Answer:
the value of x is 3
Step-by-step explanation:
Hope this helps!!!! :)
Answer:
one is a
two is c
three is b
Step-by-step explanation:
In the western region of the state the times of all boys running in this event are normally distributed with standard deviation 12 seconds, but with mean 5 minutes 22 seconds. Find the proportion of boys from this region who qualify to run in this event in the state meet. (Hint: normalcdf)
Here is the full question.
The average finishing time among all high school boys in a particular track event in a certain state is 5 minutes 17 seconds. Times are normally distributed with standard deviation 12 seconds.
A. The qualifying time in this event for participation in the state meet is to be set so that only the fastest 5% of all runners qualify. Find the qualifying time in seconds (round it to the closest second). (Hint: Convert minutes to seconds.)
B. In the western region of the state the times of all boys running in this event are normally distributed with standard deviation 12 seconds, but with mean 5 minutes 22 seconds. Find the proportion of boys from this region who qualify to run in this event in the state meet. (Hint: normalcdf)
Answer:
a. x ≅ 337 seconds.
b. P(x > 337 ) = 0.1056
Step-by-step explanation:
A.
Given that ;
Mean [tex]\mu =[/tex] 5 minutes 17 seconds =( (60× 5)+17 ) seconds = 317 seconds ( since 60 seconds make 1 minute.
Standard deviation: [tex]\sigma[/tex] = 12 seconds.
Only the fastest 5% of all runners qualify
The objective is to determine the qualifying time in seconds
Let's look for the Z-score of 0.95;
The Z-score is 1.645 from the tables
[tex]x= ( \sigma * z ) + \mu[/tex]
[tex]x = ( 12 * 1.645 ) + 317 \\ \\x = 336.74[/tex]
x ≅ 337 seconds.
B. Given that the standard deviation = 12 seconds
Mean = 5 minutes 22 seconds = (5 × 60 + 22 )seconds = 322 seconds
he objective is to find P(x > 337 ) i.e the proportion of boys from this region who qualify to run in this event in the state meet.
we are using command normalcdf (SEE THE ATTACHED FILE BELOW FOR THE COMPUTATION)
we have P(x > 337 ) = 0.1056
What is the gcf of 96x5 and 64x2
Answer:
The GCF is going to be 32
Answer:
32x^2
Step-by-step explanation:
B on edge
last year we had 250 of employees and due to attrion we lost 12% we only have blank employees left ?
Answer:
220
Step-by-step explanation:
If we lost 12% we still have 100 - 12 = 88% of the employees left. 88% can be written as 0.88. 0.88 * 250 = 220 employees left.
g Question 6 1 pts A 3x3 matrix with real entries can have (select ALL that apply) Group of answer choices three eigenvalues, all of them real. three eigenvalues, all of them complex. two real eigenvalues and one complex eigenvalue. one real eigenvalue and two complex eigenvalues. only two eigenvalues, both of them real. only two eigenvalues, both of them complex. only one eigenvalue -- a real one. only one eigenvalue -- a complex one.
Answer:
(A)three eigenvalues, all of them real.
(D)one real eigenvalue and two complex eigenvalues.
(G)only one eigenvalue -- a real one.
Step-by-step explanation:
Given an [tex]n \times n[/tex] matrix, the characteristic polynomial of the matrix is the degree n polynomial in one variable λ:
[tex]p(\lambda) = det(\lambda I- A)[/tex]
If such [tex]n \times n[/tex] matrix A has real entries, its complex eigenvalues will always occur in complex conjugate pairs.
Therefore, for a [tex]3 \times 3[/tex] matrix with real entries, the following are possible:
(A)three eigenvalues, all of them real.
(D)one real eigenvalue and two complex eigenvalues.
(G)only one eigenvalue -- a real one.
A [tex]3 \times 3[/tex] matrix with real entries cannot have the following:
(B)three eigenvalues, all of them complex.
(C)two real eigenvalues and one complex eigenvalue.
(E)only two eigenvalues, both of them real.
(F)only two eigenvalues, both of them complex.
(H)only one eigenvalue -- a complex one.
A college basketball player makes 80% of his freethrows. Over the course of the season he will attempt 100 freethrows. Assuming free throw attempts are independent, the probability that the number of free throws he makes exceeds 80 is approximately:____________.
A) 0.2000
B) 0.2266
C) 0.5000
D) 0.7734
Answer:
The probability that the number of free throws he makes exceeds 80 is approximately 0.50
Step-by-step explanation:
According to the given data we have the following:
P(Make a Throw) = 0.80%
n=100
Binomial distribution:
mean: np = 0.80*100= 80
hence, standard deviation=√np(1-p)=√80*0.20=4
Therefore, to calculate the probability that the number of free throws he makes exceeds 80 we would have to make the following calculation:
P(X>80)= 1- P(X<80)
You could calculate this value via a normal distributionapproximation:
P(Z<(80-80)/4)=1-P(Z<0)=1-50=0.50
The probability that the number of free throws he makes exceeds 80 is approximately 0.50
The probability that the number of free throws he makes exceeds 80 is approximately 0.5000.
Given that,
A college basketball player makes 80% of his free throws.
Over the course of the season, he will attempt 100 free throws.
Assuming free throw attempts are independent.
We have to determine,
The probability that the number of free throws he makes exceeds 80 is.
According to the question,
P(Make a Throw) = 80% = 0.80
number of free throws n = 100
Binomial distribution:
Mean: [tex]n \times p = 0.80 \times 100 = 80[/tex]
Then, The standard deviation is determined by using the formula;
[tex]= \sqrt{np(1-p)} \\\\=\sqrt{80\times (1-0.80)}\\\\= \sqrt{80 \times 0.20 } \\\\= \sqrt{16} \\\\= 4[/tex]
Therefore,
To calculate the probability that the number of free throws he makes exceeds 80 we would have to make the following calculation:
[tex]P(X>80)= 1- P(X<80)[/tex]
To calculate this value via a normal distribution approximation:
[tex]P(Z<\dfrac{80-80}{4})=1-P(Z<0)=1-0.50=0.5000[/tex]
Hence, The probability that the number of free throws he makes exceeds 80 is approximately 0.5000.
To know more about Probability click the link given below.
https://brainly.com/question/21586810
Which of the following measurements is more precise?
4.69 m or 8.99 m
Answer:
The measures represent the same precisionWhen we talk about precision in measurements, we need to mention the significant figures, because that determines the precision.
Specifically, the more significant figures there are, more precise will be the number.
In this case, you can observe that both numbers have the same number of significant figures, which is 3, which means both numbers are equal in precision.
Does anyone know this?
3. What would you expect the relationship between the length of a baby at birth and
the month in which the baby was born to be?
A positive correlation
B negative correlation
C no correlation
On a coordinate plane, triangle A B C is shifted 4 units up and 3 units to the left to form triangle A prime B prime C prime. Triangle ABC is reflected over the line y = 1. What are the coordinates of B’? (–2, 3) (–2, 5) (2, –3) (4, –3)
Answer:
(–2, 5)
Step-by-step explanation:
I know its late now but here is the answer.
Answer:
The answer is a
Step-by-step explanation:
A 2-pack of scented candles costs $0.95. What is the unit price, rounded to the nearest cent?i mark the 1st answer brainliest
Step-by-step explanation:
Cost of 2 pack = 0.95
Cost of 1 pack = 0.95 ÷ 2 = 0.475
Unit price = 0.475
What is true about the number 3.872? Check all that apply.
The 8 is in the tens place.
The 7 is in the hundredths place.
The 3 is in the ones place.
This number is read as "three and eight seventy-two hundredths."
3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001).
Answer:
The 7 is in the hundredths place.
The 3 is in the ones place.
3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001).
Step-by-step explanation:
Given the number 3.872, to check all the given options that are true apply to the number, let's take a look at each position occupied by each digit. In order words, let's consider their place value.
Thus,
The 3 is in the ones place and as such has a value of 3.
8 is in the tenths place having a place value of 0.8 (⁸/10)
7 is in the hundredths place having a place value of 0.07 (⁷/100)
2 is in the thousandths place having a place value of 0.002 (²/1000)
Going by these, the following statements are true :
"The 7 is in the hundredths place."
"The 3 is in the ones place."
"3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001)."
The number is pronounced as three and eight hundred seventy-two thousandths rather than the option given.
Therefore, only 3 if the options are correct
Answer: The 7 is in the hundredths place.
The 3 is in the ones place.
3.872 is equivalent to (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001).
Step-by-step explanation:
In the question, 3 is in the ones place. The first number after the decimal point is the tenths. In the question, the place value of 8 is 8 tenths; 7 is in the hundredths place.
3.872 = (3 × 1) + (8 × 0.1) + (7 × 0.01) + (2 × 0.001)
= 3 + 0.8 + 0.07 + 0.002
= 3.872
The number is pronounced as three and eight hundred seventy-two thousandths
a cone has the diameter of 3 inches. the cone holds 12 cubic inches of water. to the nearest inch, what is the height of the cone?
Answer:
The height is about 5 inches.
Step-by-step explanation:
The volume for a cone is [tex]\frac{1}{3}[/tex] × π × r² × h
The radius of the cone is 1.5
12= [tex]\frac{1}{3}[/tex] × π × 1.5² × h
12= [tex]\frac{1}{3}[/tex] × π × 2.25 × h
12=0.75×π×h
Divide both sides by 0.75
16=π×h
Divide both sides by π
5≈h
The height is about 5 inches.
what are 80 percent of 500
Answer: 400
Step-by-step explanation:
500 x 0.80 = 400
Answer:
400
Step-by-step explanation:
Of means multiply
80% * 500
Change to fraction form
80/100 * 500
Rewriting to reduce
80 * 500/100
80 * 5
400
Please answer this correctly
Answer:
169.5 yd²
Step-by-step explanation:
See attachment.
In situations like this, ALWAYS (!) make as sketch.
Divide the areas by adding dotted lines on sensible places, and write in the missing numbers for the correct distances.
The only possible difficult one is the triangle, which is the half of a rectangle. So you are dealing with a series of areas of rectangles. That is really easy if you understand what you are doing.
Total area =
area 1 + area 2 + area 3 + area 4
10*4 + 4*7 + 3*13 + (0.5 * 7*17)
40 + 28 + 42 + 59.5
Total area = 169.5 yd²
I’ll give the bralyist to the first correct answer
Let f be defined as shown.
What is f1 (-7)?
Answer:
The answer is 2
From the function when the input is 2 the output is -7. The inverse reverses the order so the input will be -7 and the output will be 2.
A new post-surgical treatment is being compared with a standard treatment. Seven subjects receive the new treatment, while seven others (the controls) receive the standard treatment. The recovery times, in days, are given below.
Treatment: 12 13 15 19 20 21 24
Control: 18 23 24 30 32 35 39
Required:
Find a 98% confidence interval for the difference in the mean recovery times between treatment and control.
Answer:
[tex] (17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745[/tex]
[tex] (17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255[/tex]
Step-by-step explanation:
For this case we have the following info given:
Treatment: 12 13 15 19 20 21 24
Control: 18 23 24 30 32 35 39
We can find the sample mean and deviations with the the following formulas:
[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]
[tex] s =\sqrt{\frac{\sum_{i=1}^n (X_i- \bar X)^2}{n-1}}[/tex]
And repaplacing we got:
[tex] \bar X_T = 17.714[/tex] the sample mean for treatment
[tex] \bar X_C = 28.714[/tex] the sample mean for treatment
[tex] s_T= 4.461[/tex] the sample deviation for treatment
[tex] s_C= 7.387[/tex] the sample deviation for control
[tex]n_T= n_C= 7[/tex] the sample size for each sample
The degrees of freedom are given by:
[tex] df= 7+7-2= 12[/tex]
The confidence interval for the difference of means is given by:
[tex] (\bar X_T -\bar X_C) \pm t_{\alpha/2} \sqrt{\frac{s^2_T}{n_T} +\frac{s^2_C}{n_C}}[/tex]
The confidence is 98% so then the significance is [tex]\alpha=0.02[/tex] and [tex] \alpha/2 =0.01[/tex]. Then the critical value would be:
[tex] t_{\alpha/2}=2.681[/tex]
And replacing we got:
[tex] (17.714-28.714) -2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -19.745[/tex]
[tex] (17.714-28.714) +2.681 \sqrt{\frac{4.461^2}{7} +\frac{7.387^2}{7}}= -2.255[/tex]
A designer makes a model of a patio using 1/2 inch square tiles each 1/2 inch square tiles = 4 square feet what area is represented by the 8 x 6 model
Answer:
[tex]192ft^2[/tex]
Step-by-step explanation:
The model of a patio was made by
using 1/2 inch square title=4 square feet.
area represented by the 8 *6 model can be calculated as follows;
FIRSTLY, the number of tiles in the 8 *6 model can be calculated by multiplying it i.e
8 *6 model =[tex]48 tiles[/tex]
Hence there are 48 tiles in 8 *6 model
It was given that 1/2 inch square title=4
square feet.
