Perform the indicated operations. 2−26 −48−16 07−6 76 −200 −73 Arrow −48−16 07−6 −200 −73 1−13 −48−16 07−6 38 −200 −73 Arrow 1-13 07−6 38 −73
Answers
Not certain if this question is complete
Answer and Step-by-step explanation:
We perform the operations given, using the rules of subtraction and addition on the number line:
Two negative signs adds up to a negative result, one negative number and positive number may add up to a negative or positive value depending on which is bigger :
2-26= -24( the positive value 2 reduces negative value by 2 and we are left with -24)
-48-16= -64( two negative values add up to a negative value)
07-6= 1( seven is bigger than 6 hence positive result)
We use the above method to solve the given expressions
+76-200-73= -124-73=-192
-48-16=-64
+7-6-200-73=-199-73=-272
+1-13=-12
-48-16=-64
+07-6=1
+38-200-73=-162-73=-235
1-13=-12
07-6=1
38-73= -35
1, -1, 3, 38 & 0, 2, -2, -24
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Step-by-step explanation:
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Answer:
[tex]t = 2.57[/tex]
Step-by-step explanation:
Given
[tex]h=-16t^2+12t+75[/tex]
Required
Determine the time to hit the ground
The ground is at point 0.
So, to solve this; we simply set [tex]h =0[/tex], then calculate the value of t
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[tex]0=16t^2-12t-75[/tex]
Reorder
[tex]16t^2-12t-75 = 0[/tex]
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[tex]t = \frac{-(-12)\±\sqrt{(-12)^2 - 4*16*(-75)}}{2*16}[/tex]
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[tex]t = \frac{12\±\sqrt{4944}}{32}[/tex]
[tex]t = \frac{12\±70.31}{32}[/tex]
Split:
[tex]t = \frac{12+70.31}{32}[/tex] or [tex]t = \frac{12-70.31}{32}[/tex]
[tex]t = \frac{82.31}{32}[/tex] or [tex]t = \frac{-58.31}{32}[/tex]
But time (t) can't be negative;
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[tex]t = \frac{82.31}{32}[/tex]
[tex]t = 2.57[/tex]
Hence, the time to hit the ground is 2.57 seconds
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Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answer
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Step-by-step explanation:
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Given :
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Steps shown in image below:
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Answer:
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Answer:
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Step one:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation: