Identify the correct order of increasing intermolecular force of attraction for the three most common states of matter.
A)
Liquid - solid - gas
B)
solid - liquid - gas
gas - liquid - solid
D)
gas - solid - liquid

Answer:

Drag, which is a force preventing the ball from going faster than it was thrown, this increases as velocity increases. Gravity, which Is pulling down on the ball.

Explanation:

Answer:

b I think. sorry if it's wrong

Answer:

Tension = 60 N

Explanation:

The ball is executing a motion like a pendulum. The lowest point of a pendulum's motion is the mean position, where its potential energy becomes zero and kinetic energy becomes maximum. At this point the rope becomes straight vertical. Hence, the tension in the rope becomes exactly equal to the weight of the object at the lowest point. Also, in this case when the ball swings through the lowest point during its motion like a pendulum, the tension in the rope will become equal to the weight of the ball.

Tension = Weight

Tension = 60 N

The reason at the time when particles in a solid or liquid move slower and closer together should be explained below.

The particles should be in the form of small pieces of matters. Also, the scientist believed that each and everything in the universe should be made of the particles. here the range of the particles should be in the range via the large  subatomic particles such as electrons or it has lower  microscopic particles.

Learn more about particles here: https://brainly.com/question/21526256

Answer:

a) Approximately 0.2066 m

b) 0.00002568443 s

c) Approximately 188.87 s

Explanation:

a) The total energy of the electron = 190GeV

The rest energy of the electron = 0.51 MeV

[tex]\dfrac{19 \ GeV}{0.51 \ MeV} = 37254.902 = \dfrac{1}{\sqrt{1 + \dfrac{u^2}{c^2} } }[/tex]

[tex]\left ( 1 - \dfrac{u^2}{c^2} \right ) = \dfrac{1}{37254.902^2} } }[/tex]

[tex]\left ( 1 - \dfrac{1}{37254.902^2} } } \right ) = \dfrac{u^2}{c^2}[/tex]

u = √(299792458² × (1 - 1/37254.902²)) = 299792457.892

β = v/c = 299792457.892/299792458 = 0.99999999964

[tex]\beta = \sqrt{1 - \left ( \dfrac{\Delta x}{\Delta x'} \right )^2}[/tex]

Δx = √(Δx'²×(1 - β²)) = √(7700²×(1 - 0.99999999964²)) ≈ 0.2066 m

The length of the tube in the electron's frame ≈ 0.2066 m

b) The time in the frame of the electron is given as follows;

Δt' = 7700/299792457.892 = 0.00002568443 s

c) The time in the frame of the tube is given as follows;

[tex]\beta = \sqrt{1 - \left ( \dfrac{\Delta t'}{\Delta t} \right )^2}[/tex]

1 - β² = (Δt'/Δt)²

Δt = √(Δt'/(1 - β²)) = √(0.00002568443 /(1 - 0.99999999964²)) ≈ 188.87 s.

Answer: D) continue in the same direction with no change of speed.

In other words, the velocity of the object won't change.

A net force of 0 means that all forces acting on the object are in balance. If the object is in motion, then it stays in motion. If the object is at rest, then it stays at rest. This is newton's first law of motion describing inertia.

Complete Question

You are helping your friend move a new refrigerator into his kitchen. You apply a horizontal force of 280 N in the positive x direction to try and move the 63 kg refrigerator. The coefficient of static friction is 0.55.

(a) How much static frictional force does the floor exert on the refrigerator? Give both magnitude and direction.

magnitude            N

direction          

   (b) What maximum force do you need to apply before the refrigerator starts to move?

Answer:

a

   The magnitude  is [tex]F_f = 339.57 \ N[/tex]

    The direction is  [negative x - axis ]

b

   The maximum force to be applied for the refrigerator to start moving is  

      [tex]F_{max} = 339.57 \ N[/tex]

Explanation:

From the question we are told that

   The horizontal force applied is [tex]F_a = 280 \ N[/tex] the direction is  +ve  x-axis

   The mass of the refrigerator is  [tex]m = 63 \ kg[/tex]

    The coefficient of static friction is  [tex]\mu_s = 0.55[/tex]

Generally the frictional force exerted on the refrigerator is mathematically represented as

            [tex]F_f = \mu * m * g[/tex]

=>         [tex]F_f = 0.55 * 63 * 9.8[/tex]

=>         [tex]F_f = 339.57 \ N[/tex]

From the value obtained we see that the static force  exerted by the floor on the refrigerator  is  greater than the force (280 N ) exerted by the person and the direction is  -ve x-axis

Generally the maximum force that is to be applied by the person is mathematically  equal to the force exerted by the floor on the refrigerator but the direction is in the positive x-axis  i.e

         [tex]F_{max} = F_f = 339.57 \ N[/tex]

V = I • R

V = (0.054 A) • (152 ohms)

V = 8.208 volts

None of the listed choices is correct.

solid...............

Because of the buoyancy of the salt particles

By listening for it underwater, using SONAR.

Hope this helped!

