Isra is analyzing the properties of several samples of elements to find out which sample is a metalloid. Which set of properties most likely belongs only to a metalloid?

N-Pentane has a higher boiling point than the other three elements

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n-Pentane and 2,2-Dimethylpropane are isomers of one another and have the same chemical formula. Only London dispersion forces (LDFs), the smallest intermolecular forces, exist between the two molecules. The connectedness of the carbon skeleton accounts for the variation in their boiling points. While 2,2-dimethylpropane is a branching hydrocarbon, n-pentane is a straight hydrocarbon. Because of the n-linear pentane's shape, which results in greater surface areas between molecules, there are more LDFs between the molecules. N-Pentane has a higher boiling point as a result.

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Complete Question

Rank the following compounds in terms by increasing boiling point, starting with the lowest boiling point first. I. 1-pentanol II. n-pentane III. 2,2-dimethylpropane IV. (R)-4-hydroxypentanoic acid.

Pi bonds, on the other hand, are ties between p-orbitals on nearby atoms. The two pi bonds in an alkyne are also perpendicular since the p-orbitals are by definition parallel to one another.

Alkynes are defined as molecules with a triple bond between two carbon atoms. One bond and two bonds combine to form the triple bond.

Alkynes are hydrocarbons that have triple bonds between carbon atoms. When it comes to molecules with one triple bond, their usual formula is CnH2n-2 (and no rings).

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The atomic mass of Indium obtained is 60.544 g

For every 1g of Oxygen  4.784 g of Indium Oxide

Atomic mass of oxygen, O2 = 16.00 g

Now,

For Indium Oxide,

Mass of oxygen present = 3*16.00 = 48.00 g

Mass of Indium Oxide = 4.784 g * 48.00 g = 229.632 g

Let atomic mass of Indium

Mass of Indium Oxide = 2*M  + 3* 16.00 g

229.632 g = 2 * M + 48.00 g

2 M = 181.632 g

M = 181.632 g / 2

M = 90.816 g

For InO

Mass of oxygen present = 1* 16.00 g = 16.00 g

Mass of InO = 4.784 g * 16.00 g = 76.544 g

Let the atomic mass of Indium = M

Mass of InO = M * 1 g + 1*16.00 g

76.544 g = M + 16.00 g

M = 60.544 g

Hence the value obtained is 60.544 g

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The approximate bond angles for the given molecules are as follows:

The bond angle of h2s is 92.1°.

The bond angle of SF2  is 98º.

The bond angle of ChCl3 is 109.5º.

The bond angle of Cf4 is 109.5º.

In an molecule, the angle formed between orbitals which contains bonding electrons pairs around the central atom is known as bond angle.

The geometry of a molecule or a compound depends on the bond angles.  It is always expressed in degrees.

For example, if a compound has an angle of 180°, it would have linear shape like in the case of CO2. It has a bong angle of 180° and its shape is linear.

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The percent yield is given by the division of the actual yield and theoretical yield. The percent yield methanol (CH₃OH) compound is calculated to be 81.57%.

The percent yield is the reaction yield that is estimated by the actual and the theoretical yield that is never greater than 100% and has been the ratio of the actual to the theoretical yield multiplied by 100.

The percent yield is given as:

Percent yield =  actual yield ÷  theoretical yield × 100%

Given,

Theoretical yield = 407 gram

Actual yield = 332 grams

Substituting values as:

Percent yield = 332 ÷ 407 × 100%

= 81.57 %

Therefore, the percent yield is 81.57%.

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Answer: milliliter

Explanation: Generally, the unit used to measure liquid are liter (L) and milliliter (mL). But the volume of liquid in a can of Coca-Cola is commonly measured in mL. Therefore, the correct answer is option b.

Answer:MILLMETER

Explanation:

Answer:

A) 4 and 3

Explanation:

You don't count the scientific notations in his problem sine they are only trailing zeros which they don't count as sig figs so look at the original numbers. Remember that zeros after decimal points or in-between natural numbers count with that said 2.020 has 4 sig figs and 5.00 has 3 sig figs

Uranium is the element which could not form in the sun and would have to be formed in a supernova

With an atomic number of 92, uranium is a metallic chemical element in the periodic table that is silvery-white. The chemical symbol for it is U. There are 92 protons and 92 electrons in an atom of uranium, of which 6 are valence electrons. The atomic weight of uranium is the greatest among all naturally occurring elements.

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Chemical splash goggles or face shields should be worn when there is a risk of splashing hazardous materials or flying particles.

Put on this protective gear before dealing with hazardous chemicals in a lab to protect your face and eyes.

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If a mixture of 0.0333 g of hydrogen and 0.0165 mol of oxygen in a closed container is sparked to initiate a reaction. 0.2976 grams of water will be formed.

If the hydrogen reacted has a mass of 0.0333 g. then

Molar mass = m / n

2.016 g/mol = 0.0333 g / n

n = 0.01651785714 mol [tex]H_{2}[/tex]

According to the actual reaction to make water:

[tex]2H_{2} +O_{2} = 2H_{2}O[/tex]

To produce two molecules of water ([tex]H_{2}O[/tex]), two molecules of diatomic hydrogen ([tex]H_{2}[/tex]) must be combined with one molecule of diatomic oxygen ([tex]O_{2}[/tex]) and energy will be released in the process. And to complete the process, one from the reactant side must be in equilibrium with the other or in excess.

If the number of moles of 0.0333 g of [tex]H_{2}[/tex] is 0.0165, then it only needs 0.00826 mol of [tex]O_{2}[/tex] to form 0.0165 mol of water. (oxygen is in excess)

[tex]n_{H_{2} } : n_{O_{2} } :n_{H_{2}O } =[/tex] 2 : 1 : 2

= 0.0165 : 0.00826 : 0.0165

If the water produced is 0.0165 mol, then its mass is:

Molar mass = m / n

18.01528 g/mol = m / 0.01651785714 mol

m = 0.2975738214 g

m = 0.2976 g

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A histogram is a chart that shows the spread of data, which allows us to see outliers and the best number that fits with the data (Option D).

A histogram is a diagram used to show the relationships between two different variables, which is represented by rectangles that indicate a specified amount of a given parameter in the representation.

In conclusion, a histogram is a chart that shows the spread of data, which allows us to see outliers and the best number that fits with the data (Option D).

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Answer:

ANSWER :: (DENSITY OF OIL IS --0.8/CM²) .

(DENSITY OF MERCURY IS --- 13.69/CM²) .

Assuming histidine residues as uncharged, the total charge of the Histone octamer at pH 7 is +146.

Histone H2A has a total of 26 positively charged residues (Arg + Lys) and 9 negatively charged residues (Asp + Glu).

The net charge is 26 – 9 = + 17

Histone H2B has a total of 28 positively charged residues (Arg + Lys) and 10 negatively charged residues (Asp + Glu).

The net charge is 28 – 10 = + 18

Histone H3 has a total of 31 positively charged residues (Arg + Lys) and 11 negatively charged residues (Asp + Glu).

The net charge is 31 – 11 = + 20

Histone H4 has a total of 25 positively charged residues (Arg + Lys) and 7 negatively charged residues (Asp + Glu).

The net charge is 25 – 7 = + 18

The histone octamer's overall charge is equal to 2 x (17 + 18 + 20 + 18) = +146.

The complete question is:

Based on the amino acid sequences of each histone, estimate the charge of a histone octamer at pH 7. Assume that histidine residues are uncharged at this pH.

Histone H2A

M S G R G K Q G G K A R A K A K T R S S R A G L Q F P V G R V H R L L R K G N Y S E R V G A G A P V Y L A A V L E Y L T A E I L E L A G N A A R D N K K T R I I P R H L Q L A I R N D E E L N K L L G R V T I A Q G G V L P N I Q A V L L P K K T E S H H K A K G K

Histone H2B

M P E P A K S A P A P K K G S K K A V T K A Q K K D G K K R K R S R K E S Y S V Y V Y K V L K Q V H P D T G I S S K A M G I M N S F V N D I F E R I A G E A S R L A H Y N K R S T I T S R E I Q T A V R L L L P G E L A K H A V S E G T K A V T K Y T S S K

Histone H3

M A R T K Q T A R K S T G G K A P R K Q L A T K A A R K S A P S T G G V K K P H R Y R P G T V A L R E I R R Y Q K S T E L L I R K L P F Q R L V R E I A Q D F K T D L R F Q S A A I G A L Q E A S E A Y L V G L F E D T N L C A I H A K R V T I M P K D I Q L A R R I R G E R A

Histone H4

M S G R G K G G K G L G K G G A K R H R K V L R D N I Q G I T K P A I R R L A R R G G V K R I S G L I Y E E T R G V L K V F L E N V I R D A V T Y T E H A K R K T V T A M D V V Y A L K R Q G R T L Y G F G G

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The relationship between the volume and the mass of the object is shown by option A.

Density gives the ratio of the mass to the volume of an object. We know that volume is an intrinsic property. This implies that it does not change with the amount of the substance. It can be used to identify a given substance because it does not change with the mass or the quantity of the substance present.

It is possible to see that the relationship between the volume and the mass of the object. This relationship is based on the density of the object that is under consideration. The first question that we would have to ask is if the volume changes with the mass of the object.

Given the fact that we have established that the ratio of the mass to the volume of a body is always a constant, we can conclude that the mass does not undergo any change with the volume of the object.

We can conclude that the relationship between the volume and the mass of the object is shown by option A.

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Answer:b

Explanation: Edge 22

The Dilution of a buffer solution with a small amount of water will raise the PH of the solution. Dilution is the process of "reducing the concentration of a solute in a solution by simply adding more solvent to the solution, such as water." Dilution involves increasing the amount of solvent in a solution without increasing the amount of solute.

When a solvent is added, the concentration of the solute in the solution is diluted. By removing the solvent, concentration raises the solute concentration in the solution. Dilution is the process of lowering a given solute's concentration in its solution.

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[tex]2CO + O_{2} ---- > 2CO_{2}\\2Na + 2H_{2} O---- > 2NaOH + H_{2} \\2P + 3Cl_{2} ------ > 2PCl_3} \\Pb_{3} O_{4} +HNO_{3} ------ > 2Pb(NO3)_{2} + H_{2} O + PbO_{2}[/tex]

A reaction equation is a representation of the reaction that takes place in the reaction vessel. We know that a reaction equation is balanced when the number of atoms of each of the elements is the same on both sides of the reaction equation.

We can achieve the balancing of the reaction equations by the process of an atom count. We try to find out if we have the same number of atoms on both sides of the reaction equation by carrying out a literal counting of the atoms.

Let us now attempt to write the balanced reaction equation in each case;

[tex]2CO + O_{2} ---- > 2CO_{2}\\2Na + 2H_{2} O---- > 2NaOH + H_{2} \\2P + 3Cl_{2} ------ > 2PCl_3} \\Pb_{3} O_{4} +HNO_{3} ------ > 2Pb(NO3)_{2} + H_{2} O + PbO_{2}[/tex]

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The earliest nebulae to form in the universe were made almost of Hydrogen and Helium.

The first atmosphere on Earth, 4.6 billion years ago, was most likely made up of Hydrogen and Helium. These are the two most prevalent gases in the universe. Several other gases were infused into the atmosphere as a result of outgassing or the upsurge of vapors from the Earth's core.

Planetary outgassing, comet collisions, and volcanic eruptions formed the Earth's first atmosphere. Helium and Hydrogen in the early Earth's crust were heated up and managed to escape the gravity of the Earth, only for the solar wind to blow them away.

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Answer:

P= [tex]\frac{M}{V}[/tex]

Explanation:

While Separating sand and salt by filtration and evaporation, the observation is during the filtration the sand gets accumulated in the filter paper while separating it from the salt solution, while in evaporation the salt gets accumulated.

When we tried to separate the individual components from the mixture of the salt and sand the first step is dissolving the mixture in water as the salt gets dissolved so it is easy for us to filter the sand from the solution, it is followed by the method of evaporation, in which the filtered salt solution is boiled until the water gets evaporated and we are left with the salt,  that's how salt and sand are separated from a mixture.

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The percent by mass of mercury in mercuric oxide is

93 %.

The molecular formula of mercuric oxide is HgO. Mercury is liquid at room temperature and readily combines with oxygen to form mercuric oxide. Mercury is represented by the symbol Hg. The mass percent is defined as the ratio of the mass of the reactant to the mass of the product into 100. When mercuric oxide undergoes decomposition, it gives mercury and oxygen. And this reaction is endothermic.

The balanced equation for the reaction of mercury oxide is,

[tex]2HgO (s)→ 2Hg (l) + O _{2}(g)[/tex]

Mass of mercury oxide = 28.4 g

Mass of the oxygen = 2 g

The percent by mass of mercury in mercury oxide is,

[tex]Mass ℅= \frac{Mass \: of \: Mercury }{Mass \: of \: Mercury \: oxide} \times 100[/tex]

[tex]= \frac{28.4 - 2}{28.4} \times 100[/tex]

= 93 %

Therefore, the percent by mass of mercury in mercury oxide is 93 %.

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Answer:

On July 4, 1776—the day the Declaration of Independence was approved by the Second Continental Congress—the prevailing mood was trepidation and fear.

Explanation:

Answer:

the number in front of the chemical

Explanation:

example: 4c is 4 carbon 4 os the coefficient of c

The liquid poured into the graduated cylinder has a specific weight, density, and specific gravity of 22,222.22 N/m3, 2,265.26 kg/m3, and 2.26526, respectively.

Given: weight = 10 N  and volume = 450 mL or 0.450 L

The specific weight of a substance is defined as its weight per unit volume or density of a substance multiplied to the acceleration of gravity. To obtain a specific weight with units of N/m3, we will be converting the volume from L to m3.

Specific weight = 10 N / 0.450 L = 22.22 N/L

Specific weight = (22.22 N/L) * (1000 L/ 1 m3) = 22,222.22 N/m3

The density can be determined by dividing specific weight by the acceleration of gravity.

Density = Specific Weight / gravity

Density = 22,222.22 N/m3 / 9.81 m/s2

Density = 2,265.26 kg/m3

Specific gravity is a dimensionless quantity of the ratio of the density of a substance to the density of water. The density of water that will be used is 1000 kg/m3.

Specific gravity = Density of substance / Density of water

Specific gravity = 2,265.26 kg/m3 / 1000 kg/m3

Specific gravity = 2.26526

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Correct order of the following elements in order of decreasing atomic radius are as follow N>F>Na>Cl

Atomic radius is the distance from atoms nucleus to the outer edge of the electron cloud. atomic radius decreases across a period and increases down the group across a period effective nuclear charge increases  as electron shielding remain constant. In this order nitrogen and Florine  are arranged in period from left to right and also sodium and chlorine are arranged in period from left to right. we move from left to right in a period atomic radius decreases.

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Various criteria can be used to categorize chemical substances. One such approach is based on the distinct components present.

All other chemicals are categorized as inorganic, and organic compounds are defined as those possessing a carbon atom backbone. Organometallic compounds are organic molecules bound to metal atoms, as their name suggests.

The sorts of bonds that a compound has served as the basis for another classification system for chemical compounds. Ions are present in ionic compounds, which are held together by the attraction interactions between the ions with opposing charges. One of the most well-known ionic compounds is table salt or sodium chloride.

Reactivity, or more specifically, the kinds of chemical reactions that the compounds are most likely to experience, is the basis of a third classification system.

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If copper (ii) chloride solution splashes on your skin while preparing the answer, you ought totell your teacher about the accident right away and use water to rinse the part of your skin that came in contact with the chemical.

 Copper Chloride (CuCl₂) is light brown solid which forms a blue green dihydrate solution on absorbing moisture.

From the above conclusion we can say that, If copper (ii) chloride solution splashes on your skin while preparing the solution, you should tell your teacher about the accident right away and use water to rinse the part of your skin that came in contact with the chemical.

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A system of two atoms, each having only 3 quantum states of energies 0, e and 2s. The system is in contact with a heat reservoir at temperature T.

The quantum state of a particle is defined by the values of its quantum numbers, so what this implies is that no two electrons within the same atom can have the identical set of quantum numbers.

In natural philosophy, a quantum state may be a mathematical entity that gives a probability distribution for the outcomes of every possible measurement on a system. Knowledge of the quantum state along with the foundations for the system's evolution in time exhausts all which will be predicted about the system's behavior.

For example, the spin of an isolated electron can tackle one amongst only two values; there aren't any other quantum states available for the electron and no intermediate values, since spin is quantized . As a physical parameter is varied, quantum fluctuations can drive a natural action into a special phase of matter.

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Answer:

True

Explanation:

the time you plant crops matters alot. especially in times before pesticides and greenhouses.

Answer: False

Explanation:

People went by what the seasons were to find out what to grow. Calendars merely helped with remembering important dates like when is Halloween, when is president's day, etc..

The initial weight of mercury oxide in the sample was 59.1 g HgO.

chemical reaction

2HgO ⟶ 2Hg + O₂

the moles of O₂

pV = nRT

n = (pV)/(RT)

Data:

p = 0.970 atm

V = 4.50 L

R = 0.082 06 L·atm·K⁻¹mol⁻¹

T = 390.0 K

Calculation:

n = (0.970 × 4.500)/(0.082 06 × 390.0)

n = 0.1364 mol O₂

the moles of HgO

The molar ratio is 1 mol O₂/2 mol HgO.

Moles of HgO = 0.1364 mol O₂ × (2 mol Hg/1 mol O₂)

Moles of HgO = 0.2728 mol HgO

the mass of HgO

Mass of HgO = 0.2728 mol HgO × (216.59 g HgO/1 mol HgO)

Mass of HgO = 59.1 g HgO

For the creation of various organic mercury compounds and specific inorganic mercury salts, mercury(II) oxide, or HgO, serves as a source of elemental mercury.

This red or yellow crystalline substance is also utilised in mercury batteries and zinc-mercuric oxide electric cells as an electrode (combined with graphite).

Mercuric oxide is a colourless, crystalline powder that ranges from yellow to orange-yellow.

It serves as a seed protectant, a pigment, a preservative, and an ingredient in alkaline batteries and cosmetics.

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