PLEASE HELP WILL GIVE BRAINLIEST

Segment AB has been dilated about point Q. What is the scale factor?​

Answer:

Infinity

Step-by-step explanation:

-4y + 4y + 2 = 2

2 = 2 = always true

Answer:

The answer is Infinitely many

Step-by-step explanation:

Answer:

m = 9

Step-by-step explanation:

Isolate the variable by dividing each side by factors that don't contain the variable.

Answer: The answer is,

$5,110

Option (B)

The tax of a single person that earns $33,200 is $5110

The earnings (E) is given as:

[tex]E = \$33,200[/tex]

From the tax table, the equation to calculate the tax of a single person within the income range $28400 to $68,799.99 is:

[tex]Tax =0.25E - 3190[/tex]

So, we have:

[tex]Tax =0.25 \times 33200 - 3190[/tex]

[tex]Tax =8300 - 3190[/tex]

Evaluate the like terms

[tex]Tax =5110[/tex]

Hence, the tax of a single person that earns $33,200 is $5110

Read more about income tax at:

https://brainly.com/question/1775528

Answer:sorry but i can't help you i got work okay.

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

25/10=2.5

Answer:

2.5

Step-by-step explanation:

Answer:

yes yes yes yes yes yes yes

Answer:

121π square centimeters

Step-by-step explanation:

We can find the radius of the circle by taking the average of the two diameters provided. (15+7)/2=11. Then we plug that into the area of a circle equation. Area = π[tex]r^{2}[/tex] and that yields the answer.

Answer:

they are both the same equal

Step-by-step explanation:

can i get brainliest

Answer:

$90 profit

Step-by-step explanation:

Answer:

The area would be 25.

Step-by-step explanation:

The formula for area is base × height.

2 [tex]\frac{1}{2}[/tex] × 10 = 25

Answer:

y-intercept=5

x-intercept=-2

Step-by-step explanation:

To find the y intercept, plug in 0 for x. So you get 10(0)-4y=-20. Simplify, and clear out the negatives on both sides because they cancel each other out. 4y=20 would be your final equation. y=5.

To find the x intercept, you plug in 0 for y this time. The equation is 10x-4(0)=-20. Simplify to get, 10x=-20. You cannot remove the negative because there isn't a negative sign on the 10x. -20/10 is -2.

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Answer:

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{4x-sin(4x)}{16} +c[/tex]

Step-by-step explanation:

Given

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx[/tex]

Required

Evaluate

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx[/tex]

Rewrite as:

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \int\limits {cos(x)\ sin(x)\ sin(2x)} \, dx[/tex]

In trigonometry:

[tex]sin(2x) = 2\ sin(x)\ cos(x)[/tex]

Divide both sides by 2

[tex]\frac{1}{2}sin(2x) = \frac{2\ sin(x)\ cos(x) }{2}[/tex]

[tex]\frac{1}{2}sin(2x) = sin(x)\ cos(x)[/tex]

[tex]\frac{1}{2}sin(2x) = cos(x)\ sin(x)[/tex]

Substitute [tex]\frac{1}{2}sin(2x)[/tex] for [tex]cos(x)\ sin(x)[/tex]

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \int\limits {\frac{1}{2}sin(2x)\ sin(2x)} \, dx[/tex]

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \int\limits {\frac{1}{2}sin^2(2x)} \, dx[/tex]

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{2}\int\limits {sin^2(2x)} \, dx[/tex]

Let [tex]u = 2x[/tex]

Differentiate:

[tex]du = 2 \ dx[/tex]

Make [tex]dx[/tex] the subject

[tex]dx = \frac{1}{2}du[/tex]

Substitute [tex]\frac{1}{2}du[/tex] for [tex]dx[/tex]

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{2}\int\limits {sin^2(2x)} \, \frac{1}{2}du[/tex]

Substitute 2x for u

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{2}\int\limits {sin^2(u)} \, \frac{1}{2}du[/tex]

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{2}*\frac{1}{2}\int\limits {sin^2(u)} \, du[/tex]

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{4}\int\limits {sin^2(u)} \, du[/tex]

At this point, we apply the reduction formula:

Which is:

[tex]\int\limits {sin^n(u)} \, du = \frac{n-1}{2}\int\limits sin^{n-2}(u)\ du\ - \frac{cos(u)sin^{n-1}(u)}{n}\du[/tex]

Let n = 2; So, we have:

[tex]\int\limits {sin^2(u)} \, du = \frac{2-1}{2}\int\limits sin^{2-2}(u)\ du\ - \frac{cos(u)sin^{2-1}(u)}{2}\du[/tex]

[tex]\int\limits {sin^2(u)} \, du = \frac{2-1}{2}\int\limits sin^{0}(u)\ du\ - \frac{cos(u)sin^{2-1}(u)}{2}\du[/tex]

[tex]\int\limits {sin^2(u)} \, du = \frac{1}{2}\int\limits sin^{0}(u)\ du\ - \frac{cos(u)sin^{2-1}(u)}{2}\du[/tex]

