Jillian picked coins from her piggy bank and recorded the number of coins in the table below.

Based on the results shown in the table, what is the probability that the coin Jillian picks will be a quarter

A..........

Step-by-step explanation:

Answer:

38º

Step-by-step explanation:

the angles that are across from each other like

are equal.

So, <6 = 38º (This is also because of the Vertical Angle Theorem / VAT)

Answer:

I think it's 4.5

Step-by-step explanation:

I divided the servings by the packages and I got 4.5 for each of them.

Answer:

t=40

Step-by-step explanation:

first, add 21 to -21=0

to keep it balanced add 21 to 19=40

so t=40

hope this helps

Answer:

the answer is 72 inches

Step-by-step explanation:

a²+b²=c²

a²+900=6084

a²=5184

a=72

Answer:

2.5cm

Step-by-step explanation:

area of trapezium = 4 * area of parallelogram

1/2(a+b)*h=4* bh

1/2(5+11)*4= 4* 3.2x

8*4=4*3.2x

8/3.2=x

2.5cm=x

Answer:

impossible

Step-by-step explanation:

the formula for triangle sides is a^2 + b^2 = c^2

and these numbers dont equal that

9514 1404 393

Answer:

  D)  (0, -5)

Step-by-step explanation:

A graphing calculator is helpful. It shows that the point (0, -5) is in the solution spaces of both inequalities.

__

If we consider only the case of x=0, then the solution space reduces to ...

  -8 < y ≤ 4 . . . . . the constants of the two inequalities

Here, it is easy to see that y=-5 is in the solution space.

  (0, -5) is a solution

Answer:

40

Step-by-step explanation:

Answer: 4.3

Step-by-step explanation:

11x2=22

22/3= 7.3

7.3-3= 4.3

Answer:

Area = [tex]x^{2} +2x+2[/tex]

Perimeter = [tex]4x+1[/tex]

Step-by-step explanation:

So the shape is made up of one [tex]x^{2}[/tex], two xs and two 1s

add that together you get [tex]x^{2} +2x+2[/tex]

Starting at the top left you have a side length of 1. Then it goes down 1 before an x. Then you have up 1 and over 1, which is 2. Going down the right side you have a 1 and an x. Then the bottom is 1, x, and 1. You go up another x and then 1 to meet back where you started.

In total that is [tex]4x+1[/tex]

Answer:

the P-value = 0.1977

conclusion: Since the p-value is not small;

we reject null hypothesis

hence, the data does not support claim that more than half of the bathroom scales underestimate weight.

Step-by-step explanation:

 Given the data in the question;

let X represent the number of successes ( the weight is underestimated ) in n independent Bernoulli trials, each with the success probability p

X - Bin( n,p).

so

Null hypothesis             H₀ : p ≤ 0.5

Alternative hypothesis Hₐ : p > 0.5

now, compute np₀ and n( 1 - p₀ )

np₀ = (50)(0.5)

np₀ = 25

n( 1-p₀ ) = (50)(1 - 0.5)

n( 1-p₀ ) = 25

we can see that both values are greater than 10.

∴ the sample proportion is approximately normally distributed;

P" - N ( p₀, [tex]\frac{p_{0}(1-p_0)}{n}[/tex] )

sample proportion p" = 28/50 = 0.56

standard deviation will be;

σ[tex]_{p"[/tex] = √( p₀(1-p₀) / n )

σ[tex]_{p"[/tex] = √( 0.5(1-0.5) / 50 )

σ[tex]_{p"[/tex] = √( 0.25 / 50 )

σ[tex]_{p"[/tex] = 0.07071

Next is the Z-score

z = p" - p₀ / σ[tex]_{p"[/tex]

z =  0.56-0.5 / 0.07071

z = 0.06 / 0.07071

z = 0.85

from table,

the probability that a standard normal random variable takes on a value greater than 0.85 is approximately 0.1977

Therefore, the P-value = 0.1977

conclusion: Since the p-value is not small;

we reject null hypothesis

hence, the data does not support claim that more than half of the bathroom scales underestimate weight.

p = 0.197663

Answer:60$

Step-by-step explanation:

Answer:

XX, YY, ZZ

Step-by-step explanation:

Answer: y=5x

Step-by-step explanation: Slope= 10/2=5 Plugged it in equation y=mx+b and solved for b to get b=0

Answer:

Three irrational numbers between 6 and 7 are

i )6.2020020002...

ii) 6.5010010001....

iii)6.9010010001.... etc.

•••♪

[tex] \huge\boxed{\mathfrak{Answer}}[/tex]

3 irrational numbers with a value between 6 & 7 can be :-

Answer:

exterior angle = the sum of two remote interior angles

14x + 1 = 89 + 5x - 7

=> 9x = 81

=> x = 9

substitute x = 9 into angle H (5x - 7)

=> 5(9) - 7 = 45 - 7 = 38

Answer: 3 1/3

Step-by-step explanation: You change 8 1/6 to improper fraction which is 49/6 and change 4 5/6 to improper fraction which is 29/6. Next you take 49/6 and subtract 29/6 which is 20/6.After that you simplify 20/6 by divide both sides by 2 which gives you 10/3.Lastly change 10/3 to a mixed number which is 3 1/3.

Hope it helps :) and look at pic below.

Answer:

I THINK the answer is ⊥, I'm really not confident on this one.

