If 500 cal of heat are added to a gas, and the gas expands doing 500 J of work on its surroundings, what is the change in the internal energy of the gas?

Answer: 8280

Explanation: This is the answer that my online school curriculum said was right.

God loves you!!!

Answer:

This isn't an answer, but rather a question for the answer that was given (which was correct! Thank you so much!) I was trying to figure out how to comment because I am in no way trying to steal points or anything like that, but I have a genuine question that I couldn't figure out any other way to ask...

How did you come up with 8280? Whenever I do it I get 8289....

I would like to know the process for future reference. Thank you for your help and again, I apologize for taking these points with no answer to contribute.

Answer:

H' = H/4

Explanation:

By applying the law of conservation of energy to this problem, we know that:

Elastic Potential Energy Stored by Spring = Gravitational Potential Energy of ball

(1/2)kx² = mgH

H = (1/2)kx²/mg   -------------- equation (1)

where,

H = Height reached by the ball

x = compression of spring

k = stiffness of spring

m = mass of ball

g = acceleration due to gravity

Now, if we make the compression to half of its value:

x' = x/2

then:

H' = (1/2)k(x/2)²/mg

H' = (1/4)(1/2)kx²/mg

using equation (1), we get:

H' = H/4

Answer:

6,000 kg

Explanation:

Answer:

Delivery truck

Explanation:

Answer:

Remote Sensing

Explanation:

Answer:

it is scientific knowledge

Explanation:

got i right on edge

The scientific knowledge refers to information gathered by the systematic study of nature.

A generalized corpus of laws and ideas developed employing the scientific method to describe an interesting occurrence or behavior is referred to as scientific knowledge.

Science would be the systematic study of the composition and dynamics of the physical as well as the natural world via experimentation and observation.

the systematic study of natural circumstances and phenomena. empirical proof. the term for the facts and figures that support an explanation in science.

Therefore, the correct answer will be option (C)

To know more about scientific knowledge.

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Answer:

The function is missing in the question. The function of the transverse pulse in the wire is given by [tex]$y=\frac{6}{x^2 +3}$[/tex]  

Explanation:

A transverse wave can be defined as the wave whose direction of displacement is always perpendicular to the direction of propagation. For example, surface wave at water bodies. While a pulse can be defined as a sudden change in a constant quantity such as a pulse of the radiation or current.

Let the wire of infinite length in both the directions and also the magnitude of deflection of wire be in the same shape except the point of maximum deflection to move along the wire.

Thus the equation of the pulse moving the in the positive x-direction moving at the speed of 2.10 m/s is

[tex]$y=\frac{6}{(x-2.10)^2 +3}$[/tex].

Answer:

The correct answer will be:

(A) 24955495.07 N/m²

(B) 97482.40 N/m²

Explanation:

(A)

The given values are:

mass,

m = 50 kg

diameter

= 0.50 cm

then,

radius,

r = 0.25 cm

 = 0.0025 m

As we know,

⇒ [tex]A = area \ of \ cross \ section[/tex]

       [tex]=\pi r^2[/tex]

and,

⇒ [tex]stress = \frac{mg}{A}[/tex]

On substituting the values, we get

              [tex]=\frac{(50)(9.8)}{\pi (0.0025^2)}[/tex]

              [tex]=24955495.07 \ N/m^2[/tex]

(B)

mass,

m = 5000 kg

radius,

r = 20 cm

 = 0.2 m

Now,

⇒ [tex]stress=\frac{\frac{5000}{4} (9.8)}{\pi (0.2^2)}[/tex]

              [tex]=97482.40 \ N/m^2[/tex]

Answer:

8.4 N/m

Explanation:

m = Mass of block = 4.63 gm

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

x = Displacement of spring = 0.45 cm

a = Acceleration of subject = 0.832g

k = Spring constant

Force is given by

[tex]F=ma[/tex]

From Hooke's law

[tex]F=kx[/tex]

So

[tex]ma=kx\\\Rightarrow k=\dfrac{ma}{x}\\\Rightarrow k=\dfrac{4.63\times 10^{-3}\times 0.832\times 9.81}{0.45\times 10^{-2}}\\\Rightarrow k=8.4\ \text{N/m}[/tex]

The force constant of the spring is 8.4 N/m.

Answer:

20m/s

Explanation:

u = 0m/s

t = 2s

a = +g = 10m/s²

t = 2d

v = ?

v = ut + 1/2at²

v = 0(2) + 1/2(10)(2)²

v = 0 + 5(4)

v = 20m/s

Answer:

268.22m/s

Explanation:

Given;

    10mile/min to m/s

We need to convert between the two units;

  Using the dimensions;

    1 mile  = 1609.34m

     60s  = 1min

Now;

    10 x [tex]\frac{mile}{min}[/tex] x [tex]\frac{1min}{60s}[/tex] x [tex]\frac{1609.34m}{1mile}[/tex]

  = 268.22m/s

Complete question:

Resistor is made of a very thin metal wire that is 3.2 mm long, with a diameter of 0.4 mm. What is the electric field inside this metal resistor? If the potential difference due to electric field between the two ends of the resistor is 10 V.

Answer:

The electric field inside this metal resistor is 3125 V/m

Explanation:

Given;

length of the wire, L = 3.2 mm = 3.2 x 10⁻³ m

diameter of the wire, d = 0.4 mm = 0.4 x 10⁻³ m

the potential difference due to electric field between the two ends of the resistor, V = 10 V

The electric field inside this metal resistor is given by;

ΔV = EL

where;

ΔV is change in electric potential

E = ΔV / L

E = 10 / (3.2 x 10⁻³ )

E = 3125 V/m

Therefore, the electric field inside this metal resistor is 3125 V/m

Answer:

both

Explanation:

baby for fun, toddler for vengence

Answer:

The value is  [tex]w = 0.1167 \ rev/second[/tex]

Explanation:

From the question we are told that

    The rate at which the plate rotates is  [tex]w =7.0 \ rev/min[/tex]

Generally the revolution per second is mathematically represented as

       [tex]w = \frac{7.0}{60}[/tex]

=>    [tex]w = 0.1167 \ rev/second[/tex]

Answer:

b

Explanation:

i took the quiz i think its right

Answer:

Force = 49N

Explanation:

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

[tex] F = ma[/tex]

Where;

F represents force measured in Newton.

m represents the mass of an object measured in kilograms.

a represents acceleration measured in meter per seconds square.

Given the following data

Mass = 5kg

We know that acceleration due to gravity = 9.8m/s²

To find the Force:

[tex] F = 5*9.8 [/tex]

Force = 49N

Answer:

The average momentum of the bird is 0.26 kgm/s

Explanation:

The formula to be used here is that of momentum which is

momentum (in kgm/s) = mass (in kg) × velocity (in m/s)

The velocity of the bird is

velocity (in m/s) = distance (in meter) ÷ time (in seconds)

distance in meters = 125km × 1000 = 125,000 m

time in seconds = 4 hrs × 60 × 60 = 14,400 secs

velocity = 125000/14400

velocity = 8.68 m/s

momentum (p) = 0.03 × 8.68

p = 0.26 kgm/s

The average momentum of the bird is 0.26 kgm/s

The average momentum of the bird (in unit vector notation) is (0.1842i + 0.1842j) kgm/s.

Since the unladen swallow that weighs 0.03 kg flies straight northeast (that is at a bearing of 45°) a distance of 125 km in 4.0 hours.

Its position vector after 4.0 hours is d = (125kmcos45)i + (125kmsin45)j = (125000 × 1/√2)i + (125000 × 1/√2)j

= (62500√2)i + (62500√2)j.

If the initial position of the swallow is d' = 0i + 0j, then its total displacement after 4 hours is, D = d - d'

= (62500√2)i + (625000√2)j - (0i + 0j)

= (62500√2)i + (62500√2)j m

The unladen swallow's average velocity, v = D/t where

So, v =  [(62500√2)i + (62500√2)j m]/14400 s =  (88388.35)i/14400 + (88388.35)j /1440

= 6.14i + 6.14j m/s

The average momentum of the unladen swallow is p = mv where

So, p = mv

p = 0.03 kg × (6.14i + 6.14j m/s)

p = (0.1842i + 0.1842j) kgm/s

So, the average momentum of the bird (in unit vector notation) is (0.1842i + 0.1842j) kgm/s.

Learn more about average momentum here:

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Answer:

The distance of the bar D = 1153 km

Explanation:

The electric force is the one that takes place between electric charges.

