Answer:
D
Explanation:
Interference is the interaction between waves that meet.
Find the direction of the sum of
these two vectors:
can someone help me but please no links
Answer:
1. sand and water
2. suspension
mark me as brainliest plz
Solved Exa
Example 1. An iron ball of mass 3 kg is
released from a height of 125 m and falls
freely to the ground. Assuming that the
value of g is 10 m/s2, calculate
(i) time taken by the ball to reach the
ground
(ii) velocity of the ball on reaching the
ground
(iii) the height of the ball at half the time it
takes to reach the ground.
According to the equations of motion, the time taken to reach the ground is 5 seconds.
Using;
s = ut + 1/2gt^2
s = distance
u = initial velocity
t = time taken
g = acceleration due to gravity
Note that u = 0 m/s since the object was dropped from a height
Substituting values;
125 = 1/2 × 10 × t^2
125 = 5t^2
t^2 = 125/5
t^2 = 25
t = 5 secs
Velocity on reaching the ground is obtained from
v = u + gt
Where u = 0 m/s
v = gt
v = 10 × 5
v = 50 m/s
At half the time it takes to reach the ground;
s = ut + 1/2gt^2
Where u = 0 m/s
s = 1/2gt^2
s = 1/2 × 10 × (2.5)^2
s = 31.25 m
Learn more about equation of motion: https://brainly.com/question/8898885
Answer:
(i) time taken by the ball to reach the
ground is 5 sec.
(ii) velocity of the ball on reaching the
ground is 50 m/s.
(iii) the height of the ball at half the time it
takes to reach the ground is 31.25 m.
Step-by-step explanation:
Solution :(i) time taken by the ball to reach the
ground
[tex]\longrightarrow{\sf{ \: \: s= ut + \dfrac{1}{2} a{(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: 125= 0 \times t + \dfrac{1}{2} \times 10 \times {(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: 125= 0 + \dfrac{10}{2} \times {(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: 125= 0 + 5\times {(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: 125= 5\times {(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = \dfrac{125}{5}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = \dfrac{ \cancel{125}}{\cancel{5}}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {(t)}^2 = 25}}[/tex]
[tex]\longrightarrow{\sf{ \: \: t = \sqrt{25} }}[/tex]
[tex]\longrightarrow \: \: {\sf{\underline{\underline{\red{ t = 5 \: sec}}}}}[/tex]
Hence, the ball taken 5 sec to reach the ground.
[tex]\begin{gathered}\end{gathered}[/tex]
(ii) velocity of the ball on reaching the
ground
[tex]\longrightarrow{\sf{ \: \: {v}^{2} - {u}^{2} = 2as}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {v}^{2} - {0}^{2} = 2 \times 10 \times 125}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {v}^{2} = 20 \times 125}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {v}^{2} = 2500}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {v} = \sqrt{2500} }}[/tex]
[tex]\longrightarrow{\sf{ \: \: \underline{\underline{ \red{{v} = 50 \: m/s }}}}}[/tex]
Hence, the velocity of ball is 50 m/s.
[tex]\begin{gathered}\end{gathered}[/tex]
(iii) the height of the ball at half the time it
takes to reach the ground.
[tex]\longrightarrow{\sf{ \: \: s= ut + \dfrac{1}{2} a{(t)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= 0 \times \dfrac{5}{2} + \dfrac{1}{2} \times 10 \times { \left( \dfrac{5}{2} \right)}^2}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= 0 + \dfrac{10}{2} \times { \left( \dfrac{5}{2} \times \dfrac{5}{2} \right)}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times { \left( \dfrac{5 \times 5}{2 \times 2} \right)}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times { \left( \dfrac{25}{4} \right)}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10}{2} \times \dfrac{25}{4}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{10 \times 25}{2 \times 4}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{250}{8}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: s= \dfrac{\cancel{250}}{\cancel{8}}}}[/tex]
[tex]\longrightarrow{\sf{ \: \: {\underline{\underline{\red{s= 31.25 \: m}}}}}}[/tex]
Hence, the height of the ball to reach the ground is 31.25 m.
[tex]\underline{\rule{220pt}{3.5pt}}[/tex]
A spring of spring constant 30.0 N/m is attached to a 2.3 kg mass and set in motion. What is the period and frequency of vibration for the 2.3 kg mass?
Answer:
1. The period is 1.74 s.
2. The frequency is 0.57 Hz
Explanation:
1. Determination of the the period.
Spring constant (K) = 30 N/m
Mass (m) = 2.3 Kg
Pi (π) = 3.14
Period (T) =?
The period of the vibration can be obtained as follow:
T = 2π√(m/K)
T = 2 × 3.14 × √(2.3 / 30)
T = 6.28 × √(2.3 / 30)
T = 1.74 s
Thus, the period of the vibration is 1.74 s.
2. Determination of the frequency.
Period (T) = 1.74 s
Frequency (f) =?
The frequency of the vibration can be obtained as follow:
f = 1/T
f = 1/1.74
f = 0.57 Hz
Thus, the frequency of the vibration is 0.57 Hz
The period of the vibration is 1.76 s and the frequency of the vibration is 0.57 s-1.
Using the formula;
T = 2π√(m/K)
Where;
T = period
m = mass
K = spring constant
Substituting values;
T = 2(3.142)√2.3/30
T = 6.284 × 0.28
T = 1.76 s
Recall that the period is the inverse of frequency;
f = 1/T
f = 1/1.76 s
f = 0.57 s-1
Learn more about spring constant: https://brainly.com/question/4291098
Explain what does a calorimeter measure?
Measuring the heat of chemical reactions or physical changes.
What do we call the Earth's magnetic field that extends outward from Earth in all
directions?
Answer:
Geomagnetic Field
Explanation:
Write the SI unit of time and temperature
Answer:
The SI unit of time is second (s) and temperature is Kelvin (K)
Explanation:
hope it is helpful to you
Currents of devices that are in a series circuit ar the same, but the __________can be different, which causes __________to be different as well.
Answer: its flowing, reaction
Explanation: this is because currents in a device have a flowing object inside
Is Algae Biotic or Abiotic?
AM and FM stand for two different processes that are used to code voices and music for transmission. What does AM stand for? 1. Amplitude Modulation 2. Amplitude Mediation A
Answer:
1. Amplitude Modulation
Explanation:
AM is an acronym for Amplitude Modulation and it's refers to a process that is typically used for coding sounds such as voices and music for transmission from one point to another.
On the other hand, FM is an acronym for frequency modulation used for the propagation and transmission of sound waves.
Basically, the two forms of modulation are used for broadcasting in radio transmission.
Electromagnetic waves is a propagating medium used in all communications device to transmit data (messages) from the device of the sender to the device of the receiver.
Generally, the most commonly used electromagnetic wave technology in telecommunications is radio waves.
Radio waves can be defined as an electromagnetic wave that has its frequency ranging from 30 GHz to 300 GHz and its wavelength between 1mm and 3000m. Therefore, radio waves are a series of repetitive valleys and peaks that are typically characterized of having the longest wavelength in the electromagnetic spectrum.
A 1036 nm film with an index of refraction n=2.62 is placed on the surface of glass n=1.52. Light (λ=520.0 nm) falls hits the perpendicular to the surface from air. You want to increase the thickness so the reflected light cancels. What is the minimum thickness of the film that you must add?
Answer:
[tex]55.64\ \text{nm}[/tex]
Explanation:
[tex]\lambda[/tex] = Wavelength falling on film = 520 nm
n = Refractive index of film = 2.62
T = Thickness of film
m = Order
We have the relation
[tex]2T=\dfrac{m\lambda}{n}\\\Rightarrow T=\dfrac{m\lambda}{2n}\\\Rightarrow T=\dfrac{m\times 520}{2\times 2.62}\\\Rightarrow T=99.24m[/tex]
The thickness should be greater than 1036 nm. This means [tex]m=11[/tex]
[tex]T=99.24\times 11=1091.64\ \text{nm}[/tex]
Thickness of the film to be added would be
[tex]\Delta T=1091.64-1036=55.64\ \text{nm}[/tex]
Thickness of the film to be added is [tex]55.64\ \text{nm}[/tex].