Answer:D

Explanation:

It was right o khan academy

A dog jumps 0.80 M to catch a treat. The dog's displacement vector is shown below.

Which diagram shows the vertical and horizontal components of the dog's displacement?

THE ANSWER IS IN THE ATTACHMENT!

Answer:

There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.

Explanation:

From Physics we know that radioactive materials decay at exponential rate, whose differential equation is:

[tex]\frac{dm}{dt} = -\lambda\cdot m[/tex] (1)

Where:

[tex]\frac{dm}{dt}[/tex] - Rate of change of the mass of the radioactive material, measured in kilograms per second.

[tex]m[/tex] - Current mass of the radioactive material, measured in kilograms.

[tex]\lambda[/tex] - Decay constant, measured in [tex]\frac{1}{s}[/tex].

The solution of the differential equation is:

[tex]m(t) = m_{o}\cdot e^{-\lambda\cdot t}[/tex] (2)

Where:

[tex]m_{o}[/tex] - Initial mass of the radioactive material, measured in kilograms.

[tex]t[/tex] - Time, measured in seconds.

If we know that [tex]m_{o} = 20\,kg[/tex], [tex]\lambda = 0.179\,\frac{1}{s}[/tex] and [tex]t = 300\,s[/tex], then the initial mass of the radioactive material is:

[tex]m(t) = (20\,kg)\cdot e^{-\left(0.179\,\frac{1}{s} \right)\cdot (300\,s)}[/tex]

[tex]m(t) \approx 9.537\times 10^{-23}\,kg[/tex]

There are [tex]9.537\times 10^{-23}[/tex] kilograms of radioactive material after 300 seconds.

Answer:

12.0V

12.0V

Explanation:

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Answer:

2.00 A

Explanation:

Answer:

a. 2 kg*m/s

b. [tex]p_{T_{f}} = 0.5v_{f} = 2 kg*m/s[/tex]

c. 4 m/s

Explanation:

a. The momentum of the system ([tex]p_{Ti}[/tex]) before the blob of clay strikes the cart is:

[tex] p_{Ti} = p_{b} + p_{c} [/tex]

Where:

[tex]p_{b}[/tex] is the momentum of the blob clay

[tex]p_{c}[/tex] is the momentum of the car      

[tex] p_{Ti} = m_{b}v_{b} + m_{c}v_{c} [/tex]

Since the car is initially at rest, [tex]v_{c}[/tex] = 0

[tex] p_{Ti} = 200 g*\frac{1 kg}{1000 g}*10 m/s + 0 = 2 kg*m/s [/tex]

b. The momentum of the system after they come together:

[tex]p_{T_{f}} = m_{b}v_{b} + m_{c}v_{c}[/tex]

Since they come together, [tex]v_{b}[/tex] =

[tex]p_{T_{f}} = v_{f}(m_{b} + m_{c}) = v_{f}(0.2 kg + 0.3 kg) = 0.5v_{f}[/tex]   (1)

Because we do not have the final speed we can not calculate the final momentum.

c. We can find the speed of the clay and car by conservation of the momentum:

[tex] p_{i} = p_{f} [/tex]

The initial momentum of the system was founded in part "a" (p = 2 kg*m/s), so we have:

[tex] 2 kg*m/s = m_{b}v_{b_{f}} + m_{c}v_{c_{f}} [/tex]

Again, when they come together, the final speed is the same:

[tex] 2 kg*m/s = v_{f}(m_{b} + m_{c}) [/tex]                

[tex] v_{f} = \frac{2 kg*m/s}{0.2 kg + 0.3 kg} = 4 m/s [/tex]

Now, since we found the final speed we can calculate the momentum of the system after they come together (equation 1):        

[tex] p_{T} = 0.5v_{f} = 0.5 kg*4m/s = 2 kg*m/s [/tex]

I hope it helps you!                  

Answer:

7.53 km

Explanation:

We at given;

Speed of runner; v_r = 8.5 km/hr

Speed of bird; v_y = 17 km/hr

L = 6.4 km

We know that; time = distance/speed.

We are told that the bird starts from 6.4 km from the start and that it flies back to meet the runner after it reaches the finish line. If the total distance back to the runner is x, it means bird distance is 6.4 + (6.4 - x) = 12.8 - x

Thus;

Time of bird(t_y) = (12.8 - x)/17

Thus,

Time of runner(t_r) = x/8.5 hr

To find x, we have to equate the times of the runner and the bird.

Thus;

x/8.5 = (12.8 - x)/17

Multiply both sides by 17 to get;

2x = 12.8 - x

2x + x = 12.8

3x = 12.8

x = 12.8/3

x = 4.27 km

Thus, cumulative distance traveled by bird is; 12.8 - 4.27 = 7.53 km

Answer:

the correct answer is b

Answer:

true

Explanation:

just did it on ck12 lol

Answer:

t = 2.38 [s]

Explanation:

To solve this problem we must use the following equation of kinematics. We must clarify that both the acceleration and the initial velocity were taken as positive, since the velocity of the movement coincides with the direction of the acceleration.

