my code get an input of 1900 and it should output not a leap year but it fails first line of code. It should output not a Leap any number with 1500 not divisble by 4 with/out a remainder should output (not a leap year. )


input_year = int(input())

if input_year % 4 == 0: #fails on this step, 1900 should be false
print(input_year, "- is Leap Year")

elif input_year % 100 == 0:
print(input_year, "- leap year")

elif input_year % 400 ==0:
print(input_year, "is a leap year")

else:
print(input_year, "- not a leap year")

Answers

Answer 1

Answer:

Explanation:

The code does not fail on the first step since 1900 divided by 4 is actually 475 and has no remainder, meaning that it should return True. The code won't work because the if statements need to be nested in a different format. The correct algorithm would be the following, which can also be seen in the picture attached below that if we input 1900 it would output is not a leap year as it fails on the division by 400 which gives a remainder of 0.75

input_year = int(input())

if input_year % 4 == 0:

   if input_year % 100 == 0:

       if input_year % 400 == 0:

           print(input_year, "is a leap year")

       else:

           print(input_year, "- not a leap year")

   else:

       print(input_year, "is a leap year")

else:

   print(input_year, "- not a leap year")

My Code Get An Input Of 1900 And It Should Output Not A Leap Year But It Fails First Line Of Code. It

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Answers

Answer:

Answered below.

Explanation:

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Answers

Answer:

The program in Java is as follows:

import java.util.*;

public class Main{

 public static void SelectionSorter(String[] my_array){

     System.out.print("\nAfter sort: ");

     for (int ind=0; ind < 22; ind++ ){

         int min = ind;

         for (int k=ind+1; k < 23; k++ )

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public static void main(String[] args) {

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 for ( int j=0; j < 23; j++ ){        System.out.print(myarray[j]+" ");    }

 SelectionSorter(myarray);

}

}

Explanation:

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 public static void SelectionSorter(String[] my_array){

This prints the header for After sort

     System.out.print("\nAfter sort: ");

This iterates through the array

     for (int ind=0; ind < 22; ind++ ){

This initializes the minimum index to the current index

         int min = ind;

This iterates from current index to the last index of the array

         for (int k=ind+1; k < 23; k++ )

This compares the current array element with another

         if (my_array[k].compareTo(my_array[min] ) < 0 ){ min = k;  }

If the next array element is smaller than the current, the elements are swapped

         String temp = my_array[ind];

         my_array[ind] = my_array[min];

         my_array[min] = temp;    }

This iterates through the sorted array and print each array element

   for (int j=0; j < 23; j++){   System.out.print(my_array[j]+" ");}

    }

The main begins here

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This declares the array

 String [] myarray = new String [23];

This gets input for the array elements

 for(int i= 0;i<23;i++){ myarray[i] = input.nextLine();  }

This prints the header Before sort

 System.out.print("Before sort: ");

This iterates through the array elements and print them unsorted

 for ( int j=0; j < 23; j++ ){        System.out.print(myarray[j]+" ");    }

This calls the function to sort the array

 SelectionSorter(myarray);

}

}

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Answers

Answer:

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Answers

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Answers

Solution :

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Answer:

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Explanation:

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Explanation:

Answer:

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Answers

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Answer:

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Explanation:

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Answers

Answer:

Q=It

and

p=IV

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I=P/V

I =7/9

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0-10
O Unknown
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Answers

Answer:

c. 10

Explanation:

Given

[tex]D3 = 30[/tex]

[tex]D4 = 20[/tex]

Required

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Answer:

Sorry mate I tried it was wrong

Explanation:

Sorry again

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