I need helppppppppppp. Btw the question is “Select three populations shown in the prairie ecosystem.”

Answer: FeF3      Iron(III) fluoride

Explanation: 5.6 g = 1/10 mole Fe

11.3-5.6g F = 5.7 = 3/10 mole F

Answer:

The balanced molecular equation for the reaction is:

[tex]2HNO_{3_{(aq)} }[/tex] + [tex]K_{2} CO_{3} _{(s)}[/tex] → [tex]2KNO_{3} _{(s)}[/tex] + [tex]H_{2} O_{(l)[/tex] + [tex]CO_{2} _{(g)}[/tex]↑

Explanation:

The weak nitric acid reacts with the strong potassium base to produce salt, water and carbon dioxide which is given off.

Molecular ratio of reactants is 2 : 1.

All phases are represented in the equation: aq for aqueous, l for liquid and g for gas (notice how they are written in subscript).

I hope this was helpful.

Answer:

0.011mole

Explanation:

Given parameters:

Mass of potassium in the banana = 0.42g

Unknown:

Number of moles of potassium in the banana = ?

Solution:

To solve this problem, we use the expression below:

     Number of moles  = [tex]\frac{mass}{molar mass}[/tex]  

Molar mass of K  = 39g/mol

   Number of moles  = [tex]\frac{0.42}{39}[/tex]   = 0.011mole

Explanation:

Moreover, increasing use of fossil fuels also causes serious environmental problems. Hence, there is a pressing need to use renewable energy sources like solar energy, wind, tide, biomass and energy from waste material. (i) it reduces the dependence on fossil fuels for energy. (ii) they donot produces pollution.

Answer:

Lithium oxide, Li₂O.

Explanation:

Hello!

In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:

[tex]M_2O+H_2 \rightarrow 2M+H_2O[/tex]

Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:

[tex]5.00gM_2O*\frac{1molM_2O}{(2x+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{xgM}{1molM} = 2.32gM[/tex]

Thus, we perform the operations in order to obtain:

[tex]\frac{10x}{2x+16}=2.32[/tex]

So we solve for x as shown below:

[tex]10x = 2.32(2x+16)\\\\10x = 4.64x+37.12\\\\x = \frac{37.12}{10-4.64}\\\\x= 6.93 g/mol[/tex]

Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.

Best regards!

Answer:

B.

Explanation:

Answer:

B is the correct answer

Explanation:

Answer:

A substance is a pure single form of matter. It cannot be separated into other kinds of matter by any physical process.

sorry i can only figure out 1 but the answer is

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124

hope you do good on your test :D

Answer:

1-6

3 1 3 3 2 2

Explanation:

Answer:

the flow rate of the gas stream leaving the condenser is 71.9 moles/min

Explanation:    

Given the data in the question and the figure below;

N2 BALANCE

(100% - 18%) × ( mole rate in ) = ( 100% - 5%) × ( mole rate out)

0.82 × ( mole rate in ) = 0.95 × ( mole rate out)

mole rate in = 0.95 × ( mole rate out) / 0.82

mole rate in = 1.1585365853 × ( mole rate out)

now;

HEXANE BALANCE

0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate  --- equ 1

but condensate = 1.5 L/min × ( density of hexane ) × 1/molar mass of hexane

we know that;

density of hexane is 0.6548 g/mL

and molar mass of hexane is 86.18 g/mol

so,

condensate = 1.5 L/min × ( 0.6548 g/mL × 1000 mL/L ) × ( 1/86.18 g/mol)

condensate = 11.3970758876

now lets substitute into equation 1

0.18 × ( mole rate in ) = 0.0500 × ( mole rate out) + condensate

⇒ 0.18 × ( 1.1585365853 × ( mole rate out) ) = 0.0500 × ( mole rate out) + 11.3970758876

⇒ 0.208536585354(mole rate out) = 0.0500( mole rate out) + 11.3970758876

⇒ 0.208536585354(mole rate out) - 0.0500( mole rate out) = 11.3970758876

⇒ 0.158536585354(mole rate out) = 11.3970758876

mole rate out = 11.3970758876 / 0.158536585354

mole rate out =  71.889247 ≈ 71.9 moles/min

Therefore, the flow rate of the gas stream leaving the condenser is 71.9 moles/min

Answer:

The name of the process happening in the picture is explained below in details.

