Please answer this correctly

Answer:

One plane has a speed of 450 km/h and the other has a speed of 900 km/h.

Step-by-step explanation:

I am going to say that:

The speed of the first plane is x.

The speed of the second plane is y.

One plane is flying at twice the speed of the other.

I will say that y = 2x. We could also say that x = 2y.

Two airplanes leave an airport at the same time, flying in the same direction

They fly in the same direction, so their relative speed(difference) at the end of each hour is y - x = 2x - x = x.

If after 4 hours they are 1800 km apart, find the speed of each plane

After 1 hour, they will be x km apart. After 4, 1800. So

1 hour - x km apart

4 hours - 1800 km apart

4x = 1800

x = 1800/4

x = 450

2x = 2*450 = 900

One plane has a speed of 450 km/h and the other has a speed of 900 km/h.

Answer:

No.

Step-by-step explanation:

A point has no length, height or depth. It only has position.

A line has one dimensional length.

Answer:

25

Step-by-step explanation:

I'm going with $25 since socks should cost as much as underwear, you wear them underneath and they're an essential.

Answer:

Null hypothesis is rejected,

test statistic= 15.76

Step-by-step explanation:

sample mean= 113,

sample standard deviation= 68

H0: mean of sample =100

Ha: mean of sample > 100

test statistic= (population mean- sample mean)/√(standard deviation/sample size)

test statistic= (113-100)/√(68/100)= 15.76

Degrees of freeedom= 100-1=99

p-value= 1.658 (from t distribution table for DF=99 and alpha=0.05)

Since p-value is smaller than test statistic, null hypothesis is rejected

Answer:

[tex] P(X \leq 1)= P(X=0) +P(X=1) [/tex]

And using the probability mass function we can find the individual probabiities

[tex]P(X=0)=(15C0)(0.82)^0 (1-0.82)^{15-0}=6.75x10^{-12}[/tex]

[tex]P(X=1)=(15C1)(0.82)^1 (1-0.82)^{15-1}=4.61x10^{-10}[/tex]

And replacing we got:

[tex] P(X \leq 1)= P(X=0) +P(X=1)= 4.68x10^{-10}[/tex]

And for this case yes we can conclude that 1 a significantly low number of adults requiring eyesight​ correction in a sample of 15 since the probability obtained is very near to 0

Step-by-step explanation:

Let X the random variable of interest "number of adults who need correction", on this case we now that:

[tex]X \sim Binom(n=15, p=0.82)[/tex]

The probability mass function for the Binomial distribution is given as:

[tex]P(X)=(nCx)(p)^x (1-p)^{n-x}[/tex]

Where (nCx) means combinatory and it's given by this formula:

[tex]nCx=\frac{n!}{(n-x)! x!}[/tex]

We want to find this probability:

[tex] P(X \leq 1)= P(X=0) +P(X=1) [/tex]

And using the probability mass function we can find the individual probabiities

[tex]P(X=0)=(15C0)(0.82)^0 (1-0.82)^{15-0}=6.75x10^{-12}[/tex]

[tex]P(X=1)=(15C1)(0.82)^1 (1-0.82)^{15-1}=4.61x10^{-10}[/tex]

And replacing we got:

[tex] P(X \leq 1)= P(X=0) +P(X=1)= 4.68x10^{-10}[/tex]

And for this case yes we can conclude that 1 a significantly low number of adults requiring eyesight​ correction in a sample of 15 since the probability obtained is very near to 0

Answer:

The probability of getting the same colour twice is approximately 34%.

Step-by-step explanation:

The probability of getting each color is:

Then, we can calculate the probability of getting the color red twice as:

[tex]P(x_1=R;x_2=R)=P(x=R)^2=(3/11)^2=9/121[/tex]

We have to repeat this for the color blue and green:

[tex]P(x_1=B;x_2=B)=P(x=B)^2=(4/11)^2=16/121\\\\P(x_1=G;x_2=G)=P(x=G)^2=(4/11)^2=16/121[/tex]

Then, the probability of getting the same color twice in two spins can be calculated as:

[tex]P=P(x_1=R;x_2=R)+P(x_1=B;x_2=B)+P(x_1=G;x_2=G)=\\\\P=9/121+16/121+16/121\\\\P=41/121\approx0.34[/tex]

Answer:

0.1800 to 4 places of decimals.

Step-by-step explanation:

Using the Binomial formula

Probability = 10C5* (0.95)^95 * (0.05)^5

= 100! / 95!*5! *  (0.95)^95 * (0.05)^5

= 0.1800178.

Answer:

1) 48 years.

2) Question incorrect.

11 isn't a factor of 64, and 368 isn't a multiple of 64. 11 also isn't a factor of 368, hence, it would be impossible to find the unknown second number with all of these false information in the question.

Step-by-step explanation:

Let the ages of Kissi, Esinam and Lariba be x, y and z respectively.

Ratio of the ages of Kissi and Esinam is 3:5

x:y = 3:5

(x/y) = (3/5)

5x = 3y

x = (3y/5) (eqn 1)

Ratio of the ages of Esinam and Lariba is 3:5

y:z = 3:5

(y/z) = (3/5)

5y = 3z

z = (5y/3) (eqn 2)

The sum of their 3 ages is 147

x + y + z = 147 (eqn 3)

Substituting the values of x and z from eqn 1 and 2 into eqn 3, we have

(3y/5) + y + (5y/3) = 147

(49y/15) = 147

y = (147×15/49) = 45.

x = (3y/5) = (3×45/5) = 27

z = (5y/3) = (5×45/3) = 75

The ages of Kissi, Esinam and Lariba are then 27, 45 and 75 respectively.

The difference in the ages of the oldest amf the youngest is thus, 75 - 27 = 48 years.

2) This question seems to be faulty and incorrect as 11 isn't a factor of 64, and 368 isn't a multiple of 64. 11 also isn't a factor of 368, hence, it would be impossible to find the unknown second number with all of these false information in the question.

Hope this Helps!!!

Answer:

[tex]7.9584 \times 10^8[/tex]

Step-by-step explanation:

[tex]8.05 \times 10^8 - 9.16 \times 10^6[/tex]

[tex]805000000-9160000[/tex]

[tex]=795840000[/tex]

Answer:

C

Step-by-step explanation:

Plugged into calculator

Vertical asymptotes: x=-2

Horizontal asymptotes: y=0

No oblique asymptotes

Answer:

The range of p-values

0.01 < p < 0.025

Step-by-step explanation:

Explanation:-

Given random sample size 'n' = 7

Assume that the populations are normally distributed

Null Hypothesis :H₀:μd=0.

Alternative Hypothesis:H₁:μd<0.

Degrees of freedom

ν = n-1 =7-1 =6

given the test statistic  t = - 3.201

we will use single tailed test in t-distribution table

The test statistic t= 3.201 is lies between the critical values is 0.01 and 0.025

The range of p-values

0.01 < p < 0.025  (check t- distribution table single tailed test)

Final answer:-

The range of p-values

0.01 < p < 0.025

Answer:

c) Yes, because the p-value = 0.0172

Step-by-step explanation:

The following table is obtained:

Categories       Observed(fo)        Expected (fe)        (fo-fe)²/fe

NW Oregon        3109           4357*0.727=3167.539       1.082

SW Oregon        902             4357*0.207=901.899           0

Central Oregon    244          4357*0.048=209.136         5.812

Eastern Oregon    102           4357*0.028=121.996         3.277

Sum =                    4357        4357                                   10.171

(1) Null and Alternative Hypotheses

The following null and alternative hypotheses need to be tested:

H0​:p1​=0.727,p2​=0.207,p3​=0.048,p4​=0.028

Ha​: Some of the population proportions differ from the values stated in the null hypothesis

This corresponds to a Chi-Square test for Goodness of Fit.

(2) Rejection Region

Based on the information provided, the significance level is α=0.05, the number of degrees of freedom is df=4−1=3, so then the rejection region for this test is R={χ2:χ2>7.815}.

(3) Test Statistics

The Chi-Squared statistic is computed as follows:

[tex]X^2=\sum^n_{i=1}\frac{(O_i-E_i)^2}{y} \\\\= 1.082+0+5.812 +3.277 = 10.171[/tex]

(4) Decision about the null hypothesis

Since it is observed that

[tex]X^2 = 10.171 > X_c^2 = 7.815[/tex]

it is then concluded that the null hypothesis is rejected.

(5) Conclusion

It is concluded that the null hypothesis H_o is rejected. Therefore, there is enough evidence to claim that some of the population proportions differ from those stated in the null hypothesis, at the α=0.05 significance level.

Answer:

a) 13913

b) 4913.82

Step-by-step explanation:

The compound interest formula is given by:

[tex]A(t) = P(1 + \frac{r}{n})^{nt}[/tex]

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per year and t is the time in years for which the money is invested or borrowed.

In this question:

Investment of 9000, so [tex]P = 9000[/tex]

Interest rate of 8%, so [tex]r = 0.08[/tex]

Compounded quarterly, so [tex]n = 4[/tex]

5 years and 6 months, that is, 5 years and half, so [tex]t = 5.5[/tex]

(a) How much would the value of her savings at the end of the term?

[tex]A(t) = P(1 + \frac{r}{n})^{nt}[/tex]

[tex]A(5.5) = 9000(1 + \frac{0.08}{4})^{4*5.5} = 13913.82[/tex]

(b) How much is the interest earned by your savings?

The amount subtracted by the principal. So

13913.82 - 9000 = 4913.82

Answer:

94 more students should be included in the sample.

Step-by-step explanation:

We have that to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1-0.99}{2} = 0.005[/tex]

Now, we have to find z in the Ztable as such z has a pvalue of [tex]1-\alpha[/tex].

So it is z with a pvalue of [tex]1-0.005 = 0.995[/tex], so [tex]z = 2.575[/tex]

Now, find the margin of error M as such

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

How many students we need to sample to be 99% sure that the sample mean x is within 1 semester hour of the population mean?

We need to survey n students.

n is found when M = 1.

We have that [tex]\sigma = 4.7[/tex]

So

[tex]M = z*\frac{\sigma}{\sqrt{n}}[/tex]

[tex]1 = 2.575*\frac{4.7}{\sqrt{n}}[/tex]

[tex]\sqrt{n} = 2.575*4.7[/tex]

[tex](\sqrt{n})^{2} = (2.575*4.7)^{2}[/tex]

[tex]n = 146.47[/tex]

Rounding up

147 students need to be surveyed.

How many more students should be included...?

53 have already been surveyed

147 - 53 = 94

94 more students should be included in the sample.

Answer:

D

Step-by-step explanation:

Lines EF and GH are already parallel. Translating them 2 units to the side without changing how far apart they are vertically means they won't intersect and will remain the same distance apart.

Answer:

D

Step-by-step explanation:

They are parallel lines

Answer:

Step-by-step explanation:

Trends over time - Line charts

Cross tabulation - column or bar chart

The relationship among 3 quantitative variables - Bubble charts or clusteréd column or bar chart

The relationship between 2 quantitative variables - scatter plot

Frequency distribution of quantitative data - Histogram

Show differences in numbers across categories - Bar chart or column charts.

Answer:

[tex]E_{A} =0.25*160=40[/tex]  

[tex]E_{B} =0.25*160=40[/tex]

[tex]E_{C} =0.4*160=64[/tex]

[tex]E_{D} =0.05*160=8[/tex]  

[tex]E_{F} =0.05*160=8[/tex]  

And now we can calculate the statistic:  

[tex]\chi^2 = \frac{(36-40)^2}{40}+\frac{(42-40)^2}{40}+\frac{(60-64)^2}{64}+\frac{(14-8)^2}{8}+\frac{(8-8)^2}{8} =5.25[/tex]  

The answer would be:

c. 5.25

Step-by-step explanation:

The observed values are given by:

