~I will mark as BRANLIEST and give you 55 points if you answer correctly.

Step-by-step explanation:

10 more than 178.25 is add so

178.25 + 10 = 188.25

Answer:

x= 0, 2, -6

Hope this helps!

Answer:

|5| = 5 and |2| = 2 and because 5 > 2, our answer is |5| > |2|.

Answer:

|5|

Step-by-step explanation:

5 is greater than 2

Answer:

8 units.

Step-by-step explanation:

The smaller of the right triangles formed is similar to the whole triangle so

4/x = x/16   where  x = the shorter leg

x^2 = 64

x = 8.

The length of the shorter leg of the right triangle is 3 units.

Let's denote the length of the shorter leg of the right triangle as "x." Since the altitude drawn to the hypotenuse divides it into segments of lengths 4 and 12, we can set up a proportion between the two triangles formed.

According to the similarity of triangles, the length of the shorter leg to the length of the segment of the hypotenuse it divides is the same as the length of the longer leg to the length of the other segment of the hypotenuse.

So, we can set up the proportion:

x / 4 = 12 / (hypotenuse length).

Now, we know that the hypotenuse length is equal to the sum of the two segments (4 + 12 = 16). We can substitute it into the proportion:

x / 4 = 12 / 16.

Now, cross-multiply and solve for x:

16x = 4 * 12,

16x = 48,

x = 48 / 16,

x = 3.

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Answer:

(0,34)

Step-by-step explanation:

For each rise of 14 in the x direction, this graph rises by -8 in the y direction. This means that, when x is 0, and the graph intersects the y axis, the y value will be 50-8-8=34. Therefore, the y intercept of this line is (0,34). Hope this helps!

Answer:

The answer is (0,34)

Answer:

p-value (0.0208) is less than alpha = 0.05 reject H0.

Step-by-step explanation:

we have the following data:

sample size = n = 75

x, the number to evaluate is 45

the sample proportion would be: x / n = 45/75

p * = 0.6

Now, the null and alternative hypotheses are:

H0: P = 0.72

Ha: P no 72

two tailed test

statistic tes = z = (p * - p) / [(p * (1-p) / n)] ^ (1/2)

replacing we have:

z = (0.6 - 0.72) / [(0.72 * (1-0.72) / 75)] ^ (1/2)

z = -2.31

p-vaule = 2 * p (z <-2.31)

using z table, we get:

p-vaule = 2 * (0.0104)

p-vaule = 0.0208

Therefore, p-value (0.0208) is less than alpha = 0.05 reject H0.

Answer: (-6, 0)

Step-by-step explanation:

X-intercepts of equations are any points on the equation that lie on the x-axis, or the horizontal line "y = 0".

In order to find the x-intercept of an equation, find the points that will satisfy the equation "y = 0":

y = (x + 6)(x - 3)

y = 0

(x + 6)(x - 3) = 0

With this equation, you can find which points lie on the x-axis.

When x = -6, the equation is: 0 * -9 = 0, which is correct.

When x = 3, the equation is 9 * 0 = 0, which is correct.

Make sure you're picking the correct coordinate out of the answer choices.

The x-coordinates are -6 and 3, and the y-coordinates are 0, because the points lie on the x-axis.

The correct answer is (-6, 0).

(3, 0) is also correct, but the question does not require it.

Answer:

D

Step-by-step explanation:

Answer:

A. 1.8 ×[tex]10^{30}[/tex] Kg

B i. 3.0 × [tex]10^{17}[/tex] seconds

  ii. 9.6 × [tex]10^{9}[/tex] years

C. After 9.2 × [tex]10^{9}[/tex] (9.2 billion) years

Step-by-step explanation:

Given that the mass of the Sun = 2× [tex]10^{30}[/tex] Kg.

Mass of hydrogen when Sun was formed = 76% of 2× [tex]10^{30}[/tex] Kg

                            = [tex]\frac{76}{100}[/tex]  ×2× [tex]10^{30}[/tex] Kg

                           = 1.52 × [tex]10^{30}[/tex] Kg

Mass of hydrogen available for fusion = 12% of 1.52 × [tex]10^{30}[/tex] Kg

                           = [tex]\frac{12}{100}[/tex] × 1.52 × [tex]10^{30}[/tex] Kg

                           = 1.824 ×[tex]10^{30}[/tex] Kg

A. Total mass of hydrogen available for fusion over the lifetime of the sun is 1.8 ×[tex]10^{30}[/tex] Kg.

B. Given that the Sun fuses 6 × [tex]10^{11}[/tex] Kg of hydrogen each second.

i. The Sun's initial hydrogen would last;

                                     [tex]\frac{1.8*10^{30} }{6*10^{11} }[/tex]

                                 = 3.04 × [tex]10^{17}[/tex] seconds

The Sun's hydrogen would last 3.0 × [tex]10^{17}[/tex] seconds

ii. Since there are 31536000 seconds in a year, then;

The Sun's initial hydrogen would last;

                                     [tex]\frac{3.04*10^{17} }{31536000}[/tex]

                                 = 9.640 × [tex]10^{9}[/tex] years

The Sun's hydrogen would last 9.6 × [tex]10^{9}[/tex] years.

C. Given that our solar system is now about 4.6 × [tex]10^{9}[/tex] years, then;

                               [tex]\frac{9.6*10^{9} }{4.6*10^{9} }[/tex]

                             = 2.09

So that;   2 × 4.6 × [tex]10^{9}[/tex] = 9.2 × [tex]10^{9}[/tex] years

Therefore, we need to worry about the Sun running out of hydrogen for fusion after 9.2 × [tex]10^{9}[/tex] years.

Part(A): The total mass of hydrogen available 9.6 billion years.

Part(B): The total time is 5.10 billion years.

Part(D): The hydrogen will last [tex]5.04\times 10^9 \ years[/tex]

Our sun is the largest object in our solar system. The mass of the sun is approximately [tex]1.988\times 1030[/tex] kilograms

Part(A):

Given that,

The total mass of the Sun =[tex]2\times10^{30} kg[/tex]

Mass of hydrogen in Sun =  [tex]2\times10^{30} \times0.76\ kg[/tex]

The mass of hydrogen ever available for fusion is,

[tex]2\times10^{30} \times 0.76 \times 0.12 kg = 1.824\times 10^{29}[/tex]

Mass of hydrogen fuses each second = 600 billion kg/second.

Time hydrogen will last in seconds=[tex]1.824\times 10^{29}seconds.[/tex]

[tex]= 0.00304\times 10^{29 }= 3.04\times 10^{17}.[/tex]

Time hydrogen will last in seconds =[tex]1 year = 31,536,000 seconds.[/tex]

[tex]31,536,000 x = 3.04\times 10^{17} = 9.6 \ billion \ years.[/tex]

(B) Present age of sun = [tex]9.6-4.5 \ billion \ years[/tex]

The time when we need to worry about Sun running out of hydrogen for fusion = 5.10 billion years.

(D) The solar system is 4.6 billion years old that is [tex]4.6\times 10^9\ years[/tex]

And in part (B) we have calculated that hydrogen will last [tex]9.64\times 10^9[/tex] then,

[tex]9.64\times 10^9-4.6\times 10^9=5.04\times 10^9[/tex]

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Answer:

  1/12

Step-by-step explanation:

  blue = (3/8)collection

  blue&pocket = (2/9)blue = (2/9)(3/8)collection

  blue&pocket = (6/72)collection = (1/12)collection

1/12 of Noah's collection is blue and has a pocket.

Answer:

B. (f + g)(x) = x - 7

Step-by-step explanation:

→Set it up, like so:

-3x - 5 + 4x - 2

→Add like terms (-3x and 4x, -5 and -2):

x - 7

Answer:

see below

Step-by-step explanation:

[tex]\frac{x-c}{d} > y[/tex]

x - c > dy

x > dy + c

Answer: It’s 2

Step-by-step explanation:

look at picture

Answer:

  A.  G(x) = (x -3)^3 -(x -3)

Step-by-step explanation:

The graph before it was shifted left will be a right-shift of the equation shown. That is accomplished by replacing x with (x-1.5). Then the right-shifted equation is ...

