It takes Santa a total distance of 1800 miles to cover a portion of his
Texas route, he does this in 3 hours, how fast is Santa moving? *
2400 mph
600 mph
350 mph
150 mph
please help!! hurry

Answer:

A=l×b

A=20×14

A=280

tan(90)=14/aq

aq×tan(90)=14/aq×as

aqtan(90)=14

aqtan(90)/tan(90)=14/tan(90)

aq=0.16

Answer:

2(6x²+11xy−4y²)

Step-by-step explanation:

Factor 12x²+22xy−8y²

12x+22xy−8y²

=2(6x²+11xy−4y²)

a) Positive b)   Degree per minute    c) Interpretation of f'(20)=2

So as we have we are given in the question: T = f(t)

where T is the temperature in degrees Fahrenheit of a cold yam placed in a hot oven and t is the time in minutes since the yam was put in the oven .f'(t) will represent the rate of change in temperature.

f'(t) will represent the change in temperature of yam when 1 minute has passed since it was kept in oven.

Since the temperature will always increase in oven, f'(t) will have a positive sign. units of f'(20)Since, f'(t) represent the rate of change in temperature. the unit will be degrees Fahrenheit per minute .f'(20)=2f'(20) will tell the change in temperature when 20 minutes have passed after the yam has been kept in oven .Thus, the given statement means that 20 minutes after the yam was kept for  in the oven, the temperature of yam was increasing by 2 degree Fahrenheit per minute.

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By using differential equations' concept, we get that there is no sugar in the beginning.

A differential equation is an equation that connects the derivatives of one or more unknown functions.

Given:

Pure water = 2840 litres

sugar = 0.01kg per liter

Rate of sugar entering the tank = 4liter/min

New solution drains out at the rate = 4 litre/min

To find: sugar in the beginning.

Finding:

(a) In the beginning, the tank contains only pure water and no solution of water with sugar.

Hence, the sugar is null for t = 0.

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x2 − 10x − 24 x 2 - 10 x - 24 this expression is equivalent to x² 10x 24 (x 1)(x 24) (x 4)(x 6)(x 2)(x 12)(x 3)(x 8).

A logarithmic articulation is a numerical expression that incorporates factors, constants, coefficients, and mathematical tasks. To increase two logarithmic articulations, we duplicate each term of the main articulation with each term of the subsequent articulation and join every one of the items. In a mathematical articulation, a term might comprise of a steady, one variable, a result of at least two factors, a result of both the variable and consistent part. Moreover, the mathematical terms can be both positive and negative. There are significantly three sorts of mathematical articulations.

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Answer: x = 36

Step-by-step explanation:

Solve for x by simplifying both sides of the equation, then isolating the variable.

x = 36

Step-by-step explanation:

1/4 (x-8) =7

times both sides by 4

x-8=28

add 8 to both sides

x=36

The required equation of the line is y = 43 which is parallel to line y = 16 and passes through the point at (-7, 43).

The slope of the line is defined as the angle of the line. It is denoted by m

Slope m = (y₂ - y₁)/(x₂ -x₁ )

Consider two points on a line—Point 1 and Point 2. Point 1 has coordinates (x₁,y₁) and Point 2 has coordinates (x₂, y₂)

First, we have to determine the slope of the line y = 16 by placing it into a slope-intercept form:

y = 16

Therefore, the slope of the line is m = 0

Since the required line passes through the point at (-7, 43).

Let the line  (y - y₁) = m(x -x₁  )

Here x₁ = -7, y₁ = 43

Substitute the values in the equation,

So, y - (43) = 0(x-(-7))

⇒ y - 43  = 0

⇒ y  = 43

Hence, the required equation of the line is y = 43 which is parallel to line y = 16 and passes through the point at (-7, 43).

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Answer:

it is which of the following is a reactant

Step-by-step explanation:

Based on the points obtained from Ali and Habib in the game we can say that:

a. The difference between their scores is: 38.812

b. The estimate is not enough to find the winner

To solve this problem we must perform the following algebraic operations with the given information

Information about the problem:

To calculate the difference between their scores we must perform the following subtraction:

Difference between their scores = Al's points - Habib's points

Difference between their scores = 43.901 - 5.089

Difference between their scores =38.812

Due to the difference between their scores is less than 40,000 points, it is not yet possible to define a winner.

We can say that they are the set of numbers and symbols that are related by the different mathematical operation signs such as addition, subtraction, multiplication, division among others.

