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Number 9 and 10!

The correct answer is option c) Three moles of sodium, Na.

We know that

18g of H₂O = 1 mol

So, no. of atoms in H₂O = 3 x 6.022 x 10²³

                                           = 1.81 x 10²⁴ atoms(both H&O atoms combined)

Now,

No. of atoms in 1 mol of H₂ = 2 x 6.022 x 10²³

                                             = 1.2044 x 10²⁴ atoms.

No. of atoms in 2 mol of NaCl = 2 x 6.022 x 10²³

                                                  = 1.2044 × 10²⁴ atoms.

No. of atoms in 2 mol of O₂ = 2 x 6.022 x 10²³

                                              = 1.2044 × 10²⁴ atoms.

No. of atoms in 3 mol Na  = 3 x 6.022 x 10²³  

                                              = 1.81 x 10²⁴ Na atoms.

Therefore, 3 mol of Na contains as many atoms as 18g of H₂O i.e., 1.81 x 10²⁴ atoms.

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Which Of The Following Contains As Many Atoms As 18 G Of Water, H2O?

a) One mole of hydrogen, H₂

b) Three moles of sodium, Na

c) Two moles of sodium chloride, NaCl

d) Two moles of oxygen, O₂

s block - group 1 and 2 , p block - group 13 to 18 , d block - group 3 to 12, f block - group 3

Thus we can conclude that ,they are names as s,p,d and f blocks because the last electrons enter s, p , d and f orbitals respectively.

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Answer: To Know That They Did Nothing Wrong

Explanation:

For Example, They Maybe Put The Wrong Thing
Or They Made The Different One Instead Of What They Were Supposed To Do

Answer:

B

Explanation:

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The mass of the solution formed when 20 g of sugar dissolved in 150 g of tea is 170 g.

The net mass of solution is calculated as the algebraic addition of the mass of the solute which is stirred into the mass of the solvent.

During the formation of solution, the sugar molecules are dissolved into tea in which sugar molecules fitted into the intermolecular spaces present between the water molecules of the tea and form a homogenous mixture.

Solvent is the substance or mixture which present in large amount in the solution.

Solute is the substance or mixture which present in small amount in the solution.

Given,

Mass of solute (sugar) = 20g

Mass of solvent (tea) = 150g

Total mass of solution = 20 + 150

= 170g.

Thus we concluded that the mass of the solution formed when 20 g of sugar dissolved in 150 g of tea is 170 g.

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Answer:

Potential energy in a double bond is going to be higher than the potential energy of a single bond due to the force needed to break a double bond as opposed to a single. Single bond is weaker, which means less energy is needed to break it. Double bonds are stronger, requiring more energy to break the bond.

Explanation:

Answer:

Explanation:

The pH of a solution can be found by using the formula

[tex]pH = - log [ {H}^{+} ][/tex]

From the question we have

[tex]pH = - log(3.16 \times {10}^{ - 8} ) \\ = 7.500312...[/tex]

We have the final answer as

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The structure of tRNA resembles cloverleaf. 

 tRNA is called transfer RNA, which is a small RNA molecule which plays important role in protein synthesis.-It serves as link between messenger RNA and the growing chain of amino acids that make up protein.

 tRNA molecules fold into structure resembling cloverleaf  with four important sites:-

•The acceptor stem (3’-CCA) have an amino acid

•The anticodon  attaches  with the mRNA codon (via complementary base pairing)

•The T arm attaches  with the ribosome (via the E, P and A binding sites)

•The D arm of tRNA activating enzyme (help in adding the amino acid to the acceptor stem).

CCA is codon codes for  prolein amino acid in polypeptide chain.

AUG is initiator codon codes for methionine.

UAG, UAA and UGA are stop codons.

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A piece of magnesium in the shape of cube measuring with height of 5.62 cm, and this magnesium sample having mass of 1.41 g has a density of 1.78 g/cm³.

What is Density?

Density is known as the mass of substance per unit volume. Density is denoted by a Greek symbol ρ. Density is equal to the mass substance divided by its volume. The SI unit of Density is g/cm ³or kg/m³.

                                     ρ = m

                                             v

where,

ρ = density

m = mass

v  = volume

Given :

Height of the cylinder is 5.62 cm ,

Diameter of the cylinder is 1.34 cm

Radius = D/2 = 1.34/2 cm

Radius = 0.67 cm

Volume of cylinder = πr²h

Volume of cylinder = 3.14 × (0.67)² × 5.62

                                = 7.92 cm³

 Density =   Mass  

                 Volume

Density = 14.1

                 7.92

 Density = 1.78 g/cm³

Hence, the density of sample = 1.78 g/cm³ .

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The energy of the radio wave in kilojoules is obtained as 6.2 * 10^-25 J.

The term wave has to do with a disturbance along a medium which transfers energy. There are different kinds of wave. In this case, a radio wave is a type of electromagnetic wave. The electromagnetic waves do not require a medium for their propagation. This implies that they are able to move on their own with no medium.

Thus;

We know that;

Frequency of the wave = 9.3x10^8 Hz

Plank's constant =  6.626 x 10^-34 J.s

E = hf

E = energy of the wave

h = Plank's constant

f = frequency of the waves

E = 9.3x10^8 Hz *  6.626 x 10^-34 J.s

= 6.2 * 10^-25 J

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Answer:

879.5616802

Explanation:

(N/Na)*W

The Molarity of solution if a 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius is 2.69M.

Given,

Density of the solution = 1.15 g/mL

Molarity of the sulphiric acid = 2.45M

Molar mass of sulphuric acid = 98 g

Density is given as:

[tex]Molarity(\frac{1}{molarity} +\frac{mol.wt}{1000} )\\\\=2.45(\frac{1}{molarity} + \frac{98}{1000} )\\\\(\frac{1}{molarity} = (\frac{1.15}{2.45} + \frac{98}{1000} \\\\(\frac{1}{molarity} = 0.469 - 0.098\\\\(\frac{1}{molarity} = 0.371\\\\Molarity = 2.69m\\\\[/tex]

The Molarity of solution if a 2.45M of sulphiric acid solution has a density of 1.15g/ml at 20degree celesius is 2.69M.

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Answer:

23 moles

Explanation:

Given data:

number of moles of propane = 7.5 mol

Number of moles of carbon dioxide produced = ?

Solution:

Chemical equation:

C₃H₈ + 5O₂     →      3CO₂ + 4H₂O

Now we will compare the moles of propane and carbon dioxide.

                        C₃H₈             :             CO₂

                             1                :               3

                           7.5              :           3/1×7.5 = 22.5

22.5≅ 23 moles

The maximum number of moles of [tex]CO_2[/tex] that can be recovered from the reaction vessel would be 0.17 moles.

The reaction vessel contains:

The equation of the reaction would be as follows:

[tex]2CO + O_2 --- > 2CO_2[/tex]

The mole ratios of the reactants to the product are as follows:

4.800 g of CO = 4.8/28

                        = 0.17 moles

4.800 g of [tex]O_2[/tex] = 4.8/32

                      = 0.15 moles

Since the mole ratio of CO to  [tex]O_2[/tex] is 2 to 1, 0.17 of CO is limiting.

The mole ratio of CO to  [tex]CO_2[/tex] is 1 to 1. Thus, the equivalent mole of  [tex]CO_2[/tex] that can be recovered is also 0.17.

In other words, the maximum number of moles of  [tex]CO_2[/tex] that can be recovered from the reaction vessel is 0.17 moles.

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The empirical formula of the compound that decomposes is [tex]N_{2} O[/tex]

The term decomposition refers to a type of reaction in which a substance is broken down into its components. We know that a compound is composed of atoms. When there is a decomposition reaction, the atoms of the compound break down.

We can see that the products of the decomposition reaction are nitrogen and oxygen. The red spheres represent oxygen atoms, and the smaller, blue spheres represent nitrogen atoms.

We know that nitrous oxide decomposes to give nitrogen and oxygen. Thus the empirical formula of the compound is [tex]N_{2} O[/tex].

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Answer:

2 electrons

Explanation:

Given that hydrogen is not able to donate its single electron,  the water molecule forms by the sharing of electrons between two hydrogen atoms and an oxygen atom.

This is the type of bond which occurs when the electrons of an atom are shared unlike electrovalent bond which is formed when the electrons are transferred from one atom to another.

In this case, since hydrogen can't transfer electron and oxygen needs two electrons to achieve its stable configuration then two hydrogen atoms will share one electron each with the oxygen atom which results in the formation of water.

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Explanation:

magnesium can be used for the construction as only when the metal is divided into fine pieces or as a thin sheet, magnesium will burn rapidy.

Answer:

\frac  {P_{1}V_{1}}{T_{1}}=\frac  {P_{2}V_{2}}{T_{2}}

Explanation:

Gay-Lussac's law states that at constant volume, the pressure of a gas is directly proportional to the absolute temperature, P ∝ T at constant V. These three gas laws can be combined into a so-called combined gas law, P 1 V 1 T 1 = P 2 V 2 T 2.

Answer:

SO₄²⁻(aq) + Ba²⁺(aq) ⇒ BaSO₄(s)

Explanation:

Let's consider the molecular equation that occurs when aqueous solutions of ammonium sulfate and barium nitrate are mixed.

(NH₄)₂SO₄(aq) + Ba(NO₃)₂(aq) ⇒ BaSO₄(s) + 2 NH₄NO₃(aq)

The complete ionic equation includes all the ions and insoluble species.

2 NH₄⁺(aq) + SO₄²⁻(aq) + Ba²⁺(aq) + 2 NO₃⁻(aq) ⇒ BaSO₄(s) + 2 NH₄⁺(aq) + 2 NO₃⁻(aq)

The net ionic equation includes only the ions that participate in the reaction and the insoluble species.

SO₄²⁻(aq) + Ba²⁺(aq) ⇒ BaSO₄(s)

Answer: 4.48

Explanation: If the last digit in the fractional part of 4.482 is less than 5, then simply remove the last the digit of the fractional part.

Answer:

Determining an Empirical Formula from Combustion Data

Explanation:

Step 1: Identify the mass of carbon dioxide and water produced by the combustion.

Step 2: Find how many moles of carbon are in carbon dioxide.

Step 3: Find how many moles of hydrogen are in water.

Answer:

b.

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Answer: watch Video of HC1O4 + P4010 -> H3PO4 + Cl₂o7 How Do I Balance It?

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Explanation:  video is called      How to Balance HClO4 P4O10 = H3PO4 Cl2O7 (Perchloric acid Phosphorus pentoxide)

Play How to Balance HClO4 P4O10 = H3PO4 Cl2O7 (Perchloric acid Phosphorus pentoxide)

2:22 minute video

How to Balance HClO4 P4O10 = H3PO4 Cl2O7 (Perchloric acid Phosphorus pentoxide)

Answer: (D) 0.025 mol [tex]O_2[/tex]

Explanation:

The given balanced equation is :

[tex]4NH_3+5O_2\rightarrow 4NO+6H_2O[/tex]

According to stoichiometry :

4 moles of ammonia [tex](NH_3)[/tex] reacts with = 5 moles of oxygen [tex](O_2)[/tex]

Thus 0.30 moles of  ammonia  [tex](NH_3)[/tex]  reacts with = [tex]\frac{5}{4}\times 0.30=0.375[/tex] moles of oxygen [tex](O_2)[/tex]

Now as given moles of oxygen are more than the required amount, oxygen is the excess reagent.

moles of oxygen [tex](O_2)[/tex] left = 0.40 - 0.375 = 0.025

Thus 0.025 mol [tex]O_2[/tex] excess reagent remains.

The amount of excess reagent remaining when 0.30 mole NH3 reacts with 0.40 mole O2  is 0.025 mole of O2

An excess reagent is a reactant which is left and can keep reacting after whole reaction.

A limiting reagent is a reactant that is totally consumed in the whole process of the reaction.

The chemical equation for the reaction is represented as:

[tex]\mathbf{4NH_3 + 5O_2 \to 4NO + 6H_2O}[/tex]

From the above reaction,

4 moles of ammonia reacts with 5 moles of oxygen molecule;

If 0.30 moles of ammonia reacts, then the numbers of moles of oxygen required can be computed as:

[tex]\mathbf{= \dfrac{0.3 \times 5}{4}}[/tex]

= 0.375 moles of oxygen.

But, we are given that 0.40 moles of oxygen is present.

Therefore, the amount of oxygen in excess is

= 0.40 moles - 0.375 moles

= 0.025 moles of O2

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Answer:

530.835 g

Explanation:

First we convert 244 g of benzoic acid (C₇H₆O₂) to moles, using its molar mass:

Theoretically, one mol of ethyl benzene would produce one mol of benzoic acid. But the experimental yield tells us that one mol of ethyl benzene will produce only 0.4 moles of benzoic acid.

With the above information in mind we convert 2.00 moles of benzoic acid into moles of ethyl benzene:

Finally we convert moles of ethyl benzene (C₈H₁₀) into grams, using its molar mass:

Answer:

The forelimbs of a bat are different from other mammals as they are modified into wings for the purpose of flying.