  G(x) = ((x-1.5) -1.5)^3 -((x -1.5) -1.5)

  G(x) = (x -3)^3 -(x -3) . . . . matches choice A

Answer:

The first one matches with f(x)√x because a square root cannot be negative

The second one matches with f(x)=√(x-5) because the square root would be negative if it were less than five.

The third one matches with f(x)=8x because there is nothing that makes it a not possible answer

The last one matches with 7/(x-8) because there cannot be a denominator of zero.

Answer: itz 605

Step-by-step explanation:

Answer:

Classifications would include

Rational; Fraction; Can be turned into Decimal; Positive

Those would be classifications

Answer: rational number, 0.375

Step-by-step explanation:

Answer:

LCM = 75

Step-by-step explanation:

1: Multiply the factor by the greatest number

Description:

The least common  multiple for 75,5,3 is 75.

LCM= Least common Multiple

Please mark brainliest

Hope this helps.

Answer:

75

Step-by-step explanation:

Break each number into prime factors

75 = 25*3 = 5*5*3

5 = 5*1

3 = 3*1

Multiply by the greatest number of each factor

3 = 1 time

5 = =2 times

The least common multiple = 3 * 5*5 = 75

Answer:

Step-by-step explanation:

[tex]r^{-7} +s^{-12} \\Use Negative Power Rule: x^{-a} =\frac{1}{x^{a} } \\r^{\frac{1}{7} } +s^{\frac{1}{12} } \\[/tex]

I hope i am correct

Answer:

100

Step-by-step explanation:

When t=0 (no time has passed), the coin is at height 100. This means the bridge must be 100 units high for this to be possible.

Answer:

100

Step-by-step explanation:

:3

Answer:

1

Step-by-step explanation:

divide vertical drop by horizontal drop

or vertical increase by horizontal increase

for example, in the graph when y increases by 1 x increases by 1

1/1=1 and thus the gradient is 1

the whole equation is y=x+3

Answer:

The slope = 1.

Step-by-step explanation:

If we count squares down for the top arrow then left to the point where the line cuts the horizontal axis we get 10 and 10.

So the slope = 10/10 = 1.

Answer:

12 45

Step-by-step explanation:

plane leaves London at 09 35

plane arrives in Los Angeles after 11 hrs and 10 min

considering time difference:

local arrival time:

Answer:

The answer is 3.01 x 10’23

Step-by-step explanation:

I got the answer to wrong and guessed the first one and it was correct

Answer:

Step-by-step explanation:

Hello!

There are two values of n in the text, I'll use the one that appears in all the questions.

The variable of interest is

X: pollutants found in waterways near large cities. (ppm)

This variable has a normal distribution with parameters μ= 9ppm and σ= 1.5ppm

1) X~N(μ;σ²)

X~N(9;2.25)

2) The distribution of the sample mean is X~N(μ;σ²/n)

σ²/n= 2.25/37= 0.06

X~N(9;0.06)

3) P(X>9.6)

To calculate this probability you have to use the standard normal distribution. Using the population parameters, you can calculate the corresponding Z value:

Z= (X-μ)/σ= (9.6-9)/1.5= 0.4

P(Z>0.4)= 1-P(Z≤0.4)= 1 - 0.65542= 0.34458

The probability of selecting a city at random and finding 9.6ppm pollutants.

4) In this item, instead of calculating the probability of one value of the variable you have to calculate the probability of the sample average taking a determined value. Because of this, you have to work using the distribution of the sample mean, instead of the distribution of the variable.

P(X[bar]>9.6)

Z= (X[bar]-μ)/(σ/√n)= (9.6-9)/√0.06= 2.45

P(Z>2.45)= 1 - P(Z≤2.45)= 1 - 0.99286= 0.00714

5) The assumption of a normal distribution is not necessary for item 4. Since the sample size is large enough (greater than 30) you can apply the central limit theorem and approximate the distribution of the sample mean to normal, regarding the distribution of the original variable.

