If you wanted to find a sample of fermium, which has an atomic number of 100, where would you look?
A. Deep within the earth
B. In the earths atmosphere
C. In outer space
D. In Science Lab

Answer: A

Explanation:

The weight W palced at a distance of 45 cm on a half meter ruler pivote at its midpoint is 15 N.

To calculate the weight W, we use the principle of moment.

It states that, if a body is at equilibrium, the sum of clockwise moment is equal to the sum of anticlockwise moment.

From the question,

Clockwise moment (F×d ) = Anticlockwise moment (W×D).......... Equation1

Make W the subject of the equation

Given:

Substitute these values into equation 2

Hence, the weight W is 15 N

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Given that,

The rate of change of current = 3.2 A/s

Emf induced in the coil = 5.7 V

To find,

The magnitude of the mutual inductance of the two coils.

Solution,

The mutual inductance between the coils is given by the formula as follows :

[tex]\epsilon=M\dfrac{dI}{dt}\\\\M=\dfrac{\epsilon}{\dfrac{dI}{dt}}\\\\M=\dfrac{5.7}{3.2}\\\\=1.78\ H[/tex]

So, the mutual inductance of the two coils is 1.78 H.

Answer:

3.08m/s²

Explanation:

Given parameters:

Radius = 20m

Tangential velocity  = 7.85m/s

Unknown:

Centripetal acceleration  = ?

Solution:

Centripetal acceleration is the acceleration of a body along a circular path.

 it is mathematically given as;

       a  = [tex]\frac{v^{2} }{r}[/tex]  

v is the tangential velocity

r is the radius

      a  = [tex]\frac{7.85^{2} }{20}[/tex]   = 3.08m/s²

Answer:

The horse moves due to kinetic energy and is walking balanced because of the gravitational energy

Explanation:

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A bowling ball results in kinetic friction compared to a sliding bowling ball.

According to Conservation of momentum, if a bowling ball hits some pins, the momentum that lost by the bowling ball is known to be equal to the momentum obtained by the pins.

The friction that is used in bowling is kinetic friction because the more oil that is placed down, the lower the friction that is found between the ball and that of the lane surface. The  little friction, the stronger it is for the bowler to be able to send the ball in a curved path and thus the formula to find the kinetic friction is know to be : µk=F k/mg.

Therefore, A bowling ball results in kinetic friction compared to a sliding bowling ball.

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Answer:

9.2m

Explanation:

Think of the woman's path as a triangle. She walks 7m horizontally and 6m vertically. These are the two legs of a triangle. In order to find her distance from the origin, we can use pythagorean theorem to find the hypotenuse of the triangle. The hypotenuse will give us the direct measurement from the origin (0,0) to her current point (7,6).

a²+b²=c²

(7)²+(6)²=c²

49+36=c²

85=c²

Find the square roots of both sides to get c=9.21954...

Round your answer to the nearest 10th:

c=9.2m

The woman is approximately 9.2m from the origin.

Answer:

The car's acceleration is [tex]3\ m/s^2[/tex]

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes uniformly over time.

The final speed is given by:

[tex]v_f=v_o+at[/tex]

Where a the constant acceleration, vo the initial speed, vf the final speed, and t the time, the following relation applies:

Using the equation above we can solve for a:

[tex]\displaystyle a=\frac{v_f-v_o}{t}[/tex]

The car is initially at rest (vo=0) and t=10 seconds later it's moving at vf=30 m/s, thus its acceleration is:

[tex]\displaystyle a=\frac{30-0}{10}[/tex]

[tex]\displaystyle a=\frac{30}{10}=3[/tex]

[tex]a = 3\ m/s^2[/tex]

The car's acceleration is [tex]3\ m/s^2[/tex]

Answer:

v = 0.6c = 1.8 x 10⁸ m/s

Explanation:

From Einstein's theory of relativity, we know that the length of an object contracts while traveling at a speed relative to speed of light. The contraction is according to following equation:

[tex]L = L_{0}\sqrt{1 - \frac{v^2}{c^2}}[/tex]

where,

L = Relative Length

L₀ = Rest Length

According to given:

L = 0.8 L₀

c = speed of light = 3 x 10⁸ m/s

v = relative speed of train = ?

Therefore,

[tex]0.8L_{0} = L_{0}\sqrt{1 - \frac{v^2}{c^2} } \\\\0.8 = \sqrt{1 - \frac{v^2}{c^2} }[/tex]

squaring on both sides:

[tex]0.64 = 1-\frac{v^2}{c^2}\\\\\frac{v^2}{c^2} = 1-0.64 \\v^2= 0.36c^2\\[/tex]

taking square root on both sides:

v = 0.6c = 1.8 x 10⁸ m/s

The mass of the cylinder made of lead is 644.33 kg.

Mass can be defiend as the quantity of matter a contained in a body. The S.I unit of mass is kilogram (kg).

To calculate the mass of the cylindrical lead, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute the values above into equation 1

Hence, the mass of the cylinder made of lead is 644.33 kg.

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Answer:

6

Explanation:

The magnetic field inside a solenoid is given by the following formula:

[tex]B = \mu_{0}nI[/tex]

where,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For Solenoid 1:

[tex]B_{1} = \mu_{0}n_{1}I ------------------- equation 1[/tex]

For Solenoid 2:

n₂ = 6n₁

Therefore,

[tex]B_{1} = \mu_{0}n_{2}I\\B_{1} = 6\mu_{0}n_{1}I ----------------- equation 2[/tex]

Diving equation 1 and equation 2:

[tex]\frac{B_{2}}{B_{1}} = \frac{6\mu_{0}nI}{\mu_{0}nI}\\\\\frac{B_{2}}{B_{1}} = 6[/tex]

Hence, the correct option is:

6

The ratio of the magnetic fields in interior 2 to interior 1 will be

[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]

The formula for the magnetic fields inside the solenoid will be given:

[tex]B=\mu_onI[/tex]

here,

B = Magnetic Field Inside Solenoid

μ₀ = permittivity of free space

n = No. of turns per unit length

I = Current Passing through Solenoid

For the first Solenoid

[tex]B_1=\mu_on_1I[/tex]..................(1)

For the second solenoid

[tex]n_2=6n_1[/tex]

Now

[tex]B_2=\mu_on_2I[/tex]

[tex]B_2=\mu_o(6n_1)I[/tex]..................(2)

Diving equation 1 and equation 2:

[tex]\dfrac{B_2}{B_1} =\dfrac{\mu_o(6n_1)I}{\mu_on_2I}[/tex]

[tex]\dfrac{B_2}{B_1} =6[/tex]

Thus the ratio of the magnetic fields in interior 2 to interior 1 will be

[tex]\dfrac{B_2}{B_1} =\dfrac{6}{1}[/tex]

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The acceleration of the plane after 5 seconds will be 14 m/s².

The rate of change of velocity with respect to time is called acceleration. Mathematically -

a = Δv/Δt

Given is a small plane that starts from rest and accelerates uniformly to the east to a takeoff velocity of 70 m/s in 5 seconds.

The acceleration of the body can be calculated as follows -

a = Δv/Δt

a = (70 - 0)/(5 - 0)

a = 70/5

a = 14 m/s²

Therefore, the acceleration of the plane after 5 seconds will be 14 m/s².

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Answer:

-79

Explanation:

because I know because that's what the answer is because it is -79 when it hits the ground

Starting at New Moon, The visual distance increases for about 2 weeks, then decreases for about the next 2weeks, until the next New Moon.

On the average, it changes by about 12° per day.

Answer:

The tension in the string is 52.89 N.

Explanation:

Given;

mass of the string, m = 19.1 g = 0.0191 kg

length of the string, L = 1.95 m

⇒mass per unit length, μ = 0.0191 / 1.95 = 0.009795 kg/m

Also Given;

frequency of the string, F = 440 Hz

wavelength of the sound wave, λ = 16.7 cm = 0.167 m

⇒the speed of the wave, v = Fλ = 440 x 0.167 = 73.48 m/s

The tension T in the string is calculated as;

[tex]v = \sqrt{\frac{T}{\mu} } \\\\v^2 = \frac{T}{\mu}\\\\T = v^2 \mu\\\\T = (73.48)^2 (0.009795)\\\\T = 52.89 \ N[/tex]

Therefore, the tension in the string is 52.89 N.

Hello!

[tex]\large\boxed{F = 100N}[/tex]

Use the equation F = m · a (Newton's Second Law) to solve. Substitute in the given values:

F = 5 · 20

F = 100N

30.76/s is the angular speed of the car traveling at a constant speed of 14m/s and having a tire of  diameter of 0.91m

The rate of change of angular displacement is known as Angular velocity . The unit of angular velocity is radians/second. The same formula describes both angular velocity and angular velocity. Angular velocity is a vector quantity that expresses both direction and magnitude, but angular velocity expresses only magnitude. Angular velocity (ω) is a scalar measure of rotational speed. The angular distance traveled in one full rotation is 2π and the time is duration (T).

here from the given data that is a constant speed of 14. It tires have a diameter of 0.91

ω=θ/t

V=2πr/t

=14m/s

ω=v/r

=14/0.45

=30.76

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the question you provided was incomplete and I have added the incomplete part that is to find the angular speed of the given data.

The acceleration of the electrical current is -2.4 m/s².

Acceleration can be defined as the rate of change of velocity.

To calculate the acceleration of the electric current, we use the formula below.

Formula:

Where:

From the question,

Given:

Substitute these values into equation 1

Hence, the acceleration of the electrical current is -2.4 m/s².

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Answer: it will take 1.9 × 10⁶ yrs for one mole of the radioactive material to decay so that just one atom remains

Explanation:

Given that;

Half life t_1/2 = 24,000 years

initial amount of radio active element = 1 mole

now one mole of a substance has Avagadro number of atoms which is initially 6.023 × 10²³ which are present and finally only 1 atom is left

using the formula

t_1/2 = 0.693/k

In[ N₀/N_t] = kt

N₀ is the initial amount, N_t is the amount left after t time, t is the time, k is the rate constant.

now we substitute

t_1/2 = 0.693/k

k = 0.693/ t_1/2

k = 0.693 / 24,000 years

k = 0.000028875 yr⁻¹

so

In[ N₀/N_t] = kt

t = 1/0.000028875 yr⁻¹ In [ 6.023 × 10²³ / 1 ]

= 34632.0346 In[6.023 × 10²³]

= 34632.0346 × 54.7550

= 1896277.0545 yrs ≈ 1.9 × 10⁶ yrs

Therefore it will take 1.9 × 10⁶ yrs for one mole of the radioactive material to decay so that just one atom remains

Answer:

The appropriate response will be "Infrared has a longer wavelength and lower photon energy".

Explanation:

Answer:

3.69 rad/s

Explanation:

From the question given above, the following data were obtained:

Period (T) = 1.7 s

Angular frequency (ω) =?

Thus, we can obtain the angular frequency (ω) by applying the following formula:

ω = 2π/T

Period (T) = 1.7 s

Pi (π) = 3.14

Angular frequency (ω) =?

ω = 2π/T

ω = 2 × 3.14 / 1.7

ω = 6.28 / 1.7

ω = 3.69 rad/s

Thus, the angular frequency of the motion is 3.69 rad/s

Answer:

16m/s

Explanation:

Given the following data;

Force, F = 16N

Mass, m = 5kg

Time, t = 5 seconds.

First of all, we would find the acceleration of the object.

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is given by the formula;

[tex] F = ma[/tex]

Where;

Making acceleration (a) the subject, we have;

[tex]Acceleration, a = \frac{F}{m}[/tex]

Substituting into the equation;

[tex]Acceleration, a = \frac{16}{5}[/tex]

Acceleration, a = 3.2 m/s²

Now, to find velocity;

We would use the first equation of motion given by the formula;

[tex] V = U + at[/tex]

Where;

We know that acceleration due to gravity is 9.8m/s² and initial velocity (U) is 0 since the object is at rest.

Substituting into the equation, we have;

[tex] V = 0 + 3.2*5[/tex]

[tex] V = 0 + 16[/tex]

Velocity, V = 16m/s.

Complete Question

Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of [tex]0.025 \ m^3[/tex]. If the temperature of the gas is 290 K. what is the rms speed of the gas atoms? The atomic mass of Argon is 39.9 u.(l u= 1.66x10-27 kg) Enter your answer in m/s

Answer:

The value is [tex]V_{rms} = 425.75 \ m/s[/tex]

Explanation:

From the question we are told that

     The volume of the space in between the two glass sheet is  [tex]a = 0.025 \ m^3[/tex]

     The temperature of the gas is [tex]T = 290 \ K[/tex]

       The atomic mass of Argon is  [tex]m = 39.9 \ u = 39.9 * 1.66 *10^{-27} = 6.623 *10^{-26} \ kg[/tex]

Generally the root mean square velocity is mathematically represented as

      [tex]V_{rms} = \sqrt{\frac{3 K T}{ m } }[/tex]

Here K is the Boltzmann constant  with value [tex]k = 1.38 *10^{-23} \ m^3 \cdot kg \cdot s^{-2} \cdot K^{-1}[/tex]

So

     [tex]V_{rms} = \sqrt{\frac{3 * 1.38 *10^{-23} * 290 }{ 6.6234*10^{-26} } }[/tex]

=>   [tex]V_{rms} = 425.75 \ m/s[/tex]

Answer:

A = 2 m from fulcrum

Explanation:

Product of anti clockwise  = Product of  clockwise moment

5 × 4 = 10 × A

20 = 10 x A

A = 20 / 10

A = 2 m from fulcrum

Answer:

Yes it is matter

Explanation:

In physics, usually the word "electricity" isn't really used. "Electric current" is more common, and is defined as the flow of charges, where the charges are held by particles (electrons). Electrons have mass, so they are definitely matter.

Answer:

All the cells in an organism have exactly the same function

The statements that describe the processes involved in the accretion of planetesimals and protoplanets are :

II. Both processes involve nebular materials becoming solid particles.

IV. In both cases, masses of stuff are clumped together and gases are trapped.

Accretion basically involves the accumulation of particles into a massive object by gravitationally attracting more matter, mainly the gaseous matter, in an accretion disk.

A protoplanet is basically a large planetary embryo that has originated within a protoplanetary disc and which also has undergone internal melting to produce a differentiated interior.

Planetesimals are known to be small rock-type objects which are

formed by collisions with other objects present in the solar system.

Hence, the statements that describe the processes involved in the accretion of planetesimals and protoplanets are :

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The complete question is mentioned below:

Which statements describe processes involved in the accretion of planetesimals and protoplanets?

( I ) Both involve the melting of solid materials in the nebula.

( II ) Both involve the formation of solid particles from nebular materials.

( III ) Both involve the work of the gravitational push on nebular materials.

( IV ) Both involve the trapping of gases and the clumping of masses of matter.

( V ) Both involve the growing of gas grains with the addition of atoms and molecules.