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Since, the sides ab || dc, ad || bc, and ad || bc . hence, the given quadrilateral abc is a prallelogram.

According to the given question.

We have the vertices of a quadrilateral abcd such that a(1, 0), b(5, 0), c(7, 2) and d(3, 2).

As we know that, a parallelogram is a two-dimensional geometrical shape, whose sides are parallel to each other. It is a type of polygon having four sides (also called quadrilateral), where the pair of parallel sides are equal in length.

Since, we have to prove that the given quadrilateral is a parallelogram by using slope. From the definition of the parallelogram we can say that, the opposite sides of the parallelogram are parallel to each other.

Now,

slope of side ab = 0-0/(5 -1) = 0

slope of side dc = 2 -2/(3-7) = 0

slope of the side ad = 2 -0/(3 -1) = 1

slope of the side bc =  2 -0/(7 -5) = 1

Here, the slopes of the opposite sides ab and dc, and ad and bc are equals and we know that when the slope of two line are equals then the lines are parallel to each other.

Therefore,  the sides ab || dc, ad || bc, and ad || bc . hence, the given quadrilateral abc is a prallelogram.

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The set of inequalities that represents the constraints of the situation is y ≤ 2x, x + y ≥ 30 and a point (x, y) that is the feasible region is (10, 20)

The given parameters are:

Number of hours = at least 30 hours a week

This means that

x + y ≥ 30

Also, we have:

The number of hours Daniel works as a tutor (y) is at most twice the number he works as a teacher (x).

This means that

y ≤ 2x

Substitute y ≤ 2x in x + y ≥ 30

x + 2x ≥ 30

This gives

3x ≥ 30

Divide

x ≥ 10

Substitute x ≥ 10 in y ≤ 2x

y ≤ 2 x 10

Evaluate

y ≤ 20

Hence, the set of inequalities that represents the constraints of the situation is y ≤ 2x, x + y ≥ 30 and a point (x, y) that is the feasible region is (10, 20)

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Answer:

D

Step-by-step explanation:

It looks line you are asking for the slope.  The slope is the change in y over the change in x

Ordered pairs are writing in the from (x,y)  The first number is the x value and the second number is the y value.

[tex]\frac{0 - (-13)}{-8 - (-2)}[/tex]  I am subtracting the y's on the top and the x's on the bottom.

[tex]\frac{0 + 13}{-8 + 2}[/tex]  Subtracting a negative is the same as adding a positive.

[tex]\frac{13}{-6}[/tex]   The fraction is negative, so the negative sign can go on the top or the bottom.

Answer: D=(8,10) Y=(-2,6) N=(2,-6) U=(-8,-5) G=(8,-11) O=(4,-5)

Step-by-step explanation:

On the coordinate plane, left or down means decreasing in value and right or up means increasing in value.

if you take a point and it's at (1,2) and translate it 3 to the left and 4 upwards, your new point would be (-2,6). This is because you subtracted(cause you were going left) 3 from 1 (cause it's your x value), and added(cause you were going up) 4 to 2 (cause it's your y value.)

Answer:

[tex]f(3) = \frac{2}{5} [/tex]

Step-by-step explanation:

f(x) = 4/5x - 2

f(3)=4/5(3)−2

f(3)=4/5(3)−2

f(3)=12/5+−2

f(3)=(12/5+−2)(Combine Like Terms)

f(3)=2/5

The quadratic equation with a repeated root is:

8*x^2 - 32*x  +32

And the repeated root is x = 2

For a quadratic equation:

0 = a*x^2 + b*x + c

We define the discriminant as:

D = b^2 - 4ac

If D = 0, we have only one real root (or two repeated roots). Then we just need to see which of the given quadratic equations has a discriminant of zero.

1) -x^2 + 18x + 81

The discriminant is:

D = 18^2 - 4*(-1)*81 = 648

2) 3x^2 - 6x + 9

The discriminant is:

D = (-6)^2 - 4*3*9 = -72

3) 8*x^2 - 32*x  +32

The discriminant is:

D = (-32)^2 - 4*8*32 = 0

So this is the one with a discriminant of zero.

The roots are given by:

8*x^2 - 32*x  +32 = 0

Using Bhaskara's formula we will get:

x = (- (-32) ± √( (-32)^2 - 4*8*32))/(2*8)

x = (32/16) = 2

The repeated root is x = 2

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The difference of the algebraic expression is 2. 7m² - 4n² - 8. 2m

To represent the difference in standard form is leave in the power or exponent of a variable or number.

