Insurance Underwriters have established that the probability of city experiencing disasters in the next five years is 0.3 for a Tornado, 0.4 for Hurricane, and 0.1 for both Tornado and Hurricane. A) What is the probability of city experiencing only a Tornado in the next five years?B) What is the probability of city experiencing neither a Tornado nor Hurricane in the next five years?

Answer:

The first one matches with f(x)√x because a square root cannot be negative

The second one matches with f(x)=√(x-5) because the square root would be negative if it were less than five.

The third one matches with f(x)=8x because there is nothing that makes it a not possible answer

The last one matches with 7/(x-8) because there cannot be a denominator of zero.

Answer:

B. (f + g)(x) = x - 7

Step-by-step explanation:

→Set it up, like so:

-3x - 5 + 4x - 2

→Add like terms (-3x and 4x, -5 and -2):

x - 7

Answer:

LCM = 75

Step-by-step explanation:

1: Multiply the factor by the greatest number

Description:

The least common  multiple for 75,5,3 is 75.

LCM= Least common Multiple

Please mark brainliest

Hope this helps.

Answer:

75

Step-by-step explanation:

Break each number into prime factors

75 = 25*3 = 5*5*3

5 = 5*1

3 = 3*1

Multiply by the greatest number of each factor

3 = 1 time

5 = =2 times

The least common multiple = 3 * 5*5 = 75

Answer:

The number of female faculty in the Department with a PhD is 8.

Step-by-step explanation:

There are 14 + 30 = 44 faculty members.

Of those, x are male and y are female.

Then

x + y = 44.

The number of female faculty who do not have a PhD is 10 more than the number of females who have a PhD.

y = z + w

z is the number of females with PhD.

w is the number of females without PhD.

w = z + 10

If a third of the male faculty in the Department have a PhD

[tex]\frac{x}{3} + z = 14[/tex]

Now, we can write all variables as functions of z, which is the number of female faculty in the Department with PhD.

The objective is:

To find z from the first equation, that is:

[tex]x + y = 44[/tex]

To do this, we have to write x and y as functions of z.

Writing x and y as functions z.

[tex]\frac{x}{3} + z = 14[/tex]

[tex]\frac{x}{3} = 14 - x[/tex]

[tex]x = 3(14 - z)[/tex]

[tex]x = 42 - 3z[/tex]

And

[tex]y = z + w[/tex]

In which

[tex]w = 10 + z[/tex]

So

[tex]y = z + 10 + z[/tex]

[tex]y = 2z + 10[/tex]

Replacing:

[tex]x + y = 44[/tex]

[tex]42 - 3z + 2z + 10 = 44[/tex]

[tex]-z + 52 = 44[/tex]

[tex]z = 52 - 44[/tex]

[tex]z = 8[/tex]

The number of female faculty in the Department with a PhD is 8.

Step-by-step explanation:

10 more than 178.25 is add so

178.25 + 10 = 188.25

Answer:

  1/12

Step-by-step explanation:

  blue = (3/8)collection

  blue&pocket = (2/9)blue = (2/9)(3/8)collection

  blue&pocket = (6/72)collection = (1/12)collection

1/12 of Noah's collection is blue and has a pocket.

Answer:

x= 0, 2, -6

Hope this helps!

Answer:

[tex]r=25.7\%[/tex] will ensure that accumulated amount at the end of one year is 1.5 times more than amount invested

Step-by-step explanation:

Given: An amount was invested at r% per quarter.

To find: value of r such that accumulated amount at the end of one year is 1.5 times more than amount invested

Solution:

Let P denotes amount invested and n denotes time

As an amount (A) was invested at r% per quarter,

[tex]A=P\left ( 1+\frac{r}{400} \right )^{4n}[/tex]

According to question, accumulated amount at the end of one year is 1.5 times more than amount invested.

So,

[tex]A=1.5P+P=2.5P\\A=2.5P\\P\left ( 1+\frac{r}{400} \right )^{4n}=2.5P[/tex]

Put n = 1

[tex]P\left ( 1+\frac{r}{400} \right )^{4}=2.5P\\\left ( 1+\frac{r}{400} \right )^{4}=2.5\\1+\frac{r}{400} =(2.5)^{\frac{1}{4}}\\\frac{r}{100}=(2.5)^{\frac{1}{4}}-1\\r=100\left [ (2.5)^{\frac{1}{4}}-1 \right ]\\=25.7\%[/tex]

Answer: itz 605

Step-by-step explanation:

Answer:

I'm not sure if Leila is allowed to run 0 laps.

6 ≤ t ≤ 48

Step-by-step explanation:

To find the number of possible laps, you just find the smallest possible number and the largest.

1 = smallest

8 = largest

But, you have to multiply by 6 to find the time.

6 ≤ t ≤ 48

Answer:

B

Step-by-step explanation:

The triangular prism must have a larger base than the cylinder

Answer:

12 45

Step-by-step explanation:

plane leaves London at 09 35

plane arrives in Los Angeles after 11 hrs and 10 min

considering time difference:

local arrival time:

Answer:

see below

Step-by-step explanation:

[tex]\frac{x-c}{d} > y[/tex]

x - c > dy

x > dy + c

Answer:

C. Parameter since the data set of all 14 teams is a population.

Explanation:

Find the attachment

Answer:

Option (B).