[tex]sin^0(u) = 1[/tex]

So, we have:

[tex]\int\limits {sin^2(u)} \, du = \frac{1}{2}\int\limits 1\ du\ - \frac{cos(u)sin^{2-1}(u)}{2}\du[/tex]

Integrate 1 with respect to u

[tex]\int\limits {sin^2(u)} \, du = \frac{1}{2}u - \frac{cos(u)sin^{2-1}(u)}{2}\du[/tex]

[tex]\int\limits {sin^2(u)} \, du = \frac{1}{2}u - \frac{cos(u)sin(u)}{2}\du[/tex]

Recall that:

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{4}\int\limits {sin^2(u)} \, du[/tex]

So, we have:

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{4}[ \frac{1}{2}u - \frac{cos(u)sin(u)}{2}\du][/tex]

Open bracket

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{8}u - \frac{cos(u)sin(u)}{8}[/tex]

Recall that:  [tex]u = 2x[/tex] and  [tex]du = 2 \ dx[/tex]      [tex]dx = \frac{1}{2}du[/tex]

So, the expression becomes:

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{8}2x - \frac{cos(2x)sin(2x)}{8}[/tex]

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{4}x - \frac{cos(2x)sin(2x)}{8}[/tex]

Add constant c

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{4}x - \frac{cos(2x)sin(2x)}{8} +c[/tex]

----------------------------------------------------------------------------------------

In trigonometry:

[tex]sin(2\theta) = 2sin(\theta)cos(\theta)[/tex]

Divide both sides by 2

[tex]\frac{1}{2}sin(2\theta) = \frac{2sin(\theta)cos(\theta)}{2}[/tex]

[tex]\frac{1}{2}sin(2\theta) = sin(\theta)cos(\theta)[/tex]

Replace 2x with [tex]\theta[/tex]

[tex]\frac{1}{2}sin(2*2x) = sin(2x)cos(2x)[/tex]

[tex]\frac{1}{2}sin(4x) = sin(2x)cos(2x)[/tex]

----------------------------------------------------------------------------------------

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{4}x - \frac{cos(2x)sin(2x)}{8} +c[/tex] becomes

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{4}x - \frac{sin(4x)}{2*8} +c[/tex]

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{1}{4}x - \frac{sin(4x)}{16} +c[/tex]

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{x}{4} - \frac{sin(4x)}{16} +c[/tex]

The solution can be further simplified as:

[tex]\int\limits {cos(x)\ sin(2x)\ sin(x)} \, dx = \frac{4x-sin(4x)}{16} +c[/tex]

Answer:The answer is graph B.

Step-by-step explanation: It keeps going up at 0.50 because that is the price PER OUNCE for a serving between 0-8 ounces. The line on the graph is going straight at 4 because that is the price for ANY SERVING over 8 ounces/up to 12 ounces.

Answer:

Step-by-step explanation:

H=2/3

Answer:

one real solution

Step-by-step explanation:

:)

Answer:

DEF =77.4 inches I attached an answer sheet so you can know how to work out the problem

Answer:

49

Step-by-step explanation:

204-8=196 in buses

each bus= 196÷4=49

Answer:

[tex]35degrees[/tex]

Answer:

first is 4+4=8.........second is 22×2=11 ..........third is 8÷11=0.7272727273 u can do it 0.72

Step-by-step explanation:

hope this help

Answer:

0.72

Step-by-step explanation:

Answer:25 yards on the first day.In numerals:XXV

Step-by-step explanation:its pretty simple he cleared the same amount for the first five days.Then 8 more on the sixth.So since 133 in total subtract 8 and divide by 5.133-8=125/5=25 25 yards.

Answer:

B

Step-by-step explanation:

Answer:

the answer should be B

Step-by-step explanation:

C.) The independence of the two ice machines means that knowing how much one machine fills does not help us predict how much the other fills.

[tex]\huge{\mathfrak{\purple{Answer}}}[/tex]

Equation: x² - 15x = 16

Factors: x = -16 and x = 1

[tex]\huge{\mathfrak{\purple{Explanation}}}[/tex]

Given

A number squared minus fifteen times the number is equal to 16.

Equation: x² - 15x = 16

Factors:

x² - 15x - 16 = 0

So,

(x - 16) (x + 1)

=> x - 16 = 0, x + 1 = 0

= x = -16 and x = 1

#HopeItHelps

Answer:

E and F

Step-by-step explanation:

✔️To eliminate the variable y, we can multiply the first equation, -x + 4y = 1 by 7 and the second equation, 8x - 7y = 42 by 4. This will leave us with the variable x alone to solve for.

✔️Alternatively, we may decide to eliminate the variable x first by multiplying the first equation, -x + 4y = 1 by 8. Both equations would be equivalent, thus when we can easily eliminate the variable x leaving us with variable y to solve for.

Answer:

sum=n+m=-2+5=3 is a answer

Answer:

a

Step-by-step explanation: