Joe takes his dog to the local dog park every morning, too. He walks with his dog 5 blocks south, 5 blocks west, and 5 blocks north in order to get to the park. What is his total displacement?

Answer:

1The force is with u. Lol no Idea if this is correct sry if u fail. I go must now

The question is confusing for the initial direction of the green ball. We assume to the left.

Answer:

The mass of the green ball is 360 Kg

Explanation:

Law Of Conservation Of Linear Momentum

The total momentum of a system of bodies is conserved unless an external force is applied to it. The formula for the momentum of a body with mass m and velocity v is

P=mv.

If we have a system of bodies, then the total momentum is the sum of the individual momentums

[tex]P=m_1v_1+m_2v_2+...+m_nv_n[/tex]

If some collision occurs, the velocities change to v' and the final momentum is:

[tex]P'=m_1v'_1+m_2v'_2+...+m_nv'_n[/tex]

In a system of two masses, the law of conservation of linear momentum

is written as:

[tex]m_1v_1+m_2v_2=m_1v'_1+m_2v'_2[/tex]

Let's call m1=30 Kg the mass of the red ball moving to the right at v1=4 m/s, m2 (unknown) the mass of the green ball moving at v2=-5 m/s to the left (assumed).

After the collision, the red ball rolls to the left at v1'=-2 m/s and the green ball is at v2'=-4.5 m/s. Thus:

[tex]30*4+m_2*(-5)=30*(-2)+m_2(-4.5)[/tex]

Operating:

[tex]120-5m_2=-60-4.5m_2[/tex]

[tex]120+60=5m_2-4.5m_2[/tex]

[tex]180=0.5m_2[/tex]

[tex]m_2=180/0.5=360[/tex]

The mass of the green ball is 360 Kg

Answer:

damage to a house and trees posibly

Answer:

Which structural damage might be expected if a Category 1 hurricane is predicted to hit an area?

Responses

A high percentage of framed homes could be destroyed, with total roof failure and wall collapse.

A high percentage of framed homes could be destroyed, with total roof failure and wall collapse.

ANSWER : ( Well-constructed frame homes could have damage to the roof, shingles, and vinyl siding.

Explanation: i did the quiz it was easy

Answer:

False

Explanation:

The heating coil of a water heater has a resistance of 20 ω and operates at 210 v.  It takes 5 hrs to raise the it take to raise the temperature of 200 kg of water from 15oc to 80oc.

Obstruction is a proportion of the resistance to flow stream in an electrical circuit. Opposition is estimated in ohms, represented by the Greek letter omega (Ω). Ohms are named after Georg Simon Ohm (1784-1854), a German physicist who concentrated on the connection between voltage, current and opposition. In any case, obstruction and conductance are broad as opposed to mass properties, implying that they additionally rely upon the size and state of an item. Channels permit the free progression of power. Yet, in materials, for example, semiconductors and covers, the power encounters a specific power that goes against the free progression of electrons.

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The total Earth's magnetic field is 56 μT.

The magnetic influence on moving magnetic materials, electric charges, and electric currents is described by a magnetic field, which is a vector field. A force acting on a charge while it travels through a magnetic field is perpendicular to both the velocity and the magnetic field.

The axis of a circular coil with five turns and a diameter of D = 30.0 cm, oriented vertically, is perpendicular to the horizontal component of the Earth's magnetic field.

When positioned in the coil's center, a horizontal compass deviates 45.0° from magnetic north due to a coil current of I = 0.600 A.

Now, the current is switched off.

The dip needle makes an angle of Φ = 13.0°.

Let B be the magnetic field and R be the radius of the circular coil.

Then the total magnitude of the Earth's magnetic field will be:

B(h) = B sin Ф

B = B(h) / sin Ф

B = ( 12.6 μT ) / ( sin 13.0° )

B = 56 μT

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Answer:

I=V/R

Explanation:

Ohm's law gives the mathematical relationship between, current, voltage and the resistance of the circuit. Its mathematical form is given by :

V = IR ....(1)

V = voltage (in volts)

I = current (in Ampere)

R = resistance (in ohms)

Equation (1) can be rewritten as :

[tex]I=\dfrac{V}{R}[/tex]

Hence, the correct relation is I=V/R.

Given that,

Mass of magnesium, m = 2 kg

Heat added to it, Q = 8160 J

Increase in temperature, [tex]\Delta T=4\ K[/tex]

To find,

The specific heat of magnesium.

Solution,

Th formula that is used to find the heat required to raise the temperature in terms of specific heat is given by :

[tex]Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{8160\ J}{2\ kg\times 2\ K}\\\\c=2040\ J/kg-K[/tex]

So, the specific heat of magnesium is [tex]2040\ J/kg-K[/tex].

Answer:

Explanation:

The acceleration of an object given it's mass and the force acting on it can be found by using the formula

[tex]a = \frac{f}{m} \\ [/tex]

f is the force

m is the mass in kg

From the question

5000 g = 5 kg

We have

[tex]a = \frac{55}{5} \\ [/tex]

We have the final answer as

Hope this helps you

Answer:

fridge microwave washer dryer tv fan dishwasher fish tank lights toaster coffee pot

Answer:

A.) a proton and an electron

Answer:

C

Explanation:

the answer is a posotive and a negative ion

Answer:  Given Force = 12 N

                  Mass = 3kg  and 6kg

F= mass. acceleration

A= F/M

A(3kg object) = 12/3 = 4m/s^2

A(6kg object) = 12/6 = 2m/s^2

(a) The ball will stay in the air for 4.08 s.

(b) The ball travels 141 m horizontally before hitting the ground.

This is a projectile motion problem, to solve the problems above, we need to use the formula of (a) Time of flight and (b) Range.

(a)

⇒ Formula

⇒Where:

From the question,

⇒Given:

⇒Assuming:

⇒Substitute these values into equation 1

Also,

(b) For Range

⇒ Formula

⇒Substitute these values above into equation 2

Hence, (a) The ball will stay in the air for 4.08 s (b) The ball travels 141 m horizontally before hitting the ground

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A. The ball stay in the air for 4.08 seconds.

B. The ball travel nearly 141 meter before hitting the ground.

Given that,  Initial velocity (v) of ball is 40 m/s, at an angle of 30 degrees above the horizontal.

[tex]v=40m/s, \theta=30,g=9.8m/s^{2}[/tex]

Here we use formula,

  [tex]t=\frac{2v*sin\theta}{g}\\\\range(R)=\frac{v^{2}*sin2\theta }{g}[/tex]

Substituting values in above equations.

[tex]t=\frac{2*40*sin30}{9.8}=\frac{2*40*0.5}{9.8}=4.08s\\\\R=\frac{(40)^{2}*sin60 }{9.8} =\frac{1600*0.866}{9.8} =141m[/tex]

Hence, The ball stay in the air for 4.08 seconds and The ball travel nearly 141 meter before hitting the ground.

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Answer:

It would kill her

Explanation:

Hello!

a = 3 m/s²

Use the equation F = m · a (Newton's Second Law) to solve.

We are given the force and mass, so plug these values into the equation:

60 = 20 · a

60 = 20a

Divide both sides by 20:

60/20 = 20a/20

a = 3 m/s²

Capillarity phenomenon is applied in the drawing of kerosene by the wicks of a kerosene stove.

A liquid's ability to flow through small openings without the aid of outside forces is known as capillarity. Cotton or cotton threads make up the majority of the wicks.

The process of a liquid flowing in a small space without the aid of, or even in opposition to, any outside forces like gravity is known as capillary action.

Surface tension causes a liquid in a capillary tube to have the inclination to rise or descend, which is known as capillarity. the uses of capillarity. 1. Even a tall tree uses the capillary rise to give water to the leaves at the top.

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Answer:

aye man you alright? I’m here for you if u need anything. just keep ur head king and stay strong, I’m sorry for what happened. she probs left bc she wanted another guy, lost feelings, or family/personal issues etc.

Answer:

item/object; more

Explanation:

A variable is defined as an object or item that can have more than one single value.

A variable is defined as a quantity that can have more than one single value.

In the context of mathematics and science, a variable is a symbol or quantity that can change or vary. It represents an unknown or changing value that can take on different values in different situations or scenarios. Variables are used to describe relationships, equations, and patterns in various fields such as mathematics, physics, economics, and more.

Variables are an essential concept in scientific research and experimentation. They allow scientists to investigate how changes in one factor can affect another factor. In an experiment, variables are typically categorized into two main types: independent variables and dependent variables. The independent variable is the one that the researcher manipulates or controls to observe its effect on the dependent variable, which is the outcome being measured.

For example, in a study investigating the effects of different amounts of fertilizer on plant growth, the amount of fertilizer would be the independent variable, as it is being controlled by the researcher. The plant growth would be the dependent variable, as it depends on the different amounts of fertilizer applied.

Overall, variables are fundamental components of scientific inquiry, data analysis, and problem-solving, enabling researchers and scientists to understand and describe the relationships and patterns within various phenomena.

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Answer:

The force of gravitational attraction is 8.454 x 10⁻⁸ N.

Explanation:

Given;

mass of the boy, m₁ = 78 kg

mass of the girl, m₂ = 65 kg

distance between the boy and the girl, r = 2 meters

The force of gravitational attraction is given as;

[tex]F = \frac{Gm_1m_2}{r^2}[/tex]

where;

G is gravitational constant = 6.67 x 10⁻¹¹ Nm²/kg²

r is the distance between two masses, m₁ and m₂

[tex]F = \frac{Gm_1m_2}{r^2} \\\\F = \frac{(6.67 \times 10^{-11})(78 \times 65)}{2^2}\\\\F = 8.454 \times 10^{-8} \ N[/tex]

Therefore, the force of gravitational attraction is 8.454 x 10⁻⁸ N.

The force per unit length by I₂ on I₁ is 8 × 10⁻⁵ N/m.

The force between two parallel currents I₁ and I₂ that are spaced apart by r is measured as the ratio F/L. If the currents are flowing in the same direction, the force is attracting; if not, it is repulsive.

Currents are carried in the same direction by two lengthy parallel conductors that are spaced apart by 10.0cm.

I₁ = 5.00 A and I₂ = 8.00 A are the currents carried by the first and second wires, respectively.

r = 10 cm

Let the current flow along both wires in the x direction, with the first wire located at y = 0 and the second at y = 10 cm.

Now, the magnitude of the magnetic field created by I₂ at the location of I₁ is:

[tex]B = \frac{\mu_{0} I}{2 \pi r}(-\hat{k})[/tex]

[tex]B = \frac{4 \pi \times 10^{-7} \times 8}{2 \pi \times 0.1}[/tex]

[tex]B = (1.60 \times 10^{-5})(-\hat{k})[/tex]

Then the force per unit length exerted by I₂ on I₁ will be:

[tex]F_B = I_{1}( L \times B) = (5) [ (1)\hat{i} \times 1.60 \times 10^{-5}(-\hat{k}) ][/tex]

[tex]F_B = 8 \times 10^{-5}{~} N[/tex] towards the second wire.

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The displacement of the ball rolled down the incline is determined as 0.54 m.

The displacement of an object is the change in the position of the object.

Displacement is a vector quantity and has a direction and magnitude. It is represented as an arrow that points from the starting position to the final position.

The displacement of the ball is calculated as follows;

d = Δx

where;

d = 0.86 m - 0.32 m

d = 0.54 m

Thus, the displacement of the ball rolled down the incline is determined as 0.54 m.

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The complete question is below;

A ball is rolled down an incline from the 0.86 meter mark to the 0.32 meter mark. Find the displacement of the ball.

A meteoroid is a rock in space when it enters a planet's atmosphere it is a meteor, any piece remaining after impact is a meteorite.

Meteoroids are small objects floating in space. They are made up of rocks, iron, and dust. In our solar system, meteoroids orbit the Sun and some planets.

When these meteoroids enter the atmosphere of earth, they become meteors. These meteors started to burn and shine due to friction.

Meteorites are the surviving un-burnt piece of meteors that hit the surface of the Earth.  

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Answer:

The frequency of the infrared light is approximately 3.156 × 10¹⁴ Hz

Explanation:

Given that the wavelength of infrared light, λ = 9.50 × 10⁻⁷ m, we have;

The speed of light (which is constant), c = v × λ = 299,792,458 m

Where v = The frequency of the infrared light, we have;

v = c/λ = 299,792,458/(9.50 × 10⁻⁷) ≈ 3.156 × 10¹⁴ Hz

The frequency of the infrared light = v ≈ 3.156 × 10¹⁴ Hz.

Answer:

The difference is that water is an incompressible fluid — its density is almost constant as the pressure changes — while air is a compressible fluid — its density changes with pressure. Atmospheric pressure is the pressure exerted on a surface by the weight of the atmosphere (a compressible fluid) above it.

Explanation:

Answer:

Net force = 509.90 N

Explanation:

Given that,

Force exerted by wind is 500 N South on a sailboat.

The force exerted by water is 100 N on the sailboat.

Two forces are acting at an angle of 90 degrees. We can find the net force acting on the sailboat. Let it is F.

[tex]F=\sqrt{500^2+100^2} \\\\=509.90\ N[/tex]

So, the net force on the sailboat is 509.90 N.

Answer: The Answer is 10 Ampere

Explanation:

The Formula

Resistance= Voltage ÷ current

Current= Resistance÷ current

Resistance= 12 ohms

Potential difference=120volts

hence Current= 10 Ampere

Hope it helps please leave a like if u are satisfied

bye

Answer:

change 20 min into hr = 0.33 hr

Explanation:

convert= divide the time by 60 because 60 mins make 1 hr

Answer:

the car do different amount of work depending on how fast they finish is my answer

Explanation:

I hope so it is helpful for you

Answer: B. The car that finishes last has the lowest power.

Explanation:

Answer:

40 N

Explanation:

We first need to calculate the acceleration of the tron ball.

Since acceleration, a = (v - u)/t where u = initial velocity of iron ball = 17m/s, v = final velocity of iron ball = 27m/s and t = time taken for the change in velocity = 5 s.

So, a = (v - u)/t

= (27 m/s - 17 m/s)/5 s

= 10 m/s ÷ 5 s

= 2 m/s²

We know force on iron ball, F = ma where m = mass of iron ball = 20 kg and a = acceleration = 2 m/s²

So, F = ma

= 20 kg × 2 m/s²

= 40 kgm/s²

= 40 N

So, the magnitude of the force on the iron ball is 40 N.