Answer:
14.3 m/s
Explanation:
velocity equation
v= d/t
v= 60/4.2
v=14.28
round it to 1 decimal place
v= 14.3m/s
A falling object is said to reach a constant velocity (terminal velocity)..
a. when there is no gravitational force acting on it.
b. when there is no air resistance acting on it.
c. when air resistance equals the acceleration of gravity on it.
d. when it stops falling.
If forces acting on an object are unbalanced, which factor may result from an unbalanced force? A.The net force is negative. B.There is zero net force. C.The forces cancel each other out. D.There is no change in motion.
Answer:
A. The net force is negative.Explanation:
just took the test :)
Answer:
#AExplanation:
please help lol
im on my sisters acc btw
Answer:
sitting leg curls= hamstring
shrugs=shoulders
machine curls=biceps
bench press= pectorals
How do the individual forces compare when the rider experiences a sensation being lighter than his normal weight ? What is the acceleration direction when this occurs ?
Answer:
When the elevator is accelerating downward, the person feels lighter due to the downward normal force being less than the person's weight.
Explanation:
A person riding in an elevator subjected to a series of unbalanced forces depending on the direction the elevator is travelling.
Two forces are acting on the person; the force of gravity and the upward normal force from the elevator.
When the elevator is going upwards with acceleration a, the person feels heavier than his normal weight, due to the upward normal force being greater than the person's weight. N = mg + ma
When the elevator is moving downwards with acceleration a, the person feels lighter due to the downward normal force being less than the person's weight. N = mg - ma
However, when the elevator is moving up or down at constant velocity ie. acceleration a = 0, the person experience a normal force equal to weight. N = mg
When the elevator is moving downwards with acceleration a = g, the person experiences weightlessness. N = (mg - mg) = 0
Which of the following is NOT a way that a machine makes work easier to do?
A. Change the size of a force
B. Change the type of force
C. Change the direction of the force
D. Change distance a force acts
Answer:
c
Explanation:
ur changing the way it move not to make it easier
The direction of the force, has nothing to do with how the machine will work easier. The correct option is C
A machine is any devices that make work easier. An ideal machine takes in small effort to overcome large load.
Since work has to be done in a machine, and work is the product of force and perpendicular distance, for a machine to work easier, the work done will depend on size of the force applied, the type of force applied, and also, the magnitude of the distance involved.
The direction of the force, has nothing to do with how the machine will work easier. Therefore, the correct option is C
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A cannon is fired with an initial horizontal velocity of 20 m/s and initial vertical velocity of 25 m/s. After 3s in the air, the canon hits its target. How far away was the canon from its Target?
Answer:
140.16m
Explanation:
To get the distance the cannon is away from its target, we will apply the equation of motion;
S = ut + 1/2gt²
u is the resultant initial velocity
g is the acceleration due to gravity
t is the time taken.
Given
g = 9.8m/s²
t = 3s
u = √20²+25²
u = √400+625
u = √1025
u = 32.02m/s
Substitute the values into the formula and get the distance S;
S = 32.02(3)+ 1/2(9.8)3²
S = 96.06+44.1
S = 140.16m
Hence the cannon was 140.16m away from its target
The Moon has a radius of 1.7 × 106 m and a mass of 7.3 × 1022 kg. Find the gravitational field on the surface of the Moon.
Answer:
10.7*[tex]10^{6}[/tex]
Explanation:
15. Which element will donate electrons?
nitrogen
chlorine
aluminum
sulfur
Using a force of 10 N, you
push a shopping cart 10 m.
How much work did
you
do?
Answer:
100 JExplanation:
The work done by an object can be found by using the formula
workdone = force × distance
From the question we have
workdone = 10 × 10
We have the final answer as
100 JHope this helps you
Cody’s car accelerates from 0m/s to 65 m/s northward in 25 seconds. What is the acceleration of the car?
Answer:
v=v(initial)+at
45=0+15a
a= 3m/sec²
Explanation:
edge 2020
Una fuerza resultante constante de módulo igual a 40 [N], actúa sobre un cuerpo que se mueve en línea recta.¿Que distancia ha recorrido ese cuerpo si su energía cinética varió en 8 [J]?
Responder:
0,2 m
Explicación:
Usando la fórmula para calcular el trabajo realizado expresada como;
Workdone = Fuerza * Distancia
Dado
Fuerza = 40N
Trabajo realizado = 8 julios
Necesario
Distancia
Sustituya los parámetros dados en la fórmula como se muestra;
Distancia = Trabajo / Fuerza
Distancia = 8/40
Distancia = 0,2 m
Por tanto, el cuerpo recorrió una distancia de 0,2 m
A 100 Watt lightbulb uses 360000 Joules ever hour. How many lightbulbs could be powered for one hour by the energy from the Hiroshima bomb?
Answer:
200 million electric light bulbs.
Explanation:
First, we must calculate the power of the electric bulb, for this, we use the following equation that relates the energy as a function of time.
[tex]P=E/t[/tex]
where:
P = power [W] (units of watts)
E = energy = 360000 [J] (units of Joules)
t = time = 1 [h] = 3600 [s]
[tex]P = 360000/3600\\P= 100[W][/tex]
In 1 hour 1 electric lightbulb produces 100 [W], now we need to know the amount of energy produced by the Hiroshima bomb. A search made by the internet give us the data of 20 [GW] or [Gigawatts].
We need to remember that 1 Giga = 1 x10⁹
Energy Hiroshima explosion= 20*10⁹[W]
Amount = (20x10⁹)/100
Amount = 200 x10⁶ [bulbs]
That is, we would need an amount of 200 million electric light bulbs.
surface?
What is the mass of an object that experiences a gravitational force of 700 N near the Earth's surface
Answer:
70kg
Explanation:
Given parameters:
Gravitational force = 700N
Unknown:
Mass of the person = ?
Solution:
The weight is gravitational force on the person and can be expressed as;
W = mg
m is the mass
g is the acceleration due to gravity = 10m/s²
So;
700 = m x 10
m = 70kg
Which example illustrates Newton's second law?
A. A wheelbarrow remains stationary when no one pushes on it.
B. More mass is added to a wheelbarrow, and a larger force is
required to move it.
C. A person pushes a wheelbarrow, causing it to move forward.
D. The force of a wheelbarrow on the ground is equal to the force of
the ground on the wheelbarrow.
Answer:B
Explanation:
Mass
More mass is added to a wheelbarrow, and a larger force is required to move it - illustrates Newton's second law.
What is force?An object's push or pull is seen as exerting a force. The interaction of the objects produces push and pull. You can also use words like stretch and squeeze to describe force.
The definition of force in physics is: The push or pull on a mass-containing item changes its velocity.
Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration."
Hence more mass is added to a wheelbarrow, and a larger force is required to accelerate, i.e., move it.
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Cual es la fuerza de empuje que recibe un cuerpo de forma cilíndrica que mide 0.3 m de radio y 8m de altura, el cual se sumerge en alcohol si su densidad es de 790 Km/m3 tomando en cuenta la gravedad de 9.8m/seg2
Responder:
Fb = 17,5 kN
Explicación:
La expresión de la fuerza de empuje
Fb = ρgV ---------- 1
dónde
Fb = fuerza de flotación
ρ = densidad del fluido
g = aceleración debida a la gravedad
V = volumen de fluido
Paso uno:
datos dados
radio del cilindro = 0,3 m
altura h = 8m
densidad = 790 kg / m ^ 3
g = 9,8 m / s ^ 2
El volumen del cilindro se expresa como
V = πr ^ 2h
V = 3,142 * 0,3 ^ 2 * 8
V = 3,142 * 0,09 * 8
V = 2,26
El volumen es 2.26m ^ 3, el volumen del cilindro es igual al volumen de alcohol disparado
La expresión de la fuerza de empuje es
Fb = ρgV
sustituyendo tenemos
Fb = 790 * 9,8 * 2,26
Fb = 17514,26N
Fb = 17,5 kN
Newton's first law of motion states than an object's motion will not change
unless?
Answer:
it is hit by an external force
Explanation:
A stone is thrown vertically upwards. It takes 2 seconds to reach it highest point the acceleration due to gravity is 10m/s. With what velocity must it be thrown ?
Answer:
The velocity the stone must be thrown with is 20 m/s.
Explanation:
Given;
time taken for the stone to reach it highest point, t = 2 s
acceleration due to gravity, g = 10 m/s²
The maximum height reached by the stone at the given time is calculated as;
[tex]h = \frac{1}{2}gt^2\\\\h = \frac{1}{2}*10*2^2\\\\h = 20 \ m[/tex]
Determine the initial of the stone;
v² = u² + 2gh
where;
v is the final velocity of the stone at maximum height = 0
u is the initial velocity of the stone = ?
0 = u² - 2(10 x 20)
0 = u² - 400
u² = 400
u = √400
u = 20 m/s
Therefore, the velocity the stone must be thrown with is 20 m/s.
A bar magnet is a permanent magnet, While an electromagnetic temperary?
yes an electromagnetic is temporary
The diagram shows the forces acting on an object at an instant of time. Which of
the following statements about the forces is true? Select one answer.
Answer:
The correct option is;
The object is in horizontal equilibrium but NOT in vertical equilibrium
Explanation:
The given given forces in the force diagram are expressed in vector form as follows;
Topmost force = 2·i + 3·j
The horizontal force = 3·i
The force at the lower section = -5·i - 2·j
Adding the forces together to find the resultant force gives;
[tex]F_R[/tex] = 2·i + 3·j + 3·j + (-5·i - 2·j) = 5·i + 3·j - 5·i - 2·j = 0·i + j = j
[tex]F_R[/tex] = j
Therefore, the horizontal component of the forces are balanced as they cancel out and the object is said to be in horizontal equilibrium
However, the object has a net total resultant force component in the positive vertical direction, the object is not in vertical equilibrium.
Grade 8 Science Admin. May 2018 Released
37 A physics teacher performed a demonstration for a science class by pulling a crate across the
floor and measuring the force with a spring scale. While she pulled, a student measured the
acceleration of the crate with a handheld electronic device. The results of three trials are
shown below
Motion
F = 900 N
Actual Acceleration
of Crate
Trial
1
140 kg
Acceleration
(m/s)
0.36
0.34
0.38
0.36
2
3
Average
The teacher asked the class to calculate the acceleration of the crate based on the crate's
mass and the force she applied. What conclusion can be made about the difference between
the calculated acceleration and the actual acceleration that occurred in the trials?
A Another force in the direction of the motion produced a lower acceleration than calculated.
B An opposing force caused by friction produced a lower acceleration than calculated.
C Another force in the direction of the motion produced a higher acceleration than
calculated.
D An opposing force caused by friction produced a higher acceleration than calculated,
Answer:
B. An opposing force caused by friction produced a lower acceleration than calculated
Explanation:
Answer:
An opposing force caused by friction produced a lower acceleration than calculated.
Explanation:
PLEASE HELP ME QUICKLY!!!!!!!!!!!!!!
Answer:
I think thats the correct answer
Explanation:
A 30 N net force on a skater produces an acceleration of 0.6 m/s2 . What is the mass of the skater?
The mass of the Skater is 50 Kg.
We have a skater who is under the influence of 30 Newton of force.
We have to determine the mass of skater.
State Newton's Second law of Motion ?Newton's second law of motion states that the rate of change of momentum is directly proportional to the force applied. Mathematically-
[tex]$F\;\alpha \; \frac{dp}{dt}[/tex]
According to the question, we have -
Force on Skater - 30 N
Acceleration Produced - 0.6 [tex]m/s^{2}[/tex]
We know -
F = ma
30 = m x 0.6
m = 30/0.6 = 50 Kg
Hence, the mass of the Skater is 50 Kg
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Speed and Motion you went from the starting line to the finish line at different rates. If you repeated the activity while carrying weights but keeping your times the same, how would your kinetic energy be affected?
Answer:
It will cause kinetic energy to increase.
Explanation:
Given that Speed and Motion you went from the starting line to the finish line at different rates.
If you repeated the activity while carrying weights but keeping your times the same, the weight carried will add up to the mass of the body.
And since Kinetic energy K.E = 1/2mv^2
Increase in the mass of the body will definitely make the kinetic energy of the body to increase.
Since the time is the same, that means the speed V is the same.
Weight W = mg
m = W/g
The new kinetic energy will be:
K.E = 1/2(M + m)v^2
This means that there will be increase in kinetic energy.
A truck moves 30 km West, and then 40 km North, and then travels in a straight path back to its starting
point. The distance travelled by the truck is km and its displacement is
km
Distance = (30+40+50) = 120 km
It's back where it started, so displacement = zero
The distance traveled by truck is equal to 70 km and its displacement is 50 km.
What are distance and displacement?The distance of an object can be described as the total path traveled by an object. It is a scalar quantity as it has only magnitude, not direction. The distance is always positive, it can never be zero.
The displacement can be described as the shortest distance between two points. The displacement is a vector quantity with both direction and magnitude. The displacement of an object can be positive, negative, or zero and can increase or decrease with time.
Given, a truck moves 30 km along AB in the West as shown in the attached figure below, and then 40 km North along BC.
The distance of the truck will be = AB + BC = 30 + 40 = 70Km
The displacement (AC) can be calculated by using Pythagoras' theorem:
AC² = AB² + BC²
AC² = (30)² + (40)²
AC² = 2500
AC = 50 Km
Therefore, the distance is 70 Km and the displacement of the truck is 50 Km.
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HEY GUYS IS THIS TRUE OR FALSE????????
A ball thrown vertically upward is caught by the thrower after 2.93 s. Find the initial velocity of the ball. The acceleration of gravity is 9.8 m/s 2 . Answer in units of m/s.
Answer:
The initial velocity of the ball is 28.714 m/s
Explanation:
Given;
time of flight of the ball, t = 2.93 s
acceleration due to gravity, g = 9.8 m/s²
initial velocity of the ball, u = ?
The initial velocity of the ball is given by;
v = u + (-g)t
where;
v is the final speed of the ball at the given time, = 0
g is negative because of upward motion
0 = u -gt
u = gt
u = (9.8 x 2.93)
u = 28.714 m/s
Therefore, the initial velocity of the ball is 28.714 m/s
A block is given an initial velocity of 8.0 m/s up a frictionless 28° inclined plane. (a) What is its velocity when it reaches the top of the plane? (b) How far horizontally does it land after it leaves the plane?
Answer:
A.) 8 m/s
B.) 7.0 m
Explanation:
Given that a block is given an initial velocity of 8.0 m/s up a frictionless 28° inclined plane.
(a) What is its velocity when it reaches the top of the plane?
Since the plane is frictionless, the final velocity V will be the same as 8 m/s
The velocity will be 8 m/s as it reaches the top of the plane.
(b) How far horizontally does it land after it leaves the plane?
For frictionless plane,
a = gsinø
Acceleration a = 9.8sin28
Acceleration a = 4.6 m/s^2
Using the third equation of motion
V^2 = U^2 - 2as
Substitute the a and the U into the equation. Where V = 0
0 = 8^2 - 2 × 4.6 × S
9.2S = 64
S = 64/9.2
S = 6.956 m
S = 7.0 m
Examine the diagram of the cell cycle.
Which label identifies the step labeled W?
Anaphase: chromosomes thicken
Metaphase: chromosomes thicken
Anaphase: chromosomes are pulled apart
Metaphase: chromosomes are pulled apart
Answer:
Anaphase: chromosomes are pulled apart
Explanation:
Anaphase is a very rapid phase of meiosis and mitosis where sister chromatids (during mitosis or meiosis II) or homologous chromosomes (during meiosis I) separate and migrate to opposite poles of the cell. In the image, the diagram represents mitosis (thus separation of sister chromatids).
During this phase, following a specific signal, the sister chromatids separate abruptly. They are then "pulled" by the "microtubules" towards the pole to which they are attached. Chromatids migrate rapidly at a rate of about 1 μm / min. Anaphase is usually divided into two distinct phases.
Answer:
The answer is C
Explanation:
Question 3 of 10
Why do electric charges that move through a magnetic field produce an
electric current?
A. The magnetic field exerts a force on only the negative charges in
the wire.
B. The magnetic field exerts a force on only the positive charges in
the wire.
C. The magnetic field pushes negative charges and positive charges
in the same direction.
D. The magnetic field pushes negative charges and positive charges
in opposite directions.
Answer: D
Explanation: a p e x :)
Answer:
B. The magnetic field pushes negative charges and positive charges in opposite directions.
El extremo de una cuerda se mueve de tal manera que las partículas de la cuerda emplean 0.25 segundos para producir una vibración. ¿Cuál es el periodo? Y ¿Cuál es la frecuencia de la vibración producida
Responder:
T = 0.25 segundos
f = 4 Hz
Explicación:
Paso uno:
datos dados
se nos dice que las partículas tardan 0,25 segundos en completar una vibración
por lo tanto, el período es de 0,25 segundos
¿Qué es un período de vibración?
Un período T es el tiempo necesario para que un ciclo completo de vibración pase por un punto determinado.
la expresión para el período se da a continuación.
T = 1 / f
¿Cuál es la frecuencia de vibración?
Básicamente, se refiere a la frecuencia con la que ocurren las vibraciones.
la frecuencia es una tasa, se expresa como la inversa del período
f = 1 / T
t = 1 / 0.25
f = 4 Hz