6)

In this case, you have to work starting with the standard normal distribution and then "translate" the Z values into values of the average amount of pollutants.

The first quartile divides the bottom 25% of the distribution from the top 75%, symbolically:

P(Z≤z₁)= 0.25

z₁= -0.674

z₁= (X[bar]-μ)/(σ/√n)

z₁*(√n/σ)=X[bar]-μ

X[bar]=z₁*(√n/σ)+μ

X[bar]=(-0.674)*(√37/1.5)+9= 6.27ppm

The third quartile divides the bottom 75% of the distribution from the top 25%, symbolically:

P(Z≤z₂)= 0.75

z₂= 0.674

z₂= (X[bar]-μ)/(σ/√n)

z₂*(√n/σ)=X[bar]-μ

X[bar]=z₂*(√n/σ)+μ

X[bar]=(0.674)*(√37/1.5)+9= 11.7.3ppm

IQR= Q₃-Q₁= 11.73-6.27= 5.46ppm

I hope this helps!

Answer:

C. Parameter since the data set of all 14 teams is a population.

Explanation:

Find the attachment

Answer:

11453

Step-by-step explanation:

Answer:

x > 1

Step-by-step explanation:

Add 7 to both sides

x > 1

Answer:

B

Step-by-step explanation:

The triangular prism must have a larger base than the cylinder

Answer:

The number of female faculty in the Department with a PhD is 8.

Step-by-step explanation:

There are 14 + 30 = 44 faculty members.

Of those, x are male and y are female.

Then

x + y = 44.

The number of female faculty who do not have a PhD is 10 more than the number of females who have a PhD.

y = z + w

z is the number of females with PhD.

w is the number of females without PhD.

w = z + 10

If a third of the male faculty in the Department have a PhD

[tex]\frac{x}{3} + z = 14[/tex]

Now, we can write all variables as functions of z, which is the number of female faculty in the Department with PhD.

The objective is:

To find z from the first equation, that is:

[tex]x + y = 44[/tex]

To do this, we have to write x and y as functions of z.

Writing x and y as functions z.

[tex]\frac{x}{3} + z = 14[/tex]

[tex]\frac{x}{3} = 14 - x[/tex]

[tex]x = 3(14 - z)[/tex]

[tex]x = 42 - 3z[/tex]

And

[tex]y = z + w[/tex]

In which

[tex]w = 10 + z[/tex]

So

[tex]y = z + 10 + z[/tex]

[tex]y = 2z + 10[/tex]

Replacing:

[tex]x + y = 44[/tex]

[tex]42 - 3z + 2z + 10 = 44[/tex]

[tex]-z + 52 = 44[/tex]

[tex]z = 52 - 44[/tex]

[tex]z = 8[/tex]

The number of female faculty in the Department with a PhD is 8.

Answer:

[tex]r=25.7\%[/tex] will ensure that accumulated amount at the end of one year is 1.5 times more than amount invested

Step-by-step explanation:

Given: An amount was invested at r% per quarter.

To find: value of r such that accumulated amount at the end of one year is 1.5 times more than amount invested

Solution:

Let P denotes amount invested and n denotes time

As an amount (A) was invested at r% per quarter,

[tex]A=P\left ( 1+\frac{r}{400} \right )^{4n}[/tex]

According to question, accumulated amount at the end of one year is 1.5 times more than amount invested.

So,

[tex]A=1.5P+P=2.5P\\A=2.5P\\P\left ( 1+\frac{r}{400} \right )^{4n}=2.5P[/tex]

Put n = 1

[tex]P\left ( 1+\frac{r}{400} \right )^{4}=2.5P\\\left ( 1+\frac{r}{400} \right )^{4}=2.5\\1+\frac{r}{400} =(2.5)^{\frac{1}{4}}\\\frac{r}{100}=(2.5)^{\frac{1}{4}}-1\\r=100\left [ (2.5)^{\frac{1}{4}}-1 \right ]\\=25.7\%[/tex]