my brain hurts. halp​

Ice forms as water is poured onto dry ice is a physical change .

So , option D is correct one .

The physical change is explained in following points ,

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The density  of the rectangular  solid is 0.378 g/ [tex]cm^3}[/tex] .

Density of rectangular solid is calculated by ratio of mass by volume of the of rectangular solid .

Density = mass / volume

mass = 74.319 g ( given )

length of the rectangular solid =  9.14 cm

wide of the rectangular solid = 3.82 cm

height of the rectangular solid  = 5.63 cm

volume = length × width × height  =  9.14 cm  × 3.82 cm × 5.63 cm

volume = 196.57 [tex]cm^3}[/tex]

putting the value of mass and volume in equation ( i ) we get ,

Density = mass / volume

Density = 74.319 g / 196.57 [tex]cm^3}[/tex]  = 0.378 g/ [tex]cm^3}[/tex]

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A metal (M) forms a compound with formula MCl₂. The compound contains 57.69% Cl by mass and the metal is Chromium. Symbol of Chromium metal is Cr.

Given :

57.69 % Cl by mass means that 57.69 grams of chlorine present in 100 grams of compound.

Mass of compound = 100 g

Mass of chlorine = 57.69 g

Mass of metal = 100 - 57.69= 42.31 g

First, we will calculate the moles of chlorine, using formula

Moles = Given mass

              molar mass

Moles = 57.69

              35.45

Moles = 1.627 moles

The given formula of compound is, MCl₂

Therefore, ratio of M : Cl = 1 : 2

We will calculate the moles of metal,

2 moles of Cl combines with 1 mole of metal

1.627 mole of Cl combines with 1.627 = 0.813 mole of metal

                                                        2

calculate the molar mass of metal -

Molar mass of metal =   Given mass  

                                           moles

Molar mass = 42.31  g     = 52.04 g/mol

                       0.813 mol

The molar mass of metal is 52.04 g/mole.

From this, we can conclude that the metal is Chromium (Cr)  

So, the formula will be, CrCl₂

Hence, the identity of the metal is Chromium (Cr)

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The atoms of covalent compounds are connected by covalent bonds. Sharing one or more pairs of valence electrons results in the formation of a covalent bond.

How to name covalent compound-

1. Give the elemental name of the non-metal that is on the periodic table that is farthest to the left.

2. Give the other non-metal's name and a suffix ending, such as -ide.

3. To denote the quantity of an element in a molecule, use the prefixes mono-, di-, tri-, etc.

4. Mono is understood and not written if it is the initial prefix.

Names of covalent compounds according to the question-

1. CO₂ - Carbon Dioxide

2. CO - Carbon Monoxide

3. N₂O₄ - Dinitrogen tetraoxide

4. PCl₃ - Phosphorus trichloride

5. CBr₄ - Tetra bromomethane

6. P₂O₅ - Phosphorus pentoxide

7. PCl₅ - Phosphorus pentachloride

8. NF₃ - Nitrogen Trifluoride

9. SO₂ - Sulfur dioxide

10. SO₃ - Sulfur trioxide

11. SCl₆ - sulfur hexachloride

12. SiCl₄ - Silicon tetrachloride

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We need to add 7.5 mL of distilled water to the 1% m/V HCI solution available.

The percent concentration is one of the common units of concentration that could be used to describe the amount of substance. Let us now try to obtain the volume needed.

Given that;

C1V1=C2V2

C1 = initial concentration

V1 = Volume of the stock solution

C2 = final concentration

V2 = volume of the new solution

Thus;

V1 = C2V2/C1

V1 = 0.25 * 10/1

= 2.5 mL

Hence, the volume of distilled water needed =  10mL - 2.5 mL

= 7.5 mL

Thus, we need to add 7.5 mL of distilled water to the 1% m/V HCI solution available.

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After 90 years amount of  Cs-137 isotopes has a half-life of 30 years. would remain is equal to = 0.125 grams.

An important and useful factor of radioactive decay is half of life, which is the amount of time it takes for one half of a radioactive isotope to decay. The half of-life of a selected radioactive isotope is constant; it is unaffected by way of situations and is independent of the initial quantity of that isotope.

The half of life of a chemical reaction can be defined because the time is taken for the awareness of a given reactant to attain 50% of its preliminary awareness. The half of-life of a response is the time required for the reactant's attention to decrease to at least one-half of its initial price. The half of-life of a first-order response is consistent this is associated with the charge consistent for the reaction. t1/2 = 0.693/k

Since all radioactive reaction follows first-order reaction, The rate of reaction does not depend on initial concentration.

calculation:-

1 gram Cs-137 at T = 0

after the first half,

⇒0.5 gram Cs-137 at T = 30

After the second half,

⇒0.25 gram Cs-137 at T = 30.

After the third half,

⇒0.125 gram Cs-137 at T = 90 years.

Hence, after 90 years amount of  Cs-137 would remain is equal to = 0.125 grams.

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Answer:

Explanation:

[tex]{ \rm{MCO_{3(s)} + HX _{(aq)} \: \rightarrow \: MX_{(s)} + CO _{2(g)} + H _{2}O _{(l)} }}[/tex]

- MCO_3; Can be any metal carbonate such as Magnesium carbonate, Aluminum carbonate.....

