Please answer this correctly

Answer:

Peter gets 18£

Gordon and Gavin each get 9£

Answer:

peter = 18 Gordon = 9 Gavin = 9

Step-by-step explanation:

2+1+1 = 4

36 div 4 = 9

2 times 9 = 18

1 times 9 = 9

Answer:

[tex]y(x)=c_1e^{-3x} cos(2x)+c_2e^{-3x} sin(2x)[/tex]

Step-by-step explanation:

In order to find the general solution of a homogeneous second order differential equation, we need to solve the characteristic equation. This is basically as easy as solving a quadratic.

For a second order differential equation of type:

[tex]ay''+by'+cy=0[/tex]

Has characteristic equation:

[tex]a r^{2} +br+c=0[/tex]

Whose solutions [tex]r_1 , r_2 ,.., r_n[/tex] are the roots from which the general solution can be formed. There are three cases:

Real roots:

[tex]y(x)=c_1e^{r_1 x} +c_2e^{r_2 x}[/tex]

Repeated roots:

[tex]y(x)=c_1e^{r x} +c_1 xe^{r x}[/tex]

Complex roots:

[tex]y(x)=c_1e^{\lambda x}cos(\mu x) +c_2e^{\lambda x}sin(\mu x)\\\\Where:\\\\r_1_,_2=\lambda \pm \mu i[/tex]

Therefore:

The characteristic equation for:

[tex]y''+6y'+13y=0[/tex]

Is:

[tex]r^{2} +6r+13=0[/tex]

Solving for [tex]r[/tex] :

[tex]r_1_,_2= -3 \pm 2i[/tex]

So:

[tex]\mu = 2\\\\and\\\\\lambda=-3[/tex]

Hence, the general solution of the differential equation will be given by:

[tex]y(x)=c_1e^{-3x} cos(2x)+c_2e^{-3x} sin(2x)[/tex]

Answer:

[tex]x=-10[/tex]

Step-by-step explanation:

[tex]\frac{x}{2}=-5\\\mathrm{Multiply\:both\:sides\:by\:}2\\\frac{2x}{2}=2\left(-5\right)\\Simplify\\x=-10[/tex]

Answer:

The probability of selecting two red balls is 0.132.

Step-by-step explanation:

In a bag there are 10 balls in a bag, 4 red balls and 6 black balls.

The conditions of selecting a ball are:

It is also provided that only one ball can be picked at a time.

Now, it is given that two balls are picked.

The number of ways to select a red ball in the first draw is: [tex]{4\choose 1}=4\ \text{ways}[/tex]

Compute the probability of selecting a red ball in the first draw as follows:

[tex]P(\text{First ball is Red})=\frac{{4\choose 1}}{{10\choose 1}}=\frac{4}{10}=0.40[/tex]

Now as a red ball is selected it will not be replaced.

So, there are 9 balls in the bag now.

The number of ways to select a red ball in the second draw is: [tex]{3\choose 1}=3\ \text{ways}[/tex]

Compute the probability of selecting a red ball in the second draw as follows:

[tex]P(\text{Second ball is Red})=\frac{{3\choose 1}}{{9\choose 1}}=\frac{3}{9}=0.33[/tex]

Compute the probability of selecting two red balls as follows:

[tex]P(\text{Two Red balls})=P(\text{First ball is Red})\times P(\text{Second ball is Red})[/tex]

                            [tex]=0.40\times 0.33\\\\=0.132[/tex]

Thus, the probability of selecting two red balls is 0.132.

Answer: you would need 776 yards to make both dresses

Step-by-step explanation:

You would need to find the sum of the amount if yards needed for both dresses.

The first dress needs 418 yards

The seconds dress needs 358 yards

418 + 358 = 776

Therefore you would need 776 yards to be able to make both of the dresses

Answer:

The expected completion time of this project from now is 2.5 months.

Step-by-step explanation:

To find the expected completion time for the project, we multiply each projection by it's probability.

We have that:

0.4 = 40% probability it takes 2 months to complete the project.

0.3 = 30% probability that it takes 2.5 months to complete the project.

0.2 = 20% probability it takes 3 months to complete the project.

0.1 = 10% probability it takes 3.5 months to complete the project.

What is the expected completion time (in months) of this project from now?

E = 0.4*2 + 0.3*2.5 + 0.2*3 + 0.1*3.5 = 2.5

The expected completion time of this project from now is 2.5 months.

Answer:

  too much caramel

Step-by-step explanation:

3 ounces : 5 scoops = 3·2 ounces : 5·2 scoops = 6 ounces : 10 scoops

If the Freeze Zone shakes have 6 ounces : 8 scoops, then Ari will think they need more ice cream (2 scoops per shake) or less caramel.

As is, the ratio of caramel to ice cream is too high.

Answer:

[tex] AC = \sqrt(26) \approx 5.1 [/tex]

Step-by-step explanation:

The diagonals are AC and BD.

Now we find the lengths of the diagonals using the distance formula.

[tex] d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} [/tex]

AC:

[tex] AC = \sqrt{(6 - 5)^2 + (7 - 2)^2} [/tex]

[tex] AC = \sqrt{(1)^2 + (5)^2} [/tex]

[tex] AC = \sqrt{1 + 25} [/tex]

[tex] AC = \sqrt{26} [/tex]

BD:

[tex] BD = \sqrt{(9 - 2)^2 + (5 - 4)^2} [/tex]

[tex] BD = \sqrt{(7)^2 + (1)^2} [/tex]

[tex] BD = \sqrt{49 + 1} [/tex]

[tex] BD = \sqrt{50} [/tex]

Since sqrt(26) < sqrt(50), then the shorter diagonal is AC.

Answer: AC = sqrt(26) or approximately 5.1

Answer:

A = (5.2)

Step-by-step explanation:

c2= (6-5)^2 + (7-2)^2

To find AC we calculate within parenthesis (6-5) : 1

c2= 1 + (7-2)^2

calculate within parenthesis (7-2) : 5

c2 = 1^2 + 5^2

then calculate exponents 1^2:1

c^2 = 1+5^2

add and subtract left to right

c^2 = 1+25

c^2 =26

Sr of 26 = 5.09901951359

Which means the closest answer is A = 5.2

To find BD we calculate within parenthesis (9-2):7

c2= (9-2)^2 + (5 - 4)^2

calculate within parenthesis (5-4) : 1

c2 = (7)^2 + (1)^2

calculate exponents 1 ^2 : 1

c2 = 49 +1

add and subtract left to right

c2 = 50

Sr of 50 = 7.07106781187

Answer: The graph is

The graph is plotted and attached.

A function is a law that relates a dependent and an independent variable.

The function is y = 3/4 x + 5

The slope of the line is (3/4)

and the y intercept is 5.

The graph is plotted and attached with the answer.

To know more about Function

https://brainly.com/question/12431044

#SPJ2

Answer:

12/5

Step-by-step explanation:

Reciprocal of 2/3 is 3/2

Reciprocal of 1/8 is 8/1

Reciprocal of 5 is 1/5

[tex]\frac{3}{2} \times \frac{8}{1} \times\frac{1}{5} = \frac{24}{10} \\[/tex]

Can be simplified to

[tex]\frac{12}{5}[/tex]

Answer: she putz 9 in the last shelter

Step-by-step explanation:

Answer:

Fastest wind speed ever recorded

That is, however, a patch on the top speed ever reached by an aircraft, a record held by the Lockheed Blackbird, which tickled 2,193mph in 1976

Step-by-step explanation:

Answer:

Step-by-step explanation:

a) The probability of a Type I error in a lie detection test would be the probability that the lie detection machine incorrectly detected lie for the truth tellers. This is already given in the problem as 0.07.

Therefore,

[tex]P(Type-I) = 0.07[/tex]

Therefore 0.07 is the required probability here.

b) The probability of a Type II error in a lie detection test would be the probability that the lie detection machine incorrectly detected truth for the the people who are actually liars. This is thus 1 - reliability.

[tex]P(Type-II) = 1 - Reliability = 1- 0.86 = 0.14[/tex]

Therefore 0.14 is the required probability here.

Answer:

a) 0.070

b) 0.14

Step-by-step explanation:

Given that the tests are 86% reliable, i.e a probability of 0.86 a lie would be detected.

Probability of error = 0.070

a) For type I error, we have:

The probability of a type I error in this lie detector is the probability that the test erroneously detects a lie even when the individual is actually telling the truth, i.e

P(type I error) = P(rejecting true null)

= 0.070

b) The probability of a Type II error this lie detectot is the probability that the test erroneously detected truth insteax of lie.

i.e = 1 - reliability

P (Type II error) = P(Failing to reject false Null)

= P(Not detecting a lie)

= 1-0.86

= 0.14

Answer:

x=-77+5√ 231 x=-77-5√231

I got this answer for x and the both equations are equal

Answer:

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

[tex]C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex]   ,thus, the  function is said to be an increasing function.