Given the expression

(2.7m^2 - 3.1n) - (4n^2 + 5.1m)

First, expand the brackets

2. 7m² - 3.1 m - 4n² - 5. 1m

Then, collect like terms

2. 7m² - 4n² - 3.1m - 5. 1m

Subtract like terms, we have

2. 7m² - 4n² - 8. 2m

The difference of the algebraic expression gives 2. 7m² - 4n² - 8. 2m

Thus, the difference of the algebraic expression is 2. 7m² - 4n² - 8. 2m

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Answer:

5

Step-by-step explanation:

If you put this in a calculator it comes back with 4.79583... decimals forever.  Rounding to the nearest integer gives 5.

Answer:

5

Step-by-step explanation:

√23 : 4.795831523 whose nearest integer is 5 .

Hence, the nearest number is 5.

Answer: -8 45/56

Step-by-step explanation:

Answer: the first table with all 2s as its y values

Step-by-step explanation: the first table shows that no matter what the x value is, the graph is staying still at y=2. Its rise/run is 0 since it is not rising at all.

Answer:

The first column of the first chart due to the repetition of the numbers! hope this helps!

Answer:

75

Step-by-step explanation:

Each placemat is .15 cents

500 x .15

The standard normal variable for 3.7 is 0.67.

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Answer:

1. true

2. false

3. false

4. true

Step-by-step explanation:

The force on the object will be 12 N.

We have a moving object.

We have to determine the force on object when the acceleration of the object becomes 2 m/s².

Force is necessary to bring around a change in the state of the body. Either from rest to motion or motion to rest. It can be calculated using the formula-

Force (F) = mass (m) x acceleration (a)

According to the question -

When a force of 42 N acts on the object, then using the formula of force -

F = m x a

42 = m x 7

m(Object) = 6 Kg

When the acceleration of the object becomes 2 m/s², then -

F = m(object) x a

F = 6 x 2 = 12 N

Hence, the force on the object will be 12 N.

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The change in the temperature is 11°.

Temperature is the physical quantity which describes, how much hot is something? Or we can say it is the quantity which measures the hotness and coldness of something. There are two main quantity values to measure the temperature which are Celsius and Fahrenheit.

Mathematically we can write :

1° Celsius = 32 Fahrenheit

Suppose if we have temperature of two difference time space then we can easily find the difference between the two by simply subtracting them.

For the given question,

last year temperature = 82 degree

temperature today = 71 degree

therefore the change in the temperature in one year is :

82 - 71 = 11 degree.

Thus , the change in temperature is 11 degree.

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The total kilowatt-hours of electricity used during these two years is (6.03 x 10^9)+(4.3 x 10^11) = (0.0603 x 10^11) + (4.3 x 10^11) = 4.3603 x 10^11 using arithmetic operations.

Addition is the sum of two or more numbers or values to get a new number. The addition symbol is the plus sign (+).

Multiplication is the repeated addition of a number. If we multiply m by n, that means m is repeatedly added to itself for n times. The symbol for multiplication is ‘×’.

Given that the use of electricity in the US in 1902 was 6. 03 x 10^9 kilowatt-hours and in 1950, it was 4. 3 x 10^11 kilowatt-hours.

To find the total kilowatt-hours of electricity used during these two years, we must add the kilowatt-hours of electricity used in 1902 and 1950.

6. 03 x 10^9 kilowatt-hours can also be written as 0.0603 x 10^11 kilowatt-hours.

This implies, (6.03 x 10^9) + (4.3 x 10^11) = (0.0603 x 10^11) + (4.3 x 10^11)

= (0.0603+4)10^11

= 4.3603 x 10^11 kilowatt-hours

Therefore, the total kilowatt-hours of electricity used during these two years is 4.3603 x 10^11.

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= (-54)

Step-by-step explanation:

ATQ

4+2(x+6)^2

6(x^2+12x+216)=0 [ {a+b}^2 = a^2+2ab+b^2 ]

6x^2 +72x+216=0

Put the value of x=(-3)

So ,

6x^2 +72x+36=0

6(-3)^2+72(-3)+216=0

6×(-9)+72×(-3)+216=0

(-54)+(-216)+216=0

= -54

Hence, the solution is -54 at x=(-3).

Thank You