So to calculate the total Area occupied by the 48 tiles
[tex]Area=1/2×48[/tex]
[tex]Area=24inches^2[/tex]
If [tex]1/2inches^2=4ft^2[/tex] ( from the question)
Let X represent [tex]24inches^2[/tex]
Then, [tex]24inches^2=Xft^2[/tex]
Cross multiply
[tex]4×24=X×1/2
X=4×24×2
X=[tex]192ft^2[/tex]
[tex]24inches^2=[tex]192ft^2[/tex]
Therefore, the area represented by the 8 *6 model is [tex]192ft^2[/tex]
the time taken by a student to the university has been shown to be normally distributed with mean of 16 minutes and standard deviation of 2.1 minutes. He walks in once a day during term time, 180 days per year, and leaves home 20 minutes before his first lecture. a. Find the probability that he is late for his first lecture. b. Find the number of days per year he is likely to be late for his first lecture.
Answer:
a) 2.84% probability that he is late for his first lecture.
b) 5.112 days
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:
[tex]\mu = 16, \sigma = 2.1[/tex]
a. Find the probability that he is late for his first lecture.
This is the probability that he takes more than 20 minutes to walk, which is 1 subtracted by the pvalue of Z when X = 20. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{20 - 16}{2.1}[/tex]
[tex]Z = 1.905[/tex]
[tex]Z = 1.905[/tex] has a pvalue of 0.9716
1 - 0.9716 = 0.0284
2.84% probability that he is late for his first lecture.
b. Find the number of days per year he is likely to be late for his first lecture.
Each day, 2.84% probability that he is late for his first lecture.
Out of 180
0.0284*180 = 5.112 days
Very confused, need help quick! (see attachment) Simplify and show your work.
Answer:
27/(4x^6y^8)
Step-by-step explanation:
Target the variables first. (x^a)^b is the same as x^(a x b).
In the numerator, it is x^(2 x 3) , which is x^6, and y^(4 x 3), which is y^12.
Same principle on the bottom. the denominator is x^12 and y^20.
In the numerator, the number 4 is alone so don't do anything to it. Cube 3. The coefficient of the numerator is 4 x 3^3 . The coefficient of the denominator is 2^4. Cancel like terms. when you divide same terms' exponents, you subtract the exponent on top by the exponent on the bottom. Remember that you can only simplify LIKE terms. (x with x, y with y, number with number.)
Please answer this correctly
Answer:
Pennies: 20%
Nickels: 36%
Dimes: 18%
Quarters: 21%
Step-by-step explanation:
Pennies: [tex]\frac{125}{125+180+90+105} =\frac{125}{500} =\frac{25}{100}[/tex] or 20%
Nickels: [tex]\frac{180}{125+180+90+105} =\frac{180}{500} =\frac{36}{100}[/tex] or 36%
Dimes: [tex]\frac{90}{125+180+90+105} =\frac{90}{500} =\frac{18}{100}[/tex] or 18%
Quarters: [tex]\frac{105}{125+180+90+105} =\frac{105}{500} =\frac{21}{100}[/tex] or 21%
Angle EFB is 108º
a)Find the size of angle x.
b) which one of these justifies your answer?
A-corresponding angles
B- Alternate angles
C- vertically opposite angles
Answer:
c of what im sure about
Step-by-step explanation:
Round 8326 to the nearest hundred
Answer:
The answer is 8300.
Step-by-step explanation:
1) We round the number up to the nearest hundred, if the last two digits in the number are 50 or above.
2) We round the number down to the nearest 100 if the last two digits in the number are 49 or below.
3) If the last two digits are 00, then we do not have to do any rounding because it is already to the hundred.
A high school track is shaped as a rectangle with a half circle on either side.Jake plans on running four laps. How many meters will Jake run? Use 3.14 for Pi.
Answer:
if you go around a track one time thats 400 meters but if you go around 4 times thats 1600 meters, you dont need to use 3.14 pi for this " no offense", i do track and field myself and i do the short distance, which is 100 meters and 200 meter but for for long distance runners they go around the track 4- 8 times so it is 1600 meters is ur answer. and when u go around 8 times, thats 3200 meters.
Step-by-step explanation:
What’s the degree of the rotation?