- HX; can be any acid such as sulphuric acid, hydrochloric acid, nitric acid.....

- MX; is a metal acidic salt such as magnesium sulphate from magnesium carbonate and sulphuric acid, Aluminum chloride from Aluminum carbonate and hydrochloric acid.

The total number of atoms in 0.160g of P2O5 is 3 x 10^21 atoms.

Atoms are defined as a smallest unit into which a matter can be divided without the release of electrically charged particles.

First calculate the number of mole of P2O5

Mass of P2O5 = 0.160 g

Molar mass of P2O5 = 142g/mole

Number of mole of P2O5 = mass/ molar mass

n = 0.160/142 g/mole

n = 0.0011 mole of P2O5

One mole of P2O5 has five mole of oxygen.

Using conversion factor

= 0.0011 mole of P2O5 x [ 5 mole of oxygen/ 1 mole of P2O5]

= 0.0055 mole of oxygen

Total number of atoms = 0.0055 x 6.02 x 10^23 atom/mole

                                      = 3 x 10^21 atoms

Thus, the total number of atoms in 0.160g of P2O5 is 3 x 10^21 atoms.

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The vapour pressure of methanol at 57.2°C is 66.3 kpa.

The enthalpy of vaporization for methanol,

              =35.2 kj/mol = 35.2×1000 j/mol                  

at temperature T2=  64.7°C = 64.7 + 273 = 337.4 K

temperature T1 = 57.2 °C = 57.2 + 273 = 330.2 K

vapour pressure P2 = 101.3 kpa

vapor pressure P1 = ?

Clausius - Clapeyron equation is geven as :

ln ( P1 / P2 ) =  ΔH / R ( 1 / T2 - 1 / T1 )

ln ( P1 / 101.3 kpa ) = 35200 j/mol / 8.314 j/Kmol × ( 1/337.4 K - 1/330.2 K)

ln ( P1 / 101.3 kpa)  =  [tex]e^{-0.423}[/tex]

P1 / 101.3 kpa = 0.655

P1 = 0.655 × 101.3 kpa

P1 = 66.3 kpa

Hence, The vapor pressure at 57.2°C is 66.3 kpa.

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Answer:

Studies have revealed that evaporation—the process by which water changes from a liquid to a gas—from oceans, seas, and other bodies of water (lakes, rivers, streams) provides nearly 90% of the moisture in our atmosphere. Most of the remaining 10% found in the atmosphere is released by plants through transpiration.

Explanation:

Answer:

250 cm ^3

Explanation:

To tolerate biting forces that average 28,000 psi, modern dental restorative materials have strengths in excess of dna psi.

Deoxyribonucleic acid is a polymer made of two polynucleotide chains that coil around one another to form a double helix and which contains the genetic material necessary for the growth, development, and reproduction of all known organisms as well as a large number of viruses. The two types of nucleic acids are DNA and RNA. One of the four major types of macromolecules that are necessary for all known forms of life is nucleic acids, along with proteins, lipids, and complex carbohydrates (polysaccharides).

Due to the fact that the two DNA strands are made up of more straightforward monomeric units known as nucleotides, they are referred to as polynucleotides. Each nucleotide consists of a phosphate group, a sugar called deoxyribose, and one of the four nucleobases that contain nitrogen: cytosine (C), guanine (G), adenine (A), or thymine (T).

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Answer:

The structure has a six-carbon ring which is represented by a hexagon and it includes 3-double bonds.

Answer:

the answer is A. Chlorine combines with sodium to form table salt

Answer:

D

Explanation:

most reasonable answer

The correct interpretation of Friar Lawrence's statement in Act III of Romeo and Juliet is: A. Angry people will not listen to reason.

In this scene, Friar Lawrence is expressing his frustration and realization that rational arguments and advice are ineffective when dealing with people who are consumed by anger or driven by their emotions. He sees that Romeo, who is filled with grief and rage after being banished, is not receptive to his reasoning and is acting impulsively.

The line suggests that when people are in a state of madness or extreme emotional turmoil, they become deaf to rational counsel and are unlikely to heed any advice or guidance.

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The spontaneous fission reaction is:  

₉₈ Cf ²⁵² → ₅₄ Xe ¹⁵⁰+ ₄₄ Ru ¹⁰⁸ +4 ₀n¹

Given,

Californium-252 undergoes spontaneous fission to produce xenon-140, ruthenium-108, and an unknown number of neutrons.

The Nuclear reaction is

₉₈ Cf ²⁵² → ₅₄ Xe ¹⁵⁰+ ₄₄ Ru ¹⁰⁸ +4 ₀n¹

Spontaneous fission reaction always happens in heavier elements, that is the element with atomic numbers more than 89 and mass numbers greater than 230.

The nuclei of these elements are unstable and decay by radioactive decay in different forms like beta decay, positron, etc. At some percentage of the time, they decay by spontaneous fission.

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The mass of the snow flakes that accumulates in one hour is 15552 Kg.

We know that area is the product of the length and the breadth of the lawn. We have to first obtain the area of the lawn as;

Length = 20.0 feet  

Width =  18.0 feet

Area =  20.0 feet   *  18.0 feet  = 360 square feet

If 1 square feet accumulates 450 new snowflakes every minute

360 square feet accumulates 360 square feet *  450 new snowflakes every minute/ 1 square feet

= 162000 new snowflakes every minute

If 162000 new snowflakes accumulates in one minute

x snow flakes accumulates in 60 minutes

x = 9720000new snowflakes

If 1 snow flake has a mass of 1.60 mg

9720000 new snowflakes has a mass of  9720000 snowflakes *  1.60mg/ 1 snow flake

= 15552000 mg or 15552 Kg

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Answer:

Methanol

Explanation:

Methanol is a compound and compounds are pure substances formed by the combination of elements; they can be decomposed by ordinary chemical means. The other answers are incorrect because they are elements and elements consists of only one kind of atom and they cannot be broken down into a simpler type of matter by either physical or chemical means.

The empirical formula of the given ions and name of their compounds are given below:

Empirical formula is the simplest formula of a compound where the elements in the compounds are shown in their simplest combining ratios.

The empirical formula of some compound are equal to the molecular formula of the compound whereas in some other, compounds, the empirical formulas are multiples of the molecular formula.

The empirical formula of the given ions and name of their compounds are given below:

Cation: Co³⁺; Anion; PO³⁻ ; Empirical formula : CoPO₄; Name : Cobalt (iii) phosphate

Cation: Fe²⁺  Anion; CrO₄²⁻  Empirical formula : FeCrO₄ ; Name : Iron (ii) tetraoxochromate (vi)

Cation: Cu²⁺  Anion; OH⁻  Empirical formula : Cu(OH)₂ ; Name : Copper (ii) hydroxide

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Answer:

40 km in a hour?

Explanation:

Answer:

Cu3(PO4)2

What is meant that mass cannot be created nor destroyed in the law of conservation of mass is that, matter can take part in a chemical reaction, but the initial mass of the matter (reactants) will be equal to the final mass of the matter (products formed).

The law of conservation of mass states that the mass can neither be created nor destroyed but it can be transformed from one form to another.

Examples of law of conservation of mass;

So, in the law of conservation of mass, the sum of the masses of the reactants in a chemical reaction and products formed in the process remains unchanged.

Thus, what is meant that mass cannot be created nor destroyed in the law of conservation of mass is that, matter can take part in a chemical reaction, but the initial mass of the matter (reactants) will be equal to the final mass of the matter (products formed).

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Answer:

The law of conservation of mass states that the mass can neither be created nor destroyed but it can be transformed from one form to another.

Explanation:

The mass of carbon dioxide is obtained as 236 g of carbon dioxide.

We know that the first step when we are trying to solve any type of question that involves stoichiometry is that we have to obtain the balanced reaction equation. This would show us the kind of interaction that is able to take place in order to obtain the results that we seek.

The reaction equation is given as;

C 3 H 8 + 5 O 2 → 3 CO 2 + 4 H 2 O

If 1 mole of propane occupies 22.4 L

x mole of propane occupies 40.2 L

x = 1 mole  * 40.2 L /22.4 L

x = 1.79 moles

Now;

1 mole of propane produced 3 moles of carbon dioxide

1.79 moles of propane produced 1.79 moles * 3 moles/1 mole

= 5.37 moles of carbon dioxide

Mass of carbon dioxide =5.37 moles * 44 g/mol = 236 g of carbon dioxide.

The mass of carbon dioxide is obtained as 236 g of carbon dioxide.

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Answer:

A sentence fragment is a sentence that is missing either its subject or its main verb.

Explanation:

Incorrect: Went to the store yesterday.

Incorrect: After the classes, the library. My life nowadays

Empirical formula is C4H7.

Empirical formula- A formula that lists the relative amounts of the constituent components in a compound without specifying the number or configuration of atoms.

When a hydrocarbon (CxHy) burns, CO2 and H2O are produced.

(Note: It mentions that a hydrocarbon is burned, which suggests that oxygen isn't present.)

moles of C in the compound: 44 g x 1 mol C/mole and 27.8 g CO2 x 1 mol CO2. = 0.632 moles of carbon

9.96 g H2O x 1 mol H2O/18 g x 2 mol H/mol H2O Equals 1.11 moles of H in the molecule.

We can calculate the mass and verify that it adds up to 8.70 g to rule out the presence of oxygen in the original molecule.

mass C=0.632 mol C times 12 g/mol equals 7.58 g C

H mass equals 1.11 mol H = 1.11 g H x 1 g/mol

Total mass Equals 8.69 g.

We may divide both by the lowest value (0.632), which will give us the lowest whole number of moles.

0.632/0.632 = 1.0 moles C

H = 1.11/0.632 = 1.75 moles.

Now we can multiply them by 4 to get H's whole number, which is-

C = 4 moles.

H = 7 moles

∴Empirical equation: C4H7

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Answer:

C

Explanation:

C is the right answer for this question.