Answer:
The Predictor variable is the amount of precipitation received while the Response variable is the crop harvest.
Step-by-step explanation:
The Response variable in an experiment is the factor being measured or studied. They are also known as the dependent variables. Predictor variables are those values that explain the changes in the Response variable. They are also known as the independent variables.
In the question above, the amount of precipitation provides an explanation for the harvest of his crops. Therefore, the amount of precipitation can be rightly described as the predictor or independent variable, while the harvest of his crops is described as the response or dependent variable.
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[tex]1. \: (x - y) {2} \\ = {x}^{2} - 2xy + {y}^{2} \\ 2. \: (a + b) ^{2} \\ = {a}^{2} + 2ab + {b}^{2} \\ 3. \: (2x + 3y) ^{2} \\ = {(2x)}^{2} + 2.2x.3y + (3y) ^{2} \\ = {4x}^{2} + 12xy + {9y}^{2} \\ 4.(3x - 2y) ^{2} \\ = (3x) ^{2} - 2.3x.2y + (2y) ^{2} \\ = {9x}^{2} - 12xy + {4y}^{2} \\ hope \: it \: helps \\ good \: luck \: on \: your \: assignment[/tex]
Answer:
a) x^2−2xy+y^2
b) a^2 -ab+b^2
c)4x^2+12xy+9y^2
d)9x^2 -12xy+4y^2
Step-by-step explanation:
a) x^2−2xy+y^2
b) a^2 -ab+b^2
c)4x^2+12xy+9y^2
d)9x^2 -12xy+4y^2
We rewrite (x-y)^2 as (x-y) (x-y) to show and always see + sign at start for question a ) and question b)
a) x*x+x(−y)−yx−y(−y) = x^2−2xy+y^2
b) a^2 becomes a^2 -ab as a^2 -ab+b^2
c) As shown in notes attached and this will help you most.
d) the reasons we keep +4y is because -2y becomes -2y-2y and creates a plus.
From the top of the cliff 8m high,two boats are seen in the direction due west.find the distance between the boats if the angles of depression from the top of the cliff are 45° and 30°.Find also the actual distance of the farther boat from the top of the cliff.
Answer:
Distance between 2 boats= 5.86m (3 s.f.)
Actual distance from farther boat from top of cliff= 16m
Step-by-step explanation:
Please see the attached pictures for full solution.
en una division el 42 es el cociente el divisor 12 y el dividendo 513 ¿Cual es el resto?
Answer:
El resto es 9.
Step-by-step explanation:
En una división el cociente es el resultado que se obtiene, el divisor es el número por el que se divide otro número, el dividendo es el número que va a dividirse entre otro y el resto es lo que queda cuando un número no puede dividirse exactamente entre otro. De acuerdo a esto, la división planteada se encuentra en la imagen adjunta donde al resolverla se encuentra que el número que queda es 9 y este es el resto.
Problem 10: A tank initially contains a solution of 10 pounds of salt in 60 gallons of water. Water with 1/2 pound of salt per gallon is added to the tank at 6 gal/min, and the resulting solution leaves at the same rate. Find the quantity Q(t) of salt in the tank at time t > 0.
Answer:
The quantity of salt at time t is [tex]m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })[/tex], where t is measured in minutes.
Step-by-step explanation:
The law of mass conservation for control volume indicates that:
[tex]\dot m_{in} - \dot m_{out} = \left(\frac{dm}{dt} \right)_{CV}[/tex]
Where mass flow is the product of salt concentration and water volume flow.
The model of the tank according to the statement is:
[tex](0.5\,\frac{pd}{gal} )\cdot \left(6\,\frac{gal}{min} \right) - c\cdot \left(6\,\frac{gal}{min} \right) = V\cdot \frac{dc}{dt}[/tex]
Where:
[tex]c[/tex] - The salt concentration in the tank, as well at the exit of the tank, measured in [tex]\frac{pd}{gal}[/tex].
[tex]\frac{dc}{dt}[/tex] - Concentration rate of change in the tank, measured in [tex]\frac{pd}{min}[/tex].
[tex]V[/tex] - Volume of the tank, measured in gallons.
The following first-order linear non-homogeneous differential equation is found:
[tex]V \cdot \frac{dc}{dt} + 6\cdot c = 3[/tex]
[tex]60\cdot \frac{dc}{dt} + 6\cdot c = 3[/tex]
[tex]\frac{dc}{dt} + \frac{1}{10}\cdot c = 3[/tex]
This equation is solved as follows:
[tex]e^{\frac{t}{10} }\cdot \left(\frac{dc}{dt} +\frac{1}{10} \cdot c \right) = 3 \cdot e^{\frac{t}{10} }[/tex]
[tex]\frac{d}{dt}\left(e^{\frac{t}{10}}\cdot c\right) = 3\cdot e^{\frac{t}{10} }[/tex]
[tex]e^{\frac{t}{10} }\cdot c = 3 \cdot \int {e^{\frac{t}{10} }} \, dt[/tex]
[tex]e^{\frac{t}{10} }\cdot c = 30\cdot e^{\frac{t}{10} } + C[/tex]
[tex]c = 30 + C\cdot e^{-\frac{t}{10} }[/tex]
The initial concentration in the tank is:
[tex]c_{o} = \frac{10\,pd}{60\,gal}[/tex]
[tex]c_{o} = 0.167\,\frac{pd}{gal}[/tex]
Now, the integration constant is:
[tex]0.167 = 30 + C[/tex]
[tex]C = -29.833[/tex]
The solution of the differential equation is:
[tex]c(t) = 30 - 29.833\cdot e^{-\frac{t}{10} }[/tex]
Now, the quantity of salt at time t is:
[tex]m_{salt} = V_{tank}\cdot c(t)[/tex]
[tex]m_{salt} = (60)\cdot (30 - 29.833\cdot e^{-\frac{t}{10} })[/tex]
Where t is measured in minutes.
The probability that a randomly chosen sales prospect will make a purchase is 20%. What is the probability (to three decimal places) that the salesperson will make four or more sales if six sales calls are made on a given day
Answer:
1.7%
Step-by-step explanation:
We have to calculate the probability that the salesperson will make four or more sales if six sales calls are made on a given day, that is:
P (x => 4)
Therefore, we must calculate when x = 4, when x = 5, and when x = 6 and add. p = 0.2, n = 6
P (x = r) = nCr * p ^ r * (1 - p) ^ (n-r)
Also, nCr = n! / (r! * (n-r) !, now replacing:
P (x = 4) = 6! / (4! * (6-4)! * 0.20 ^ 4 * 0.80 ^ (6-4)
P (x = 4) = 15 * 0.001024 = 0.01536
P (x = 5) = 6! / (5! * (6-5)! * 0.20 ^ 5 * 0.80 ^ (6-5)
P (x = 5) = 6 * 0.000256 = 0.001536
P (x = 6) = 6! / (6! * (6-6)! * 0.20 ^ 6 * 0.80 ^ (6-6)
P (x = 6) = 1 * 0.000064 = 0.000064
now,
P (x => 4) = P (x = 4) + P (x = 5) + P (x = 6)
P (x => 4) = 0.01536) + 0.001536 + 0.000064
P (x => 4) = 0.01696 = 0.017
It means that the probability is 1.7%
A random sample pulled 43 catfish from a large lake. They were marked and released. A second sample pulled out 88 catfish. Seventeen had been marked. Calculate the estimated population
Answer: 114
Step-by-step explanation: You have 43 new catfish then you catch 88 but 17 of them have already been marked so you do not want to count those in the estimated population again because they have already been counted so you take 88 minus 17 and you get 71 new fish. So then you add the first new sample of fish 43 and then you add the second new sample of fish 71 and then you get 114
I need help solving this problem. It tells me that I could use any method provided above but I don't really get it. Could someone help?
The Problem:
You have to be careful when using a ladder. If you place the ladder too close to the wall, it could tip over. If you place the ladder too far from the wall, it could slide down. To prevent this, safety experts recommend the 4-to-1 Rule: for every 4 feet you want to go up the wall, place the base of the ladder one foot away from the wall.
The longest ladder available at many hardware stores is 40 feet. What is the highest you could reach with this ladder?
The problem gives me three methods to pick from to solve the problem. Each method had a clue underneath.
Hints:
Method 1: Know that the height must be 4x the base. Also know that hypotenuse is the longest side, so height must be shorter than 40 (and base must be shorter than 10 feet).
Method 2: Base^2+Height^2=40^2
Height= 4 • base
Method 3:
Base^2+Height^2=40^2
Base= 0.25 • height
The answers this problem asks for is:
The base, height and length.
Answer:
The highest you could reach with this ladder is 30 feet or 9.14 meters.
11+11 = 4 22+22 = 16 33+33 = ?
Answer:
36
Step-by-step explanation:
11*11=4
(1+1)*(1+1)=4
2 * 2 = 4
22*22=16
(2+2)*(2+2)=16
4 * 4 = 16
33*33=?
(3+3)*(3+3)=?
6 * 6 = 36
So the answer is 36
Series: 4, 16, 36
Answer: The answer is 36 :)
hope that helped
A company is constructing an open-top, square-based, rectangular metal tank that will have a volume of 49 cubic feet. What dimensions yield the minimum surface area? Round to the nearest tenth.
Answer:
b = 4.6 ft
h = 2.3 ft
Step-by-step explanation:
The volume of the tank is given by:
[tex]b^2*h=49[/tex]
Where 'b' is the length of the each side of the square base, and 'h' is the height of the tank.
The surface area can be written as:
[tex]A=b^2+4bh\\A=b^2+4b*({\frac{49}{b^2}})\\A=b^2+\frac{196}{b}[/tex]
The value of b for which the derivate of the expression above is zero is the value that yields the minimum surface area:
[tex]\frac{dA}{db} =0=2b-\frac{196}{b^2}\\2b^3=196\\b=4.61\ ft[/tex]
The value of h is then:
[tex]h=\frac{49}{4.61^2}\\h=2.31\ ft[/tex]
Rounded to the nearest tenth, the dimensions are b = 4.6 ft and h = 2.3 ft.
Nam owns a used car lot. He checked the odometers of the cars and recorded how far they had driven. He then created both a histogram and a box plot to display this same data (both diagrams are shown below). Which display can be used to find how many vehicles had driven more than 200{,}000\,\text{km}200,000km200, comma, 000, start text, k, m, end text (kilometers)? Choose 1 answer: Choose 1 answer: (Choice A) A The histogram (Choice B) B The box plot Which display can be used to find that the median distance was approximately 140{,}000\,\text{km}140,000km140, comma, 000, start text, k, m, end text? Choose 1 answer: Choose 1 answer: (Choice A) A The histogram (Choice B) B The box plot
Answer:
(a) The correct option is (A).
(b) The correct option is (B).
Step-by-step explanation:
Nam collected the data for the distance traveled by all the cars in his car lot.
(a)
A histogram is a bar graph representing the distribution of a random variable. The height of the bars of the histogram represents the frequency for a specific interval.
If Nam wants to know how many vehicles had driven more than 200,000 km, the histogram would be the best display of this data. This is because the histogram shows the frequency for various interval values.
The correct option is (A).
(b)
A boxplot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,
Minimum (shown at the bottom of the chart) First Quartile (shown by the bottom line of the box) Median (or the second quartile) (shown as a line in the center of the box) Third Quartile (shown by the top line of the box) Maximum (shown at the top of the chart).So, if Nam wants to find whether the median distance was approximately 140,000 km, a box plot would be a better choice. This is because the box plot represents the median of the data by a line within the box.
The correct option is (B).
Answer: For the first one is A second one is B
Step-by-step explanation: I took the khan test. UwU♡
Write an equation of a line that is parallel to the line 3y=-x+6 and passes through the point (6,2).
Answer:
y = x+2
y =-x+2 shows 0
We want to show 1 both sides
2y = x+2 shows 2
y = x+2 shows 0 as explained below.
Step-by-step explanation:
3y−x=6
Solve for y.
y=2+x3
Rewrite in slope-intercept form.
y=13x+2.
Use the slope-intercept form to find the slope and y-intercept.
Slope: 13 y-intercept: 2
Any line can be graphed using two points. Select two
x values, and plug them into the equation to find the corresponding y values.
xy 02, 33
Graph the line using the slope and the y-intercept, or the points.
Slope:
13y-intercept: 2x y (0,2) (3,3)
Barron's reported that the average number of weeks an individual is unemployed is 18.5 weeks. Assume that for the population of all unemployed individuals the population mean length of unemployment is 18.5 weeks and that the population standard deviation is 6 weeks. Suppose you would like to select a sample of 55 unemployed individuals for a follow-up study.
A) show the sampling distribution of x, the sample mean average for a sample of 50 unemployment individuals.B) What is the probability that a simple random sample of 50 unemployment individuals will provide a sample mean within one week of the population mean?C) What is the probability that a simple random sample of 50 unemployed individuals will provide a sample mean within a half week of the population mean?
Answer:
A) The sampling distribution for a sample size n=50 has a mean of 18.5 weeks and a standard deviation of 0.849.
B) P = 0.7616
C) P = 0.4441
Step-by-step explanation:
We assume that for the population of all unemployed individuals the population mean length of unemployment is 18.5 weeks and that the population standard deviation is 6 weeks.
A) We take a sample of size n=50.
The mean of the sampling distribution is equal to the population mean:
[tex]\mu_s=\mu=18.5[/tex]
The standard deviation of the sampling distribution is:
[tex]\sigma_s=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{50}}=0.849[/tex]
B) We have to calculate the probability that the sampling distribution gives a value between one week from the mean. That is between 17.5 and 19.5 weeks.
We can calculate this with the z-scores:
[tex]z_1=\dfrac{X_1-\mu}{\sigma/\sqrt{n}}=\dfrac{17.5-18.5}{6/\sqrt{50}}=\dfrac{-1}{0.8485}=-1.179\\\\\\z_2=\dfrac{X_2-\mu}{\sigma/\sqrt{n}}=\dfrac{19.5-18.5}{6/\sqrt{50}}=\dfrac{1}{0.8485}=1.179[/tex]
The probability it then:
[tex]P(|X_s-\mu_s|<1)=P(|z|<1.179)=0.7616[/tex]
C) For half a week (between 18 and 19 weeks), we recalculate the z-scores and the probabilities:
[tex]z=\dfrac{X-\mu}{\sigma/\sqrt{n}}=\dfrac{18-18.5}{6/\sqrt{50}}=\dfrac{-0.5}{0.8485}=-0.589[/tex]
[tex]P(|X_s-\mu_s|<0.5)=P(|z|<0.589)=0.4441[/tex]
What is the slope of the line?
Simplify the expression,
(a3/2)3
Answer:
[tex]a^{\frac{9}{2}}[/tex]
Step-by-step explanation:
[tex]\left(a^{\frac{3}{2}}\right)^3[/tex]
[tex]=a^{\frac{3}{2}\cdot \:3}[/tex]
[tex]=a^{\frac{3}{2}\cdot \frac{3}{1}}[/tex]
[tex]=a^{\frac{9}{2}}[/tex]
What is the answerrrrrrrrrrrr :(((((((((((
Answer: The answer is choice 3
Step-by-step explanation:
i think the answer is c
Step-by-step explanation:
i don't think u would want a whole explanation
Which table represents a function?
In football seasons, a team gets 3 points for a win, 1 point for a draw and 0 points for a
loss. In a particular season, a team played 34 games and lost 6 games. If the team had a
total of 70 points at the end of the season, what is the difference between games won and lost
Answer:
The difference between the games won and lost = 21 - 6 =15
Step-by-step explanation:
According to the question In a football season a team gets 3 points for a win, 1 point for a draw and 0 points for a loss.
A particular season a team played 34 games and lost 6 games . Finding the difference between game won and game lost simply means we have to know the number of game lost and game won.
The team played a total of 34 games.
Total games played = 34
Out of the 34 games played they lost 6 games. That means the remaining games is either win or draw. Therefore,
34 - 6 = 28 games was won or draw
Let
the number of games won = x
the number of game drew = y
3x + y = 70.............(i)
x + y = 28................(ii)
x = 28 - y
insert the value of x in equation(i)
3(28 - y) + y = 70
84 - 3y + y = 70
84 - 70 = 3y -y
14 = 2y
divide both sides by 2
y = 14/2
y = 7
insert the value of y in equation(ii)
x + y = 28
x = 28 - 7
x = 21
The team won 21 games , drew 7 games and lost 6 games.
The difference between the games won and lost = 21 - 6 =15
What’s the correct answer for this question?
Answer:
A.
Step-by-step explanation:
A quadrilateral inscribed in a circle has its opposite angles adding up to 180°
So
<NOP + <M = 180
4x+8x-24 = 180
12x = 180+24
12x = 204
Dividing both sides by 12
x = 17
<NOP = 4(17)
= 68°
What is the value of x?
A-17
B-26
C-39
D-41
Answer: 41
Step-by-step explanation:
a^2 + b^2 = c^2
40^2 + 9^2 = c^2
c = √1681 = 41
Answer:
D: 41
Step-by-step explanation:
Using Pythagorean Theorem
c² = a² + b²
Where c is hypotenuse, x
a is the base, 9
b is the perpendicular, 40
Putting in the formula
x² = (40)²+(9)²
x² = 1600 + 81
x² = 1681
Taking square root on both sides
x = 41
A glucose solution is administered intravenously into the bloodstream at a constant rate r. As the glucose is added, it is converted into other substances and removed from the bloodstream at a rate that is proportional to the concentration at that time. Thus a model for the concentration C = C(t) of the glucose solution in the bloodstream is dC/dt = r - kC where k is a positive constant. Assuming that C0 < r/k, find lim t→[infinity] C(t) and interpret your answer
Answer:
[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]
[tex]C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex] we can conclude that the function is an increasing function.
Step-by-step explanation:
Given that:
[tex]\dfrac{dC}{dt}= r-kC[/tex]
[tex]\dfrac{dC}{r-kC}= dt[/tex]
By taking integration on both sides ;
[tex]\int\limits\dfrac{dC}{r-kC}= \int\limits \ dt[/tex]
[tex]- \dfrac{1}{k}In (r-kC)= t +D[/tex]
[tex]In(r-kC) = -kt - kD \\ \\ r- kC = e^{-kt - kD} \\ \\ r- kC = e^{-kt} e^{ - kD} \\ \\r- kC = Ae^{-kt} \\ \\ kC = r - Ae^{-kt} \\ \\ C = \dfrac{r}{k} - \dfrac{A}{k}e ^{-kt} \\ \\[/tex]
[tex]C(t) =\frac{ r}{k} - \frac{A}{k}e^{ -kt}[/tex]
where;
A is an integration constant
In order to determine A, we have C(0) = C0
[tex]C(0) =\frac{ r}{k} - \frac{A}{k}e^{0}[/tex]
[tex]C_0 =\frac{r}{k}- \frac{A}{k}[/tex]
[tex]C_{0} =\frac{ r-A}{k}[/tex]
[tex]kC_{0} =r-A[/tex]
[tex]A =r-kC_{0}[/tex]
Thus:
[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]
b ) Assuming that C0 < r/k, find lim t→[infinity] C(t) and interpret your answer
[tex]C_{0} < \lim_{t \to \infty }C(t)[/tex]
[tex]C_0 < \dfrac{r}{k}[/tex]
[tex]kC_0 <r[/tex]
The equation for C(t) can therefore be re-written as :
[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]
[tex]C(t) =\dfrac{ r}{k} - \left (+ve \right )e^{ -kt} \\ \\C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex]
Thus; we can conclude that the above function is an increasing function.
Ann pays $300 for membership to a local gym. She is allowed to bring one guest on any visit. John pays Ann $5 to go to the gym with her occasionally. Describe what the expression 300 - 5t could represent. Then evaluate the expression for T equals five 10 15 and 20
Answer:
f
Step-by-step explanation:
what is tge surface area of tge dquare pyramid GELP IM TIMED AND ABOUT TO RUN OUT OF TIME
Answer:
Step-by-step explanation:
pls help, you will get branliest !!
Answer:
4.......................
from a deck of 52 cards, what is the probability of getting a four or diamond.
Answer:
4/13
Step-by-step explanation:
There are 13 diamonds in a deck and 3 fours that aren't diamond
13+3=16
16/52 = 4/13
Use the area to find the radius. If you could include steps that’ll be very helpful :)
Answer:
Radius = 13 m
Step-by-step explanation:
Formula for area of circle is given as:
[tex]A = \pi {r}^{2} \\ \\ \therefore \: 169\pi \: = \pi {r}^{2} \\ \\ \therefore \: {r}^{2} = \frac{169\pi }{\pi} \\ \\ \therefore \: {r}^{2} = 169 \\ \\ \therefore \: {r} = \pm \sqrt{169} \\ \\\therefore \: r = \pm \: 13 \: m \\ \\ \because \: radius \: of \: a \: circle \: can \: not \: be \: a \: negative \: \\quantity \\ \\ \huge \red{ \boxed{\therefore \: r = 13 \: m }}[/tex]
Which of the following terminating decimals is equivalent to -1 3/4
Answer:
-1.75
Step-by-step explanation:
A package of 10 batteries is checked to determine if there are any dead batteries. Four batteries are checked. If one or more are dead, the package is not sold. What is the probability that the package will not be sold if there are actually three dead batteries in the package
Answer:
There is a probability of 76% of not selling the package if there are actually three dead batteries in the package.
Step-by-step explanation:
With a 10-units package of batteries with 3 dead batteries, the sampling can be modeled as a binomial random variable with:
n=4 (the amount of batteries picked for the sample).p=3/10=0.3 (the proportion of dead batteries).k≥1 (the amount of dead batteries in the sample needed to not sell the package).The probability of having k dead batteries in the sample is:
[tex]P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}[/tex]
Then, the probability of having one or more dead batteries in the sample (k≥1) is:
[tex]P(x\geq1)=1-P(x=0)\\\\\\P(x=0) = \dbinom{4}{0} p^{0}q^{4}=1*1*0.7^4=0.2401\\\\\\P(x\geq1)=1-0.2401=0.7599\approx0.76[/tex]
Which of the following best forms the figure shown
Answer:
2 rays that meet at an endpoint
Step-by-step explanation: A ray starts with a dot, or point and continues on forever with an arrow. There are two rays in that drawing that start at the same endpoint.
Answer:
2 rays that meet at an endpoint.
Step-by-step explanation:
A ray is straight but has one endpoint and the other end go on infinitely.
A line is straight and goes on infinitely.
A line segment is straight and has two endpoints.
The picture shows two rays meeting at an endpoint.
Find the population mean or sample mean as indicated.
Sample 17, 13, 5, 12, 13
Answer:
13
Step-by-step explanation:
I think
2. Calculate the midpoint of the given
segment
|(-2, -3)
(0.1)
(2, 3)
Answer:0,1
Step-by-step explanation:
It’s on edge