Step-by-step explanation:

From the table shown in the figure attached,

There is a common difference of 5 in every successive and previous term, so the relation is a linear relation.

Let the equation representing the relation is,

y - y' = m(x - x')

where m = slope of the line

Now we choose two ordered pairs from the table,

Let the points are (10, 54) and (11, 59)

Slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

      m = [tex]\frac{59-54}{11-10}[/tex]

      m = 5

Now the equation of of the line passing through (10, 54) and slope = 5

y - 54 = 5(x - 10)

y - 54 = 5x - 50

y = 5x - 50 + 54

y = 5x + 4

By substituting the values of x and y from the ordered pairs given in the options we find option B satisfies the equation.

For (2, 14),

14 = 5×2 + 4

14 =  14 [True]

For (3, 19),

19 = 5×3 + 4

19 = 19 [True]

Therefore, option (B) will be the answer.

Answer:

c. 7.25

Step-by-step explanation:

Given the following information from an experiment:

[tex]\left\begin{array}{ccc}&$Sample Size&$Sample Mean \\$Treatment 1&5&4\\$Treatment 2&10&8\\$Treatment 3&5&9\end{array}\right[/tex]

Total Sample Size =5+10+5=20

Therefore, the overall mean

[tex]=\dfrac{(5 \times 4)+ (10 \times 8) + (5 \times 9)}{20} \\=\dfrac{145}{20}\\\\=7.25[/tex]

Answer:

The answer is 3.01 x 10’23

Step-by-step explanation:

I got the answer to wrong and guessed the first one and it was correct

Answer:

x > 1

Step-by-step explanation:

Add 7 to both sides

x > 1

Answer:

Step-by-step explanation:

[tex]r^{-7} +s^{-12} \\Use Negative Power Rule: x^{-a} =\frac{1}{x^{a} } \\r^{\frac{1}{7} } +s^{\frac{1}{12} } \\[/tex]

I hope i am correct

Answer:

1. B

Step-by-step explanation:

1. We are testing against the null hypothesis which is a single mean that sauce the average load is 0.8A

2. The level of significance is 1% (99% confidence interval)

3. The null hypothesis: u = 0.8

Alternative hypothesis: u =/ 0.8

4. a. The Student's t, since we assume that x has a normal distribution with known σ

5. Using the formula t = (x - u) / σ√n

Where x = 1.22 u = 0.8 σ = 0.44 n = 9

t = (1.22-0.8) / 0.44√9

t = 0.42/(0.44x3)

t = 0.42/1.32

t = 0.318

P value for 0.318 at 1% level of significance at 8 degree of freedom is 0.7586. Since our p value here is greater than 0.01, we can convince that there is not enough statistical evidence that indicate that the Toylot claim of 0.8 A is too low.

Answer:

Classifications would include

Rational; Fraction; Can be turned into Decimal; Positive

Those would be classifications

Answer: rational number, 0.375

Step-by-step explanation:

Answer:

The mean number of bags that arrive on time to its intended destination is 1260 with a standard deviation of 21.59.

Step-by-step explanation:

For each bag, there are only two possible outcomes. Either it arrives on time to it's intended destination, or it does not. The probability of a bag arriving on time is independent of other bags. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

[tex]E(X) = np[/tex]

The standard deviation of the binomial distribution is:

[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]

Luggage checked-in at Airline A arrives on time to its intended destination with a probability of 0.63.

This means that [tex]p = 0.63[/tex]

In a random sample of 2000 bags

This means that [tex]n = 2000[/tex]

Mean and standard deviation of the number of bags that arrive on time to its intended destination:

[tex]E(X) = np = 2000*0.63 = 1260[/tex]

[tex]\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{2000*0.63*0.37} = 21.59[/tex]

The mean number of bags that arrive on time to its intended destination is 1260 with a standard deviation of 21.59.

Answer:

8 units.

Step-by-step explanation:

The smaller of the right triangles formed is similar to the whole triangle so

4/x = x/16   where  x = the shorter leg

x^2 = 64

x = 8.

The length of the shorter leg of the right triangle is 3 units.

Let's denote the length of the shorter leg of the right triangle as "x." Since the altitude drawn to the hypotenuse divides it into segments of lengths 4 and 12, we can set up a proportion between the two triangles formed.

According to the similarity of triangles, the length of the shorter leg to the length of the segment of the hypotenuse it divides is the same as the length of the longer leg to the length of the other segment of the hypotenuse.

So, we can set up the proportion:

x / 4 = 12 / (hypotenuse length).

Now, we know that the hypotenuse length is equal to the sum of the two segments (4 + 12 = 16). We can substitute it into the proportion:

x / 4 = 12 / 16.

Now, cross-multiply and solve for x:

16x = 4 * 12,

16x = 48,

x = 48 / 16,

x = 3.

To learn more about triangle click on,

https://brainly.com/question/30847435

#SPJ2

Answer:

32

Step-by-step explanation:

r:m

2:14

1:7

m=224

r=224 divided by 7

224/7=32

Edit: unless it is proportional to r^2 in which case it is a different answer

Answer:

m=504

Step-by-step explanation:

Answer:

Step-by-step explanation:

Hello!

There are two values of n in the text, I'll use the one that appears in all the questions.

The variable of interest is

X: pollutants found in waterways near large cities. (ppm)

This variable has a normal distribution with parameters μ= 9ppm and σ= 1.5ppm

1) X~N(μ;σ²)

X~N(9;2.25)

2) The distribution of the sample mean is X~N(μ;σ²/n)

σ²/n= 2.25/37= 0.06

X~N(9;0.06)

3) P(X>9.6)

To calculate this probability you have to use the standard normal distribution. Using the population parameters, you can calculate the corresponding Z value:

Z= (X-μ)/σ= (9.6-9)/1.5= 0.4

P(Z>0.4)= 1-P(Z≤0.4)= 1 - 0.65542= 0.34458

The probability of selecting a city at random and finding 9.6ppm pollutants.

4) In this item, instead of calculating the probability of one value of the variable you have to calculate the probability of the sample average taking a determined value. Because of this, you have to work using the distribution of the sample mean, instead of the distribution of the variable.

P(X[bar]>9.6)

Z= (X[bar]-μ)/(σ/√n)= (9.6-9)/√0.06= 2.45

P(Z>2.45)= 1 - P(Z≤2.45)= 1 - 0.99286= 0.00714

5) The assumption of a normal distribution is not necessary for item 4. Since the sample size is large enough (greater than 30) you can apply the central limit theorem and approximate the distribution of the sample mean to normal, regarding the distribution of the original variable.

6)

In this case, you have to work starting with the standard normal distribution and then "translate" the Z values into values of the average amount of pollutants.

The first quartile divides the bottom 25% of the distribution from the top 75%, symbolically:

P(Z≤z₁)= 0.25

z₁= -0.674

z₁= (X[bar]-μ)/(σ/√n)

z₁*(√n/σ)=X[bar]-μ

X[bar]=z₁*(√n/σ)+μ

X[bar]=(-0.674)*(√37/1.5)+9= 6.27ppm

The third quartile divides the bottom 75% of the distribution from the top 25%, symbolically:

P(Z≤z₂)= 0.75

z₂= 0.674

z₂= (X[bar]-μ)/(σ/√n)

z₂*(√n/σ)=X[bar]-μ

X[bar]=z₂*(√n/σ)+μ

X[bar]=(0.674)*(√37/1.5)+9= 11.7.3ppm

IQR= Q₃-Q₁= 11.73-6.27= 5.46ppm

I hope this helps!

Answer:

p-value (0.0208) is less than alpha = 0.05 reject H0.

Step-by-step explanation:

we have the following data:

sample size = n = 75

x, the number to evaluate is 45

the sample proportion would be: x / n = 45/75

p * = 0.6

Now, the null and alternative hypotheses are:

H0: P = 0.72

Ha: P no 72

two tailed test

statistic tes = z = (p * - p) / [(p * (1-p) / n)] ^ (1/2)

replacing we have:

z = (0.6 - 0.72) / [(0.72 * (1-0.72) / 75)] ^ (1/2)

z = -2.31

p-vaule = 2 * p (z <-2.31)

using z table, we get:

p-vaule = 2 * (0.0104)

p-vaule = 0.0208

Therefore, p-value (0.0208) is less than alpha = 0.05 reject H0.

Answer: Options B and D.

Step-by-step explanation:

We start with the equation:

(-2 3/7)*(-6/11)

now, you need to recall the signs relations:

(+)*(+) = +

(-)*(+) = -

(-)*(-) = +

Then our initial equation has a positive sign.

a)  (3/8)*(-6/7) here we have (+)*(-), so this is negative, this option is not correct.

b) (1 2/9)*(2 16/17) here we have (+)*(+), so this is positive, this option is correct.

c)  (-9/20)*(3 4/5) here we have (-)*(+), so this is negative, this option is not correct.

d) (-1/3)*(-2/3) here we have (-)*(-), so this is positive, then this option is correct.

Answer:

The awnser is B and D

Step-by-step explanation:

Answer:

1

Step-by-step explanation:

divide vertical drop by horizontal drop

or vertical increase by horizontal increase

for example, in the graph when y increases by 1 x increases by 1

1/1=1 and thus the gradient is 1

the whole equation is y=x+3

Answer:

The slope = 1.

Step-by-step explanation:

If we count squares down for the top arrow then left to the point where the line cuts the horizontal axis we get 10 and 10.

So the slope = 10/10 = 1.

Answer:

D = 0 , Dx = 4 , Dy = -6 , Dz = 2

Step-by-step explanation:

As per cramer's rule,

D = |   7    6    4  |  = 0

      |   3    3    3  |

      |   4    4    4  |

Dx =  |  10    6    4  | = 4

        |   1    3    3    |

        |   2    4    4   |

Dy = |   7    10    4  | = -6

       |   3    1     3   |

       |   4    2    4   |

Dz =  |  7    6    10 | = 2

        |   3    3    1   |

        |   4    4    2  |