A: 36

B: 42

C: 60

D: 14

E: 8

Total =160

We need to conduct a chi square test in order to check the following hypothesis:  

H0: There is no difference in the proportions for the final grades

H1: There is a difference in the proportions for the final grades

The level of significance assumed for this case is [tex]\alpha=0.01[/tex]  

The statistic to check the hypothesis is given by:  

[tex]\chi^2 =\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}[/tex]  

Now we just need to calculate the expected values with the following formula [tex]E_i = \% * total[/tex]  

And the calculations are given by:  

[tex]E_{A} =0.25*160=40[/tex]  

[tex]E_{B} =0.25*160=40[/tex]

[tex]E_{C} =0.4*160=64[/tex]

[tex]E_{D} =0.05*160=8[/tex]  

[tex]E_{F} =0.05*160=8[/tex]  

And now we can calculate the statistic:  

[tex]\chi^2 = \frac{(36-40)^2}{40}+\frac{(42-40)^2}{40}+\frac{(60-64)^2}{64}+\frac{(14-8)^2}{8}+\frac{(8-8)^2}{8} =5.25[/tex]  

The answer would be:

c. 5.25

Now we can calculate the degrees of freedom for the statistic given by:  

[tex]df=(categories-1)=(5-1)=4[/tex]

And we can calculate the p value given by:  

[tex]p_v = P(\chi^2_{4} >5.25)=0.263[/tex]  

The p value is higher than the significance so we have enough evidence to FAIL to reject the null hypothesis

Answer:

A

Step-by-step explanation:

We know that in normal distribution, approximately 34% of bags will fall with in one standard deviation on one side. On both sides within the range of 1 standard deviation, 34 + 34 = 68 % of bags will fall.

Our range is:

1600 to 1620

1610 - 10 to 1610 + 10

So the answer is 1

That means, that 68% is the answer.

Answer:

The answer is A.

Step-by-step explanation:

Approximately 68%

Answer:

There were 30 people attending at the start of the concert

Step-by-step explanation:

The coefficient of the value raised to an exponent in these types of functions is always the "starting" value. In your case, '30' is the coefficient, so it is the starting value. FYI: 1.10 is the rate at which the people increase, t is time passed, 20 is a constant, and P is the total number of people after the time goes by.

Answer:

There were 30 people attending at the start of the concert.

Step-by-step explanation:

30 is the coefficient, so that's your starting point, basically.

Answer:

Options (C) and (F)

Step-by-step explanation:

Polynomial function is,

f(x) = x³ - x² - 5x - 3

Possible rational roots of the given function will be = [tex]\frac{\pm1, \pm3}{\pm1}[/tex]

By putting x = -1

f(-1) = (-1)³ - (-1)² -5(-1) - 3

     = -1 - 1 + 5 - 3

     = 0

Therefore, x = -1 will a root of the given function.

Now we apply synthetic division to get the other roots,

-1 |  1       -1       -5      -3

      ↓      -1         2      3

     1       -2       -3      0

Therefore, factored form of the polynomial will be (x + 1)(x² - 2x - 3).

Now we will find the roots of (x² -2x - 3).

x² - 2x - 3 = x² - 3x + x - 3

                = x(x - 3) + 1(x - 3)

                = (x + 1)(x - 3)

For roots of the function, f(x) = 0

(x + 1)(x - 3) = 0

x = -1, 3

Therefore, roots of the function are x = -1, 3

Options (C) and (F) are the answers.

Answer:

100 inches Over 1 minute times × 1 foot Over 12 inches

Step by Step explanation

Remember that

1ft=12in

The expression converts 100 inches per minute to feet per minute is

100 inch / min x 1 ft/ 12 inch.

The same attribute is expressed using a unit conversion, but in a different unit of measurement. Time can be expressed in minutes rather than hours, and distance can be expressed in miles, kilometres, feet, or any other measurement unit.

We know

1 feet = 12 inch

We have to convert 100 inches per minute to feet per minute.

So, 100 inches

= 100 inch / min x 1 ft/ 12 inch

= 8.33 ft per minute

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Answer:

2(-2y+9)/3+y

Step-by-step explanation:

Answer:

49

Step-by-step explanation:

25²-24²

625-576

=49

use calculator lah dehh

Answer:

The answer is option 1.

Step-by-step explanation:

You have to apply Tangent Rule, tanθ = opposite/adjacent:

[tex] \tan(θ) = \frac{oppo.}{adj.} [/tex]

[tex]let \: oppo. = 5 \\ let \: adj. = b \\ let \: θ = 30[/tex]

[tex] \tan(30) = \frac{5}{b} [/tex]

The correct answer is option (A) tan(30)=5/b

The steps are as follow:

AB = 10 cm

BC = 5 cm

AC = b cm

tan(x) = opposite side / adjacent side

tan(30) = BC / AC

tan(30) = 5 / b

So, the correct answer is option (A) tan(30)=5/b

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Answer:

DID IT oN EDGEN UITY

Step-by-step explanation:

The first graph correctly represents our piecewise function f(x) = - 1.5x + 3.5 for x < 2 and 4 + x for x ≥ 2.

A function that is piecewise-defined by numerous subfunctions, each of which has a separate domain interval for which it is applicable.

Piecewise definition is more of an expression of the function than it is a property of the function.

Given a piecewise function f(x) = - 1.5x + 3.5 for x < 2 and 4 + x for x ≥ 2.

Now, strictly less or greater than will be shown as an open circle in the graph and less than or greater than equal to will be shown by a closed circle on the graph.

If we observe the first graph when x = 0, y = 3.5, and the end is represented as an open circle which is < 2 and when x ≥ 2 it is 6 and represented with a closed circle.

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Multiply 2 by 1/2 to get 1.

Multiply 1 by 2/3 to get 2/3.

Multiply 2/3 by 3/4 to get 6/12 = 1/2.

Multiply 1/2 by 4/5 to get 4/10 = 2/5.

Multiply 2/5 by 5/6 to get 10/30 = 1/3.

Multiply 1/3 by 6/7 to get 6/21 = 2/7. (I suspect there's a typo in the question.)

And so on, so that the nth term in the sequence is multiplied by n/(n + 1) to get the (n + 1)th term.

Recursively, the sequence is given by

[tex]\begin{cases}a_1=2\\a_n=\dfrac{n-1}na_{n-1}&\text{for }n>1\end{cases}[/tex]

We can solve this exactly by iterating:

[tex]a_n=\dfrac{n-1}na_{n-1}=\dfrac{n-1}n\dfrac{n-2}na_{n-1}=\dfrac{n-1}n\dfrac{n-2}{n-1}\dfrac{n-3}{n-2}a_{n-3}=\cdots[/tex]

and so on down to

[tex]a_n=\dfrac{(n-1)\cdot(n-2)\cdot(n-3)\cdot\cdots\cdot3\cdot2\cdot1}{n\cdot(n-1)\cdot(n-2)\cdot\cdots\cdot4\cdot3\cdot2}a_1[/tex]

or

[tex]a_n=\dfrac{(n-1)!}{n!}a_1[/tex]

and with lots of cancellation, we end up with

[tex]a_n=\dfrac{a_1}n=\boxed{\dfrac2n}[/tex]

Answer:

Divide 2 by n.

Step-by-step explanation:

Answer:

Study 2

Step-by-step explanation:

Okay, so in this question we are given the data or parameters or information Below;

=>" two studies were conducted on the effectiveness of a peer mentoring program."

=> "Self-evaluation ratings among participants before, during, and after the program were measured in both studies."

=> In Study 1, 12 participants were observed"

=> "Study 2, 16 participants were observed."

=> " If Fobt = 3.42 in both studies"

Say Vo = study 2 and V1 = study 1.

Hence, Vo: not effective.

V1 = effective.

The study in which the decision will be to reject the null hypothesis at α= 0.05 level of significance is the STUDY 2.

This is because the value of F > f-critical.

Answer:

1

Step-by-step explanation: