On a chilly 12∘C day, you quickly take a deep breath--all your lungs can hold, 4.0 L. The air warms to your body temperature of 37∘C.
If the air starts at a pressure of 1.0 atm, and you hold the volume of your lungs constant (a good approximation) and the number of molecules in your lungs stays constant as well (also a good approximation), what is the increase in pressure inside your lungs?

Answer:

Moving slower in the negative direction.

Explanation:

This pig has an initial velocity of -10 (negative) and is accelerating at a rate of 2 m/s/s (positive). Since the acceleration has an opposite sign than the velocity, the object will be slowing down. Since the initial velocity was negative, it will be slowing down in the negative direction.

The term which is described as a seamount with a flattened top is called as guyots.

Guyot, commonly known as Tablemount, is an uninhabited submarine volcano with a flat peak that is more than 200 meters (660 feet) above sea level. These flat summits could be more than 10 kilometres in circumference (6 miles).

Seamounts called guyots have grown above sea level. The seamount's top was eroded by erosion by waves, leaving it with a flattened shape. The sea bottom gradually falls as a result of the ocean floor moving away from oceanic ridges, submerging the flattened guyots to form undersea flat-topped peaks. Once the guyot is formed, on it's top a coral colony will start developing and little by little make a circle shaped island, which represents the formation of the atoll.

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Answer:

20000J or 20kJ

Explanation:

Given parameters:

Efficiency of the battery = 80%

Amount of energy transferred  = 16000J

Unknown:

How much energy was transferred to the battery = ?

Solution:

Since the battery is 80% efficient, it loses 20% of energy anytime it wants to store energy.

 Now, 16000J of energy is contained in the battery, the original amount of energy sent to the battery;

   Let the amount of energy sent to the battery be y

  80% of y  = 16000

       0.8y  = 16000

            y  = 20000J or 20kJ

Answer:

The value is  [tex]S_a = 72.56 \ dB[/tex]

Explanation:

From the question we are told that

     The sound level is  [tex]S = 60 dB[/tex]

     The distance from the source is d = 1 m  

     The number of sources  is  n =  18

Generally the sound which the person is been exposed to is mathematically represented as

            [tex]S_a = S + 10log(18)[/tex]

=>         [tex]S_a = 60 + 10log(18)[/tex]

=>         [tex]S_a = 72.56 \ dB[/tex]

Answer:

im not really good at explaining, but i found this website url:

https://www.numerade.com/questions/a-cyclist-travels-from-point-a-to-point-b-in-10-min-during-the-first-20-min-of-her-trip-she-maintain/

same question just with the explanation

Given :

A copper rod has a length of 1.7 m and a cross-sectional area of [tex]3.2 \times 10^{-4} \ m^2[/tex].

One end of the rod is in contact with boiling water and the other with a mixture of ice and water.

To Find :

The mass of ice per second that melts.

Solution :

Amount of heat transfer from boiling water to ice through the copper bar is :

[tex]Q = \dfrac{kA\Delta T }{L}\\\\Q = \dfrac{390\times 3.2 \times 10^{-4} \times 100}{1.7}\\\\Q = 7.34 \ J/s[/tex]

Let, amount of ice melts per second is :

[tex]m=\dfrac{Q}{L_f}[/tex]

Here, [tex]L_f[/tex] is the latent of fusion of water and is equal to [tex]L_f = 3.34\times 10^5 \ J/s[/tex].

Putting all values in above equation, we get :

[tex]m=\dfrac{7.34}{3.34\times 10^5}\\\\m = 2.19 \times 10^{-5} \ kg/s[/tex]

Hence, this is the required solution.

Explanation:

a matter is solid gas and liquid

Answer:

matter is anything made of mass which occupys volume

Explanation:

matter is a thing which concludes mass and mentioned and also has volume ( volume is defined as space too) so everything is made of matter

Answer:

here is the answer

Explanation:

117974.472

Answer:

The value is [tex]L = 0.0073 \ H[/tex]      

Explanation:

From the question we are told that

    The number of turns is  [tex]N = 650 \ turns[/tex]

     The length is  [tex]l = 28 \ cm = 0.28 \ m[/tex]

      The radius of the cross-section is [tex]r = 3.5 \ cm = 0.035 \ m[/tex]

