Just answer no worker needed to show

answer as by using mid point formula and then after equating the corresponding co ordinates we get the answer -7 and -3

Answer: 3/2 for improper fraction and 1 1/2 for a mixed number

Step-by-step explanation:

Carmen's total earning will be 10x when 10% earning is assumed to be x.

What is proportion ?

A proportion is an equation based on the equality of two ratios.

Let x be the earning of Carmen's that is equals to 10% of total earning.

Then total earning that is 100% will be equals to the multiplication 10% and x both with 10 :

10%( total earning of Carmen's ) = x

100%( total earning of Carmen's ) = 10x

Therefore, Carmen's total earning will be 10x when 10% earning is assumed to be x.

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Answer:

Suri= 40.7   Baseball=C   19=19.417   20=11.167   Tens=6  Thousanths=9  Hundreths=7  Tenths=5     Write in standard form=82.007    4.567   72.85

Write in expanded form= 20+4+0.1+0.07   30+6+0.9    1+0.8+0.02+0.004

Step-by-step explanation:

i gotchu

If Samuel cuts [tex]\frac{4}{7}[/tex] inches discs of metal, then he can make 7 discs from a metal post that measures [tex]\frac{1}{3}[/tex] foot in length

Given,

The total length of metal post= [tex]\frac{1}{3}[/tex] foot

Convert foot to inches

1 foot = 12 inches

[tex]\frac{1}{3}[/tex] foot= 4 inches

The length of each disc of metal = [tex]\frac{4}{7}[/tex] inches

Number of metal post that he can cut = Total length of metal post / The length of each disc of metal

[tex]=\frac{4}{\frac{4}{7} } \\=4(\frac{7}{4})\\ =7[/tex]

Hence, if Samuel cuts [tex]\frac{4}{7}[/tex] inches discs of metal, then he can make 7 discs from a metal post that measures [tex]\frac{1}{3}[/tex] foot in length

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Based on the variation statement, the variation equation is P = kW

The mathematical statement is given as

The pressure exerted on the floor by a person’s shoe heel varies in direct proportion on his or her weight

A direct variation is represented as ∝

In this case, we have

P = Pressure

W = Weight

So, we have the variation to be

P ∝ W

Express as an equation

P = kW

Where k represents the constant of variation

Hence, the variation equation is P = kW

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A. The probability of his character casting a spell will be 1/6.

B. The odds against choosing a green block is 2/9.

A. It should be noted that probability has to do with the chance of a particular thing happening.

In this case, the odds in favor of his character casting a spell are 1/6, therefore the probability of his character casting a spell is 1/6.

B. When a child has a box full of colored building blocks and he chooses one block without looking, the probability of choosing a green block is 7/9, therefore, the odds against choosing a green block will be:

= 1 - P(green block)

= 1 - 7/9

= 2/9

Therefore, the odds against choosing a green block will be 2/9.

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The lateral area of the cone is 394 square inches

The formula for lateral area of a cone is expressed as;

Lateral area = πr √h² + r²

Given that;

Substitute the values into the formula

Lateral area = 3. 142(6) √20² + 6²

Lateral area = 18. 85 √436

Lateral area = 18. 85 × 20. 8

Lateral area = 394 square inches

Thus, the lateral area of the traffic cone is 394 square inches

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The circumference and area of the circle are 13cm and 13cm^2 respectively

The formula for circumference of a circle is expressed as:

Circumference = 2πr

From the graph shown, we have the radius of the circle as 2 cm

Substitute the value into the formula

Circumference = 2 × 3. 142 × 2

Multiply through

Circumference = 12. 568

Circumference = 13cm

The formula for area of a circle is expressed as:

Area = πr^2

Substitute the value into the formula

Area = 3. 142 × (2)^2

Area = 3. 142 × 4

Area = 12. 568

Area = 13cm^2

Thus, the circumference and area of the circle are 13cm and 13cm^2 respectively.

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Answer:

See below

Step-by-step explanation:

Look for where the vertical line x = -2 crosses the graph.....the value is shown below.....

If 8/9 is multiplied by 3/7 then the product will not be greater than either of the two factors.

According to the question

on multiplying 8/9 by 3/7 we get

=8/9*3/7

=(8*3)/(9*7)

=24/63

=0.38095         ...(i)

On comparing it with two factors,

8/9 = 0.88888         .....(ii)

and

3/7 = 0.42857        ......(iii)

As we can see that on comparing equation (i) with equation (ii) and

equation (i) with equation (iii)    , we get that the product of 8/9 and 3/7 is less than both 8/9 and 3/7 .

Therefore , if 8/9 is multiplied by 3/7 then the product will not be greater than either of the two factors.

The given question is incomplete , the complete question is

If 8/9 is multiplied by 3/7 , will the product be greater than either of the 2 factors ?

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It should be noted that the area of the shaded figure based on the information will be 9600 m².

It should be noted that the area of a rectangle is calculated by multiplying the length by the width that's given.

It should be noted that this shape can be used

to form two rectangles and the areas will be added together.