The electric force with which two point charges are attracted or repelled at rest is directly proportional to their product, inversely proportional to the square of the distance that separates them and acts in the direction of the line that joins them.

Recall that:

Electrical force(F) = I*B*L

where;

I = the current,

B = the magnetic field strength,

L = the length of the bar

However;

From the second equation of motion,

F = Ma

Since; (F) = I*B*L

Then,

Ma = IBL,

where;

M is the mass;

a is the acceleration

Making the acceleration (a) the subject of the formula, we have

a = IBL/M

Similarly;

From the third equation of motion;

v^2= u^2+2as,

where v and u are the final velocity and the initial velocity respectively

Here u = 0

Also; let distance s = D

Then

v^2 = 2aD

where;

a = IBL/M

Making the distance D  the subject of the formula, we get:

D = v^2/2a = v2*M/(2IBL)

D = 11200² × 20/(2×2300×0.86×0.55)

D = 1153047.155 m

D = 1153 km

Answer: The acceleration results if a net force of 4F acts on a mass of 6m is 2/3a.

Explanation:

Force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is:

F= mass( kg) × acceleration( m/ s²)

Acceleration is defined as the rate at which the velocity of an object changes. From the formula of force given above it can be determined by making it the subject of formula. Therefore acceleration= Force/ mass.

From the question,

Force= 4F

Mass= 6m

Therefore acceleration= F/m

= 4/6

Acceleration= 2/3a

The required magnitude of acceleration when force is 4F and mass is 6m is 2/3a.

Given data:

The magnitude of net force is, 4F.

The value of mass is, 6m.

Apply the Newton's second law which says that force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is

F = ma

a = F/m ..........................................(1)

here, a is the acceleration.

Solving as when the force becomes 4F and mass becomes 6m.

[tex](4F) = (6m) \times a'\\\\a '= \dfrac{4F}{6m}\\\\a '= \dfrac{2}{3}a[/tex]

Thus, the required magnitude of acceleration when force is 4F and mass is 6m is 2/3a.

Learn more about the Newton's Second law here:

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Answer:

Maximum speed ( v ) = 10.4 m/s (Approx)

Explanation:

Given:

Amplitude A = 15.0 cm = 0.15 m

Frequency f = 11.0 cycles/s (Hz)

Find:

Maximum speed ( v )

Computation:

Angular frequency = 2πf

Angular frequency = 2π(11)

Angular frequency = 69.14

Maximum speed ( v ) = WA

Maximum speed ( v ) = 69.14 x 0.15

Maximum speed ( v ) = 10.371

Maximum speed ( v ) = 10.4 m/s (Approx)

Answer:

Hey

Explanation:

Answer:

1.52g

Explanation:

Given parameters:

Force  = 125N

Mass combined  = 82kg

Unknown:

Acceleration of the bicycle  = ?

Solution:

From Newton second law of motion suggests that:

   Force = mass x acceleration

  Acceleration = [tex]\frac{force}{mass}[/tex]  = [tex]\frac{125}{82}[/tex]   = 1.52g

Answer:

The answer that was correct for me was A. 55 N pulling left, and 16 N, 17N p

pulling Right

Explanation:

Answer: [tex]M_{total}=[/tex] 1.85

Explanation: Estimate the total mass of a binary system is done by a reformulation of Kepler's Third Law, which states that the square of the period of a planet's orbit is proportional to the cube of its semimajor axis, i.e.:

[tex]a^{3}=(M_{1}+M_{2})P^{2}[/tex]

where

a is semimajor axis in astronomical units (AU);

P is period measured in years;

[tex]M_{1}+M_{2}[/tex] is total mass of the two-stars system;

For the two stars faraway in the Milky Way:

1 year is equivalent of 365 days, so period in years:

[tex]P=\frac{594}{365}[/tex]

P = 1.63 years

Calculating total mass:

[tex]a^{3}=(M_{total})P^{2}[/tex]

[tex]M_{total}=\frac{a^{3}}{P^{2}}[/tex]

[tex]M_{total}=\frac{1.7^{3}}{1.63^{2}}[/tex]

[tex]M_{total}=[/tex] 1.85

The total mass of the two-object system is 1.85 mass units.