[tex]x =x_{o} +v_{o} *t+(\frac{1}{2} )*a*t^{2}[/tex]

where:

x - Xo = distance = 47 [m]

Vo = initial velocity = 8 [m/s]

a = gravity acceleration = 9.81 [m/s²]

t = time [s]

Now replacing these values in the equation:

47 = 8*t + 0.5*9.81*t²

47 = 8t + 4.905t²

47 = 4.905*t(1.63 + t)

9.58 = t*(1.63 + t) solving this equation (cuadratic)

we found that t = 2.38 [s]

Answer:

7.69km/hr due east

Explanation:

Given parameters:

Displacement due west  = 3km

Displacement due east = 2km

Time taken  = 8 minutes

Unknown:

Average velocity  = ?

Solution:

Average velocity is the rate of change of displacement with time.

  Velocity  = [tex]\frac{displacement}{time }[/tex]

 Displacement is deals with the start and the end;

  Here, displacement  = 3km - 2km  = 1km due east

Time  = 8min

     60min  = 1hr

       8min = [tex]\frac{8}{60}[/tex]   = 0.13hr

 Average velocity = [tex]\frac{1km}{0.13hr}[/tex]   = 7.69km/hr due east

Answer:

Mass, m = 71.42 kg

Explanation:

Given that,

Normal force acting on a box, F = 700 N

We need to find the mass of a box. Let it is m. Normal force acting on an object is balanced by its weight such that,

F = mg

Where m is the mass of the box

[tex]m=\dfrac{F}{g}\\\\m=\dfrac{700\ N}{9.8\ m/s^2}\\\\m=71.42\ kg[/tex]

So, the mass of the box is 71.42 kg.

Answer:

Speed of lighter ball is 4 m/s.

Explanation:

Applying the principle of conservation of linear momentum,

momentum before collision = momentum after collision.

[tex]m_{1}[/tex][tex]u_{1}[/tex] + [tex]m_{2}[/tex] [tex]u_{2}[/tex] = [tex]m_{1}[/tex][tex]v_{1}[/tex] - [tex]m_{2}[/tex][tex]v_{2}[/tex]

[tex]m_{1}[/tex] = 3 kg, [tex]u_{1}[/tex] = 8 m/s, [tex]m_{2}[/tex] = 2 kg, [tex]u_{2}[/tex] = 0 m/s ( since it is at rest), [tex]v_{1}[/tex] = 2 m/s, [tex]v_{2}[/tex] = ?

(3 x 8) + (2 x 0) = (8 x 2) - (2 x [tex]v_{2}[/tex])

24 + 0 = 16 - 2[tex]v_{2}[/tex]

2[tex]v_{2}[/tex] = 16 - 24

2[tex]v_{2}[/tex] = -8

[tex]v_{2}[/tex] = [tex]\frac{-8}{2}[/tex]

   = -4 m/s

This implies that the light ball moves at the speed of 4 m/s in the opposite direction of the heavier ball after collision.

Answer:

B

Explanation:

V=IR    I= curren V=volt R=resistor

8=2.R   8/2=R R=4

Answer:

5 no

Explanation:

actually the 4kg lying on table has no influence

it slides towards 4kg weight hung

as it has excess 2kg force

force=miu × m ×g

The magnitude of acceleration of the entire system is  [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.

Given data:

The masses  suspended from the table are, m = 2 kg and m' = 4 kg.

And the mass kept on the table is, m'' = 4 kg.

The frictional force will oppose the motion of mass 4 kg, kept on the table. Then the required value of frictional force is,

[tex]f = \mu \times m'' \times g\\\\f = 0.11 \times 4 \times 9.8\\\\f = 4.312 \;\rm N[/tex]

Since, the mass kept on the right side is more. Then at equilibrium,

-f + m''g + (m' +m)a = m'g

Here,

a is the magnitude of acceleration of the system.

Solving as,

-4.312+ 4(9.8) + (4 -2)a = 4(9.8)

2a = 4.312

[tex]a \approx 2.1315 \;\rm m/s^{2}[/tex]

Thus, we can conclude that the magnitude of acceleration of the entire system is  [tex]2.1315 \;\rm m/s^{2}[/tex]. Hence, option (5) is correct.

Learn more about the linear acceleration here:

https://brainly.com/question/14214161

Answer: The answer is c!

A heater in a fish tank warming the water at the bottom of the tank is an another example of convection.

Convection, which is the extensive movement of molecules within gases and liquids, is the mechanism through which heat is transported. Although most of the heat transfer occurs as a result of fluid motion, conduction is initially employed to transfer heat from the item to the fluid.

Convection is therefore demonstrated by a heater in a fish tank warming the water at the tank's bottom.

Learn more about convection of heat here:

brainly.com/question/16600140

#SPJ2

Answer:

I'm sorry to inform that I couldn't find an answer to this question. Socratic can help! This learning app, powered by Google AI, helps you understand your school work at a high school and university level. Ask Socratic a question and the app will find the best online resources for you to learn the concepts.

Explanation: