Please help me out here!!

Answer:

x=is the number searched

we have to solve this equation:

(2/5)x=14

x=14*5/2=35

35

Step-by-step explanation:

Answer: no she dosen't

Step-by-step explanation:

If you were to add up all three numbers

49.95+19.95+21.95=91.85

Which means she is $1.85 short to buy all of the items

The price of an adult ticket is x= $10

What is mathematical expression?

A mathematical expression is defined as the collection of the numbers variables and functions by using signs like addition, subtraction, multiplication, and division.

Let the adult ticket be x

Let the children ticket be y

first day,

1*x + 6*y = 52

x + 6y = 52   equation 1

second day,

1*x + 8*y = 66

x + 8y = 66   equation 2

Solving both the equations

Subtracting equation 2 -equation 1, we get

x + 8y - x - 6y = 66 - 52

2y = 14

y = 7

putting the value of y in equation 1, we get

x + 6*7 = 52

x = 52 - 42

x = 10

Therefore, price of an adult ticket is x= $10

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Answer:

[tex]\textsf{Increasing function}: \quad \left[0, \dfrac{1}{16}\right)[/tex]

[tex]\textsf{Decreasing function}: \quad \left(\dfrac{1}{16}, \infty\right)[/tex]

Step-by-step explanation:

Given function:

[tex]f(x)=\sqrt{x}-2x[/tex]

As a negative number cannot be square rooted, the domain of the function is restricted to [0, ∞).

[tex]\textsf{A function is \textbf{increasing} when the \underline{gradient is positive}}\implies f'(x) > 0[/tex]

[tex]\textsf{A function is \textbf{decreasing} when the \underline{gradient is negative}} \implies f'(x) < 0[/tex]

Differentiating produces an algebraic expression for the gradient as a function of x.  Therefore, differentiate the given function:

[tex]\begin{aligned}f(x) & = \sqrt{x}-2x\\& = x^{\frac{1}{2}}-2x\\\implies f'(x) & = \dfrac{1}{2}x^{\left(\frac{1}{2}-1\right)}-2x^{(1-1)}\\ & = \dfrac{1}{2}x^{-\frac{1}{2}}-2x^0\\ & = \dfrac{1}{2\sqrt{x}}-2\end{aligned}[/tex]

Increasing function

To find the interval where f(x) is increasing, set the differentiated function to more than zero and solve for x:

[tex]\begin{aligned}f'(x) & > 0\\\implies \dfrac{1}{2\sqrt{x}}-2 & > 0\\\dfrac{1}{2\sqrt{x}} & > 2\\\ \dfrac{1}{2} & > 2\sqrt{x}\\\dfrac{1}{2 \cdot 2} & > \sqrt{x}\\ \dfrac{1}{4} & > \sqrt{x}\\ \sqrt{x} & < \dfrac{1}{4}\\\left(\sqrt{x}\right)^2 & < \left(\dfrac{1}{4}\right)^2\\ x & < \dfrac{1}{16}\end{aligned}[/tex]

As the domain is restricted, the function is increasing when:

[tex]\textsf{Solution}: \quad 0 \leq x < \dfrac{1}{16}[/tex]

[tex]\textsf{Interval notation}: \quad \left[0, \dfrac{1}{16}\right)[/tex]

Decreasing function

To find the interval where f(x) is decreasing, set the differentiated function to less than zero and solve for x:

[tex]\begin{aligned}f'(x) & < 0\\\implies \dfrac{1}{2\sqrt{x}}-2 & < 0\\\dfrac{1}{2\sqrt{x}} & < 2\\\ \dfrac{1}{2} & < 2\sqrt{x}\\\dfrac{1}{2 \cdot 2} & < \sqrt{x}\\ \dfrac{1}{4} & < \sqrt{x}\\ \sqrt{x} & > \dfrac{1}{4}\\\left(\sqrt{x}\right)^2 & > \left(\dfrac{1}{4}\right)^2\\ x & > \dfrac{1}{16}\end{aligned}[/tex]

Therefore, the function is decreasing when:

[tex]\textsf{Solution}: \quad x > \dfrac{1}{16}[/tex]

[tex]\textsf{Interval notation}: \quad \left(\dfrac{1}{16}, \infty\right)[/tex]

Note: The answer quoted in the original question is incorrect for the quoted function (please refer to the attached graph for proof).

Differentiation Rules

[tex]\boxed{\begin{minipage}{4.8 cm}\underline{Differentiating $ax^n$}\\\\If $y=ax^n$, then $\dfrac{\text{d}y}{\text{d}x}=nax^{n-1}$\\\end{minipage}}[/tex]

Answer:

B, J, C.

Collinear points means the points are on the same straight line, which means they have the same gradient. B, J, C are the only points on the sane straight line.

Answer:

Reflection over y- axis

An expression in math is a sentence with a minimum of two numbers or variables and at least one math operation. a) R=R is a reflexive property.

b) 5-P  Substitution Property, c) If 3 = x and y = -2 Then the expression y = x + b can be written as -2 = 3 + b is a substitution property, d) a=4 Then it can be said that a = b e)DEIR then DF = LR Segment Addition Postulate

f)VW - WY - VT is a Transitive Property

What is Expression?

An expression in math is a sentence with a minimum of two numbers or variables and at least one math operation.

We have match the given expression with an appropriate property.

a) R=R is a reflexive property.

b) 5-P  Substitution Property

c) If 3 = x and y = -2 Then the expression y = x + b can be written as -2 = 3 + b is a substitution property

d) a=4 Then it can be said that a = b  

e)DEIR then DF = LR Segment Addition Postulate

f)VW - WY - VT is a Transitive Property

Therefore .a) R=R is a reflexive property. b) 5-P  Substitution Property, c) If 3 = x and y = -2 Then the expression y = x + b can be written as -2 = 3 + b is a substitution property, d) a=4 Then it can be said that a = b e)DEIR then DF = LR Segment Addition Postulate f)VW - WY - VT is a Transitive Property.

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A triangle in which one of the interior angles is 90° is called a right triangle. The longest side opposite to the right angle is the hypotenuse and the two arms of the right angle are the height and the base.

The area of each triangle is 200 square inches.

A triangle in which one of the interior angles is 90° is called a right triangle. The longest side opposite to the right angle is the hypotenuse and the two arms of the right angle are the height and the base.

We have,

The area of a right triangle is given by:

= 1/2 x base x height

We have from the figure,

Base = 20 inches

Height = 20 inches

Area = 1/2 x 20 x 20

Area = 10 x 20

Area = 200 square inches

Thus the area of each triangle is 200 square inches.

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The complete question is:

You work as an assistant to a carpenter who designed the tabletop below. He tells you that each shape is a right triangle, and each is the same size. You now need to calculate the area of one triangle so that you can begin building the tabletop. What is the area of each triangle in square inches?

A. 200 square inches

B. 400 square inches

C. 570 square inches

D. 2,800 square inches

E. 5,600 square inches

To have $600,000 for retirement in 30 years with 6% interest , we need to deposit $498.29 in the account each month.

As given in the question,

Final amount 'A'= $600,000

Time 't' = 30years

Rate of interest 'r'= 6%

Month =12

Let 'P' be the amount deposit in the account each month

[tex]A = \frac{(P(1+\frac{r}{m})^{mt}-1 )}{\frac{r}{m} }\\\\\implies 600,000 = \frac{(P(1+\frac{6}{12\times 100})^{12\times 30}-1 )}{\frac{6}{12\times 100} }\\\\\implies 600,000 \times \frac{1}{200}= P (\frac{12.06}{12})^{360}-1 \\\\\implies 3000 +1 = P(1.005)^{360} \\\\\implies P = \frac{3001}{6.02258} \\\\\implies P = \$498.29[/tex]

Therefore, to have $600,000 for retirement in 30 years with 6% interest , we need to deposit $498.29 in the account each month.

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Answer:2

Step-by-step explanation: x+1+2x=3x+1        3x+1=7        3x=7-1       x=6/3   x=2

hope it helps

Answer:

3

Step-by-step explanation:

x+1+2x=7

variables should be on the left and the whole number on the right.

something like this: x+2x=7-1

simplify the equation: 3x=6

find x: x= 6/3=2

so u know x is 2

then substitute the 2 into x. so 2+1 =3#

Your answer is three.

The number of cashews in the can are 52.

Here, we are given that the ratio of walnuts to peanuts in a can of mixed nuts is 3 to 5.

⇒ walnuts : peanuts = 3 : 5

The number of walnuts in the packet are = 18

⇒ 18 : peanuts = 3 : 5

18/ peanuts = 3/5

peanuts = (5/3) × 18

peanuts = 30

Now, we know that the total number of nuts = 100

⇒ cashews + walnuts + peanuts = 100

cashews + 18 + 30 = 100

cashews + 48 = 100

cashews = 100 - 48

cashews = 52

Thus, the number of cashews in the can are 52.

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Answer:

1/4 gallon

Step-by-step explanation:

Just multiply the numerator and denominator of the given rate by 2:

2(1/8) gallon 1/4 gallon

------------------ = ---------------- = 1/4 per gallon

2(1/2) hour 1 hour

it will be 7:8

Step-by-step explanation:

28/4 32/4

7 8

LCM can help us to compare the two of the given fractions. The correct option is A, -(3/4) < -(5/16).

The least common multiple that is divisible by both a and b is the smallest positive integer, lowest common multiple, or smallest common multiple of two numbers a and b, generally indicated by LCM.

Bring both the terms to the same denominator for easy comparison. Now, since the LCM of 4 and 16 is 16. Therefore, we can write the two of the fractions as,

-(3/4) = -(3×4)/(4×4) = -12/16

-(5/16) = -5/16

Further, we can write the comparison of the two fractions as,

-12/16 < -5/16

-(3/4) < -(5/16)

Hence, the correct option is A, -(3/4) < -(5/16).

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Answer:

f(4)=9

Step-by-step explanation:

The given function is

F(x)=3x-3

so,

f(4)=3*4-3

f(4)=12-3

f(4)=9

putting 4 in place of x we get answer of the question.

Answer:

help this yuo what is yuor problem

The plane where the point is located and which has a fixed z coordinate (1,2,3) is y=2x.

Given that,

The plane where the point is located and which has a fixed z- coordinate (1,2,3).

The plane has the point (1, 2, 3) and the z-axis.

Any plane that has the z-axis is of the type that (0,0,1)

Therefore, By cross product of the two points we can find the equation.

Let take a matrix with x,y and z

We can se in the picture there is a matrix.

We now find the determination of that matrix .

determination means the scalar value calculated for a given square matrix is the determinant of a matrix. The determinant is a concept in linear algebra, and its components are square matrixes. It can be viewed as the matrix transformation's scaling factor. useful for performing calculus operations, computing the inverse of a matrix, and solving systems of linear equations.

-2x+y=0

y=2x

Therefore, The plane where the point is located and which has a fixed z coordinate (1,2,3) is y=2x.

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Answer:
(-10,-10)Step-by-step

explanation:

Yes 9x-9y=03x-4y=10In

elimination, we want both equations to have the same form and like terms to be lined up.  We have that.  We also need one of the columns with variables to contain opposites or same terms. Neither one of our columns with the variables contain this.  We can do a multiplication to the second equation so that the first terms of each are either opposites or sames. It doesn't matter which.  I like opposites because you just add the equations together. So I'm going to multiply the second equation by -3.I will rewrite the system with that manipulation:9x-9y=0-9x+12y=-30----------------------Add them up!0+3y=-30     3y=-30       y=-10So now once you find a variable, plug into either equation to find the other one.I'm going to use 9x-9y=0 where y=-10.So we are going to solve for x now.9x-9y=0 where y=-10.9x-9(-10)=0  where I plugged in -10 for y.9x+90=0  where I simplified -9(-10) as +90.9x     =-90 where I subtracted 90 on both sides.x=       -10 where I divided both sides by 9.The solution is (x,y)=(-10,-10)

Answer:

[tex]10^{-4}[/tex]

Step-by-step explanation:

0.0001

1/10,000

1/[tex]10^{4}[/tex]

[tex]10^{-4}[/tex]

Answer:

24/15

Step-by-step explanation:

120 : 75 =

120/5 : 75/5 =

24 : 15 =

24/15

Answer:

8 : 5 or 8/5

Step-by-step explanation:

starts as 120 : 75

divide both by 5

= 24 : 15

divide both by 3

= 8 : 5 or 8/5

you just need to get them down to the smallest they can. in this case it is 8 and 5. for every 8 $10 bills there are, you have 5 $20 bills.

The lateral area of the square pyramid that has a base of 10ft and height of 10 ft is calculated as: 200 ft²

A square pyramid is a solid that has a square base and four triangular lateral faces.

The lateral area of the square pyramid is therefore the total area of the four triangular lateral faces of the square pyramid.

Area of one triangular lateral face = 1/2(base)(height)

Lateral area of the square pyramid = Total area of the four triangular lateral faces = 4 × 1/2(base)(height) = 2(base)(height)

We know the following:

Base = 10 ft

Height = 10 ft

Therefore:

Lateral area of the square pyramid = 2(10)(10)

Lateral area of the square pyramid = 200 ft²

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The inequality for 2/3 I 4v + 6 I - 2 ≤ 10 is -6≤v≤3.

Given the inequality is 2/3 I 4v + 6 I - 2 ≤ 10

Isolate the variable by dividing each side by factors that don't contain the variable.

2/3 I 4v + 6 I  ≤ 10 +2

arrange the constants on the right side.

2/3 I4v + 6I ≤ 12

multiply the terms.

8v + 12/3 ≤ 12    or -8v - 12/3 ≤ 12

8v + 12 ≤ 36       or  -8v -12 ≤ 36

8v ≤ 36 -12         or  -8v ≤ 36 + 12

8v ≤ 24               or   -8v ≤ 48

v ≤ 24/8              or    v ≤ 48/8

v ≤ 3                   or    v≥-6

therefore, -6 ≤ v ≤ 3.

Hence the inequality is -6 ≤ v ≤ 3.

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Answer:

-15/4 = x

Step-by-step explanation:

17 = -13 -8x

Solving for x

Add 13 to each side

17 +13 = -13+13-8x

30 = -8x

Divide each side by -8

30/-8 = -8x/-8

Simplify by dividing the top and bottom by 2

-15/4 = x

The transformed function can be seen in the image below, and the rule is:

g(x)= x/3 + 7

Here we have the parent function, and we want to apply a translation of 7 units up and stretch it vertically by a scale factor of 3

First, we need to apply the translation, remember that a vertical translation of N units is written as:

g(x) = f(x) + N

If we want the translation to be upwards, then we need to use a positive value of N, so in this case we wil have:

g(x) = f(x) + 7

And now we apply a stretch of scale factor 3, this means that we need to divide the variable inside of the function by 3, so we get:

g(x) = f(x/3) + 7

This will give:

g(x)= x/3 + 7

Where we use the fact that f(x) = x

The graph of this function can be seen below.

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Answer:

Price per pound = $0.64

which means one pound of banana costs 0.64$.

so,If 1 pound costs 0.64$ then 6.7 pounds would cost:

1 pound = $0.64

6.7 pounds= 0.64× 6.7

that is equal to $4.288.

Step-by-step explanation:

Price per pound = $0.64

which means one pound of banana costs 0.64$.

so,If 1 pound costs 0.64$ then 6.7 pounds would cost:

1 pound = $0.64

6.7 pounds= 0.64× 6.7

that is equal to $4.288.

Answer:

10-18i

Step-by-step explanation:

1(1-9i)+9(1-9i)

1-9i+9-9i

1+9-9i-9i

10-18i