Generally the cross-sectional area  is mathematically represented as

       [tex]A = \pi * r^2[/tex]

=>    [tex]A = 3.142 * 0.035^2[/tex]

=>    [tex]A = 0.00384 \ m^2[/tex]

Generally the inductance is mathematically represented as

      [tex]L = \frac{N^2 * \mu _o * A }{ l}[/tex]

Here  [tex]\mu_o[/tex] is the permeability of free space with value [tex]\mu_o = 4\pi * 10^{-7} N/A^2[/tex]

=>    [tex]L = \frac{ 650^2 * 4\pi * 10^{-7} * 0.00384 }{0.28}[/tex]

=>    [tex]L = 0.0073 \ H[/tex]      

[tex]acslerishne[/tex]

Answer:

[tex]F=10\ N[/tex]

Explanation:

[tex]We\ are\ given\ that,\\Mass\ of\ the\ bowling\ bowl=5\ kg\\Acceleration\ of\ the\ ball=2\ m/s^2\\Hence,\\As\ we\ know\ that\ F=ma\\Here,\\Force\ of\ the\ bowling\ ball\ when\ it\ hits\ the\ pins=Mass\ of\ the\ bowling\ bowl* its\ Acceleration.\\Hence,\\F=5*2\\F=10\ Newtons\\[/tex]

Answer:

96.7 s

Explanation:

Time of flight in projectile can be calculated thus:

T = 2 × u × sin ϴ/ g

Where;

T = time of flight (s)

u = initial velocity (m/s)

ϴ = Angle of projectile (°)

g = acceleration due to gravity (9.8m/s²)

Based on the provided information; u = 670m/s, ϴ = 45°

Hence, using T = 2.u.sin ϴ/ g

T = 2 × 670 × sin 45° ÷ 9.8

T = 1340 × 0.7071 ÷ 9.8

T = 947.52 ÷ 9.8

T = 96.68

T = 96.7s

Answer:

true

Explanation:

noble gases are octet meaning they they have eight electrons in their outer shell so the are stable

The distance between the cities along the route is 87.95 Km

Speed is the distance travelled per unit. Mathematically, it can be expressed as:

Speed = distance / time

Speed = distance / time

Cross multiply

Distance = speed × time

Distance = 82.1 × (30.1 / 60)

Distance = 41.19 Km

Speed = distance / time

Cross multiply

Distance = speed × time

Distance = 83.1 × (9.11 / 60)

Distance = 12.62 Km

Speed = distance / time

Cross multiply

Distance = speed × time

Distance = 41.3 × (49.6 / 60)

Distance = 34.14 Km

Total distance = 41.19 + 12.62 + 34.14

Total distance = 87.95 Km

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Answer:

True

Explanation:

Because I had a test on this

Answer:

I think the answer is  

a "cookbook" recipe for performing scientific investigations

Explanation:

Answer:

for 10 some advantages are that it has a much better bandwidth,low power loss, and it allows for longer transmission distance.

The resultant of the external forces that act on Amy are the force due to gravity, friction and air resistance which equals 243.26 N

Given that,

Force due to air resistance, [tex]F_{air}[/tex] = 10 N

Angle of slope, θ = 30°

Mass, m = 60 kg

Coefficient of dynamic friction, μ = 0.08

Force due to gravity, w = m g

w = 60 * 9.8 = 588 N

Since the slope is at an angle, the weight exerted on the ground is not along the axis of slope. So resolving the axis into its vertical and horizontal components,

cos θ = [tex]w_{y}[/tex] / w

[tex]w_{y}[/tex] = 588 * cos 30°

[tex]w_{y}[/tex] = 509.2 N

Frictional force, [tex]F_{fr}[/tex]  = μ * [tex]F_{N}[/tex]

where,

[tex]F_{N}[/tex] = Normal force = [tex]w_{y}[/tex]

[tex]F_{N}[/tex] = 509.2 N

[tex]F_{fr}[/tex]  = 0.08 * 509.2

[tex]F_{fr}[/tex]  = 40.74 N

sin θ = [tex]w_{x}[/tex] / w

[tex]w_{x}[/tex] = 588 * sin 30°

[tex]w_{x}[/tex] = 294 N

Force due to gravity, [tex]F_{g}[/tex] = [tex]w_{x}[/tex]