Answer:

They are perpendicular ⊥

Step-by-step explanation:

The full question with the answer options is as follows:

Each figure below represents a fraction. Which figure is NOT equivalent to the others?

the answer options are as follows:

a.  [tex]\frac{2}{3}[/tex]

b.  [tex]\frac{4}{6}[/tex]

c.  [tex]\frac{3}{4}[/tex]

d. [tex]\frac{8}{12}[/tex]

Answer:

The correct answer is c:

Step-by-step explanation:

To know when two or more fractions are equivalent, we must multiply the numerator of one fraction by the denominator of the other fraction, the result must be the same value.

[tex]\frac{2}{3} x \frac{4}{6}[/tex] =   (2x6) =12   ;  (3x4)=12

[tex]\frac{2}{3} x \frac{8}{12}[/tex] = (2x12)=24 ;    (3x8) =24

[tex]\frac{4}{6} x \frac{8}{12}[/tex] = (4x12)=48;     (6x8)=48

it is C

Step-by-step explanation:

i did the test

Answer:

The answer is actually B.

Step-by-step explanation:

I have an actual explanation to this! But I don't like dealing with pdfs, also typing it out will be a lot. Ik I am late, but to whomever else needs help that's the answer! Glad to help:)

Answer:

Alright but first

How is this 7th grade stuff?

I thoguh yall were doing algebra. But it kinda looks like it but here’s a brief explanation anyway.

If you dont know a vualure, use other surrounding it to help you sovle this final thingy. Like if its division, multiply. addditon, subtract. multiply, Davison. Just tdo inver properties on both sides and isolate the number that x in it Either be dividing or multiplying. When your left with a final value just solve, whatever thing that lies next to that equal sign is your answer.

2) 6

3) -36

4) 40

5) 9

6) -4

7) 63

8) -48

9) -5

10) -7

Answer:

[tex](a)\ g(x) = \frac{2}{3}(x+1)[/tex]

[tex](b)\ h(y) = \frac{1}{3}[1 + 4y][/tex]

[tex](c)[/tex] [tex]P(x>0.5) =\frac{5}{12}[/tex]

Step-by-step explanation:

Given

[tex]f(x,y) = \left \{ {{\frac{2}{3}(x+2y)\ \ 0\le x \le 1,\ 0\le y\le 1} \right.[/tex]

Solving (a): The marginal density of X

This is calculated as:

[tex]g(x) = \int\limits^{\infty}_{-\infty} {f(x,y)} \, dy[/tex]

[tex]g(x) = \int\limits^{1}_{0} {\frac{2}{3}(x + 2y)} \, dy[/tex]

[tex]g(x) = \frac{2}{3}\int\limits^{1}_{0} {(x + 2y)} \, dy[/tex]

Integrate

[tex]g(x) = \frac{2}{3}(xy+y^2)|\limits^{1}_{0}[/tex]

Substitute 1 and 0 for y

[tex]g(x) = \frac{2}{3}[(x*1+1^2) - (x*0 + 0^2)}[/tex]

[tex]g(x) = \frac{2}{3}[(x+1)}[/tex]

Solving (b): The marginal density of Y

This is calculated as:

[tex]h(y) = \int\limits^{\infty}_{-\infty} {f(x,y)} \, dx[/tex]

[tex]h(y) = \int\limits^{1}_{0} {\frac{2}{3}(x + 2y)} \, dx[/tex]

[tex]h(y) = \frac{2}{3}\int\limits^{1}_{0} {(x + 2y)} \, dx[/tex]

Integrate

[tex]h(y) = \frac{2}{3}(\frac{x^2}{2} + 2xy)|\limits^{1}_{0}[/tex]

Substitute 1 and 0 for x

[tex]h(y) = \frac{2}{3}[(\frac{1^2}{2} + 2y*1) - (\frac{0^2}{2} + 2y*0) ][/tex]

[tex]h(y) = \frac{2}{3}[(\frac{1}{2} + 2y)][/tex]

[tex]h(y) = \frac{1}{3}[1 + 4y][/tex]

Solving (c): The probability that the drive-through facility is busy less than one-half of the time.

This is represented as:

[tex]P(x>0.5)[/tex]

The solution is as follows:

[tex]P(x>0.5) = P(0\le x\le 0.5,0\le y\le 1)[/tex]

Represent as an integral

[tex]P(x>0.5) =\int\limits^1_0 \int\limits^{0.5}_0 {\frac{2}{3}(x + 2y)} \, dx dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 \int\limits^{0.5}_0 {(x + 2y)} \, dx dy[/tex]

Integrate w.r.t. x

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 (\frac{x^2}{2} + 2xy) |^{0.5}_0\, dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 [(\frac{0.5^2}{2} + 2*0.5y) -(\frac{0^2}{2} + 2*0y)], dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}\int\limits^1_0 (0.125 + y), dy[/tex]

[tex]P(x>0.5) =\frac{2}{3}(0.125y + \frac{y^2}{2})|^{1}_{0}[/tex]

[tex]P(x>0.5) =\frac{2}{3}[(0.125*1 + \frac{1^2}{2}) - (0.125*0 + \frac{0^2}{2})][/tex]

[tex]P(x>0.5) =\frac{2}{3}[(0.125 + \frac{1}{2})][/tex]

[tex]P(x>0.5) =\frac{2}{3}[(0.125 + 0.5][/tex]

[tex]P(x>0.5) =\frac{2}{3} * 0.625[/tex]

[tex]P(x>0.5) =\frac{2 * 0.625}{3}[/tex]

[tex]P(x>0.5) =\frac{1.25}{3}[/tex]

Express as a fraction, properly

[tex]P(x>0.5) =\frac{1.25*4}{3*4}[/tex]

[tex]P(x>0.5) =\frac{5}{12}[/tex]

Answer:

yessssssssss.........

Answer: 7.0 because you add 10 to - 3 it makes7.0

Step-by-step explanation: