Just some Naruto couples having a Boxing Match.

Who do you think will win?! Naruto and Hinata or Pain and Konan?!

Complete question:

Resistor is made of a very thin metal wire that is 3.2 mm long, with a diameter of 0.4 mm. What is the electric field inside this metal resistor? If the potential difference due to electric field between the two ends of the resistor is 10 V.

Answer:

The electric field inside this metal resistor is 3125 V/m

Explanation:

Given;

length of the wire, L = 3.2 mm = 3.2 x 10⁻³ m

diameter of the wire, d = 0.4 mm = 0.4 x 10⁻³ m

the potential difference due to electric field between the two ends of the resistor, V = 10 V

The electric field inside this metal resistor is given by;

ΔV = EL

where;

ΔV is change in electric potential

E = ΔV / L

E = 10 / (3.2 x 10⁻³ )

E = 3125 V/m

Therefore, the electric field inside this metal resistor is 3125 V/m

Answer:

268.22m/s

Explanation:

Given;

    10mile/min to m/s

We need to convert between the two units;

  Using the dimensions;

    1 mile  = 1609.34m

     60s  = 1min

Now;

    10 x [tex]\frac{mile}{min}[/tex] x [tex]\frac{1min}{60s}[/tex] x [tex]\frac{1609.34m}{1mile}[/tex]

  = 268.22m/s

Answer: [tex]M_{total}=[/tex] 1.85

Explanation: Estimate the total mass of a binary system is done by a reformulation of Kepler's Third Law, which states that the square of the period of a planet's orbit is proportional to the cube of its semimajor axis, i.e.:

[tex]a^{3}=(M_{1}+M_{2})P^{2}[/tex]

where

a is semimajor axis in astronomical units (AU);

P is period measured in years;

[tex]M_{1}+M_{2}[/tex] is total mass of the two-stars system;

For the two stars faraway in the Milky Way:

1 year is equivalent of 365 days, so period in years:

[tex]P=\frac{594}{365}[/tex]

P = 1.63 years

Calculating total mass:

[tex]a^{3}=(M_{total})P^{2}[/tex]

[tex]M_{total}=\frac{a^{3}}{P^{2}}[/tex]

[tex]M_{total}=\frac{1.7^{3}}{1.63^{2}}[/tex]

[tex]M_{total}=[/tex] 1.85

The total mass of the two-object system is 1.85 mass units.

Answer:

answer is 61.8 m/s; 32.9

l am not sure

Answer:

C. The net force applied to the ball is zero.

Explanation:

From Newton's second law of motion;

F = ma

Where F is the force on an object, m is its mass and a is its acceleration.

Therefore, the force on an object is a product of its mass and acceleration as it travel from one point to another.

Since acceleration relates to the rate of change in velocity to time. Then when the object moves at uniform velocity (especially along a straight path), its acceleration is zero.

So that;

F = m x 0

  = 0

No force is applied on the object.

Therefore for the ball in the given question, the net force applied to the ball is zero because it rolls with constant speed along a straight path.

Answer: A plane mirror always forms a virtual image (behind the mirror). The image and object are the same distance from a flat mirror, the image size is the same as the object size, and the image is upright.

Explanation:

Answer:

Force = 49N

Explanation:

Force is given by the multiplication of mass and acceleration.

Mathematically, Force is;

[tex] F = ma[/tex]

Where;

F represents force measured in Newton.

m represents the mass of an object measured in kilograms.

a represents acceleration measured in meter per seconds square.

Given the following data

Mass = 5kg

We know that acceleration due to gravity = 9.8m/s²

To find the Force:

[tex] F = 5*9.8 [/tex]

Force = 49N

Answer:

Reverse check the answer

Explanation:

I believe it is very important that once someone is done with any calculation, the person ought to go over the calculations again. And even, recheck the answer in inverted form.

This is so because while doing the calculations, we can possibly make errors that we won't notice until after submission. Knowing 2 * 3 = 6, but writing 2 * 3 = 5 in the course of calculations can happen to anybody. So therefore, cross checking and reverse checking is needed

Answer:

it is scientific knowledge

Explanation:

got i right on edge

The scientific knowledge refers to information gathered by the systematic study of nature.

A generalized corpus of laws and ideas developed employing the scientific method to describe an interesting occurrence or behavior is referred to as scientific knowledge.

Science would be the systematic study of the composition and dynamics of the physical as well as the natural world via experimentation and observation.

the systematic study of natural circumstances and phenomena. empirical proof. the term for the facts and figures that support an explanation in science.

Therefore, the correct answer will be option (C)

To know more about scientific knowledge.

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Answer:

See connections below

Explanation:

1   [tex]\Rightarrow[/tex] b

2   [tex]\Rightarrow[/tex] a

3   [tex]\Rightarrow[/tex] d

4   [tex]\Rightarrow[/tex] i

5   [tex]\Rightarrow[/tex] g

6   [tex]\Rightarrow[/tex]  h

7   [tex]\Rightarrow[/tex]  c

8   [tex]\Rightarrow[/tex]  e

9   [tex]\Rightarrow[/tex] f

Answer:

C

Explanation:

Current passing through the loop in either direction

Answer:

[tex]q_1=5.64\times 10^{-7}\ \text{C}[/tex] and [tex]q_2=2.32\times 10^{-6}\ \text{C}[/tex]

Explanation:

[tex]F_1=0.072\ \text{N}[/tex]

[tex]F_2=0.115\ \text{N}[/tex]

r = Distance between shells = 40.4 cm

[tex]q_1[/tex] and [tex]q_2[/tex] are the charges

[tex]k[/tex] = Coulomb constant = [tex]8.99\times10^{9}\ \text{Nm}^2/\text{C}^2[/tex]

Force is given by

[tex]F_1=\dfrac{kq_1q_2}{r^2}\\\Rightarrow q_1q_2=\dfrac{F_1r^2}{k}\\\Rightarrow q_1q_2=\dfrac{0.072\times 0.404^2}{8.99\times 10^{9}}\\\Rightarrow q_1q_2=1.307\times 10^{-12}\\\Rightarrow q_1=\dfrac{1.307\times 10^{-12}}{q_2}[/tex]

[tex]F_2=\dfrac{kq^2}{r^2}\\\Rightarrow q=\sqrt{\dfrac{F_2r^2}{k}}\\\Rightarrow q=\sqrt{\dfrac{0.115\times 0.404^2}{8.99\times 10^{9}}}\\\Rightarrow q=1.44\times 10^{-6}\ \text{C}[/tex]

[tex]q=\dfrac{q_1+q_2}{2}\\\Rightarrow q_1+q_2=2q\\\Rightarrow q_1+q_2=2\times1.44\times 10^{-6}\\\Rightarrow q_1+q_2=2.88\times 10^{-6}[/tex]

Substituting the above value of [tex]q_1[/tex] we get

[tex]\dfrac{1.307\times 10^{-12}}{q_2}+q_2=2.88\times 10^{-6}\\\Rightarrow q_2^2-2.88\times 10^{-6}q_2+1.307\times 10^{-12}=0\\\Rightarrow \frac{-\left(-0.00000288\right)\pm \sqrt{\left(-0.00000288\right)^2-4\times \:1\times \:1.307\times 10^{-12}}}{2\times \:1}\\\Rightarrow q_2=2.32\times 10^{-6}, 5.64\times 10^{-7}[/tex]

[tex]q_1=\dfrac{1.307\times 10^{-12}}{q_2}=\dfrac{1.307\times 10^{-12}}{2.32\times 10^{-6}}\\\Rightarrow q_1=5.63\times 10^{-7}[/tex]

[tex]q_1=\dfrac{1.307\times 10^{-12}}{q_2}=\dfrac{1.307\times 10^{-12}}{5.64\times 10^{-7}}\\\Rightarrow q_1=2.32\times 10^{-6}[/tex]

Since we know [tex]q_1<q_2[/tex]

[tex]q_1=5.64\times 10^{-7}\ \text{C}[/tex] and [tex]q_2=2.32\times 10^{-6}\ \text{C}[/tex].

Answer:

0.87

Explanation:

To solve this, we use the principle of Archimedes. Archimedes Principal of flotation states that "the buoyant force of an object is equal to the total weight of the fluid it displaces."

In the attachment, I stated the mathemacal formula, of which

F(B) = The buoyant force

w(fl) = The weight of the salt water displaced

p(iron) = density of iron

p(salt) = density of the salt water = 1025 kg/m³

F' = weight of the iron in air

F = weight of the iron in salt water

p(man) = density of man = 7680 kg/m³

The rest are the easy calculations done by substituting the values

Answer:

6,000 kg

Explanation:

Answer:

The value is  [tex]w = 0.1167 \ rev/second[/tex]

Explanation:

From the question we are told that

    The rate at which the plate rotates is  [tex]w =7.0 \ rev/min[/tex]

Generally the revolution per second is mathematically represented as

       [tex]w = \frac{7.0}{60}[/tex]

=>    [tex]w = 0.1167 \ rev/second[/tex]

Answer:

None of them: the direction of the pressure fluctuations is parallel to the direction of motion of the wave

Explanation:

Answer: The acceleration results if a net force of 4F acts on a mass of 6m is 2/3a.

Explanation:

Force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is:

F= mass( kg) × acceleration( m/ s²)

Acceleration is defined as the rate at which the velocity of an object changes. From the formula of force given above it can be determined by making it the subject of formula. Therefore acceleration= Force/ mass.

From the question,

Force= 4F

Mass= 6m

Therefore acceleration= F/m

= 4/6

Acceleration= 2/3a

The required magnitude of acceleration when force is 4F and mass is 6m is 2/3a.

Given data:

The magnitude of net force is, 4F.

The value of mass is, 6m.

Apply the Newton's second law which says that force exerted on an object can be defined as a pull or a push on an object which leads to it's displacement. Force is taken to be a vector quantity because it has both magnitude and direction. The formula which can be used to determine force exerted on an object in physics is

F = ma

a = F/m ..........................................(1)

here, a is the acceleration.

Solving as when the force becomes 4F and mass becomes 6m.

[tex](4F) = (6m) \times a'\\\\a '= \dfrac{4F}{6m}\\\\a '= \dfrac{2}{3}a[/tex]

Thus, the required magnitude of acceleration when force is 4F and mass is 6m is 2/3a.

Learn more about the Newton's Second law here:

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Answer:

The correct answer will be:

(A) 24955495.07 N/m²

(B) 97482.40 N/m²

Explanation:

(A)

The given values are:

mass,

m = 50 kg

diameter

= 0.50 cm

then,

radius,

r = 0.25 cm

 = 0.0025 m

As we know,

⇒ [tex]A = area \ of \ cross \ section[/tex]

       [tex]=\pi r^2[/tex]

and,

⇒ [tex]stress = \frac{mg}{A}[/tex]

On substituting the values, we get

              [tex]=\frac{(50)(9.8)}{\pi (0.0025^2)}[/tex]

              [tex]=24955495.07 \ N/m^2[/tex]

(B)

mass,

m = 5000 kg

radius,

r = 20 cm

 = 0.2 m

Now,

⇒ [tex]stress=\frac{\frac{5000}{4} (9.8)}{\pi (0.2^2)}[/tex]

              [tex]=97482.40 \ N/m^2[/tex]

Answer:

Remote Sensing

Explanation:

Answer:

Delivery truck

Explanation:

Answer:

8.4 N/m

Explanation:

m = Mass of block = 4.63 gm

g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]

x = Displacement of spring = 0.45 cm

a = Acceleration of subject = 0.832g

k = Spring constant

Force is given by

[tex]F=ma[/tex]

From Hooke's law

[tex]F=kx[/tex]

So

[tex]ma=kx\\\Rightarrow k=\dfrac{ma}{x}\\\Rightarrow k=\dfrac{4.63\times 10^{-3}\times 0.832\times 9.81}{0.45\times 10^{-2}}\\\Rightarrow k=8.4\ \text{N/m}[/tex]

The force constant of the spring is 8.4 N/m.

Answer:

Hey

Explanation:

Before they meet Earth -- meteoroids

While they're falling -- meteors

After they hit the ground -- meteorites

Answer:

one of the graph is postion-time graph while the other one is velocity-time graph

Answer:

The average momentum of the bird is 0.26 kgm/s

Explanation:

The formula to be used here is that of momentum which is

momentum (in kgm/s) = mass (in kg) × velocity (in m/s)

The velocity of the bird is

velocity (in m/s) = distance (in meter) ÷ time (in seconds)

distance in meters = 125km × 1000 = 125,000 m

time in seconds = 4 hrs × 60 × 60 = 14,400 secs

velocity = 125000/14400

velocity = 8.68 m/s

momentum (p) = 0.03 × 8.68

p = 0.26 kgm/s

The average momentum of the bird is 0.26 kgm/s

The average momentum of the bird (in unit vector notation) is (0.1842i + 0.1842j) kgm/s.

Since the unladen swallow that weighs 0.03 kg flies straight northeast (that is at a bearing of 45°) a distance of 125 km in 4.0 hours.

Its position vector after 4.0 hours is d = (125kmcos45)i + (125kmsin45)j = (125000 × 1/√2)i + (125000 × 1/√2)j

= (62500√2)i + (62500√2)j.

If the initial position of the swallow is d' = 0i + 0j, then its total displacement after 4 hours is, D = d - d'

= (62500√2)i + (625000√2)j - (0i + 0j)

= (62500√2)i + (62500√2)j m

The unladen swallow's average velocity, v = D/t where

So, v =  [(62500√2)i + (62500√2)j m]/14400 s =  (88388.35)i/14400 + (88388.35)j /1440

= 6.14i + 6.14j m/s

The average momentum of the unladen swallow is p = mv where

So, p = mv

p = 0.03 kg × (6.14i + 6.14j m/s)

p = (0.1842i + 0.1842j) kgm/s

So, the average momentum of the bird (in unit vector notation) is (0.1842i + 0.1842j) kgm/s.

Learn more about average momentum here:

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Answer:

t = 1.32 s

Explanation:

We are given;. Frequency of C4 note; F_c = 262 Hz

In conversions, we know that 1 Hz = 1 cycle/s

Thus, F_c = 262 cycles/s

Now, we want to find out how much time it takes for 346 air pressure maxima to pass a stationary listener.

346 air pressure maxima denotes that the air pressure maxima is 346 cycles.

Thus, time will be;

t = 346 cycles/262 cycles/s

t = 1.32 s

The time taken for the musical note to pass the stationary listener is 1.32 s.

The given parameters:

The frequency of a sound wave is defined as the number of cycles completed per second by the wave.

[tex]F = \frac{n}{t}[/tex]

where;

The time taken for the musical note to pass the stationary listener is calculated as follows;

[tex]262 = \frac{n}{t} \\\\t = \frac{n}{262} \\\\t = \frac{346}{262} \\\\t = 1.32 \ s[/tex]

Thus, the time taken for the musical note to pass the stationary listener is 1.32 s.

Learn more here:https://brainly.com/question/15613196

Answer:

T = 3990 N

Explanation:

The free body diagram for the elevator consists of a tension force pointing up, and its weight pointing down. So the elevator's net force is:

F = T - 2940N

ad at the same time, using Newton's second law, we have that this net force should equal the elevator's mass (300 kg) times its acceleration (a):

T - 2940N = 300kg (3.5m/s^2)

then

T = 2940 N + 1050 N

T = 3990 N