Step-by-step explanation:

Given that:

[tex]\dfrac{dC}{dt}= r-kC[/tex]

[tex]\dfrac{dC}{r-kC}= dt[/tex]

Taking integration on both sides ;

[tex]\int\limits\dfrac{dC}{r-kC}= \int\limits \ dt[/tex]

[tex]- \dfrac{1}{k}In (r-kC)= t +D[/tex]

[tex]In(r-kC) = -kt - kD \\ \\ r- kC = e^{-kt - kD} \\ \\ r- kC = e^{-kt} e^{ - kD} \\ \\r- kC = Ae^{-kt} \\ \\ kC = r - Ae^{-kt} \\ \\ C = \dfrac{r}{k} - \dfrac{A}{k}e ^{-kt} \\ \\[/tex]

[tex]C(t) =\frac{ r}{k} - \frac{A}{k}e^{ -kt}[/tex]

here;

A is an integration constant

In order to determine A, we have [tex]C(0) = C0[/tex]

[tex]C(0) =\frac{ r}{k} - \frac{A}{k}e^{0}[/tex]

[tex]C_0 =\frac{r}{k}- \frac{A}{k}[/tex]

[tex]C_{0} =\frac{ r-A}{k}[/tex]

[tex]kC_{0} =r-A[/tex]

[tex]A =r-kC_{0}[/tex]

Thus:

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}[/tex]

2. Assuming that C0 < r/k, find lim t→[infinity] C(t) and interpret your answer

[tex]C_{0} < \lim_{t \to \infty }C(t) \\ \\C_0 < \dfrac{r}{k} \\ \\kC_0 <r[/tex]

The equation for C(t) can  be rewritten as :

[tex]C(t) =\dfrac{ r}{k} - \left (\dfrac{r-kC_{0}}{k} \right )e^{ -kt}C(t) =\dfrac{ r}{k} - \left (+ve \right )e^{ -kt} \\ \\C(t) =\dfrac{ r}{k}- e^{ -kt}[/tex]

Thus;  the  function is said to be an increasing function.

Answer:

Step-by-step explanation:

Corresponding means for population 1 and population 2 form matched pairs.

The data for the test are the differences between the mean for population 1 and mean for population 2.

μd =​ the mean for population 1 minus the mean for population 2.

Population 1 population 2 diff

19 24 - 5

25 27 - 2

31 36 - 5

52 53 - 1

49 55 - 6

34 34 0

59 66 - 7

47 51 - 4

17 20 - 3

51 55 - 4

Sample mean, xd

= (- 5 - 2 - 5 - 1 - 6 + 0 - 7 - 4 - 3 - 4)/10 = - 3.7

xd = - 3.7

Standard deviation = √(summation(x - mean)²/n

n = 10

Summation(x - mean)² = (- 5 + 3.7)^2 + (- - 2 + 3.7)^2 + (- 5 + 3.7)^2+ (- 1 + 3.7)^2 + (- 6 + 3.7)^2 + (0 + 3.7)^2 + (- 7 + 3.7)^2 + (- 4 + 3.7)^2 + (- 3 + 3.7)^2 + (- 4 + 3.7)^2 = 73.7

Standard - eviation = √(73.7/10

sd = 2.71

For the null hypothesis

H0: μd ≥ 0

For the alternative hypothesis

H1: μd < 0

The distribution is a students t. Therefore, degree of freedom, df = n - 1 = 10 - 1 = 9

The formula for determining the test statistic is

t = (xd - μd)/(sd/√n)

t = (- 3.7 - 0)/(2.71/√10)

t = - 4.32

We would determine the probability value by using the t test calculator.

p = 0.00097

Since alpha, 0.1 > than the p value, 0.00097, then we would reject the null hypothesis. Therefore, at 0.1 level of significance, we can conclude that these data are sufficient to indicate that the mean for population 2 is larger than that for population 1.

