How are the sun and Earth's moon different? (2 points)
a
The sun is a ball of gases that revolves around Earth, while the moon is the center of the solar system.
b
The sun is a ball of rock and gas, while the moon is a ball of rock that revolves around the sun.
c
The sun is the center of the solar system, while the moon is a ball of rock that revolves around Earth.
d
The moon is the center of the solar system, while the sun is the center of the Milky Way.
However, in day-to-day experience, the strangeness of Einstein's ideas doesn't help us, and Newton's notions do just fine. In everyday Life, when gravity isn't especially intense, Newton's and Einstein's ways of thinking lead to similar results. The two explanations work like different languages that express the same thing.
—A Black Hole Is NOT a Hole, Carolyn Cinami DeCristofano
Why is it important to learn about Newton's view of gravity? *
It is similar to Einstein's theory.
It is important to know other languages.
It works in most daily situations.
It explains how a black hole works.
Answer:
It works in most daily situations.
Explanation:
:)
Answer:
C. It works in most daily situations.
Explanation:
Edge-nuity 2022
Granite cools very slowly from magma and therefore has very large crystals that are visible with the naked eye. Granite can be classified as —
A.
an igneous rock.
B.
a metamorphic rock.
C.
a sedimentary rock.
D.
an extrusive rock.
Answer:
A
Explanation:
Igneous rock forms from cooled lava
What is a net ionic equation? A. An equation that shows only those particles involved in the reaction, and that is balanced for mass but not for charge B. An equation that shows only those particles involved in the reaction, and that is balanced for both mass and charge C. An equation that describes the flow of oxygen in a combustion reaction D. An equation that shows the cations as reactants and the anions as products
Answer:
B. An equation that shows only those particles involved in the reaction, and that is balanced for both mass and charge
Explanation:
A net ionic equation is a chemical equation that will only show the elements, compounds, and ions that are directly involved in the chemical reaction. It comes from the balanced molecular equation and should be balanced by both mass and charge.
Groups of atoms repeat to make up a substance?
True
False
Answer:
ITS TRUE!!!!!
7. Which of the following physical changes is experienced by women during the luteal stage of the
menstrual cycle?
a. Mood swings b. Changes in appetite c. Depression or sadness d. Headaches or
backaches
Answer:
The correct answer is Choice D.
(Headaches or backaches)
Explanation:
Hope this helps!
Please mark me as Brainlinieast.
14. A 70 N tight rope walker is walking 20 meters above ground. About how much Gravitational Potential Energy does the performer have? 1,400 J 1,200 J 800 J
Answer:
It is 1,400 j
Explanation:
That is what i know
Answer:
1,400J
Explanation:
the formula for calculating Gravitational Potential Energy is mass×gravitational field strength×height
70×10×20=1,400
Choose all the nucleophiles.
Choose one or more:
CH3SNa
NaNH2
H3O+
CH3OH
CH3CH2CH3
NH4+
OH-
(CH3)3CLi
Answer:
CH3CH2CH3
(CH3)3CLi
CH3SNa
Explanation:
What is FALSE about nitrogen gas and carbondioxide?
1- Both are compounds
2- Both are gases
3- Elements in both substances are non-metals
4- Both are made up of atoms
Answer: Both are compounds
Explanation:
[tex]\text{N}_{2}[/tex] is an element, not a compound.
Why does the offspring have identical inherited traits as the parent?
Please help I'm not sure what the answers are
Answer:
An element's mass number (A) is the sum of the number of protons and the number of neutrons. The small contribution of mass from electrons is disregarded in calculating the mass number.
Predict the electron pair geometry and the molecular structure of each of the following molecules or ions: (a) ClNO (N is the central atom); Determine: electron-pair geometry ; molecular structure ; (b) CS2; Determine: electron-pair geometry ; molecular structure ; (c) Cl2CO (C is the central atom); Determine: electron-pair geometry ; molecular structure ; (d) Cl2SO (S is the central atom); Determine: electron-pair geometry ; molecular structure ; (e) SO2F2 (S is the central atom); Determine: electron-pair geometry ; molecular structure ; (f) XeO2F2 (Xe is the central atom); Determine: electron-pair geometry ; molecular structure ; (g) ClOF2 (Cl is the central atom); Determine: electron-pair geometry ; molecular structure ;
Answer:
See explanation
Explanation:
In ClNO , nitrogen is the central atom here. The central atom has a tetrahedral electron pair geometry and a lone pair on the nitrogen atom. Due to the lone pair, the electron pair geometry is now trigonal pyramidal.
The molecule CS2 has a linear molecular geometry. There are four electron groups around the central atom hence the electron pair geometry is tetrahedral but the molecular geometry results from the repulsion of the two double bonds.
The electron domain geometry for Cl2CO is tetrahedral since there are four electron pairs around the central atom. However, the molecular geometry is trigonal planar due to the sp2 hybridization of the central carbon atom.
The electron domain geometry of Cl2SO is tetrahedral due to the four electron pairs around the central atom. However, due to the lone pair on sulphur, the molecular geometry is triagonal pyramidal.
In SO2F2, sulphur the central atom is surrounded by four electron pairs which are all bonding groups hence both the molecular geometry and the electron pair geometry is tetrahedral.
In XeO2F2, the central atom is Xe. There are five electron pairs around the Xe central atom four of which are bonding groups. The electron domain geometry and molecular geometry is trigonal bipyramidal.
For ClOF2 , the central atom Cl is surrounded by four electron pairs hence the electron pair geometry is tetrahedral but it is an AX3E(three bonding groups and one lone pair are present in the structure) specie hence it is trigonal pyramidal.
What is the number of particles after gluecose is mixed with water
Answer: dissolves
Explanation:
When you stir a spoonful of sugar into a glass of water, you are forming a solution. This type of liquid solution is composed of a solid solute, which is the sugar, and a liquid solvent, which is the water. As the sugar molecules spread evenly throughout the water, the sugar dissolves.
1. A sample of oxygen gas has a volume of 150 ml when its pressure is 440 mmHg. If the pressure is
Increased to standard pressure and the temperature remains constant, what will the new volume be?
Answer:86.84
Explanation:
1. In nature, most organisms produce through sexual reproduction. However, there are some that undergo (4)_____. Plants like strawberries and potatoes grow without seeds and spores, instead of using (5)____. In (6)______, you have a single-celled organism that copies the information inside of itself and divides into two identical organisms. Through (7)______, new organisms like yeast grow on parent organisms and split off once they're mature enough to survive independently. This isn't to be confused with (8)_____, which involves organisms splitting apart and growing independently of one another.
Word Bank for #4-8:
• budding
• binary fission
• vegetative propagation
• asexual reproduction
• fragmentation
Answer:
(4) asexual reproduction (5) vegetative propagation (6) binary fission (7) budding (8) fragmentation
The correct words to fill the given blanks would be as follows:
4). A-s-e-x-u-a-l reproduction.
5). Vegetative propagation.
6) Binary fission
7). Budding
8) Fragmentation
Reproduction
Reproduction is denoted as the process by which living organisms generate their younger beings.
Some organisms generate through s-e-x-u-a-l mediums while others generate through the A-s-e-x-u-a-l process.
The a-s-e-x-u-a-l methods of reproduction include:
BuddingFragmentationBinary FissionVegetative Propagation.Spore FormationLearn more about "Organisms" here:
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The annual production of sulfur dioxide from burning coal, fossil fuels,
auto exhaust, and other sources is about 130 million tons. When solid sulfur
reacts with oxygen gas it produces gaseous sulfur dioxide. What is the mass
in grams of sulfur that is needed to produce 2.30 Kg of sulfur dioxide?
*Don’t forget from your metric you were given that 1 Kg = 1000 g.
Answer:
1150g
Explanation:
The equation for producing sulphur dioxide is [tex]S + O_{2} ==> SO_{2}[/tex]
Looking at the ratios, you need 1 mole of sulphur for every 1 mole of sulphur dioxide
Sulphur dioxide has a molar mass of 32 + (2 x 16) = 64g
2.30 x 1000 = 2300
2300 / 64 = 35.9375
35.9375 x 32 = 1150g of sulphur
There is a series of nitrogen oxides with the general formula N?O?. What is the empirical formula of one that contains 63.66% nitrogen?
Answer:
N₂O
Explanation:
Empirical formula is defined as the simplest whole number ratio of atoms presents in a molecule
For a nitrogen oxide that contains 63.66% of nitrogen, the percent of oxygen must be:
100-63.66 = 36.34% Oxygen
This percent is the percent in mass. To solve this question we must convert the mass of each atom to moles in order to find the simplest whole number ratio:
Moles of the atoms:
N = 63.66g * (1mol / 14g) = 4.547 moles N
O = 36.34g * (1mol / 16g) = 2.271 moles O
The ratio N:O is:
4.547 moles N / 2.271 moles O = 2
That means there are 2 atoms of N per atom of O and the empirical formula is:
N₂OOne tank of gold fish is fed the normal amount of food once a day. A second tank is fed twice a day. A third tank is fed four times a day during a six week study. The fish's weight is recorded daily. What is the problem and the hypothesis?
Answer:
Problem: What is the effect of the amount of fish feed on the mass of goldfish?
Hypothesis: I think that feeding the goldfish four times a day will greatest increase in the mass of the goldfish.
Explanation:
The problem tends to ask question to which the research is conducted. It open ways for ideas towards a particular topic.
While the hypothesis is a tentative or assumed stand on a subject. It is further tested through an experiment or survey and if after many trials it gives same results and the obtained results is concordant with the hypothesis, the hypothesis will then become accepted and a theory or law is formed thereafter.
18) What is the following number representing: 10m/s West *
3 points
Force
Acceleration
Mass
Area
Pressure
Velocity
Speed
Impulse
Momentum
Speed
Explanation:
The distance travelled by a body per unit time
What experimental evidence led Rutherford to conclude the following: (a) The nucleus of the atom contains most of the atomic mass. The nucleus of the atom contains most of the mass since only a collision with a very dense, massive object would cause an alpha particle to be the source. (b) The nucleus of the atom is positively charged. The positive alpha particles their initial flight indicating that the nucleus of the atom is also positively charged. (c) The atom consists of mostly empty space. Most alpha particles pass through the gold foil leading to the conclusion that the atom is mostly empty space.
Answer:
See Explanation
Explanation:
The experiment of Ernest Rutherford involved the bombardment of a thin gold foil with alpha particles from a radioactive source. A zinc sulphide screen was used to follow the movement of the alpha particles.
It was discovered that most of the alpha particles followed a straight path through the gold foil. Some of them were scattered through large angles and few were even scattered in the backward direction.
Since alpha particles were heavier than electrons, they must have been deflected by very strong forces.
These experimental evidences led to the conclusions stated in the question.
When a 0.3546 g of vanadium metal is heated in air, it reacts with oxygen to achieve a
final mass of 0.6330 g. Calculate the empirical formula of this vanadium oxide
Answer:
V2O5 is the empirical formula of vanadium oxide
Explanation:
The molecular mass of Vanadium is 50.949 g/mol
Number of moles of vanadium = 0.3456 g/50.949 g/mol = 0.00696 moles
The molecular mass of Oxygen is 16.0 g/mol
Number of moles of Oxygen = (0.6330 – 0.354) g/16 g/mol = 0.0174 moles
Emperical formula
V (0.00696 moles/0.00696 moles) O (0.0174 moles /0.00696 moles)
V 1 O2.5
Multiply by two get a whole number
V2 O5
How many moles are in 1.3 x1023 atoms of He?
Answer:
he ans she and he and she but she was he so how was he
Explanation:
The use of uranium-238 to determine the age of a geological formation is a beneficial use of
O 1.
nuclear fusion
2.
nuclear fission
3.
radioactive isomers
4.
radioactive isotopes
Answer:
4- radioactive isotopes
Explanation:
I don't remember exactly but this question was on the regents
Uranium-238 is a non- fissile element. It is a radioactive isotope that can be best used to determine geological formations. Thus, option 4 is correct.
What are radioactive isotopes?Radioactive isotopes are elements that have an unstable atomic nucleus and can undergo radioactive decay to produce new particles and energy. They have the same atomic number as that of their parent species.
Isobars are a substance that has atomic mass and do not include uranium. Nuclear fusion and fission are the processes of nuclear energy that combine or splits the unstable nucleus to form a new particle.
Therefore, option 4. Uranium-238 is a radioactive isotope.
Learn more about radioactive isotopes here:
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Sven perform this reaction with 15.0 grams of sodium sulfate and an excess of iron (III) phosphate to make iron (III) sulfate and sodium phosphate. In the actual experiment, 10.0 grams of sodium phosphate are experimentally made, what is the percent yield?
2FePO4+3Na2SO4-->Fe2(SO4)3+2Na3PO4
Answer:
85.5%
Explanation:
To get the experimental value, you need to convert 15.0 grams of Na2SO4 to grams of Na3PO4. You do this with stoichiometry.
Convert grams of Na2SO4 to moles with molar mass. Then convert to moles of Na3PO4 with the mole-to-mole ratio according to the balanced chemical equation. Then convert moles of Na3PO4 to grams with the molar mass.
15.0 g Na2SO4 x (1 mol/142.04 g) x (2 Na3PO4/3Na2SO4) x (163.94 g/1 mol) = 11.7 g Na3PO4
Percent Yield = (actual value/experimental value) x 100
Actual Value = 10.0 g
Experimental Value = 11.7 g
10.0g/11.7 g = 85.5%
A weak base. B. has a K. of 4.46 x 10-10 A solution with an unknown initial concentration is tested, and found to have a pH of 8.39. Determine the initial concentration of B.
Answer:
0.013MB
Explanation:
What is the standard units of mass, length and time in the (a) CGS system (b) SI system
Explanation:
a. CGS system: centimetre as the unit of length, the gram as the unit of mass, and the second as the unit of time
b. SI system: metre as the unit of length, the kilogram as the unit of mass, and the second as the unit of time
If a nuclear reactor were to have a meltdown, radioactive materials could escape in the form of gases from the reactor into the atmosphere and harm humans and the environment. One safety system that might be able to prevent such an escape is a:
A containment building.
hope this helpedddd
how can we find out the mass of the marble
In a collection of marbles, 25% of the marbles have a mass of 5.00 g and 75% of the marbles have a mass of 7.00 g. The average mass of a marble is 6.50 g.
How much water needs to be added
to 55 mL of 3.0 M stock solution to
produce a .75 M solution?
Answer:
165 ml
Explanation:
We are given;
Initial volume; V_a = 55 ml
Initial molarity; M_a = 3 M
Molarity of desired solution; M_b = 0.75 M
Volume of desired solution; V_b = (55 + x) ml
Where x is the volume of water to be added.
To solve for V_b, we will use the equation ;
M_a•V_a = M_b•V_b
V_b = (M_a•V_a)/M_b
V_b = (3 × 55)/0.75
V_b = 220 mL
Thus;
(55 + x) = 220
x = 220 - 55
x = 165 mL
Answer:
gotta concert mL to L
3.0=mol/0.055( you multiply morality and liter)
0.165 mol
you divide the mole by the other given molarity
0.165/0.75= 0.22 L
0.22 *1000= 220 mL
Explanation:
2 questions. will give brainliest if i can figure out how
What happens to the electrons of a reducing agent during a reaction?
a.Electrons are gained
b.Electrons are lost
c.Electrons are held
d.Electrons are doubled
When is a substance reduced during an oxidation reduction reaction?
a.After one substance is oxidized
b.Before one substance is oxidized
c.Same time as one substance is being oxidized
d.Only oxidation occurs
1= b. electrons are lost
2= a. after one substance is oxidized