaction involves the interaction of reactants. The substance X ,must be an acid and in this case is CH3COOH

In chemistry, a reaction is said to occur when substances interact in such a way that other new substances are formed.

Now let us look at the particular reaction; NaOH + X ----> NaCH3COO + H2O. The substance X must be an acid. Hence, the most likely susbstance is CH3COOH.

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Answer:

The answer is 60W

Power = Work done/ time

time = 1 second

Work done = 60J

Power = 60/1

= 60W

Hope this helps.

Answer:

Visible wavelengths range from 0.0007 milimeters for red light, through orange, yellow, green, and blue, to 0.0004 milimeters for violet light.

Ultraviolet is shorter wavelengths than violet.

Hope This Helps.

Answer:

organic chemistry

because it is study of carbon containing substances

Organic chemistry is the branch of Chemistry where hydrocarbons are the compounds of carbon and hydrogen.

Organic chemistry is the study of the structure, properties, composition, reactions, and preparation of carbon-containing compounds.

Hydrocarbons Derivatives are compounds which are made up of hydrogen and carbon with specific functional groups attached to them.

Examples:- Aldehydes, ketones, carboxylic acids, alcohols, alkyl halides, ethers, amines etc.

Hence, organic chemistry is the branch of Chemistry where

hydrocarbons are the compounds of carbon and hydrogen.

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Answer: SI prefixes are used to form decimal multiples and submultiples of SI units. They should be used to avoid very large or very small numeric values.

Explanation: ^^^

Answer:

Explanation:

Pv = n RT

P =7.65, T= 310K, for glucose n = moles= weight/molar mass= weight/180, R is gas constant

7.65* V =W/180 *0.0821 * 310

w/v= 7.65*180/0.0821*310 = 1377/25.45 = 54.10 =5.4%

Answer:

F

Explanation:

"The mass of the products is equal to the mass of the reactants" is true about the principle of the conservation of mass.

So, option f is correct one.

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Answer:

[tex]\large \boxed{1.615 \times 10^{25}\text{ molecules water}}[/tex]

Explanation:

You must calculate the mass of the water, convert it to moles, and then calculate the number of molecules.

1. Mass of water

[tex]\text{Mass } = \text{499.8 mL} \times \dfrac{\text{0.967 g}}{\text{1 mL}} = \text{483.3 g}[/tex]

2. Moles of water

[tex]\text{Moles of water} = \text{483.3 g water} \times \dfrac{\text{1 mol water}}{\text{18.02 g water}} = \text{26.82 mol water}[/tex]

3. Molecules of water

[tex]\text{No. of molecules} = \text{26.82 mol water} \times \dfrac{6.022 \times 10^{23}\text{ molecules water}}{\text{1 mol water}}\\\\= \mathbf{1.615 \times 10^{25}}\textbf{ molecules water}\\\text{The sample contains $\large \boxed{\mathbf{1.615 \times 10^{25}}\textbf{ molecules water}}$}[/tex]

The number of molecules of water  present in the bottle is 1.62×10²⁵ molecules.

We'll begin by calculating the mass of the water in the bottle.

Mass = Density × Volume

Mass of water = 0.967 × 499.8

Mass of water = 483.3066 g

Finally, we shall determine number of molecules of water in the bottle.

From Avogadro's hypothesis,

1 mole of water = 6.02×10²³ molecules

But,

1 mole of water = 18 g

Thus, we can say that:

18 g of water = 6.02×10²³ molecules

Therefore,

483.3066 g of water = (483.3066 × 6.02×10²³) / 18

483.3066 g of water = 1.62×10²⁵ molecules

Thus, the number of molecules of water in the bottle is 1.62×10²⁵ molecules.

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12,194 L is the answer!

Explanation:

Water has the maximum density at the temperature of 4°Celsius. So, it expands at temperatures higher or lower than 4°C, knowing that at the temperature of -25°C the water can't have a lower volume than the one at 15°C.

Answer:

12, 194 L

That's your answer!!!

Answer:

See the answer below

Explanation:

Aqueous solution of copper II nitrate contains solute of copper II nitrate dissolved in water. The equation for the reaction is as below:

[tex]Cu(NO_3)_2 (s)[/tex] + [tex]H_2O (l)[/tex] --> [tex]Cu(NO_3)_2 (aq)[/tex]

Hence, the solute chemical is copper II nitrate while the solvent is water.

Chemical formula of copper II nitrate - [tex]Cu(NO_3)_2[/tex]

Chemical formula of water - [tex]H_2O[/tex]

Answer: The boiling point of a 3.70 m solution of phenol in benzene is [tex]89.5^0C[/tex]

Explanation:

Elevation in boiling point:

[tex]\Delta T_b=i\times k_b\times m[/tex]

where,

[tex]\Delta T_b[/tex] = change in boiling point

i= vant hoff factor = 1 (for benzene which is a non electrolyte )

[tex]k_b[/tex] = boiling point constant = [tex]2.53^0C/kgmol[/tex]

m = molality = 3.70

[tex]T_{solution}-T_{solvent}=i\times k_b\times m[/tex]

[tex]T_{solution}-80.1^0C=1\times 2.53\times 3.70[/tex]

[tex]T_{solution}=89.5^0C[/tex]

Thus  the boiling point of a 3.70 m solution of phenol in benzene is [tex]89.5^0C[/tex]

Answer:

First Question:

C. ΔTb = Kbm

Second Question:

C. 9.36° C

Third Question:

89.5

Explanation:

Got it right.

Answer: 1.29 moles of ethylene glycol must be added to 1 kg of water to make a solution with a freezing point of -2.4°C. Molality of solution is 1.29 m.

Explanation:

Depression in freezing point is given by:

[tex]\Delta T_f=i\times K_f\times m[/tex]

[tex]\Delta T_f=T_f^0-T_f=(0-(-2.4))^0C=2.4^0C[/tex] = Depression in freezing point

i= vant hoff factor (for non electrolyte , i = 1)

[tex]K_f[/tex] = freezing point constant for water= [tex]1.86^0C/kgmol[/tex]

m= molality =[tex]\frac{\text{moles of solute}}{\text{weight of solvent in kg}}[/tex]

m= molality =[tex]\frac{x}{1kg}[/tex]

[tex]2.4^0C=1\times 1.86^0C/kgmol\times \frac{x}{1kg}[/tex]

[tex]x=1.29[/tex]

Molality = [tex]\frac{\text{moles of solute}}{\text {weight of solvent in kg}}=\frac{1.29mol}{1kg}=1.29m[/tex]

Thus 1.29 moles of ethylene glycol must be added to 1 kg of water to make a solution with a freezing point of -2.4°C. Molality of solution is 1.29 m.

Answer:

1) C (m=T f/Kf)

2) 2.4 C

3) 1.3 m

4) 1.3 moles

Explanation:

This is correct on ed

Answer:

yh you are correct. the pattern is correct! :)

Answer:

Yep! :)

Explanation:

Answer:

23.6°C

Explanation:

Step 1:

Data obtained from the question. This include the following:

Mass = 0.125kg = 0.125 x 1000 = 125g

Initial temperature (T1) = 22°C

Heat (Q) generated in 4.5mins = 835J

Specific heat capacity (C) of water = 4.184J/g°C

Change in temperature (ΔT) =?

Final temperature (T2) =?

Step 2:

Determination of the change in temperature, ΔT of water.

This can be obtained as shown below:

Q = MCΔT

835 = 125 x 4.184 x ΔT

Divide both side by 125 x 4.184

ΔT = 835 / (125 x 4.184)

ΔT = 1.6°C

Therefore, the change in temperature, ΔT is 1.6°C

Step 3:

Determination of the final temperature of water.

This can be obtained as follow:

Initial temperature (T1) = 22°C

Change in temperature (ΔT) = 1.6°C

Final temperature (T2) =?

Change in temperature (ΔT) = Initial temperature – Final temperature

ΔT = T2 – T1

1.6 = T2 – 22

Collect like terms

T2 = 1.6 + 22

T2 = 23.6°C

Therefore, the final temperature of the water is 23.6°C.

Answer:

Explanation:

Average Atomic mass of any element =[ ∑ Abundance* mass of element] /100

                                                                = 10*20 +11*80 /100

                                                                = .........

Hope this helps you

Answer:

[tex]V=1.61L[/tex]

Explanation:

Hello,

In this case, the undergoing chemical reaction is:

[tex]Mg+2HCl\rightarrow MgCl_2+H_2[/tex]

Next, we compute the reacting moles of each reactants:

[tex]n_{Mg}=3.712gMg*\frac{1molMg}{24.305 gMg}=0.153molMg[/tex]

[tex]n_{HCl}=1.385\frac{molHCl}{L}*0.1042L=0.144molHCl[/tex]

Then, as magnesium and hydrohloric acid are in a 1:2 molar ratio 0.153 moles of magnesium will completely react with 0.306 moles of hydrochloric acid yet we only have 0.144 moles, therefore, limiting reactant is hydrochloric acid. Thus, we compute the produced moles of hydrogen:

[tex]n_{H_2}=0.144molHCl*\frac{1molH_2}{2molHCl} =0.072molH_2[/tex]

Finally, we use the ideal gas equation with T=298K and 1atm (STP conditions) to compute the liters of hydrogen gas:

[tex]PV=nRT\\\\V=\frac{nRT}{P}=\frac{0.072mol*0.082\frac{atm*L}{mol*K}*273K}{1atm}\\ \\V=1.61L[/tex]

Best regards.

Answer:

49 g/L is the concentration of the acid

Explanation:

Firstly, we proceed to write the equation of reaction.

2NaOH + H2SO4 ——-> Na2SO4 + 2H2O

We can see that 1 mole of the base reacted with two moles of the acid.

kindly note that dm^3 is same as liter

Firstly, we need to get the concentration of the reacted sulphuric acid in g/L

we use the simple titration equation below;

CaVa/CbVb = Na/Nb

From the question;

Ca = ?

Va = 25 cm^3

Cb = 20 g/L

we convert this to concentration in mol/L

Mathematically, that is concentration in g/L divided by molar mass in g/mole

molar mass of NaOH = 40 g/mol

so we have; 20g/L / 40 = 0.5 mol/L

Vb = 50 cm^3

Na = 1

Nb = 2

Where C represents concentrations, V volumes and N , number of moles

Now, substitute the values;

Ca * 25/0.5 * 50 = 1/2

25Ca/25 = 0.5

So Ca = 0.5 mol/L

Now to get the concentration of H2SO4 in g/L

What we do is to multiply the concentration in mol/L by molar mass in g/mol

That would be 0.5 * 98 = 49 g/L

The concentration of the acid in grams per litre is 49g/L

From the question,

We are to determine concentration of the sodium hydroxide solution.

First, we will write a balanced chemical equation for the reaction.

The balanced chemical equation for the reaction is

2NaOH + H₂SO₄ → Na₂SO₄ + 2H₂O

This means,

2 moles of NaOH is required to completely neutralize 1 mole of H₂SO₄

From the formula

[tex]\frac{C_{A}V_{A} }{C_{B}V_{B} }=\frac{n_{A} }{n_{B} }[/tex]

Where

[tex]C_{A}[/tex] is the concentration of acid

[tex]C_{B}[/tex] is the concentration of base

[tex]V_{A}[/tex] is the volume of acid

[tex]V_{B}[/tex] is the volume of base

[tex]n_{A}[/tex] is the mole ratio of acid

[tex]n_{B}[/tex] is the mole ratio of base

From the question

[tex]V_{A}= 25 \ cm^{3}[/tex]

[tex]C_{B} = 20 \ g/dm^{3}[/tex]

Convert this to mol/dm³

Molar mass of NaOH = 40 g/mol

Using the formula

[tex]Concentration\ in \ mol/dm^{3} =\frac{Concentration\ in \ g/dm^{3}}{Molar\ mass}[/tex]

∴ Concentration of the NaOH in mol/dm³ = [tex]\frac{20}{40}[/tex]

Concentration of the NaOH in mol/dm³ = 0.5 mol/dm³

∴ [tex]C_{B} = 0.5 \ mol/dm^{3}[/tex]

and

[tex]V_{B} = 50 \ cm^{3}[/tex]

From the balanced chemical equation

[tex]n_{A} = 1[/tex]

[tex]n_{B} = 2[/tex]

Putting the parameters into the formula, we get

[tex]\frac{C_{A} \times 25}{0.5 \times 50}= \frac{1}{2}[/tex]

Now, this becomes

[tex]2 \times 25 \times C_{A}=0.5 \times 50 \times 1[/tex]

Then, we get

[tex]50 C_{A} = 25[/tex]

∴ [tex]C_{A} = \frac{25}{50}[/tex]

[tex]C_{A} = 0.5 \ mol/dm^{3} = 0.5 \ mol/L[/tex]

Now, we will determine the concentration in g/L

From the formula,

Concentration in g/L = Concentration in mol/L × Molar mass

From the question,

Molar mass of sulfuric acid = 98

∴ Concentration of the acid in g/L = 0.5 × 98

Concentration of the acid in g/L = 49 g/L

Hence, the concentration of the acid in grams per litre is 49g/L

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