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A food package is dropped from a helicopter flying horizontally at a height of 125m. If the magnitude of the velocity of the packageafter 2seconds is 25m/s. Find

a. The speed of the helicopter at the moment the package is dropped.

b. The position of the package after 2s.

c. The time of flight of the food package

d. The horizontal distance covered.​

Answers

Answer 1

Answer:

a. The speed of the helicopter at the moment the package is dropped is approximately 15.519 m/s

b. The position of the package 2s after it is dropped is (31.038 m, -9.8 m)

c. The time of flight of the food package is approximately 5.105 seconds

d. The horizontal distance covered is approximately 79.22 m

Explanation:

The given parameters are;

The height at which the helicopter is flying = 125 m

The magnitude of the velocity of the package after 2 seconds, v = 25 m/s

a. The vertical velocity of the package, [tex]v_y[/tex], is given as follows;

[tex]v_y[/tex] = [tex]u_y[/tex] + g·t

Where;

[tex]u_y[/tex] = 0 m/s for the dropped food package

t = The duration of the package in the air = 2 s

g = The acceleration due to gravity = 9.8 m/s²

Therefore;

[tex]v_y[/tex] = g·t = 9.8 m/s² × 2 s = 19.6 m/s

We have,  [tex]v = \sqrt{v_x^2 + v_y^2}[/tex],

Where;

vₓ = The horizontal velocity of the food package = The horizontal speed of the helicopter

therefore, [tex]v_x = \sqrt{v^2 - v_y^2}[/tex], which gives;

[tex]v_x = \sqrt{v^2 - v_y^2} = \sqrt{25^2 - 19.6^2} \approx 15.519 \ m/s[/tex]

The speed of the helicopter at the moment the package is dropped ≈ 15.519 m/s

b. The vertical if the package after 2 s is given as follows;

The vertical position of the package after 2 s is given by the kinematic equation, h = 1/2·g·t² = 1/2 × 9.8 m/s² × 2 s = 9.8 m

The food package is located 9.8 m vertically below the point where it is dropped

The horizontal position, x, of the package after 2 s is given by the following kinematic equation, x = vₓ × t

Therefore, x = 15.519 m/s × 2 s ≈ 31.038 m

The coordinates of the location of the package 2 seconds after it is dropped is (31.038 m, 9.8 m)

c. The time of flight, [tex]t_{tot}[/tex], of the food package which is the time it takes the package to reach the ground from 125 m, is given as follows;

[tex]t_{tot} = \sqrt{\dfrac{2 \cdot h}{g} } = \sqrt{\dfrac{2 \times 125 \ m}{9.8 \ m/s^2} } \approx 5.051 \ seconds[/tex]

The time of flight of the food package, [tex]t_{125}[/tex] ≈ 5.105 seconds

d. The horizontal distance covered, [tex]x_{tot}[/tex] = vₓ × [tex]t_{tot}[/tex] ≈ 15.519 m/s × 5.105 s = 79.224495 m ≈ 79.22 m.


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Answers

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Answers

Answer:

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Explanation:

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You drive 10 meters backwards and then 20 more meters backwards in 30 seconds. What is your average velocity?

Answers

Answer:

Average velocity= 1 m/s

Explanation:

Step one:

given data

total distance covered =  10 meters backwards+  20 more meters backwards

toatal distance= 10+20= 30 meters

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Required

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Step two:

the expression for the average velocity is

Average velocity= total distance/total time taken

Average velocity= 30/30

Average velocity= 1 m/s

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Answers

Answer:

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Answers

Answer:

C,D

Explanation:

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Answers

Answer:

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Explanation:

Momentum

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Since all objects have mass, if it's moving, then it has momentum. It can be calculated as the product of the mass by the velocity of the object:

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If only magnitudes are considered:

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p = 1,000 kg * 35 m/s

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The momentum of the car is 35,000 kg.m/s

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Momentum

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If m is the mass and v is the velocity of an object, then the object's momentum p is given below.

[tex]p = mv[/tex]

Given that the mass of the car is m=1,000 kg and travels at v=35 m/s. The momentum is given below.

[tex]p = 1000 \times 35[/tex]

[tex]p = 35000 \;\rm kg m/s[/tex]

Hence we can conclude that the momentum of the car is 35000 kgm/s.

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Answers

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Answer:

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Explanation:

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Answers

Answer:

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Explanation:

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Answers

Answer:

1,378.9ms²

Explanation:

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Required

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

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Given parameters:

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Answers

Answer: 588.9 m/s

Explanation:

Given that :

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Time, t = 10 seconds

From trigonometry ;

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

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Answers

Answer:

If the temperature of the air in the balloon is less than the temperature of the air surrounding the balloon then the balloon will appear slightly deflated because of the difference in temperature.

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Answers

Answer:            Below...

Explanation:

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Derived Quantities:          can be defined through the fundamental quantities... some examples are velocity, volume, pressure

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Answers

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Explanation:\\\

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Answers

Answer:

The first one is: His weight on the Earth before take-off and the weight after take-off back on Earth once he gets back should be recorded as his Independent variable and his dependent variable.

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Answers

Answer:

c

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the first 35 to 40 acceleration will be 5 same as 40 to 45 ,

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"Speed is the distance traveled per unit of time. It is how fast an object is moving. Speed is the scalar quantity that is the magnitude of the velocity vector. It doesn't have a direction."

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