Answer: The answer is C 90
Step-by-step explanation: Rotations is ¼ and the Radians is π/2
When Sunita weighed herself on Monday, she found that she had gained 1 1/4 kg. Earlier her weight was 46 3/8 kg. What was her weight on Monday? Please give me Statements! Please Do it fast(Its ok if you dont do it fast ok its not like that much of an urgent) #GoAwayCoronaVirus
Answer:
[tex]47\frac{5}{8}[/tex]
Step-by-step explanation:
Weight from before + Weight gained
[tex]46\frac{3}{8} +1\frac{1}{4}[/tex]
Convert to improper fractions.
[tex]371/8 + 5/4[/tex]
Find the common denominator.
[tex]371/8 + 10/8[/tex]
Add.
[tex]381/8[/tex]
Convert to a mixed fraction.
[tex]47\frac{5}{8}[/tex]
Answer:
47 5/8 kg
Step-by-step explanation:
Ealier weight + gained weight = Monday's weight
46 3/8 + 1 1/4
= 371/8 + 5/4
= 371/8 + 10/8
= 381/8
= 47 5/8 kg
Express the following ratio in its simplest form.
4:12
Answer:
3:12
Step-by-step explanation:
Answer:
1:3
Step-by-step explanation:
Think 4:12 as a fraction for a moment, it would be 4/12. Now completely simplify 4/12, you get 1/3. Now put 1/3 as a ratio, it would be 1:3.
Please mark BRAINLIEST, thanks!
HELP!!! PLEASE!!!
The U.S. Federal Income Tax is a progressive tax, which means that higher incomes are taxed at higher percent rates.
The table shows the 2018 Federal Income Tax rates that are applied to the incomes of unmarried individuals.
Tuan is an unmarried man who earned a taxable income of $48$48,000000 during 2018.
Use the table to complete the statements below.
Answer:
10%$29,175$2,046$6,499.50Step-by-step explanation:
a) The %tax comes from the "Rate" column on the line "up to $9525". It is 10%.
__
b) Simply compute the difference shown:
$38,700 -$9,525 = $29,175
__
c) 22% of $9,300 is ...
0.22 × $9,300 = $2,046
__
d) The total from the three previous calculations is ...
$952.50 +3,501.00 +2,046.00 = $6,499.50
Answer:
10%
$29,175
$2,046
$6,499.50
got it right on ttm.
Step-by-step explanation:
just believe me it works
PLEASE HURRY! Circle B is shown. Line segments A B and C B are radii. The length of A B is 6. Sector A B C is shaded. The measure of central angle ABC is StartFraction pi Over 2 EndFraction radians. What is the area of the shaded sector? 6Pi units squared 9Pi units squared 18Pi units squared 36Pi units squared
Answer:
(B)[tex]9 \pi $ units squared[/tex]
Step-by-step explanation:
In circle B, AB is one of the radii; and
AB=6
Central Angle of ABC [tex]=\dfrac{\pi}{2}$ radians[/tex]
Now, Area of a Sector
[tex]\text{Area of a Sector}=\dfrac{\theta}{2\pi} \times \pi r^2 \\=\dfrac{\frac{\pi}{2}}{2\pi} \times \pi \times 6^2\\=\dfrac{\pi}{4\pi} \times \pi \times 6^2\\=\dfrac{36}{4} \times \pi \\= 9 \pi $ units squared[/tex]
Answer:
b
Step-by-step explanation:
g It is known that 20% of products on a production line are defective. Products are inspected until first defective is encountered. a) What is the probability that the experimenter must inspect six products
Question:
It is known that 20% of products on a production line are defective. Products are inspected until first defective is encountered. a) What is the probability that the experimenter must inspect six products to find a defective product?
Answer:
P(x = 6) = 0.0655
P(x = 6) = 6.55%
Step-by-step explanation:
It is given that 20% of products on a production line are defective.
p = 0.20
Then
q = 1 - p = 1 - 0.20 = 0.80
Which means that 80% of products on the production line are not defective.
We want to find out the probability that the experimenter must inspect six products to find a defective product.
Let x is the number of inspections to get a defective product.
P(x = 6) = ?
If out of 6 inspections 1 is defective then it means 5 are not defective
so the probability is
P(x = 6) = p¹ × q⁵
P(x = 6) = 0.20¹ × 0.80⁵
P(x = 6) = 0.20 × 0.32768
P(x = 6) = 0.0655
P(x = 6) = 6.55%
Therefore, there is 6.55% chance that the experimenter finds a defetive product in 6 inspections.
Which of the following expressions represents "the sum of n and the sum of 8 and 6"? n(8 + 6) n + (8 + 6) (n + 6)8