Therefore, it should be noted that the area of the rectangle will be:

= (60 × 60) + (100 × 60)

= 3600 + 6000

= 9600 m²

In conclusion, it should be noted that the area of the shaded figure based on the information will be 9600 m².

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Answer:

Step-by-step explanation:

-4 ≥ x

-0 ≤ x

I don't think you can combine this into one statement.

Your line looks something like

<---------------O                 O------------------------->

                 -4               -0

Shade in the 2 Os. The shaded in Os  are included in the way the line looks.

4x

5+4/2=5 imput x since you cant forget your variable

The rate that the cars should be rented to produce the maximum income is: 41 Dollars/Day, Maximum income 7615.

Let y represent the  income

Let  x  represent the increase in rental price after increasing the rental price is 40+x.

Let 190-5x represent the number of cars rental after a rental price increase

Income expression

y=(190-5x) (40+x)

Let differentiate y with respect to x and set y' =0 to determine the maximum income

Hence,

y=(190-5x) (40+x)

=(190) (40) + 190 (x) -5x(40) -5x-(x)

=7600 +190x-200x-5x²

y= -5x² +10x+7600

Differentiate with respect to x

y'=d/dx ( -5x² +10x+7600)

y'=-10x+10x

set y'=0

-10x+10=0

10x=10

x=10/10

x=1

Maximum Rate =40+x

=40+1

=41 Dollars/Day

Maximum Income is

y= ( -5x² +10x+7600)

=(−5(1)²+10(1)+7600)

=−5(1)+10+7600

=5+10+7600

=7615

Therefore the rate that the cars should be rented to produce the maximum income is: 41 Dollars/Day, Maximum income 7615.

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Answer:

z>7.67

Step-by-step explanation:

-9>3z+14

3z<-14-9

3z<-23

3z>23

z>(23÷3)

z>7.67

Answer:1200

Step-by-step explanation:

Answer:

3x+2 = 14.12

f(4) = 0

Answer: EVALUATE

3x+8f

f(x)=3x+2f(4)=

Multiply 2 and 4 to get 8.

3x+8f

DIFFERENTIATE W.R.T. X

3

Step-by-step explanation:

[tex]\huge\text{Hey there!}[/tex]

[tex]\text{If John is currently 9 years old and we’re trying to figure out how old he will be}\\\text{in 20 years.}[/tex]

[tex]\text{Let us label your equation to:}[/tex]

[tex]\text{9 - a = 20 OR BETTER YET a - 9 = 20; your “a”-value will be labeled as}\\\text{John future age.}[/tex]

[tex]\textsf{Equation:}[/tex]

[tex]\mathsf{a - 9 = 20}[/tex]

[tex]\textsf{ADD 9 to BOTH SIDES}[/tex]

[tex]\mathsf{a - 9 + 9 = 20 + 9}[/tex]

[tex]\textsf{SIMPLIFY IT}[/tex]

[tex]\mathsf{a = 20 + 9}[/tex]

[tex]\mathsf{a = 29}[/tex]

[tex]\huge\text{Therefore, your answer should be:}[/tex]

[tex]\huge\boxed{\mathsf{John\ will \ be \ \boxed{\mathsf{29}} \ years \ old}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]

a. Organizing the transaction data in accounts under an accounting equation for each year is as follows.

Accounting Equation: Assets = Liabilities + Equity

Year 1:

        Cash        Accounts      =     Liabilities     + Equity

                       Receivable

1)                           $31,130                                  $31,130  Service Revenue

2)     $24,904      (24,904)

3)                                 (311)                                      (311)  Bad Debts Expense

Bal. $24,904         $5,915                                $30,819

Year 2:

        Cash        Accounts      =     Liabilities     + Equity

                       Receivable

Bal. $24,904       $6,226                                 $30,819 Retained Earnings

1)                               (233) +233

2)                       $36,329                                $36,329  Service Revenue

3)     $32,151        (32,151)

4)                             (285)                                     (285) Bad Debts Expense

Bal. $57,055      $9,808                               $66,863  

b. Determining the following amounts is as follows:

                                                                             Year 1            Year 2

1. Net income                                                    $30,819       $36,044

2. Net cash flow from operating activities       24,904           32,151

3. Balance of accounts receivable at the end  6,226             10,171

4. Net realizable value of accounts receivable 5,915            9,808

Year 1:

1) Accounts Receivable $31,130 Service Revenue $31,130

2) Cash $24,904 Accounts Receivable $24,904

3) Bad Debts Expense $311 Allowance for Uncollectible Accounts $311

Year 2:

1) Allowance for Uncollectible Accounts $233 Accounts Receivable $233

2) Accounts Receivable $36,329 Service Revenue $36,329

3)  Cash $32,151 Accounts Receivable $32,151

4)  Bad Debts Expense $285 Allowance for Uncollectible Accounts $285

Net income for Year 2 = $36,044 ($36,329 - $285)

Year 1:

Net income                    $30,819

Non-cash expense                311

Accts receivable              (6,226)

Cash from operations $24,904

Year 2:

Net income                    $36,044

Non-cash expense                 52 ($285 - $233)

Accts receivable              (3,945)

Cash from operations  $32,151

Year 1:

Account Titles            Debit      Credit

1) Service Revenue $31,130

2) Cash                                  $24,904

Ending balance                      $6,226

Net Realizable Accounts Receivable = $5,915 ($6,226 - $311)

Year 2:

Account Titles            Debit      Credit

Beginning balance   $6,226

1) Allowance for Uncollectibles $233

2) Service Revenue 36,329

3)  Cash                                    32,151

Ending balance                      $10,171

Net Realizable Accounts Receivable = $9,808 ($10,171- $363)

Account Titles            Debit      Credit

Bad Debts Expense                   $311

Accounts Receivable $233

Bad Debts Expense                  285

Balance                      $363

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Required a. Organize the transaction data in accounts under an accounting equation for each year.

b. Determine the following amounts:

1. Net income for years 1 and 2.

2. Net cash flow from operating activities for Years 1 and 2.

3. Balance of accounts receivable at the end of Years 1 and 2.

4. Net realizable value of accounts receivable at the end of years 1 and 2.

The relationship between the price and cost is p > c.

The cost of manufacturing a product has a direct bearing on its price and the revenue generated by each sale. The cost of a product or service is determined by the customer's willingness to pay. Profit is the sum of the price paid less the costs incurred.

The price of Anna's greeting cards is p.

The cost of making a single greeting card is c.

Anna wants the profit to be 40% of the price of her greeting cards.

Profit = 40% of p

Profit = 40% × p = 0.4p

Now, we know

Price = Profit + Cost

p = 0.4p + c

Therefore, the relationship between cost and price is given by inequality:

p > c

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The survey results are most likely to be affected by non response bias.

Sampling bias is a form of bias wherein a sample is collected in such a manner that some members of the intended population have a lower or higher sampling probability than others.

Non-response bias is a type of a sampling bias that occurs when people are unwilling or unable to respond to a survey because of a factor that makes them differ significantly from the people who do respond to the survey. The difference between non-respondents and respondents is generally an influencing factor for the former's lack of response. Non response error is very common in mail surveys.

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Answer:

Answer is 1+- √2

Step-by-step explanation:

[tex] \frac{ - ( - 4) + - \sqrt{ {4}^{2} - 2 \times( - 8) } }{2(2)} [/tex]

[tex] \frac{4 + - \sqrt{32} }{4} [/tex]

[tex]1 + - \sqrt{2} [/tex]

Answer:

y = 4x - 27

Step-by-step explanation:

The point (8,5) contains and x and y on the line.  The x is 8 and the y is 5.  Using this and the slope given we can write the equation.  We need to solve for b.

y = mx + b

5 = 4(8) + b

5 = 32 + b  Subtract 32 from both sides of the equation

-27 = b

y = mx + b

y = 4x - 27

Answer:

pls rate as brainliest

Step-by-step explanation:

y-y1=m(x-x1)

where y1=5,x1=8 and m=4

y-5=4(x-8)

y-5=4x-16

y=4x-16+5

y=4x-11

The designation of the dependent variable and the independent variable can be d. Independent variable - value of the truck; and Dependent variable - number of years you own the truck.

In most cases, dependent variables are used to represent discrete values

Take for instance:

While independent variables are used to represent continuous values

Take for instance:

Using the above as a hint, the designation of the dependent variable and the independent variable can be d. Independent variable - value of the truck; and Dependent variable - number of years you own the truck.

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5x-16=5+4x

    +16+5

   5x=21+4x

  -4x       -4x

     x= 21

Step-by-step explanation:

Answer: answer should be;

x^2+9x+13

Step-by-step explanation:

hey there;

f {x} - g {x}

=2x^2 + 7 - x^2+9x-6

=2x^2-x^2+9x+ 7-6

=x^2+9x+13

So, this is the following answer. You may mistook the question or the question itself is wrong.

Hope it helps!

Run the Ingleby marathon for free if  A ≥ £900

Given data

a. Joe raise more than £400 and run the Ingleby marathon for free

Run the Ingleby marathon for free if A> £400

b. Joe raise at least £900 and run the Ingleby marathon for free

Run the Ingleby marathon for free if __________

The first part of the statement gives the clue and it rewritten as

a. Raise more than £400 and run the Ingleby marathon for free

Run the Ingleby marathon for free if A> £400

more than £400 is represented as A> £400

The statement means amount greater that £400 and it is written mathematically as A> £400

The second statement is done as follows:

b. Joe raise at least £900 and run the Ingleby marathon for free

Run the Ingleby marathon for free if __________

In this case Joe runs the marathon if the amount is of the that is at least £900, which implies amount of 900 and above or simply put: amount of 900 or more than 900 .

This represented mathematically as: A ≥ £900

Hence we say Run the Ingleby marathon for free if  A ≥ £900

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Complete question

The complete question is attached

Answer: maybe this will help. try searching this

Lim x 3^ + |6-2x|/ sqrt x-3 Evaluate the expression. to watch this video that I have screenshot down below.

Step-by-step explanation: