PLZ HELP AG CLASS
Shifting from hand picking to mechanical picking results in which of the following improvements?
A increased efficiency of harvest
B reduced risk of damage to trees
C increased control of sorting
D reduced need for high-tech equipment
Answer is A.
Mechanical picking results in faster harvesting and it is less time consuming compared to hand picking. therefore it increased the efficiency of harvest
If the answer is incorrect, the next possible answer would be C.
Answer:
efficiency
Explanation:
no balls
is the long-term average weather over a large area
Which of the following are not found in Cyanobacteria?
Answer:
Like all other prokaryotes, cyanobacteria lack a membrane-bound nucleus, mitochondria, Golgi apparatus, chloroplasts, and endoplasmic reticulum. All of the functions carried out in eukaryotes by these membrane-bound organelles are carried out in prokaryotes by the bacterial cell membrane.
Calculate the diploid & haploid numbers for each of the following organisms
Organism
Diploid number
Haploid number
Camel
70
Human
46
Squirrel
20
Apple
34
3
Mosquito
Frog
13
Lettuce
18
Explain how a human baby gets 46 chromosomes:
Answer:
Meiosis is the start of the process of how a baby grows. Normally, meiosis causes each parent to give 23 chromosomes to a pregnancy. When a sperm fertilizes an egg, the union leads to a baby with 46 chromosomes.
A kitten embryo is growing inside the uterus of a cat. What is happening to the cells of the kitten embryo?
A) Mitosis, the cells are differentiating
B) Meiosis, the cells are differentiating
C) Meiosis, the genes are being shuffled around
D) Mitosis, genes are being shuffled around
Please answer and don't put fake answer I really need this right.
Answer:
A
Explanation:
the cells will start to split causing growth in the embryo
Which of the following is the best explanation of the physiological reaction to the length of daylight hours often referred to as photoperiodism? Group of answer choices Plants will only flower during long day periods when the day length exceeds their necessary photoperiod. Plants are able to respond to photoperiodism, but animals are not. Migration is triggered by temperature change and not by photoperiodism. Hibernation is often triggered by photoperiodism.
Answer:
A. Plants will only flower during long day periods when the day length exceeds their necessary photoperiod
Explanation:
Photoperiodism is a phenomenon that refers to the response of an organism to the length of day. This phenomenon causes a physiological change in the organisms involved (plants or animals). However, the best studied example of change caused by photoperiodism is that of FLOWERING IN PLANTS.
Different plants flower at different times in response to the day length. Certain plants called LONG DAY PLANTS e.g. spinach and potato etc only flower when the length of day exceeds their photoperiod (threshold), which is usually 12 hours. These plants require very short periods of darkness to flower.
Hence, according to the question, FLOWERING response in plants is the best explanation to describe photoperiodism.
How does a hot spot make a volcano?
PLEASE HELPP ILL GIVE BRAINLIST!!
C. the alge, zooplankton, insect, and bluegill populations would all be affected.
Answer:
i think it is c i hope this helps
Explanation:
What is a way carbon dioxide moves from nonliving things into living things?
hi!
through the process of photo synthesis
Why the Carbon must be cycled through the carbon cycle?
Answer:
The carbon cycle describes the process in which carbon atoms continually travel from the atmosphere to the Earth and then back into the atmosphere. Since our planet and its atmosphere form a closed environment, the amount of carbon in this system does not change.
Biodiversity is highest near the __________.
A. the poles
B. oceans
C. temperate zone
D. equator
Answer:
equator
Explanation:
Due to a extended 5 year drought the seeds became much harder than they were previously which graph would represent how the bird population would change over these years
Answer:
Graph A
Explanation:
With harder seeds, birds will need larger beaks in order to crack the seeds. The birds with smaller beaks won't be able to crack the seeds and will die because they can't eat anything. Graph A is the only one that shows a distinct increase in bird beak size.
Why can yeast be considered to be a parasite?
A. Yeasts are helpful towards other organisms.
B. Yeasts are considered to be a food source by some organisms.
C. Yeast can only move by being carried by another organism.
D. Yeasts can harm other organisms.
Answer:
B
Explanation:
How does a visking tubing differ from a cell membrane?
Answer:
Visking tubing is very similar to the cell membrane. It is also a selectively permeable membrane. It has tiny holes (pores), which allow small molecules through, but stop molecules that are too large to fit through them.
Explanation:
(hope this helps)
A cell goes through mitosis every 20 minutes. How many cells will there be after 3 hours?
Answer:
Well since a single cell per 20 minutes, it would be 9 cells in 3 hours.
Explanation:
Well since there’s 60 minutes in an hour and 60/20 is 3
3*3 hours is 9
So 9 cells in 3 hours
How to Define life ?
The condition that distinguishes animals and plants from inorganic matter, including the capacity for growth, reproduction, functional activity, and continual change preceding death.
This is the definition of life.
Answer:
Life is defined as any system capable of performing functions such as eating, metabolizing, excreting, breathing, moving, growing, reproducing, and responding to external stimuli.
When parents reproduce, they pass different versions of genes, or _____, for different traits to their ____.
Answer:
characters
offsprings.
Explanation:
During meiosis, all various genes are separated. The inherited alleles constitute the genotype of the individual.
The transfer of parental to offspring characteristics is called heredity and the heritable features can be predicted.
Which of the following best describes how the RNA sequence specifies the production of an amino acid chain?
A.
Each individual RNA base codes for three amino acids.
B.
Each group of three RNA bases codes for an enzyme that connects amino acids.
C.
Each individual RNA base codes for a ribosome location where amino acids are assembled.
D.
Each group of three RNA bases codes for a specific amino acid.
Answer:
The answer is B Each group of three RNA bases codes for an enzyme that connects amino acids.
In your experiment, you found the following offspring only:Tall green: 626 offspring.Tall yellow: 313 offspring.Short green: 309 offspring.Stay with your original hypothesis/assumption, test it using chi2 test and analyze the result (whether you want to reject the hypothesis and why).(6p)
Complete question:
1. You found a new species of garden pea and have decided to repeat Mendel’s experiments. You have obtained two true-breeding pea plants that are tall (T) with yellow pods (g), and short (t) with green pods (G), respectively. Capital letters indicate dominant traits.
a. What is the genotype and phenotype of the F1 generation? (2p)
b. You allowed self-fertilization in F1 generation and obtained F2 generation. Using Punnett square to obtain the phenotypes, genotypes and their respective ratios. (4p)
2. If you obtained 1248 offspring in the F2 generation in Question 1, calculate how many offspring of each phenotypic class you would expect to have. (4p)
3. When you finish questions 1 and 2, under what assumption/hypothesis did you perform your analysis/calculation? Is there an alternative assumption/hypothesis, which may result in a different conclusion? If yes, what is the alternative assumption/hypothesis and what kind of offspring and in what numbers do you expect to obtain? (4p)
4. You only need to answer A or B to get this 6p. Please indicate which question you are answering. In your experiment, you found the following offspring only: Tall green: 626 offspring. Tall yellow: 313 offspring. Short green: 309 offspring.
A: If you stay with your original hypothesis/assumption, test it using chi2 test and analyze the result (whether you want to reject the hypothesis and why).
B: If you believe that the alternative hypothesis fits better with your data, test it using chi2 test and analyze the result (whether you want to accept the hypothesis and why).
Answer:
1) a. 100% of the progeny will be dihybrid, TtGg, exhibiting the phenotype
Tall plants with green pods.
b. F2 Gentotype:
1/16 TTGG2/16 TTGg1/16 TTgg2/16 TtGG4/16 TtGg2/16 Ttgg1/16 ttGG2/16 ttGg1/6 ttggF2 Phenotype:
9/16 Tall plants with green pods (T-G-)3/16 Tall plants with yellow pods (T-gg)3/16 Short plants with green pods (ttG-)1/16 Short plants with yellow pods (ttgg)Phenotypic ratio → 9:3:3:1
2) T-G- → 702 individuals
T-gg → 234 individuals
ttG- → 234 individuals
ttgg → 78 individuals
3)
Null Hypothesis: The population is under Hardy-Weinberg equilibrium. The alleles of this population assort independently.Alternative Hypothesis: The population is not in equilibrium. Alleles do not assort independently.4) a. There is enough evidence to reject the null hypothesis, meaning that the difference between the observed number of individuals and the expected ones is statistically significant. The population is not under equilibrium H-W. Alleles do not assort independently.
Explanation:
1) 1st Cross: True-breeding tall (T) with yellow pods (g) pea plant with a short (t) with green pods (G) plant
Tall and Green pods are the dominant traits,Short and yellow pods are recessive traits.Parentals) TTgg x ttGG
Gametes) Tg, Tg, Tg, Tg tG, tG, tG, tG
F1) 100% of the progeny will be dihybrid, TtGg, exhibiting the phenotype
Tall plants with green pods.
2nd Cross: F1 self-fertilization
Parentals) TtGg x TtGg
Gametes) TG, Tg, tG, tg
TG, Tg, tG, tg
Punnett square) TG Tg tG tg
TG TTGG TTGg TtGG TtGg
Tg TTGg TTgg TtGg Ttgg
tG TtGG TtGg ttGG ttGg
tg TtGg Ttgg ttGg ttgg
F2) Gentotype:
1/16 TTGG2/16 TTGg1/16 TTgg2/16 TtGG4/16 TtGg2/16 Ttgg1/16 ttGG2/16 ttGg1/6 ttggPhenotype:
9/16 Tall plants with green pods (T-G-)3/16 Tall plants with yellow pods (T-gg)3/16 Short plants with green pods (ttG-)1/16 Short plants with yellow pods (ttgg)Phenotypic ratio → 9:3:3:1
2) The total number of individuals in the F2 is 1248.
16 ----------------- 1248 individuals --------------- 100% of the progeny
9 T-G- ----------- X = 702 individuals-------------X = 56.25%
3 T-gg ----------- X = 234 individuals ----------- X = 18.75%
3 ttG- ------------- X = 234 individuals ---------- X = 18.75%
1 ttgg ------------- X = 78 individuals ------------ X = 6.25%
3)
Hypothesis: The population is under Hardy-Weinberg equilibrium. The alleles of this population assort independently.Alternative Hypothesis: The population is not in equilibrium. Alleles do not assort independently4) F2 composed of:
Tall green: 626 offspring. Tall yellow: 313 offspring. Short green: 309 offspring.Tall/Green Tall/Yellow Short/Green Short/Yellow
Observed 626 313 309 0
Expected 702 234 234 78
(Obs-Exp)²/Exp 8.23 26.7 24 78
X² = Σ(Obs-Exp)²/Exp = 8.23 + 23.7 + 24 + 78 = 136.93 ≅ 137
Freedom degrees = genotypes - number of alleles = 9 - 4 = 5
Significance level, 5% = 0.05
Table value/ Critical value = 11.07
X² = 137
X² > Critica value
137 > 11.07
There is enough evidence to reject the null hypothesis, meaning that the difference between the observed number of individuals and the expected ones is statistically significant. The population is not under equilibrium H-W. Alleles do not assort independently.
can you live without a spleen
Answer:
Yes
Explanation:
Although the spleen is an important part of the Immune system, you can survive without it, because the liver can also have the same functions of a spleen. Although the liver can take over these functions it cant prevent all the bacteria that a spleen can prevent.
Transcribe the following DNA strand: ATGCATTGCGAT
in selective breeding, the desirable traits are chosen.
a. true
b. false
You are tasked with characterizing responses to Epidermal Growth Factor (EGF) treatment of HeLa Cells. You grow HeLa cells then replace the culture media with media containing EGF at various concentrations, then harvest samples for Western blot analysis using an anti-phospho-MAPK antibody as a readout of receptor tyrosine kinase activity. As expected, your control (EGF treated cells) show a strong phopho-MAPK signal on your Western blot. What do you hypothesize will happen if you pre-treat HeLa cells with siRNAs (RNAi) against Ras prior to adding EGF and performing Western blot analysis with anti-phospho-MAPK
Answer:
The answer is "The EGF receptor will be activated but the signal will not be appropriate transduced"
Explanation:
It induces the replication of cell types, especially fibroblasts or epithelial cells. It enhances neuron variety's telling the difference, ripening, and survival. The proinflammatory cytokines of the EGF family are described by four disulfide bonds that confer adhesive properties. The EGF sensor is switched on and the signal is not transmitted correctly.
WILL GIVE BRAINLIEST, NO LINK SHARING OR U WILL BE BANNED
Why were Domains added to the classification system after the time of Linnaeus?
Answer: With the development of powerful microscopes, scientists discovered many single-celled organisms that didn't fit into any of Linnaeus' kingdoms. As a result, a new taxon, called the domain, was added to the classification system.
Explanation:
I need a definition of representation and diversity
Answer:
resperation is the the action of breathing.
diversity is a range of different things.
Explanation:
what is urbanization
Explanation:
the process of expanding residential areas or establishing cities or towns by constructing large buildings in search of modern facilities is called urbanization.
hope it helps
Which is a part of interphase?
O A. G, phase
B. Cytokinesis
C. Telophase
D. Prophase
Answer:
A. G¹ phaseExplanation:
In G¹ phase - RNA and Proteins are synthesised and the volume of Cytoplasm increase.
Several examples of antisense RNA regulating translation in bacterial cells have been discovered. Molecular geneticists have also used antisense RNA to artificially control transcription in both bacterial and eukaryotic genes. To inhibit the transcription of a bacterial gene with antisense RNA, what sequence might the antisense RNA contain
Answer:
An antisense sequence with complementary to the target mRNA encoded by the gene of interest
Explanation:
An antisense sequence is usually a short RNA sequence specifically designed in the laboratory to bind by complementary to the DNA/RNA sequence of interest (usually a target mRNA) whose expression is desired to be inhibited. When an antisense bind to its target mRNA, the antisense sequence acts to block translation, thereby inhibiting protein synthesis. Moreover, it has been shown that the double-stranded antisense-RNA complexes may also increase the susceptibility of the target sequence to RNase H digestion.
Need help with this one
Answer:
i think its a but i am not absoulty sure
Explanation:
Answer:
Answer A
Explanation:
I did the quiz as well lol