Mass of 2×10^21 number of atoms of an element is 0.4g. What is the mass of 0.5 mole of the element?
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Answer:

13.94 atm

Explanation:

From the question given above, the following data were obtained:

Pressure of H₂ = 2 atm

Pressure of NH₃ = 303 KPa

Pressure of CO₂ = 3000 mmHg

Pressure of N₂ = 3800 torr

Total pressure (Pₜ) in atm =?

Next, we shall convert 303 KPa, 3000 mmHg and 3800 torr to atm.

This can be obtained as follow:

Converting 303 KPa to atm

101.325 KPa = 1 atm

Therefore,

303 KPa = 303 KPa × 1 atm / 101.325 KPa

303 KPa = 2.99 atm

Thus, 303 KPa is equivalent to 2.99 atm.

Converting 3000 mmHg to atm

760 mmHg = 1 atm

Therefore,

3000 mmHg = 3000 mmHg × 1 atm / 760 mmHg

3000 mmHg = 3.95 atm

Thus, 3000 mmHg is equivalent to 3.95 atm

Converting 3800 torr to atm

760 torr = 1 atm

Therefore,

3800 torr = 3800 torr × 1 atm / 760 torr

3800 torr = 5 atm

Thus, 3800 torr is equivalent to 5 atm.

Finally, we shall determine the total pressure of the mixture as follow:

Pressure of H₂ (P₁) = 2 atm

Pressure of NH₃ (P₂) = 2.99 atm

Pressure of CO₂ (P₃) = 3.95 atm

Pressure of N₂ (P₄) = 5 atm

Total pressure (Pₜ) in atm =?

Pₜ = P₁ + P₂ + P₃ + P₄

Pₜ = 2 + 2.99 + 3.95 + 5

Pₜ = 13.94 atm

Therefore, the total pressure of the mixture is 13.94 atm

Answer

There is not as much sunlight underwater and therefore less energy can be absorbed therefore a slower process of photosynthesis.    

Explanation:

Answer:

X = 27 .

Explanation:

Centigrade scale : melting point O⁰C , boiling point 100⁰C

New scale          melting point -45⁰C   , boiling point 115⁰C

Formula relating the two scale

[tex]\frac{C- 0 }{100-0} =\frac{X-(-45)}{115-( -45) }[/tex]

[tex]\frac{C }{100} =\frac{(X+45)}{(115 +45) }[/tex]

[tex]\frac{C }{100} =\frac{(X+45)}{160}[/tex]

Given C = 45

X = ?

[tex]\frac{45 }{100} =\frac{(X+45)}{160}[/tex]

X + 45 = 72

X = 27 .

Answer:

D.

Explanation:

Yan Lang po Alam ko

Answer:

C: The actual yield depends on the reaction conditions, but the theoretical yield varies only with reactant amounts

Explanation:

Looking at the options, the correct one is Option C because the actual yield usually depends on the conditions of the reaction, while the theoretical yield usually varies with only the amount of reactant.

Answer:

CH2

Explanation:

What is the empirical formula of a compound that contains 20.0g carbon and 3.37g hydrogen? Divide by the smallest number of moles. The empirical formula is CH2.

Answer:

The air would still be too thin to breathe. The lack of atmosphere would chill the Earth's surface. Organisms that need air to breathe would die.

Explanation:

Hope it helped!

Answer:

Explanation:

Salt water intrusion can cause the fresh water in wells to become contaminated with saltwater.

There are two types of chemical compound one is covalent compound and other is ionic compound, covalent compound formed by sharing of electron and ionic compound formed by complete transfer of electron. Therefore, salt water intrusion can cause the fresh water in wells to become contaminated with salt water.

Chemical Compound is a combination of molecule, Molecule forms by combination of element and element forms by combination of atoms in fixed proportion.

An ionic compound is a metal and nonmetal combined compound. Ionic compound are very hard. They have high melting and boiling point because of strong ion bond.

The compound that is ionic in nature can be dissociated very easily in water. Since ionic compounds are polar in nature, they readily dissolve in water. Salt water intrusion can cause the fresh water in wells to become contaminated with salt water.

Therefore, salt water intrusion can cause the fresh water in wells to become contaminated with salt water.

To learn more about chemical compound, here:

brainly.com/question/26487468

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Answer:

metallic bonding

Explanation:

Copper wire consists of Cu nuclei (that are positively charged due to the positively charged protons) that are surrounded by a "sea" of delocalized electrons (that are negatively charged that move freely throughout the material which is known as metallic bonding.

Answer:

Metallic bonding.

Explanation:

Pure copper is neither covalent nor ironic. It is a bonding called metallic bonding.

Answer:

the population of the region

Hope this helps :)

Answer:

Chlorine has the highest amongst all of those

Answer: Final temperature for given mass of water is [tex]24.6^o C[/tex].

Explanation:

Given: mass = 630.1 g, specific heat = 418 [tex]J/g^{o} C[/tex], q = 950 J, T = [tex]24.2^o C[/tex]

Formula used:  [tex]q = mC \Delta T[/tex]

where, q = heat energy

            m = mass

            C = specific heat

            [tex]\Delta T[/tex] = change in temperature = [tex](T_2 - T_1)[/tex]

  950 J = [tex]630.1 g \times 4.18 J/g^o C \times (T_2 - 24.2^o)[/tex]

          [tex]T_2 = 24.6^o C[/tex]

Answer:

T2 = 24.56°C

Explanation:

Given data:

Mass of water = 630.1 g

Specific heat of water = 4.18 J/g.°C

Initial temperature = 24.2°C

Heat absorbed = 950 J

Final temperature = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

by putting values

950 J = 630.1 g × 4.18 J/g.°C ×  (T2 - 24.2°C)

950 J = 2633.82 j/°C ×  (T2 - 24.2°C)

950 J / 2633.82 j/°C =  (T2 - 24.2°C)

0.36°C  + 24.2°C = T2

T2 = 24.56°C

Answer:

1.1 × 10⁵ J

Explanation:

Step 1: Given data

Step 2: Calculate the change in the temperature

ΔT = 192.4 °C - 70 °C = 122 °C

Step 3: Calculate the heat required (Q)

We will use the following expression.

Q = c × m × ΔT

Q = 0.89 J/g.°C × 1000.0 g × 122 °C

Q = 1.1 × 10⁵ J

Answer:

hello

Explanation:

hi

Answer:

Following are the solution to the given question:

Explanation:

Let us indicate H3AsO4, an H3A triprotic acid; the ionising equations are as follows:

[tex]\to H_3A \Leftrightarrow H^+ + H_2A^- \\\\[/tex]

[tex]\to Ka_1 = \frac{[H^+][H_2A^-]}{[H_3A]}[/tex]

          [tex]= 10-2.2 = 6.31 \times 10^{-3} \ \ \ \ \ \ \ \ [since\ pKa_1 = 2.2\ and \ Ka = -\log_{10}(pKa)]\\[/tex]

[tex]\to H_2A^{-} \Leftrightarrow H^{+} + HA_2^{-}; \\[/tex]

[tex]\to Ka_2 = \frac{[H^+][HA_2^-]}{[H_2A^-]} = 10-6.8 = 1.58 \times 10^{-7} \\(since pKa2 = 6.8)\\\\\to HA_2^- \Leftrightarrow H^+ + A_3^- ;\\\\ \to Ka_3 = \frac{[H^+][A_3^-]}{[HA_2^-]} = 10-11.6 = 2.51 \times 10^{-12} \\ (given pKa_3 = 11.6)[/tex]

The initial pH; we've 0.00 mL of 0.100 M NaOH – H3A is the main species; Ka1>>Ka2>>Ka3 is also noted. They therefore ignore H2A's disconnection but set up next ICE chart.

[tex]\to H_3A \Leftrightarrow H^+ + H_2A^- \\\\[/tex]

[tex]initial \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0.100 \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ 0 \\\\[/tex]

[tex]change \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ - x \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ + x \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ + x\\\\equilibrium \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ (0.100 - x) \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x\\\\[/tex]

[tex]Ka_1 = \frac{[H^+][H_2A^-]}{[H_3A]} = \frac{(x)(x)}{(0.100 - x)}[/tex]

[tex]\text{x to be much smaller than 0.100 M}\\\\to 6.31 \times 10^{-3} = \frac{x^2}{0.100}\\\\\to x^2 = 6.31 \times 10^{-4}\\\\ \to x = 0.025\ M\\\\\to pH = -\log_{10}[H^+] = -\log_{10}(0.025) = 1.60[/tex]

Answer:

2, 19, 12 and 14 are the coefficients.

Answer:

Look at the picture below

Explanation:

Answer:

c. 300 cal

Explanation:

To calculate the heat, we use the following equation:

heat = m x Cp x ΔT

Where m is the mass of water, Cp is the specific heat of water (which is 1 cal/g.°C) and ΔT is the change in temperature (calculated as the difference between the final T and the initial T).

We have the volume of water (10 ml) but not the mass. As the density of water is 1 g/ml, the mass of water is:

density = mass/volume ⇒ mass = density x volume = 1 g/ml x 10 ml = 10 g

The change in temperature (ΔT) is:

ΔT= Final T - Initial T = 25°C - (-5°C) = 30°C

Finally, we introduce the data to calculate the heat:

heat = 10 g x 1 cal/g.°C x 30°C = 300 cal

Therefore, the correct option is c. 300 cal

Answer:

[tex]3Li_2SO_4+2K_3PO_4\rightarrow 2Li_3PO_4+3K_2SO_4[/tex]

Explanation:

Hello!

In this case, when lithium sulfate and potassium phosphate solutions are mixed to yield lithium phosphate and potassium sulfate, the following chemical equation comes up:

[tex]Li_2SO_4+K_3PO_4\rightarrow Li_3PO_4+K_2SO_4[/tex]

However, as atoms are not balanced we apply the inspection method to obtain:

[tex]3Li_2SO_4+2K_3PO_4\rightarrow 2Li_3PO_4+3K_2SO_4[/tex]

Best regards!

Answer:

100 POINTS! (50 split up) PLSSSSSSSSSS HELP!!! I REALLY NEED IT SO MUCH :( I PROMICE TO GIVE BRAINLIEST AND FIVE STARS AND A THANKS! 6TH GRADE SCIENCE! i used all my points for this!

You measure the mass of an apple using a balance. You get these three measurements:

Trial 1: 167.0 g

Trial 2: 166.9 g

Trial 3: 167.2 g

You know that the true mass of the apple is 172 g. Describe your results in terms of precision and accuracy. Explain your answer in a paragraph for the best grade.

Explanation:

Answer:

[tex]2HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+H_2O(l)[/tex]

Explanation:

Hello!

In this case, since the neutralization reaction between hydrofluoric acid and barium hydroxide (both aqueous) produce insoluble barium fluoride and liquid water, we can write the chemical reaction as follows:

[tex]HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+H_2O(l)[/tex]

However, it needs to be balanced as hydrogen and fluorine are not properly balanced, therefore, we obtain:

[tex]2HF(aq)+Ba(OH)_2(aq)\rightarrow BaF_2(s)+H_2O(l)[/tex]

Best regards!

Answer:

A) 6.023*10^23

B)6.023*10^22

Explanation:

AVAGADRO it would take nearly 1 mole of chalk so

1 mole of any substance contain 6.023*10^23 particles.

AVAGADRO it would take nearly 1 mole of ink to print so

1 mole of any substance contain 6.023*10^23 particles.

King Tut's reign came to an end at 3350 years ago

Carbon-14 is a radioactive isotope that can decay. This isotope can be used to determine how long ago an organism died by knowing the ratio from 12C to 14C

Can be formulated

[tex]\tt Nt=No\dfrac{1}{2}^{t/t1/2}[/tex]

Or we can use :

[tex]t=-\frac{1}{\lambda }\text{ln}\left(\frac{{N}_{t}}{{N}_{0}}\right)\longrightarrow t=-\frac{1}{\lambda }\text{ln}\left(\frac{{\text{Rate}}_{t}}{{\text{Rate}}_{0}}\right)[/tex]

The half-life of C-14, 5730 years, so the decay constant :

[tex]\tt \lambda =\dfrac{\text{ln 2}}{{t}_{1\text{/}2}}=\dfrac{0.693}{\text{5730 y}}=1.21\times {10}^{-4}}[/tex]

Assume the initial C-14 activity was 13.6  disintegrations/min/g of C

[tex]\tt t=-\dfrac{1}{\lambda }\text{ln}\left(\dfrac{{\text{Rate}}_{t}}{{\text{Rate}}_{0}}\right)=-\dfrac{1}{1.21\times {10}^{-4}}\text{ln}\left(\dfrac{9.07}{13.6}\right)=\text{3348}\approx 3350~y[/tex]

Answer:

light blue

Explanation:

the second one

Answer:

Their number

Explanation:

Freezing is the process of decreasing the activity of the molecules in the medium and their arrangement will change to take on the new shape but no new molecules are added or taken away

Answer:

The Sugar Act (1764),

The Currency Act (1764),

The Quartering Act (1765),

The Stamp Act (1765)

Explanation:

All of these Led to the american Revolution.

Answer:

Every chemical equation adheres to the law of every conservation of mass and the states of matter cannot be created or destroyed  

Explanation:

Answer:

The answers to your questions are given below

Explanation:

To successfully answer the questions given above, it is important that we know the various units of measurement of volume, pressure and temperature respectively.

For Volume:

Some measuring units of volume include:

1. Litre (L)

2. Millilitre (mL)

3. Cubic centimetres (cm³) etc

For Pressure:

Some measuring units of pressure include:

1. Atmosphere (atm)

2. Millimetres of Mercury (mmHg)

3. Torr

4. Pascal (Pa)

5. Kilo pascal (KPa) etc

For Temperature:

Some measuring units of temperature include:

1. Kelvin (K)

2. Degree Celsius (°C)

3. Degree Fahrenheit (°F)

Now, we shall answer the questions given above as follow:

A. 56 °C => Temperature

B. 247.3 KPa => Pressure

C. 23.3 mL => Volume

D. 298 K => Temperature

E. 1.24 atm => Pressure

F. 482 torr => Pressure

G. 0.50 L => Volume

H. 120.9 mmHg => Pressure

Answer:1.395x10^27 molecules of O2

Explanation:

2Fe + 3/2O2 —> Fe2O3

for every 2 atoms of Fe, 1.5 molecules of O2 —> 1.395x10^27