Answer:

The correct answer is - phototropism, thigmotropism, hydrotropism, and gravitropism in order ( already match correctly).

Explanation:

phototropism is a phenomenon in which plants grow towards the light or sun which is accomplished by the hormone auxin in the cells far from the light.

Thigotropism is a type of plant growth that occurs around the tree to support itself which is a touch stimuli response.

The movement of the plant in the direction of the source of the water is known as hydrotropism. In which stimuli is humidity or the water concentration.

The movement of the plant or roots of the plants towards the soil or earth is known as gravitropism here gravity is the stimuli.

Answer:

Use the drop-down menus to complete each sentence.

A plant grows toward a sunny window. This response is an example of

phototropism

.

Sometimes a plant grows around a tree for support. This response is an example of

thigmotropism

.

The roots of a plant grow toward a water source. This response is an example of

hydrotropism

.

The roots of a plant grow down into the soil. This response is an example of

gravitropism

.

Explanation:

Answer:

[tex]q_1=5.64\times 10^{-7}\ \text{C}[/tex] and [tex]q_2=2.32\times 10^{-6}\ \text{C}[/tex]

Explanation:

[tex]F_1=0.072\ \text{N}[/tex]

[tex]F_2=0.115\ \text{N}[/tex]

r = Distance between shells = 40.4 cm

[tex]q_1[/tex] and [tex]q_2[/tex] are the charges

[tex]k[/tex] = Coulomb constant = [tex]8.99\times10^{9}\ \text{Nm}^2/\text{C}^2[/tex]

Force is given by

[tex]F_1=\dfrac{kq_1q_2}{r^2}\\\Rightarrow q_1q_2=\dfrac{F_1r^2}{k}\\\Rightarrow q_1q_2=\dfrac{0.072\times 0.404^2}{8.99\times 10^{9}}\\\Rightarrow q_1q_2=1.307\times 10^{-12}\\\Rightarrow q_1=\dfrac{1.307\times 10^{-12}}{q_2}[/tex]

[tex]F_2=\dfrac{kq^2}{r^2}\\\Rightarrow q=\sqrt{\dfrac{F_2r^2}{k}}\\\Rightarrow q=\sqrt{\dfrac{0.115\times 0.404^2}{8.99\times 10^{9}}}\\\Rightarrow q=1.44\times 10^{-6}\ \text{C}[/tex]

[tex]q=\dfrac{q_1+q_2}{2}\\\Rightarrow q_1+q_2=2q\\\Rightarrow q_1+q_2=2\times1.44\times 10^{-6}\\\Rightarrow q_1+q_2=2.88\times 10^{-6}[/tex]

Substituting the above value of [tex]q_1[/tex] we get

[tex]\dfrac{1.307\times 10^{-12}}{q_2}+q_2=2.88\times 10^{-6}\\\Rightarrow q_2^2-2.88\times 10^{-6}q_2+1.307\times 10^{-12}=0\\\Rightarrow \frac{-\left(-0.00000288\right)\pm \sqrt{\left(-0.00000288\right)^2-4\times \:1\times \:1.307\times 10^{-12}}}{2\times \:1}\\\Rightarrow q_2=2.32\times 10^{-6}, 5.64\times 10^{-7}[/tex]

[tex]q_1=\dfrac{1.307\times 10^{-12}}{q_2}=\dfrac{1.307\times 10^{-12}}{2.32\times 10^{-6}}\\\Rightarrow q_1=5.63\times 10^{-7}[/tex]

[tex]q_1=\dfrac{1.307\times 10^{-12}}{q_2}=\dfrac{1.307\times 10^{-12}}{5.64\times 10^{-7}}\\\Rightarrow q_1=2.32\times 10^{-6}[/tex]

Since we know [tex]q_1<q_2[/tex]

[tex]q_1=5.64\times 10^{-7}\ \text{C}[/tex] and [tex]q_2=2.32\times 10^{-6}\ \text{C}[/tex].

Answer:

answer is 61.8 m/s; 32.9

l am not sure

Answer:

Because mechanical energy (the sum of potential and kinetic energy) is conserved, as the kinetic energy increases, the potential energy decreases. The maximum kinetic energy is achieved when the pendulum passes through the lowest point, and the maximum potential energy is achieved at the highest point.