3) for population 1,

Mean = (19 + 25 + 31 + 52 + 55 + 34 + 59 + 47 + 17 + 51)/10 = 38.4

Summation(x - mean)² = (19 - 38.4)^2 + (25 - 38.4)^2 + (31 - 38.4)^2+ (52 - 38.4)^2 + (49 - 38.4)^2 + (34 - 38.4)^2 + (59 - 38.4)^2 + (47 - 38.4)^2 + (17 - 38.4)^2 + (51 - 38.4)^2 = 2042.4

Standard deviation, s1 = √2042.4/10 = 14.3

for population 2,

Mean = (24 + 27 + 36 + 53 + 55 + 34 + 66 + 51 + 20 + 55)/10 = 42.1

Summation(x - mean)² = (24 - 42.1)^2 + (27 - 42.1)^2 + (36 - 42.1)^2 + (53 - 42.1)^2 + (55 - 42.1)^2 + (34 - 42.1)^2 + (66 - 42.1)^2 + (51 - 42.1)^2 + (20 - 42.1)^2 + (55 - 42.1)^2 = 2248.9

Standard deviation, s2 = √2248.9/10 = 15

The formula for determining the confidence interval for the difference of two population means is expressed as

Confidence interval = (x1 - x2) ± z√(s²/n1 + s2²/n2)

For a 90% confidence interval, we would determine the z score from the t distribution table because the number of samples are small

Degree of freedom =

(n1 - 1) + (n2 - 1) = (10 - 1) + (10 - 1) = 18

z = 1.734

x1 - x2 = 38.4 - 42.1 = - 3.7

√(s1²/n1 + s2²/n2) = √(14.3²/10 + 15²/10)

= 6.55

Margin of error = 1.734 × 6.55 = 11.4

The 90% confidence interval is

- 3.7 ± 11.4

Answer:

  Find the places where the derivative is zero and the second derivative is positive.

Step-by-step explanation:

By definition, a function has a minimum where the first derivative is zero and the second derivative is positive.

That will be a "local" minimum if there are other points on the function graph that have values less than that. It will be a "global" minimum if there are no other function values less than that. A global minimum is also a local minimum.

__

On a graph, a local minimum is the bottom of the "U" where the graph changes from negative slope to positive slope.

Answer:

A. The solutions are [tex]x=3i,\:x=-3i[/tex].

B. The factored form of the quadratic expression [tex]x^2+9=(x-3i)(x+3i)[/tex]

Step-by-step explanation:

A. To find the solutions to the quadratic equation [tex]x^2+9=0[/tex] you must:

[tex]\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\x^2+9-9=0-9\\\\\mathrm{Simplify}\\\\x^2=-9\\\\\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}\\\\x=\sqrt{-9},\:x=-\sqrt{-9}[/tex]

[tex]x=\sqrt{-9} = \sqrt{-1}\sqrt{9}=\sqrt{9}i=3i\\\\x=-\sqrt{-9}=-\sqrt{-1}\sqrt{9}=-\sqrt{9}i=-3i[/tex]

The solutions are:

[tex]x=3i,\:x=-3i[/tex]

B. Two expressions are equivalent to each other if they represent the same value no matter which values we choose for the variables.

To factor [tex]x^2+9[/tex]:

First, multiply the constant in the polynomial by [tex]i^2[/tex] where [tex]i^2[/tex] is equal to -1.

[tex]x^2+9i^2[/tex]

Since both terms are perfect squares, factor using the difference of squares formula

[tex]a^2-i^2=(a+i)(a-i)[/tex]

[tex]x^2+9=x^2+9i^2=\left(-3i+x\right)\left(3i+x\right)[/tex]

Answer:

-14a^2b-42ab^2+56abc

Step-by-step explanation:

You can use the FOIL method

multiply the first numbers

then inner

then outer

then last

Answer:

The second choice.

Step-by-step explanation:

Answer:

2nd graph down

Step-by-step explanation:

3a+11 > 5

Subtract 11 from each side

3a+11-11 > 5-11

3a > -6

Divide each side by 3

3a/3 > -6/3

a >-2

Open circle at 02

line going to the right

Answer:

The answer is s / s + 3

Step-by-step explanation:

I applied the fraction rule a/b divided by c/d = a/b times c/d

Please mark BRAINLIEST!

Answer:

Step-by-step explanation:

The gradient theorem applies here, because we can find a scalar function f for which ∇ f (or the gradient of f ) is equal to the underlying vector field:

[tex]\nabla f(x,y,z)=\langle2xy,x^2-z^2,-2yz\rangle[/tex]

We have

[tex]\dfrac{\partial f}{\partial x}=2xy\implies f(x,y,z)=x^2y+g(y,z)[/tex]

[tex]\dfrac{\partial f}{\partial y}=x^2-z^2=x^2+\dfrac{\partial g}{\partial y}\implies\dfrac{\partial g}{\partial y}=-z^2\implies g(y,z)=-yz^2+h(z)[/tex]

[tex]\dfrac{\partial f}{\partial z}=-2yz=-2yz+\dfrac{\mathrm dh}{\mathrm dz}\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C[/tex]

where C is an arbitrary constant.

So we found

[tex]f(x,y,z)=x^2y-yz^2+C[/tex]

and by the gradient theorem,

[tex]\displaystyle\int_{(0,0,0)}^{(1,2,3)}\nabla f\cdot\langle\mathrm dx,\mathrm dy,\mathrm dz\rangle=f(1,2,3)-f(0,0,0)=\boxed{-16}[/tex]

Answer:

yes all that apply to this q9

Answer:

there are 5 types of point of views

please brainliest me

Step-by-step explanation:

1rst person: Writing in first person means writing from the author's point of view or perspective. This point of view is used for autobiographical writing as well as narrative.

2 person: The second-person point of view belongs to the person (or people) being addressed. This is the “you” perspective. Once again, the biggest indicator of the second person is the use of second-person pronouns: you, your, yours, yourself, yourselves.

3 person:  In the third-person point of view, a narrator tells the reader the story, referring to the characters by name or by the third-person pronouns he, she, or they.

4 person: The term fourth person is also sometimes used for the category of indefinite or generic referents, which work like one in English phrases such as "one should be prepared" or people in people say that..., when the grammar treats them differently from ordinary third-person forms."

5 person:From a fifth person perspective, one starts to “feel” the system in a different way, recognizing that one's own perspective on and in the Anthropocene is merely a perspective, which itself is a perspective, which in turn is a perspective.

Answer:

A/h = b

Step-by-step explanation:

A = bh

Divide each side by h

A/h = bh/h

A/h = b

Answer:

[tex]b=\frac{A}{h}[/tex]

Step-by-step explanation:

→To get "b," by itself, all you need to do is divide both sides by "h," like so:

[tex]A=bh[/tex]

[tex]\frac{A}{h} =\frac{bh}{h}[/tex]

[tex]\frac{A}{h} = b[/tex]

Answer:

P(50.1 < X < 51.1) = 0.5

Step-by-step explanation:

An uniform probability is a case of probability in which each outcome is equally as likely.

For this situation, we have a lower limit of the distribution that we call a and an upper limit that we call b.

The probability that we find a value X between c and d is given by the following formula:

[tex]P(c < X < d) = \frac{d - c}{b - a}[/tex]

The lengths of a professor's classes has a continuous uniform distribution between 50.0 min and 52.0 min.

This means that [tex]a = 50, b = 52[/tex]

So

[tex]P(50.1 < X < 51.1) = \frac{51.1 - 50.1}{52 - 50} = 0.5[/tex]

Answer:

28.45.

Step-by-step explanation:

5 x 5.69

Answer:

Step-by-step explanation:

We will first translate the situation to propositional logic. First, some notation is needed: [tex]\lor[/tex] is the or logical operation and [tex]\implies[/tex] is the symbol for logical implication. Define the following events:

J: Jose took the jewelry. L: Mrs Krasov lied, C: a crime was committed. T: Mr Krasov  was in town.

We will symbol the propositions in logical symbols. Recall that [tex]\neg[/tex] means negation

If Jose took the jewelry or Mrs. Krasov lied, then a crime was committed: [tex]J\lor L \implies C[/tex]

Mr. Krasov was not in town: [tex]\neg T[/tex]

If a crime was committed, then Mr. Krasov was in town: [tex]C\implies T[/tex]

We want to check if the conclusion Jose did not take the jewerly: [tex]\neg J[/tex] can be deduced from the premises.

First, recall the following:

- if [tex] a\implies b[/tex] and a is true, then b is true.

- [tex] a\implies b[/tex] is logically equivalent to [tex]\neg b \implies a[/tex]

Coming back to the problem, we have the following premises

[tex]J\lor L \implies C, \neg T, \neg T \implies \neg C, \neg C \implies \neg(J\lor L)[/tex]

where the equivalence for the logical implication was applied. REcall that the negation of an or  statement is g iven by

[tex] \neg( a \lor b ) = \neg a \land \neg b [/tex] where [tex] \land[/tex] is the and logical operator.

USing this, we get the premises

[tex]J\lor L \implies C, \neg T, \neg T \implies \neg C, \neg C \implies \neg J\land \neg L[/tex]

Since [tex]\neg T[/tex], by having [tex]\neg T \implies \neg C[/tex], then it must be true that [tex]\neg C[/tex]. Since [tex]\neg C \implies \neg J\land \neg L[/tex], then it must be true that [tex] \neg J\land \neg L[/tex]. This final conclusion implies that it is true that [tex]\neg J[/tex] which is the statement that Jose did not take the jewelry.

Find the given attachments