[tex]F_{g}[/tex] = 294 N

The resultant of external forces acting on Amy, [tex]F_{R}[/tex] =  [tex]F_{g}[/tex] - [tex]F_{air}[/tex] - [tex]F_{fr}[/tex]  

[tex]F_{R}[/tex] = 294 - 10 - 40.74

[tex]F_{R}[/tex] = 243.26 N

Therefore, the resultant of the external forces that act on Amy is 243.26 N

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Answer:

17.71N/m

Explanation:

The period of the spring is expressed according to the expression;

[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\[/tex]

m is the mass of the object

k is the force constant

Given

m = 5.50kg

T = 3.50s

Substitute into the formula;

[tex]T = 2 \pi \sqrt{\frac{m}{k} } \\3.5 = 2 (3.14) \sqrt{\frac{5.5}{k} } \\3.5 = 6.28 \sqrt{\frac{5.5}{k} } \\\frac{3.5}{6.28} = \sqrt{\frac{5.5}{k} } \\0.557 = \sqrt{\frac{5.5}{k} } \\square \ both \ sides\\0.557^2 = (\sqrt{\frac{5.5}{k} })^2 \\0.3106 = \frac{5,5}{k}\\k = \frac{5.5}{0.3106}\\k = 17.71N/m[/tex]

Hence the force constant of the spring is 17.71N/m

Answer:

38.5

Explanation:

Answer:

A)  0.303 s  (3 s.f.)

B)  6.76 ms⁻¹  (3 s.f.)

Explanation:

Constant Acceleration Equations (SUVAT)

[tex]\boxed{\begin{array}{c}\begin{aligned}v&=u+at\\\\s&=ut+\dfrac{1}{2}at^2\\\\ s&=\left(\dfrac{u+v}{2}\right)t\\\\v^2&=u^2+2as\\\\s&=vt-\dfrac{1}{2}at^2\end{aligned}\end{array}} \quad \boxed{\begin{minipage}{4.6 cm}$s$ = displacement in m\\\\$u$ = initial velocity in ms$^{-1}$\\\\$v$ = final velocity in ms$^{-1}$\\\\$a$ = acceleration in ms$^{-2}$\\\\$t$ = time in s (seconds)\end{minipage}}[/tex]  

When using SUVAT, assume the object is modeled as a particle and that acceleration is constant.

Consider the horizontal and vertical motion of the projectile separately.

As the projectile is fired horizontally, the vertical component of its initial velocity is zero.

Acceleration due to gravity = 9.8 ms⁻²

Resolving vertically, taking ↓ as positive:

[tex]s=0.450\quad u=0\quad a=9.8[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\0.450&= (0)t+\dfrac{1}{2}(9.8)t^2\\0.450&= 4.9t^2\\t^2&= \dfrac{0.450}{4.9}\\t&=\sqrt{\dfrac{0.450}{4.9}\\t &=0.3030457634...\\ \implies t&=0.303\:\sf s\;\;(3\:s.f.)\\\end{aligned}[/tex]

The horizontal component of velocity is constant, as there is no acceleration horizontally.

Resolving horizontally, taking → as positive:

[tex]s=2.050 \quad a=0 \quad t=0.3030457634...[/tex]

[tex]\begin{aligned}\textsf{Using} \quad s & = ut+\dfrac{1}{2}at^2:\\\\2.050&= u(0.3030457634...)+\dfrac{1}{2}(0)(0.3030457634...)^2\\2.050&= 0.3030457634...u\\u&= \dfrac{2.050}{0.3030457634...}\\ u &=6.764654873...\\\implies u & = 6.76\:\sf ms^{-1}\;\;(3\:s.f.)\end{aligned}[/tex]

Answer:

The period of the ride when it is being operated at the maximum acceleration is T=2.81 s.

Explanation:

We can use the centripetal acceleration here:

[tex]a_{c}=\frac{v^{2}}{R}=\omega^{2}R[/tex]

Let's find the angular velocity ω at the maximum acceleration.

[tex]20=\omega^{2}*4[/tex]

[tex]\omega=2.24 rad/s[/tex]

The period is given by:

[tex]T=\frac{2\pi}{\omega}[/tex]

[tex]T=\frac{2\pi}{2.24}[/tex]

Therefore, the period will be T=2.81 s.

I hope it helps you!

Answer:

The value  [tex]f = 21.49 \ cm[/tex]

Explanation:

From the question we are told that

    The index of refraction is  [tex]n = 1.60[/tex]

     The outer radius of curvature is  [tex]R = 2.08 \ cm = 0.0208 \ m[/tex]

     The  inner radius is  [tex]r = 2.48 \ cm = 0.0248 \ m[/tex]

Generally from  Maker's equation we have that

       [tex]\frac{1}{f} = [n - 1 ][\frac{1}{(R)} - \frac{1}{r} ][/tex]

=>    [tex]\frac{1}{f} = [1.60 - 1 ][\frac{1}{( 0.0208 )} - \frac{1}{0.0248} ][/tex]

=>    [tex]\frac{1}{f} = 4.65[/tex]

=>    [tex]f = 0.2149 \ m[/tex]

=>    [tex]f = 21.49 \ cm[/tex]

Answer:

31.3mph North

Explanation:

Given parameters:

Distance traveled  = 1500miles

Time taken  = 48hrs

Unknown:

Velocity of the group of explorers = ?

Solution:

Velocity is the displacement divided by the time taken. It is a vector quantity with both magnitude and direction.

 So;

       Velocity = [tex]\frac{displacement}{time}[/tex]

Displacement is the distance moved in a specific direction = 1500miles North

 Insert the parameters and solve;

   Velocity = [tex]\frac{1500}{48}[/tex]   = 31.3mph North

Answer:

It reduces the force necessary to move a load a certain distance up by providing a path for the load to move at a low angle to the ground.

Explanation:

Answer:

The ratio of the new internal energy to the old is 4

Explanation:

let the old pressure of the gas = P₁

let the old volume of the gas = V₁

then, the new pressure of the gas = 2P₁

the new volume of the gas = 2V₁

The internal energy of the gas is given as;

PV = nRT

PV = k

P₁V₁ = P₂V₂

[tex]\frac{P_2V_2}{P_1V_1} = \frac{2P_1\ \times \ 2V_1}{P_1V_1} =\frac{4}{1} = 4[/tex]

The ratio of the new internal energy to the old is 4

I'm not sure of this question, yet i know you may get angry but, just know your loved and if going through a hard time i'm so so sorry, i know how it feels it sucks. take care of yourself, drink water, listen to that one song that makes you dance in your room and go do what YOU love. your beautiful your perfect and dont listen to what anyone says. i love u, everyone loves u, i know its scary but it happens to everyone life isnt a peice of cake unfortunatly and it sucks but woahh your strong! if you need someone to talk to leave a comment below, happy hoildays everyone!

P.S, im looking into the answer of this question. I may not answer it right on time (since i'm not the smartest...) but i promise ill try my best! Also, i am not doing this for points im doing this to make others smile. I hate how no one checks up on anyone, lots of people are going through a stressful time (including me) and i just want to let everyone know that its okay not to be okay! I hope that you all find happiness in every possible situation, once again  HAPPY HOLIDAYS!

The car lands at a distance of 60 m from the base of the cliff.

s = ut + 1 / 2 a[tex]t^{2}[/tex]

s = Displacement

u = Initial velocity

t =Time

a = Acceleration

u = 20 m / s

[tex]s_{y}[/tex] = 30 m

θ = 20°

g = 9.8 m / s²

Resolving the velocity into its horizontal and vertical components

sin θ = [tex]u_{y}[/tex] / u

[tex]u_{y}[/tex] = - 20 sin 20°

[tex]u_{y}[/tex] = - 6.84 m / s

Considering only the vertical components,

[tex]s_{y}[/tex] = [tex]u_{y}[/tex] t + 1 / 2 g t²

30 = - 6.84 t + 4.9 t²

4.9 t² + ( - 6.84 ) t - 30 = 0

This is in the form of a quadratic equation,

t = - ( - 6.84 ) + √ [ ( - 6.84 )² - ( 4 * 4.9 * ( - 30 ) ) ] / 2 ( 4.9 )

t = 3.2 sec

The distance we need to calculate is in horizontal direction,

[tex]v_{x}[/tex] = [tex]s_{x}[/tex] / t

[tex]s_{x}[/tex] = 20 cos 20° / 3.2

[tex]s_{x}[/tex] = 60 m

Therefore, the car lands at a distance of 60 m from the base of the cliff.

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