Answer:
We know that the gravitational acceleration in the surface of the Earth can be written as:
g = G*M/r^2
Where:
M = mass of the Earth
r = radius of the Earth.
G = gravitational constant.
The weight of an object of mass m, is written as:
W = m*g = m*(G*M/r^2)
Now, if we move our object to a place that has a mass equal to 1/6 times the mass of the Earth, and 1/3 the radius of the earth.
The gravitational acceleration on this planet is written as:
g' = G*(M/6)/(r/3)^2 = (1/6)*(G*M)/(r^2/9) = (9/6)*(G*M/r^2) = (3/2)*g
then the weight on this planet is:
W' = m*g' = m*(3/2)*g = (3/2)*(m*g)
and m*g was the weight on Earth, then:
W' = (3/2)*(m*g) = (3/2)*W
The new weight is 3/2 times the weight on Earth.
The matter between stars is called?
A. asteroid belt
B. space
C. interstellar medium
D. Kuiper Belt
Answer:
your answer is C
Explanation:
the mass of the earth is 6×10²⁴ kg and the it's radius is 6400 km . what is the mass of a man weighing 977 N in spring balance ? { G= 6.67×10-¹¹ }
Answer:
Mass of the man = 100 kg
Explanation:
Given that,
Mass of the Earth, M = 6×10²⁴ kg
The radius of the Earth, r = 6400 km
Force on man, F = 977 N
We need to find the mass of the man. Let the mass of the man be m. The gravitational force acting between two objects is given by :
[tex]F=G\dfrac{mM}{r^2}\\\\m=\dfrac{Fr^2}{GM}\\\\m=\dfrac{977\times (6400\times 10^3)^2}{6.67\times 10^{-11}\times 6\times 10^{24}}\\\\m=99.99\ kg[/tex]
or
m = 100 kg
So, the mass of the man is 100 kg.
Which property describes if a mineral breaks down into flat pieces? this is science
A Cleavage
B Color
C Fracture
D Luster
A fairground ride spins its occupants inside a flying saucer-shaped container. If the horizontal circular path the riders follow has an 8.00 m radius, at how many revolutions per minute will the riders be subjected to a centripetal acceleration whose mag
Answer:
The number of revolutions is 10.68 rev/min.
Explanation:
Given that,
Radius = 8 m
Suppose, centripetal acceleration equal to the gravity
[tex]a_{c}=g=9.8[/tex]
We need to calculate the velocity
Using formula of centripetal acceleration
[tex]a_{c}=\dfrac{v^2}{r}[/tex]
[tex]v^2=a_{c}\times r[/tex]
Put the value into the formula
[tex]v=\sqrt{9.8\times8}[/tex]
[tex]v=8.85\ m/s[/tex]
We need to calculate the value of [tex]\omega[/tex]
Using formula of velocity
[tex]v=r\omega[/tex]
[tex]\omega=\dfrac{v}{r}[/tex]
Put the value into the formula
[tex]\omega=\dfrac{8.85}{8}[/tex]
[tex]\omega=1.12\rad/s[/tex]
We need to calculate the number of revolutions
Using formula of angular frequency
[tex]\omega=\dfrac{2\pi}{T}[/tex]
[tex]\omega=2\pi N[/tex]
[tex]N=\dfrac{\omega}{2\pi}[/tex]
Put the value into the formula
[tex]N=\dfrac{1.12}{2\pi}[/tex]
[tex]N=0.178\ rev/s[/tex]
Using conversion rev/s to rev/min
[tex]N=0.178\times 60[/tex]
[tex]N=10.68\ rev/min[/tex]
Hence, The number of revolutions is 10.68 rev/min.
Length of table is 1.0 metre, 1.00 metre and 1.000 metre. Which one is more accurate?
Answer:
1.000 metre
Explanation:
I hope it's helpful
A redecor travelling of 94 m/s s lows at a anstant
race to a velocity of 22m Is over Ils How
ar dies it move during this time?
Answer:
638 m.
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 94 m/s
Final velocity (v) = 22 m/s
Time (t) = 11 s
Distance (s) =?
We can obtain the distance travelled by using the following formula:
s = (u + v) t /2
s = (94 + 22) × 11 /2
s = 116 × 11 /2
s = 1276 /2
s = 638 m
Thus, the distance travelled is 638 m.
A different scaffold that weighs 400 N supports two painters, one 500 N and the other 400 N. The reading in the left scale is 800 N. What is the reading in the right-hand scale
Answer:
500 N
Explanation:
Given that,
The upward force is 800 N and the downward forces are 400 N, 500 N, 400 N.
At equilibrium, the upward forces will become equal to the downward forces. Let the reading in the right hand scale.
x + 800 = 400 + 500 + 400
x + 800 = 1300
x = 1300 - 800
= 500 N
So, the reading in the right hand scale is 500 N.
a bus traveling at 60m/s brakes and accelerates to a stop at a rate of -6m/s^2. how far did it travel while it stopped?
Answer:
300 m
Explanation:
using constant acceleration equations:
v = vi + a * t, v = final velocity = 0m/s , vi = initial velocity = 60m/s,
a = acceleration = -6m/s², t = time
solve t
t = 10s
x = vi * t + .5 * a * t²
plug
x = 300 m
When energy changes form, energy is...
A) lost.
B) created.
C) not lost or created.
Answer:
C
Explanation:
Energy is neither created or destroyed, but it can change forms...
A football player kicks a ball with a mass of .55 kg. The average acceleration of the
football was 14.9 m/s2. How much force did the kicker supply to the football?
A.8.2 m/s2
B.)8.2 N
C.)35.24 N
D.)35.24 m/s2
Answer:
8.2N
Explanation:
I took the test and got it right :)
A ball attached to a string is whirled at a constant speed of 2.0 meters per second in a
horizontal circle of radius 0.50 meter. What is the magnitude of the ball's centripetal
acceleration?
Answer:8.0 m/s^2
Explanation: The ball is traveling in uniform circular motion at the speed of 2 m/s in a path of the radius that is 0.50 meters.
v^2/r
2.0 m/s^2/ 0.50 m= 8.0 m/s^2
The magnitude of the ball's centripetal acceleration is [tex]\rm 8 \;m/sec^2[/tex] and this can be determined by using the formula of the centripetal acceleration.
Given :
A ball attached to a string is whirled at a constant speed of 2.0 meters per second in a horizontal circle of a radius of 0.50 meters.
The following steps can be used in order to determine the magnitude of the ball's centripetal acceleration:
Step 1 - The formula of the centripetal acceleration can be used in order to determine the magnitude of the ball's centripetal acceleration.
Step 2 - The formula of the centripetal acceleration is given below:
[tex]\rm a_c=\dfrac{v^2}{r}[/tex]
Step 3 - Substitute the values of the known terms in the above formula.
[tex]\rm a_c=\dfrac{2^2}{0.5}[/tex]
Step 4 - Simplify the above expression.
[tex]\rm a_c = 8\;m/sec^2[/tex]
For more information, refer to the link given below:
https://brainly.com/question/17689540
what should be done in order to increase the gravitational force between two objects? Decrease the mass of both of the objects. Decrease the mass of one of the objects. Decrease the distance between the two objects. Increase the distance between the two objects.
Answer:
Decrease the distance between the two objects.
Explanation:
The force (F) of attraction between two masses (M₁ and M₂) separated by a distance (r) is given by:
F = GM₁M₂ / r²
NOTE: G is the gravitational force constant.
From the equation:
F = GM₁M₂ / r²
We can say that the force is directly proportional to the masses of the object and inversely proportional to the square of the distance between them. This implies that an increase in any of the masses will increase the force of attraction and likewise, a decrease in any of the masses will lead to a decrease in the force of attraction.
Also, an increase in the distance between the masses will result in a decrease in the force of attraction and a decrease in the distance between the masses, will result in an increase in the force of attraction.
Considering the question given above,
To increase the gravitational force between the two objects, we must decrease the distance between the two objects as explained above.
Answer:
Decrease the distance between the two objects.
Explanation:
hit me wit that brainliest, please and thank you
c. Describe how to use right-hand rules to relate the directions of magnetic fields, currents, moving charges, and forces. (1 point) pls some one help me
Answer:
If you point your pointer finger in the direction the positive charge is moving, and then your middle finger in the direction of the magnetic field, your thumb points in the direction of the magnetic force pushing on the moving charge.
Explanation:
it’s right
Brendan Gan is about to drive to Kuala Lumpur from Johor Bahru. The distance from Johor Bahru to Kuala Lumpur is 330 km. Brendan's car can drive 60 miles using 1 gallon of petrol The current petrol costs are RM1.85 per liter.
Calculate the total petrol cost for Brendan to drive from Johor Bahru to Kuala Lumpur.
Use: 1 gallon = 4.5 liters
1 mile = 1.61 km
Round up answer to 2 decimal places (8 marks)
Answer:
The total cost in petrol will be: RM 28.43
Explanation:
The distance to be covered is: 330 km
The car does 60 mi per 1 gallon
so we convert this into km per liter as
60 mi/gal = 60 * 1.61 / 4.5 = 21.47 km/liter
Then, if 1 liter is needed to cover 21.47 km, then to cover 330 km one would need:
330 / 21.47 liters = 15.37 liters
Since each liter costs RM 1.85, then the cost in gas will be:
1.85 * 15.37 = RM 28.43
Explain why there are missing harmonics for standing waves on a string with a loose (free) end. (Hint: Is there a pattern to how much of a wavelength fits between the ends of the string with a loose end
Answer:
It is because there are a odd number of wavelengths fitting onto the string
Explanation:
The general formula for the harmonics on a string loose at one end is f = nv/2L where n = odd integer, v = speed of wave in string and L = length of string.
For a string loose at one end, there are a odd number of wavelengths which can fit onto the string. Since this is the case, we only have harmonics of odd numbers and thus we have even number harmonics missing.
A 2.0-kg ball with an initial velocity of (4i + 3j) m/s collides with a wall and rebounds with a velocity of (–4i + 3j) m/s. What is the impulse exerted on the ball by the wall?
Answer:
-16i kgm/s
Explanation:
Impulse I = m(v - u) where m = mass of ball = 2.0 kg, u = initial velocity of ball = (4i + 3j) m/s and v = final velocity of ball = (-4i + 3j) m/s.
So, the impulse is thus
I = m(v - u)
= 2.0 kg[(-4i + 3j) m/s - (4i + 3j) m/s]
= 2.0 kg[(-4i - 4i) + (3j - 3j) m/s]
= 2.0kg[-8i + 0j] m/s
= -16i kgm/s
The impulse on a 2.0-kg ball with an initial velocity of (4i + 3j) m/s collides with a wall and rebounds with a velocity of (–4i + 3j) m/s = 16i
Impulse: This can be defined as change in momentum of a body. The s.i unit of impulse is kgm/s²
The formula of impulse is
I = m(v-u)................ Equation 1
Where, I = impulse exerted on the ball by the wall, m = mass of the ball, v = final velocity of the ball, u = initial velocity of the ball
From the question,
Given: m = 2.0 kg, v = (-4i+3j) m/s, u = (4i+3j) m/s
Substitute these values into equation 1
I = 2.0[(-4i+3j)-(4i+3j)
I = 2.0(-4i-4i+3j-3j)
I = 2.0(-8i+0j)
I = -16i.
Hence the impulse exerted by the wall on the ball is -16i
Learn more about impulse here: https://brainly.com/question/22296861
A 40kg mass is pulled along a surface by a horizontal force of 300N. Friction on the mass is 30N. What is the acceleration of the mass???
Answer:
6.75 m/s²
Explanation:
The following data were obtained from the question:
Mass (m) of object = 40 Kg
Force applied (Fₐ) = 300 N
Force of friction (Fբ) = 30 N
Acceleration (a) =?
Next, we shall determine the net force acting on the mass. This can be obtained as follow:
Force applied (Fₐ) = 300 N
Force of friction (Fբ) = 30 N
Net force (Fₙ) =?
Fₙ = Fₐ – Fբ
Fₙ = 300 – 30
Fₙ = 270 N
Thus, the net force acting on the mass is 270 N.
Finally, we shall determine acceleration of the mass. This can be obtained as follow:
Mass (m) of object = 40 Kg
Net force (Fₙ) = 270 N
Acceleration (a) =?
Net force = mass × acceleration
Fₙ = m × a
270 = 40 × a
Divide both side by 40
a = 270 / 40
a = 6.75 m/s²
Therefore, the acceleration of the mass is 6.75 m/s²
A motorcycle skids to a stop on a road.
What is the equal and opposite force for the force of the motorcycle's friction pushing on the road as
described by Newton's third law?
Choose 1 answer:
Normal force of the road pushing up on the motorcycle
Earth's force of gravity pulling down on the motorcycle
Motorcycle's force of gravity pulling up on the Earth
Friction of the road on the motorcycle in the opposite direction
Answer:
Friction of the road on the motorcycle in the opposite direction
Explanation:
Khanacademy
total potential and kinetic energy of an object.
you have to finish the word
__c____c__ pls help
Answer:
The Total Mechanical Energy
As already mentioned, the mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy). The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.
Explanation:
what is letaral inversion?
Answer:
Images that are not aligned are laterally inverted
Explanation:
When a plane mirror reverses an image so that it becomes upside down and downside up or the other way round, we say that the image is laterally inverted.
Hence the effect produced when a plane mirror reverses an image is called lateral inversion
A good example of lateral inversion ins the lettering of an ambulance
How is a controlled variable different from a responding variable?
A. A controlled variable changes due to changes in the respondin
variable during the experiment.
B. A controlled variable stays the same due to changes in the
responding variable during the experiment.
C. A controlled variable changes throughout an experiment, but a
responding variable stays the same.
D. A controlled variable stays the same throughout an experiment,
but a responding variable changes.
What is the average power developed by a motor as it lifts a 400.-kilogram mass at constant speed through a vertical distance of 10.0 meters in 8.0 seconds
Answer:
The average power developed by a motor is 4905 Watts.
Explanation:
The average power is given by:
[tex] P = \frac{W}{t} [/tex]
Where:
W: is the work
t: is the time = 8.0 s
First, let's find the work:
[tex] W = F*d [/tex]
Where:
F: is the force
d: is the displacement = 10.0 m
The force is in the vertical motion, and since the movement of the mass is at constant speed the force is:
[tex] F = mg = 400 kg*9.81 m/s^{2} = 3924 N [/tex]
Hence, the average power is:
[tex] P = \frac{F*d}{t} = \frac{3924 N*10.0 m}{8.0 s} = 4905 J/s = 4905 W [/tex]
Therefore, the average power developed by a motor is 4905 Watts.
I hope it helps you!
The average power developed by a motor as it lifts the mass is 4,900 W.
The given parameters:
mass lifted, m = 400 kgdistance traveled, d = 10 mtime of motion, t = 8.0 sThe average power developed by a motor as it lifts the mass is calculated as follows;
[tex]P = \frac{E}{t} \\\\P = \frac{mgh}{t} \\\\P = \frac{400 \times 9.8 \times 10}{8} \\\\P = 4,900 \ J/s[/tex]
Thus, the average power developed by a motor as it lifts the mass is 4,900 W.
Learn more about average power here:https://brainly.com/question/19415290
An 82 kg man drops from rest on a diving board 3.0 m above the surface of the water. What is his speed when he hits the water? On hitting the water, it takes him 0.55 s to slow down to a stop. Calculate the net force on him inside the water that brings him to a stop. What are the forces on him when he slows down inside the water?
Answer:1.1x10^3N upward
Explanation:
On moving a charge of 20 coulombs by 2 cm, 2J of work is done then the potential difference between the points is
Answer:
The potential difference between the points is: 0.1 V
Explanation:
Given
Work W = 2JCharge q₀ = 20 CTo determine
The potential difference between the points is
We can use the formula to determine the potential difference between the points
[tex]V_A-V_B=\frac{W}{q_0}[/tex]
where W is done by moving charge q₀ from point A and point B
substituting W = 2J, and q₀ = 20 C
[tex]=\frac{2}{20}[/tex]
[tex]= 0.1[/tex] V
Therefore, the potential difference between the points is: 0.1 V
An adjustable tennis ball launcher launches tennis balls into the air from level ground and that return to level ground. The tennis balls are first launched with an initial velocity (vi) of 8.0 meters per second at an angle of 50° above the horizontal. The ball has an initial horizontal velocity of 5.1 meters per second. [Neglect friction.]
Calculate the vertical component of the ball’s initial velocity.
Calculate the maximum height reached by the ball.
Calculate the time elapsed to reach its maximum height.
Calculate the total horizontal distance travelled during its flight.
Answer:
Explanation:
I just need points
galileo was the first scientist to do which of the following?
Examine the boxes below. Both boxes are identical to one another. The mass of each box is concentrated in the very center, so the center of mass is in the
middle of the box. (Remember that mass is similar to weight) The arrows represent gravity pulling down on the center of mass of each box. Which of the boxes
represents a stable system? if you were to give that box a small push, what would happen to its state of equilibrium? Describe how a disturbance to this box
would affect it. Use the terms center of mass and equilibrium in your response.
If a car travels 60 mph for a distance of 180 miles, how much time
did it take?
Answer:
3 hours
Explanation:
180 divided by 60 (mph means miles per hours by the way)
A drum is struck first with little energy. The drum is then struck with a lot of energy. Which sound will be louder? Why?
Answer:
The drum struck with a lot of energy would be louder than the drum struck with little energy because there is a harder impact on it
Explanation:
A tennis ball is thrown up to a height of 26 m. Neglecting air resistance, with what initial
velocity was it thrown up with? Use Energy equations only
Answer:
v = 22.58[m/s]
Explanation:
To solve this problem we will use the principle of energy conservation, which tells us that potential energy is transformed into kinetic energy or vice versa.
[tex]E_{kin}=E_{pot}[/tex]
We must remember that potential energy is defined as the product of mass by gravity by height.
[tex]E_{pot}=m*g*h[/tex]
And the kinetic energy can be calculated by means of the following expression.
[tex]E_{kin}=0.5*m*v^{2}\\[/tex]
Now equalizing the two equations we can determine the initial velocity.
[tex]m*9.81*26=0.5*m*v^{2}\\255.06=0.5*v^{2}\\v=\sqrt{255.06/0.5}\\v=22.58[m/s][/tex]