Explanation:

The process in the picture is photosynthesis. The plant is taking CO2 and H2O and using light to form glucose which would be the sugars and creating a byproduct of oxygen that is being released into the atmosphere. How did you know this is photosynthesis? A big thing clearly is the plant and how it’s taking H2O and CO2 and making glucose so it isn’t cellular respiration (if you don’t know what that is don’t worry, if you are learning about this you are bound to come across that later) and it’s releasing oxygen into the atmosphere and light has a function in this process according to the image.

Answer:

The water phase with the smallest temperature increase when adding 10 kcal of heat is solid ice.

Explanation:

The rest of the statements are incorrect. The density of ice is lower than the density of water. The heat capacity of solid ice is greater almost twice the heat capacity of the liquid water. The heat capacity of vapors is less than heat capacity of liquid.

Answer:

the molar mass of propane (c3H8) is

12*3+1*8

=36+8=44

Answer:

Glucose!!

Explanation:

Also keep in mind that the actual sugar produced from photosynthesis is C6H12O6, which is the basis for glucose as well as other complex molecules

Answer:

Glucose

Explanation:

photosynthesis uses the energy from the light to convert carbon dioxide molecules which makes glucose

Answer:

30 yard per second

Explanation:

300/10 = 30

Answer:

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

Explanation:

Roman numeral is used to indicate the oxidation number of an element in a compound.

The roman numeral in copper(I) oxide indicates that the oxidation number of copper in the compound is 1.

This can be seen from the following illustration:

copper(I) oxide => Cu₂O

Oxidation number of O = –2

Oxidation number of Cu₂O = 0

Oxidation number of Cu =?

Cu₂O = 0

2Cu + O = 0

2Cu – 2 = 0

Collect like terms

2Cu = 0 + 2

2Cu = 2

Divide both side by 2

Cu = 2/2

Cu = 1

Thus, we can see that the oxidation number of Cu in Cu₂O is 1. Hence the name of Cu₂O is copper(I) oxide indicating that the oxidation number of of copper (Cu) in the compound is 1.

For copper(II) oxide, we shall determine the oxidation number of Cu. This can be obtained as follow:

copper(II) oxide, CuO => CuO

Oxidation number of O = –2

Oxidation number of CuO = 0

Oxidation number of Cu =?

CuO = 0

Cu + O = 0

Cu – 2 = 0

Collect like terms

Cu = 0 + 2

Cu = 2

Thus, the oxidation number of Cu in CuO is 2. Hence the name of CuO is copper(II) oxide indicating that the oxidation number of of copper (Cu) in the compound is 2.

From the above illustrations,

We can see that the roman numeral in both copper(I) oxide, Cu₂O and copper(II) oxide, CuO are different because the oxidation number of Cu in both cases are different.

Answer:

13.22 L

Explanation:

Given data:

Volume of ammonia = ?

Mass of ammonia = 10.0 g

Temperature = standard = 273.15 K

Pressure = standard = standard = 1 atm

Solution:

First of all we will calculate the number of moles of ammonia.

Number of moles = mass/molar mass

Number of moles = 10.0 g/ 17 g/mol

Number of moles = 0.59 mol

one mole of any substance at standard temperature and pressure occupy 22.41 L . Thus, 0.59 moles of ammonia will occupy,

0.59 mol × 22.4 L / 1 mol

13.22 L

Answer: 12.4L

Explanation:

mw NH3 18

1 mole = 22.4L

10g = 10/18 moles

Answer:

1.34 * 10^-7 M

Explanation:

The Ksp of lead II chromate is 1.8 x 10^-14

So, we have that;

PbCrO4(s) -----> Pb^2+(aq) + CrO4^2-(aq)

                             s                  s

Where s = molar concentration of Pb^2+(aq) and  CrO4^2-(aq)

and;

[Pb^2+] = [CrO4^2-]

This implies that Ksp = s^2

s = √Ksp

s = √1.8 x 10^-14

s = 1.34 * 10^-7 M

Answer: 0.800 M

Basically, the ratio is 2:1, so when you have 1 M of Li2HPO4 it means you have 2 M in the concentration of lithium ions. So knowing the ratio, we know we just need to multiply 0.400 x 2.

I'm bad at explaining it, but got it right on chem101 sooo

The concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄ is 0.8 M.

The concentration of a substance is simply the amount of the substance in 1 L of water.

To obtain the concentration of lithium ion, Li⁺ in Li₂HPO₄, we'll begin by writing the dissociation equation of Li₂HPO₄. This is illustrated below:

From the balanced equation above,

1 mole of Li₂HPO₄ produced 2 moles of Li²⁺.

Finally, we shall determine the concentration of lithium ion, Li⁺ in 0.4 M Li₂HPO₄. This can be obtained as follow:

From the balanced equation above,

1 mole of Li₂HPO₄ produced 2 mole of Li⁺.

Therefore, 0.4 M Li₂HPO₄ will produce = 2 × 0.4 = 0.8M Li²⁺

Thus, 0.8 M lithium ion, Li⁺ is present in the solution.

Learn more: https://brainly.com/question/19536817

Answer:

What is ^ for?

Explanation:

Answer:

The atom contains a vey small small nucleus that contains most of its mass.

Explanation:

The Rutherford gold leaf experiment concluded that most (99%) of all the mass of an atom is in the nucleus of the atom, that the nucleus is very small (105 times small than the size of the atom) and that is is positively charged.

Answer:

44.84 ml

Explanation:

14.86

+

15.0

+

14.980

_______

44.84

Answer:

2812.6 g of H₂SO₄

Explanation:

From the question given above, the following data were obtained:

Mole of H₂SO₄ = 28.7 moles

Mass of H₂SO₄ =?

Next, we shall determine the molar mass of H₂SO₄. This can be obtained as follow:

Molar mass of H₂SO₄ = (1×2) + 32 + (16×4)

= 2 + 32 + 64

= 98 g/mol

Finally, we shall determine the mass of H₂SO₄. This can be obtained as follow:

Mole of H₂SO₄ = 28.7 moles

Molar mass of H₂SO₄ =

Mass of H₂SO₄ =?

Mole = mass / Molar mass

28.7 = Mass of H₂SO₄ / 98

Cross multiply

Mass of H₂SO₄ = 28.7 × 98

Mass of H₂SO₄ = 2812.6 g

Thus, 28.7 mole of H₂SO₄ is equivalent to 2812.6 g of H₂SO₄

Answer:

I think it will carbon hope it helps

Answer:

2.69 * 10^-6 Mol/L

Explanation:

The equation of the reaction is;

Cl2CHCO2CH3 -------------------> Cl2CHCO2H + CH3OH

To convert from ppm concentration to Mol/L, we have

M = ppm/MM * 1000

Where;

M = mol/l

MM= Molar mass

M = 1/142.97 g/mol * 1000 =

M= 6.99 * 10^-6 Mol/L

For first order reaction;

ln[A] = ln[A]o -kt

Given that

[A]o = 6.99 * 10^-6 Mol/L

[A]=??

k= 2.7 x 10-4/sec

t= 30 mins * 60 = 1800 s

ln[A] = ln[6.99 * 10^-6] -   (2.7 x 10-4 * 1800)

ln[A] = -11.87 - 0.486

ln[A] = -12.356

[A] = e^(-12.356)

[A] = 4.3 * 10^-6 Mol/L

Concentration of methanol present after 30 mins= 6.99 * 10^-6 - 4.3 * 10^-6 = 2.69 * 10^-6 Mol/L