Answer:
Explanation:
The ray of light is passing from high refractive index medium to low refractive index medium so condition for cancellation of reflected light is as follows .
2μt = (2n+1) λ/2
where μ is refractive index of the medium , t is thickness , λ is wavelength of light and n is a integer .
Putting n = 10
2x 2.62 x t = 21 x 520 / 2 nm
5.24 t = 5460 nm
t = 1042 nm
Thickness required to be added
= 1042 - 1036 = 6 nm .
Two charges, one with a charge of +10.0 x 10-6 C, the other with a charge of -3 x 10-6 C exert a force on each other with a magnitude of 1.7 Newtons on each other. Is this a repulsive or attractive force. What is the separation distance of these charges?
Answer:
b.
Explanation:
Answer:
Attractive force and r = 0.399 m
Explanation:
One charge is positive and the other charge is negative. Opposite charges attract, so there has to be a force that attracts between them.
q1 = 10.0 x 10^-6 C
q2 = -3 x 10^-6 C
F = 1.7 N
Plug those values into Coulomb's Law:
[tex]F = k\frac{q1q2}{r^{2} } \\1.7 = \frac{(9x10^{9})(10.0 x 10^{-6})(-3 x 10^{-6})}{r^{2} }[/tex]
Solve for r
r = 0.399 m
PLZZZZZ HELP MEHH ASAP!!!
Answer:
C
Explanation:
Copper is a conductor because its valence electrons can move freely from atom to atom.
a block of mass 3kg slides along a horizontal surface that has neglitjble friction except dor one section what is the magntiude of acerage frictional force exerted on the block by rough section of surface
You push on a 30 kg box with a force of 120 N. What is the acceleration of the box2
Answer:
6
Explanation:
120/30=6
Which describes an image that a concave mirror can make? Which describes an image that a concave mirror can make?
Answer: The image can be either virtual or real.
Answer:
the image can be rather real or virtual
(Click the picture)
What is the source of energy that will send the arrow flying toward the target?
A- The archers ability to aim correctly
B- The arrow’s distance from the ground
C- The springiness of the bow
D- The time it takes to release the bow
Answer:
a
Explanation:
cause her hand is straight and she followed the direction it sould be correctly unless I am messing something
How is capacitance related to the distance between the plates of a capacitor?
It is directly proportional, so the capacitance increases as the distance increases.
It is inversely proportional, so the capacitance increases as the distance increases.
It is directly proportional, so the capacitance decreases as the distance increases.
It is inversely proportional, so the capacitance decreases as the distance increases.
Answer:C
Explanation: I studied, and C is correct
Answer:
D
Explanation:
Twisting a bone along its longitudinal axis toward the midline of the body is ____________ .Twisting a bone along its longitudinal axis away from the midline of the body is ____________ .Rotation of the forearm, as if you're asking someone to hand you money or slap down on your hand, is called ____________ .Rotation of the forearm, as if you're turning over a can to empty it, is called ____________ .Movement of the thumb to approach and touch the fingertips is called ____________ .
Answer: Medial rotation
Lateral rotation
Supination
Pronation
Opposition
Explanation:
Medial rotation can be defined as the rotation of any of the body part towards the middle axis of the body. For example, movement of leg bones so that the toes are pointed towards inward.
Lateral rotation is the movement of the body parts or bones away from the middle axis of the body. For example. outward circle created by the upper limbs directed outwards.
Supination is the rotation of the forearm in such a way so that the palm is directed upwards so that hand can receive money or hand can slap a person.
Pronation is the downward motion of hand to put things down.
Opposition is the movement of the bones of the fingers the metacarpals which allow the thumb to touch the fingertips.
a rocket burns propellant at a rate of dm/dt = 3.0 kg/s, ejecting gases with a speed of 8000 m/s relative to the rocket. Find the magnitude of the thrust.
Answer: 24 kN
Explanation:
Given
The rocket burns propellant at the rate of
[tex]\dfrac{dm}{dt}=3\ kg/s[/tex]
Relative ejection of gases [tex]v=8000\ m/s[/tex]
The magnitude of thrust force is given by
[tex]F_t=v\dfrac{dm}{dt}\\\\F_t=8000\times 3=24,000\ N\ or\ 24\ kN[/tex]
When copper combines with oxygen to form copper(II) oxide, the charge of the copper ion is
A fluorescent lamp is 25% efficient. Choose the statement that correctly
describes how the lamp performs.
A ) the lamp only works for a quarter of the time
B ) 25% of the electrical energy transferred to the lamp is wasted
C ) the lamp does not work properly
D) 25% of the energy supplied to the lamp is transferred to light
Please answer correctly
Please do not answer from links
Please help
Urgent !!
Will give the brainliest!
Answer:
Explanation:
it's D b/c only 25% of the energy is making light... the rest is probably heat.. :/
A wedge with a mechanical advantage of 0.78 is used to raise a house corner from its foundation. If the output force is 7500 N, what is the input force?
Therefore, the input force is 9615.38N
Input force calculation.
T0 determine the input force needed 0.78 to raise a house corner from its foundation we need to use the formula for mechanical advantage.
Mechanical advantage = output force/ input force
Given the output force to be 7500N and the mechanical advantage 0.78.
We can rearrange the the formula
IF = 7500/0.78
IF = 9615.38N
Therefore, the input force is 9615.38N
Learn more about input force below.
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Which of the following describes half-life? Choose which apply.
A. Half-life is the amount of time it takes for half of a sample to decay.
B. The shorter the half-life, the more unstable the nuclide.
C. Half-life cannot be calculated for nuclides.
D. The longer the half-life, the more stable the nuclide
Answer:
дангггггггггггггггггггггггггггггггггггггггггггггг
Answer: D.
Explanation: I took the test
How does the frequency of infrared electromagnetic waves compare with the frequency of radio and microwaves?
A. The frequency of infrared is higher than radio and microwaves
B. The frequency of infared is lower than radio and microwaves.
C. The frequency of infared is the same as radio and microwaves.
Answer:
Answer is B.
Because the wavelength of infrared is shorter than microwave radiation
A man supports himself and the uniform horizontal beam pulling the rope with a force T.The weights of men and the beam are 883 N and 245 N respectively.Calculate the tension T in the rope and the forces exerted by the pin at A.
Answer:
T=502.5N
Ax=171.8N
Explanation:
The computation of the tension T in the rope and the forces exerted by the pin at A is shown below:
vertical forces sum = Ay + Tsin20 + T - 245 - 883 = 0
Now
horizontal forces sum = Ax - Tcos70
Now Moment about B
-Ay × 4.8 + 245 × 2.4 + 883 × 1.8=0
Ay=453.6N
Now substitute in sum of vertical forces T=502.5N
Ax=171.8N
a. The tension (T) in the rope is equal to 502.51 Newton.
b. The forces exerted by the pin at A is equal to 171.86 Newton.
Given the following data:
Weight of men = 883 N Weight of beam = 245 NTo calculate the tension (T) in the rope and the forces exerted by the pin at A:
First of all, we would determine the vertical force by taking moment about point B as shown in the diagram.
[tex]-A_y \times 4.8 + 883 \times 1.8 + 245 \times 2.4 =0\\\\-4.8A_y + 1589.4 + 588 =0\\\\4.8A_y= 3237\\\\A_y=\frac{2177.4}{4.8} \\\\A_y= 453.63 \;Netwon[/tex]
The tension (T) in the rope would be calculated by the sum of the vertical component of forces, which is given by:
[tex]\sum F_x = A_y + Tsin20 + T - 245 - 883 = 0\\\\453.63 + 0.3420T + T -1128=0\\\\1.3420T = 1128-453.63\\\\1.3420T =674.37\\\\T =\frac{674.37}{1.3420}[/tex]
Tension, T = 502.51 Newton.
To find the forces exerted by the pin at A, we sum the vertical component of forces, which is given by:
[tex]\sum F_y = A_x - Tcos70 =0\\\\A_x =Tcos70\\\\A_x = 502.51 \times cos70\\\\A_x = 502.51 \times 0.3420\\\\A_x = 171.86\;Newton[/tex]
Read more: https://brainly.com/question/17742679
explain the differences between pitch and loudness and what are they connected to?
Answer:
Loudness and pitch are distinct properties of sound. Loudness is related to the amplitude of the sound wave; pitch is related to its frequency
Explanation:
When you think of the word "respiration," you might think about the process of breathing, which is actually called ventilation. (The respiratory system consists of the windpipe, lungs, etc.) How is breathing related to cellular respiration?
Answer:
Breathing and cellular respiration are complementary processes that enable the body to produce energy by taken in oxygen which is required for the chemicals contained in food to be broken down there by producing, energy, water and carbon dioxide. The breathing and cellular respiration process also enables the removal of the produced carbon dioxide finally through nose and/or mouth
Explanation:
In cellular respiration, glucose molecules in the presence of oxygen gas are broken down into carbon dioxide and water aerobically in living cells, to release energy and produce ATP as follows;
C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O
During breathing, oxygen is inhaled into the lungs from the atmosphere and carbon dioxide is exhaled from the longs into the atmosphere, such that the carbon dioxide produced during cellular respiration is transported out of the body through the veins respiratory system, from where is passes out through the nose, while oxygen used in cellular respiration comes from breathing in oxygen into the respiratory system
The oxygen is then transported to the cells through by blood in the blood vessels of the circulatory system to the cells, where the cells use the oxygen for cellular respiration to release energy.
Two identical charged pith balls are brought together to touch each other. They are then
allowed to move freely. The charge on pith ball A is –30 nC and on pith ball B is – 5 nC.
What is the charge on each after they separate?
Answer:
-17.5 nC
Explanation:
charge A = -30 nC
charge B = -5 nC
After adding them it would be the average of the two charges because of the getting same voltage difference. so
c = (-30+(-5)) / 2 nC
c= -17.5 nC
answer is -17.5 nC
Two point charges of magnitude 5.0 nC and -3.0 nC are separated by
35.0 cm. What is the potential difference between a point infinitely far
away and a point midway between the charges?
Answer:
V = 411.43 V
Explanation:
The two forces as a result of each of the 2 charges are;
F1 = kq1•q/r
F2 = kq2.q/r
Where r = r/2 since we are dealing with potential difference at a point midway between the charges.
q1 = 5 nC = 5 × 10^(-9) C
q2 = 3 nC = 3 × 10^(-9) C
k = 9 × 10^(9) N.m²/C²
r = 35 cm = 0.35m
r/2 = 0.35/2
Thus;
F1 = (9 × 10^(9) × 5 × 10^(-9) × q)/(0.35/2)²
F1 = 1469.39q
F2 = (9 × 10^(9) × 3 × 10^(-9) × q)/(0.35/2)²
F2 = 881.63q
Net force acting midway is;
F_net = F1 + F2
F_net = 1469.39q + 881.63q
F_net = 2351.02q
Now, we know that formula for electric potential is;
V = kq/r
Thus ;
V = Fr/q derived from the earlier equation for force we used.
Where F is F_net.
V = 2351.02q × r/q
V = 2351.02r
Recall that we are dealing with midpoint and r = r/2
Thus;
V = 2351.02 × 0.35/2
V = 411.43 V