Omg I just got 17/25 questions wrong using this on an Ag test , but got 100’s every time on health

Answer:

All of the above

Explanation:

Answer:

c

Explanation:

I live in britian

Answer:

Hp = 23.86 m

Hence, 23.86 m head pump is required for this flow.

Explanation:

Solution:

Data Given:

Elevation = Z = 14.9 m

Friction of the ductile iron pipe = f = 0.019

Length of the ductile iron pipe connecting the reservoirs = 22.4 m

Diameter of the Pipe = D = 0.5 cm

Radius of the Pipe = r = D/2 = 0.25 cm

Performance Curve of the Pump = Hp = 23.9 - 7.59[tex]Q^{2}[/tex] , where Hp is in meters.

[tex]Q^{}[/tex] is in Liters/second and equation is valid for 1.5 L/s

We are asked to find out the pump head required for this flow.

We need to apply the energy equation for this problem:

Energy Equation:

[tex]\frac{P1}{\beta 1} + \frac{v1^{2} }{2g} + Z1 + Hp = \frac{P2}{\beta 2} + \frac{v2^{2} }{2g} + Z2 + H_{L}[/tex]

where, [tex]\beta[/tex] = specific weight of the fluid.  

v1 = 0

P1 = P2 = P

Z1 = 0

Z2 = 14.9

Hence,

New equation is:

[tex]Hp = \frac{v2^{2} }{2g} + Z2 + H_{L}[/tex]

And

[tex]H_{L}[/tex] = [tex]\frac{fLv^{2} }{2gD}[/tex]

So,

[tex]Hp = \frac{v2^{2} }{2g} + Z2 + \frac{fLv^{2} }{2gD}[/tex]

Now, converting formula of v into terms of Q, we get

Hp = 23.9 - 7.59[tex]Q^{2}[/tex]

[tex]Hp = \frac{Q2^{2} }{2(9.81)(\frac{\pi }{4}(0.05^{2}))^{2} } + 14.9 + \frac{(0.09)(22.4)Q^{2} }{12.1(0.05)^{2} }[/tex]

23.9 - 7.59[tex]Q^{2}[/tex] = [tex]\frac{Q2^{2} }{2(9.81)(\frac{\pi }{4}(0.05^{2}))^{2} } + 14.9 + \frac{(0.09)(22.4)Q^{2} }{12.1(0.05)^{2} }[/tex]

Solving for Q, we will get

9 - 7.59[tex]Q^{2}[/tex] = 13233.71[tex]Q^{2}[/tex] + 112555.37[tex]Q^{2}[/tex]

[tex]Q^{}[/tex] = 7.154 x [tex]10^{-5}[/tex] [tex]m^{3}/s[/tex]

Converting it into L/s

Q = 0.0715 L/s

Putting this value of Q into the Hp equation to get the required answer:

Hp = 23.9 - 7.59[tex]Q^{2}[/tex]

Hp = 23.9 - 7.59 x [tex]0.0715^{2}[/tex]

Hp = Pump head

Hp = 23.86 m

Hence, 23.86 m head pump is required for this flow.

Answer:

try b

Explanation:

Answer:

While driving in reverse gear it necessary to have reverse audible alarm , a spotter and a rear view mirror.

Explanation:

It is prefer that to not drive a vehicle in reverse. But if we are driving in reverse gear it is necessary to have a reverse audible alarm , a spotter and a rear view mirror.

Answer:

Following are the solution to this question:

Explanation:

[tex]\to \Sigma F_x = ma_x \\\\\to 3200 t^2 -440 (9.81) (\frac{8}{17}) = 440 (a) \\\\\to 3200 t^2 -2031.24 = 440 (a)\\\\\to a= 7.27t^2 -4.616\\\\\to dv=a.dt \\\\\to \int^{v}_{2} dv = \int^{2}_{0} (7.27t^2 -4.616) dt\\\\\to v-2 = 7.27 \frac{t^3}{3} - 4.616 t^{2}_{0}\\\\\to v-2 = 7.27 \frac{2^3}{3} - 4.616 {2} \\\\\to v-2 = 10.154\\\\\to v= 12.154 \ \frac{m}{s}\\[/tex]

Answer:

Sarah is a professional interior designer.

Therefore, Sarah carries the title of a _registered___ interior designer.

Explanation:

Some states require only the licensed designers to carry out interior designs, while some others allow both the licensed and unlicensed interior designers to carry on the work of interior designers.  In the states where only the licensed designers are allowed to use the title of interior designer, they are registered after passing the state-prescribed examinations and meeting some professional experience requirements. The most common exam is the National Council for Interior Design Qualification (NCIDQ) examination, which only bachelor degree holders in interior design are allowed to sit for.

Answer:

Two technicians are discussing HD-OBD for trucks

Technician a says that the simplest most familiar definition is the diagnostic function of electronic control system to identify or self-diagnose system fault and report fault codes.

Technician A is correct.

Explanation:

Onboard Diagnostics (OBD) is a vehicle's self-diagnostic tool which enables technicians to access the diagnostic information for the purpose of performance monitoring and analyzing repair needs of vehicles.  OBD2 is the diagnostic system that is included in every vehicle made after 1996.  The diagnostics can check the engine and other vehicle systems and also communicate possible vehicular glitches that happen.

Answer:

a = 40

b = 29

Explanation:

Give a place holder for the numbers that we don't know.

Lets call the two numbers a and b.

From the given info, we can write an expression and solve it:

"one number is 11 more than another number"

a = 11 + b

from this, we know that a > b.

''three times the larger number exceeds four times the smaller number by 4"

3a = 4b + 4

Now we have 2 equations, we can use them to solve using whatever method you want.

a = 11 + b

3a = 4b + 4

I will be using matrices RREF to solve for this.

a - b = 11

3a - 4b = 4

[tex]\begin{bmatrix}1 & -1 & 11\\3 & -4 & 4 \end{bmatrix}[/tex]

[tex]\begin{bmatrix}1 & 0 & 40\\0 & 1 & 29 \end{bmatrix}[/tex]

a = 40

b = 29

Answer: the drawdown of the lake in centimeters is 3.02 cm

Explanation:

Given data;

Power of motor = 1000 W

efficiency M = 50% = 0.5

so Effective power = 1000 × 0.5 = 500 W

time t = 2 hrs = 2 × 60 × 60 = 7200 secs

so

Energy = p × t = 500 × 7200 = 3,600,000 J

Now Energy required to pump water to height h = mgh (J)

3,600,000 J = mgh

m = 3,600,000 / gh

given that; h is 2.43 and we know that g is 9.81, we substitute

m = 3,600,000 / (9.81 × 2.43)

m = 3,600,000 / 23.8383

m = 151017.48 kg

Now we know that, Volume = Mass / Density          [density of water]

so, Volume = 151017.48  / 1000

Volume = 151.01748 kg/m³

given that surface area = 5000 m²

Drawdown = 151.01748 / 5000

Drawdown = 0.3020 m

we convert to centimeter

Drawdown = 0.3020 m × 100

Drawdown = 3.02 cm

Therefore the drawdown of the lake in centimeters is 3.02 cm

Answer:

The powertrain system is one of the major systems on the vehicle.

Tech B states that this system usually contains the engine and transmission.

Technician B is correct.

Explanation:

The powertrain system contains three interconnected systems: the engine, the transmission, and the drivetrain.  The engine part is the power source of the powertrain that ensures vehicular movement.  The transmission system converts the engine's power into the normal movement of the vehicle.  The drivetrain consists of the transmission, driveshafts, and the axles.  These three parts of the powertrain system work seamlessly to ensure that the vehicle is able to move with some speed back and front, as may be desired.

The initial enthalpy and the entropy of the saturated water can be found out from the table of A-12E

i.e.   [tex]$h_1= 101 \ \text{Btu/lbm}$[/tex]

       [tex]$s_1 = 0.22717 \text{ Btu/lbmR}$[/tex]

Since the process mentioned above is an adiabatic compression process, the entropy will remain constant throughout the process. Therefore, we take the value of entropy and the final pressure using the table with few interpolations and also approximations to find the final enthalpy. It is given by :

       [tex]$h_2= 116.09 \text{ Btu/lbm}$[/tex]

So the work input from the energy balance equation :

       [tex]$\dot{W} + \dot{m}h_1 = \dot{m}h_2$[/tex]

          [tex]$w=h_2 - h_1$[/tex]

              = 116.09 - 101

              = 15.09

Therefore, [tex]$w= 15.09 \text{ Btu/lbm}$[/tex]

Answer:

It's False

Explanation:

I did the assignment

Answer:

[tex]y = \cos[\ln x + \ln (5\cdot x - 2)]\cdot \left(\frac{1}{x} + \frac{5}{5\cdot x-2} \right)[/tex]

Explanation:

Let [tex]y = \sin[\ln(5\cdot x^{2}-2\cdot x)][/tex] and we proceed to find the derivative by the following steps:

1) [tex]y = \sin[\ln(5\cdot x^{2}-2\cdot x)][/tex] Given

2) [tex]y = \sin [\ln[x\cdot (5\cdot x - 2)]][/tex] Distributive property

3) [tex]y = \sin[\ln x + \ln (5\cdot x - 2 )][/tex] [tex]\ln (a\cdot b) = \ln a + \ln b[/tex]

4) [tex]y = \cos[\ln x + \ln (5\cdot x - 2)]\cdot \left(\frac{1}{x} + \frac{5}{5\cdot x-2} \right)[/tex]  [tex]\frac{d}{dx} (\sin x) = \cos x[/tex]/[tex]\frac{d}{dx}(\ln x) = \frac{1}{x}[/tex]/[tex]\frac{d}{dx}(c\cdot x^{n}) = n\cdot c\cdot x^{n-1}[/tex]/Rule of chain/Result

Answer:

Answer

have PPE on wash hands after

Explanation:

Answer:

----------

Explanation:

Ancient machines have paved the way for improvement by being the foundation for change. these machines made it possible to find flaws so in the next generations, they could fix, develop, and produce better quality machines. eventually this process has reached the present time but after today, the process will continue to produce even better quality machines than the time before. I hope this helps!

Answer:

Kimi have done to ensure that she was acting legally and ethically by following the measure that are discussed below in detail.

Explanation:

Legal measures are those measures that are outlined in regulatory laws. Ethical measures are based on the human postulates of morality and wrongdoing. The distinctions between them are these: Legal measures are based on transcribed law, while ethical measures are based on human rights and violations.

Answer:

because it had a virus

Explanation:

You're welcome. Mark me brailiest

The distance when the civil construction plans shows a distance of 131 meters across the front of a piece of property is 430 feet.

From the information given, it was stated that the civil construction plans shows a distance of 131 meters across the front of a piece of property.

Therefore, since one foot equals approximately 0.305 meters, the distance will be:

= 131/0.305

= 429.5 feet

= 430 feet approximately

In conclusion, the distance is 430 feet.

Learn more about distance on:

https://brainly.com/question/17273444

Answer:

Explanation:

Given;

current at resonance, I = 0.2 mA

applied voltage, V = 250 mV

resonance frequency, f₀ = 100 kHz

capacitance of the circuit, C = 0.04 μF

At resonance, capacitive reactance ([tex]X_c[/tex]) is equal to inductive reactance ([tex]X_l[/tex]),

[tex]Z = \sqrt{R^2 + (X_ l - X_c)^2} \\\\But \ X_l= X_c\\\\Z = R[/tex]

Where;

R is the resistance of the circuit, calculated as;

[tex]R = \frac{V}{I} \\\\R = \frac{250 \ \times \ 10^{-3}}{0.2 \ \times \ 10^{-3}} \\\\R = 1250 \ ohms[/tex]

The inductive reactance is calculated as;

[tex]X_l = X_c = \frac{1}{\omega C} = \frac{1}{2\pi f_o C} = \frac{1}{2\pi (100\times 10^3)(0.04\times 10^{-6} ) } = 39.789 \ ohms\\[/tex]

The inductance is calculated as;

[tex]X_l = \omega L = 2\pi f_o L\\\\L = \frac{X_l}{2\pi f_o}\\\\L = \frac{39.789}{2\pi (100 \times 10^3)} \\\\L= 6.3 \ \times \ 10^{-5} \ H\\\\L = 0.063 \times \ 10^{-3} \ H\\\\L = 0.063 \ mH[/tex]

Answer: [tex]\dfrac{-1}{16(x+4)^{\frac{3}{2}}}[/tex]

Explanation:

Given

[tex]y=\dfrac{\sqrt{x+4}}{4}\\\text{differentitate w.r.t x}\\\dfrac{\mathrm{d} y}{\mathrm{d} x}=\dfrac{1}{4}\times \dfrac{1}{2\sqrt{x+4}}=\dfrac{1}{8\sqrt{x+4}}[/tex]

[tex]\dfrac{\mathrm{d} y}{\mathrm{d} x}=\dfrac{(x+4)^{-0.5}}{8}[/tex]

Again differentiate for the second derivative

[tex]\frac{\mathrm{d^2} y}{\mathrm{d} x^2}=\dfrac{1}{8}\times \dfrac{-1}{2(x+4)^{\frac{3}{2}}}=\dfrac{-1}{16(x+4)^{\frac{3}{2}}}[/tex]

Answer: [tex]-\dfrac1{16}(x+4)^{-\frac32}[/tex] ; x ≥ -4.

Explanation:

Given: [tex]y=\dfrac{\sqrt{x+4}}{4}[/tex] ; x ≥ -4.

First derivative = [tex]\dfrac{dy}{dx}=\dfrac12\times\dfrac{(x+4)^{-\frac12}}{4}[/tex]        [tex][ \dfrac{d(x^n)}{dx}=nx^{n-1} ][/tex]

[tex]=\dfrac{1}{8}(x+4)^{-\frac12}[/tex] ; x ≥ -4.

Second derivative=  [tex]\dfrac{d^2y}{dx^2}=\dfrac{d}{dx}(\dfrac18(x+4)^{-\frac12})[/tex]

[tex]=\dfrac18\times-\dfrac12(x+4)^{-\frac12-1}\\\\=-\dfrac1{16}(x+4)^{-\frac32}[/tex]

The second derivative of y = [tex]-\dfrac1{16}(x+4)^{-\frac32}[/tex] ; x ≥ -4.

Answer:

What you should do changes based on the hazards you're exposed to.

You should be aware of any hazards that are present.

Answer:

a

Explanation:

aaaaaa

Answer:

the action of building something, typically a large structure.

Explanation:

mark me brainliest

The typical journal-to-bearing clearance for engines is,

B) 0.0005 to 0.0025 inch

Given that,

To find the typical journal-to-bearing clearance for engines.

Now, The range 0.0005 to 0.0025 inch represents the recommended clearance between the rotating journal of the crankshaft and the bearing surface to ensure proper lubrication and minimal friction.

Hence, The correct option for typical journal-to-bearing clearance for engines is,

B) 0.0005 to 0.0025 inch.

To learn more about journal-to-bearing visit:

https://brainly.com/question/16971319

#SPJ4

This question is incomplete, its missing an image which will be uploaded along this Answer.

Answer:

the normal component of force F_n is F((√(r²-s²)) / r)

the tangential component of force F_t is F(s/r)

Explanation:

Given the data in the image;

from the free body diagram, we write the expression for ∅

sin∅ = s/r

cos∅ = (√(r²-s²)) / r

now expression for normal component of force is;

F_n = Fcos∅

we substitute

F_n = F((√(r²-s²)) / r)

Therefore, the normal component of force F_n is F((√(r²-s²)) / r)

Also for force F_t

F_t = Fsin∅

we substitute

F_t = F(s/r)

Therefore, the tangential component of force F_t is F(s/r)