please help with 1 i would like to see the work please​

Answer:

125000mg

Explanation:

1ml = 1000mg

125(1000) = 125000mg

Answer:

%KCl = 7.05%

%Water = 92.95%

Explanation:

Step 1: Given data

Step 2: Calculate the mass of the solution

The mass of the solution is equal to the sum of the masses of the solute and the solvent.

m = 36 g + 475 g = 511 g

Step 3: Calculate the mass percentage of the solution

We will use the following expression.

%Component = mComponent/mSolution × 100%

%KCl = 36 g/511 g × 100% = 7.05%

%Water = 475 g/511 g × 100% = 92.95%

Answer:NH3 + H2O <==> NH4+ + OH-

0.10 x 0.013 = 0.0013 M (this is the hydroxide concentration)

Kw = [H+] [H-]

1.00 x 10^-14 = (x) (0.0013)

x = 7.7 x 10^-12 M

Explanation:

Answer:

they are typically found in

1)soap

2) detergent

3) baking soda etc..

Answer:

B.

Explanation:

The metal forms metallic bonds which are more greatly affected by gravity, increasing the mass.

Answer:

[tex]Q=54.8kJ[/tex]

Explanation:

Hello there!

In this case, according to the given chemical reaction, it is possible for us to realize that the 46.2 kJ of energy are given per mole of reaction, which are related to 3 moles of hydrogen; Thus, we can calculate the energy per mole of hydrogen as shown below:

[tex]\Delta H=\frac{46.2kJ}{mol} *\frac{1mol}{3molH_2}\\\\ \Delta H=15.4\frac{kJ}{molH_2}[/tex]

Now, to calculate the total energy, we convert the grams to moles of hydrogen as shown below:

[tex]Q=7.19gH_2*\frac{1molH_2}{2.02gmolH_2}*15.4\frac{kJ}{molH_2} \\\\Q=54.8kJ[/tex]

Best regards!

Answer: The Anode reaction is [tex]Fe(s)\rightarrow Fe^{2+}(aq)+2e^-[/tex]

Explanation:

Oxidation-reduction reaction or redox reaction is defined as the reaction in which oxidation and reduction reactions occur simultaneously.

Oxidation reaction is defined as the reaction in which a substance looses its electrons.Oxidation occurs at anode.

Anode : [tex]Fe(s)\rightarrow Fe^{2+}(aq)+2e^-[/tex]

Reduction reaction is defined as the reaction in which a substance gains electrons. Reduction occurs at cathode.

Cathode : [tex]Cd^{2+}(aq)+2e^-\rightarrow Cd(s)[/tex]

The correct option for the given question about Buffer Solution is Option B) which is maintains a constant or nearly constant pH when small amounts of strong acids or bases are added.

Thus we conclude that when weak acids or bases are supplied in small amounts, the pH remains steady or almost constant.

Learn more about Buffer Solution here:

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Answer:

4.9∗1022  molecules of CO2 in a 3.6 gram sample.

Explanation:

The gram molecular weight of co2 is 44 gms.

So the number of molecules in 44 gms of co2 is 6.023×10^23 .

Then the number of molecules in 3.6 gms of co2 is (6.023×10^23×3.6)÷44 = 4.92×10^22

Answer: The equilibrium constant for [tex]PX_5(g)\rightarrow PX_3(g)+X_2(g)[/tex] is 1.35

Explanation:

Equilibrium constant is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as [tex]K_c[/tex]  

For the given chemical reaction:

[tex]PX_3(g)+X_2(g)\rightarrow PX_5(g)[/tex]

The expression for [tex]K_c[/tex] is written as:

[tex]K_c=\frac{[PX_5]^1}{[PX_3]^1[X_2]^1}[/tex]

[tex]0.74=\frac{[PX_5]^1}{[PX_3]^1[X_2]^1}[/tex]

For the reverse chemical reaction:

[tex]PX_5(g)\rightarrow PX_3(g)+X_2(g)[/tex]

The expression for [tex]K_c'[/tex] is written as:

[tex]K_c'=\frac{[PX_3]^1[X_2]^1}{[PX_5]^1}[/tex]

[tex]K_c'=\frac{1}{K_c}=\frac{1}{0.74}=1.35[/tex]

The equilibrium constant for [tex]PX_5(g)\rightarrow PX_3(g)+X_2(g)[/tex] is 1.35

Answer:

221.22K or -51°C

Explanation:

We will be using the Ideal Gas Law to calculate the temperature of the gas. It is a mathematical relationship that describes the behavior of ideal gas ample for any combo of varying pressure, volume, temperature, and # of moles (n). It is derived by combing Boyle's Law, Charles' Law, Gay-Lussac's & Avogadro's Law.

Note: As always, remember that temperature must be in Kelvin not Celsius when using this equation.

Ideal Gas Law: [tex]PV = nRT[/tex], where P = pressure, V = volume (in Liters), n = # of moles, R = the ideal gas constant, and T = temperature (in Kelvin).

Based on the problem, we are given the pressure, volume, and # of moles. We are asked to find the temperature. What about R you ask? Well, R is a constant that is the value of 1 mole of gas at STP. R has various values depending on the pressure units. In this case, our pressure is in atm so the R value = 0.0821.

Onto the math - all that needs to be done now is to plug and chug. Plug in the given values to find the temperature:

Set up: [tex](7.6 atm)(12L) = (5 mol)(0.0821 L*atm/(mol*K))(T)[/tex]

==> [tex]T = \frac{(7.6 atm)(12L)}{(5 mol)(0.0821 L*atm/(mol*K))}[/tex]

==> T = 221.17K

The answer is 221.17K. To convert into Celsius, subtract by 273.15 to get -50.99 or -51°C.

Answer:

All forms of energy are either potential or kinetic energy. Potential refers to stored energy while kinetic is energy in motion.

Explanation:

hope help you pls thanks...

D is correct option

Answer:

1.332 L

Explanation:

The reaction that takes place is:

First we calculate the number of NaOH moles, using the given volume and concentration:

Then we convert NaOH moles into H₂SO₄ moles, using the stoichiometric coefficients:

Finally we calculate the required volume of a 1.75 M solution of H₂SO₄, using the concentration and number of moles:

We can convert mL into L:

Answer:

2c2gh2+5cg2o4+2h2lo

Explanation:

Answer:

The correct approach is "1 M".

Explanation:

The given values are:

Volume of HCL,

V₁ = 45 ml

In prepared solution,

V₂ = 15 ml

Concentration,

C₁ = ?

C₂ = 3.0 M

As we know,

⇒  [tex]V_1C_1=V_2C_2[/tex]

or,

⇒      [tex]C_1=\frac{V_2C_2}{V_1}[/tex]

On substituting the values, we get

⇒           [tex]=\frac{15\times 3}{45}[/tex]

⇒           [tex]=\frac{45}{45}[/tex]

⇒           [tex]=1 \ M[/tex]

Answer:

N2O5

Explanation:

1. Convert to moles

24.5g N * 1mol/14g = 1.75

70.0g * 1mol/16g = 4.375

2. Divide each value by the smallest

1.75/1.75 = 1

4.375/1.75 = 2.5

3. Multiply each by a whole number so that they are both whole numbers

1*2 = 2

2.5*2 = 5

4. These are moles of elements present in the compound

Answer: N2O5

Question: You decompose a compound containing nitrogen and oxygen in the laboratory and produce 24.5 g of nitrogen and 70.0 g of oxygen. Calculate the empirical formula of the compound.

Answer:

the  new pressure of Oz is 0.5 atm

Explanation:

The computation of the new pressure of Oz is shown below:

Given that

Original pressure of O2 (P1) = 1 atm

And, the Original volume of oxygen O2 (V1) = 75L

Now

New pressure of O2 (P2) = ?

And, the New volume of O2 (V2) = 2V1  i.e

= (2 × 75L)

= 150L

Here we applied the Boyle's law formula  

P1V1 = P2V2

1 atm × 75L = P2 × 150L

75 atm × L = 150L ×P2

Now Divide both sides by 150L to get P2

75 atm × L ÷ 150L = 150L × P2 ÷ 150L

0.5 atm = P2

Hence, the  new pressure of Oz is 0.5 atm

Answer:

A. predict whether you will be able to make a solution with pentane and tetrachloromethane

Explanation:

Sana nakatulong

The magnitude of surface tension of liquid depends on the attractive forces between the molecules. Arrange the following in increasing order of surface tension:

water, alcohol (C2H5OH) and hexane [CH3(CH2)4CH3)].  

Answer:

Hexane, Methanol, Water

Explanation:

I did the assessment

Answer:

[tex]SO_3[/tex]

Explanation:

Hello there!

In this case, according to the definition of the empirical formula as the smallest representation of the molecular formula of a chemical compound; for us to determine it, we first need to calculate the moles of sulfur in 40.05 g and those of oxygen in 59.95 g as shown below:

[tex]n_S=\frac{40.05g}{32.07g/mol}= 1.25molS\\\\n_O=\frac{59.95g}{16.00g/mol}=3.75molO[/tex]

Now, we perform the following mole ratios to figure out the subscripts in the empirical formula, by dividing over the fewest number of moles:

[tex]S=\frac{1.25}{1.25}=1 \\\\O=\frac{3.75}{1.25}=3[/tex]

Therefore, the empirical formula turns out:

[tex]SO_3[/tex]

Best regards!

Answer:

False, Solubility increases with temperature for most solids.

Explanation:

Answer:

B<Ga<Al

Explanation:

Hope this helps

Answer:

0.217 M NaOH

Explanation:

M1V1 = M2V2

M1 = 0.312 M HCl

V1 = 17.4 mL HCl

M2 = ?

V2 = 25.0 mL NaOH

Solve for M2 --> M2 = M1V1/V2

M2 = (0.312 M)(17.4 mL) / (25.0 mL) = 0.217 M NaOH

Answer:

A and C

Explanation:

The other answers didn't seem reasonable,

I took the quiz and got it right.

If I am wrong, please correct me

The biome can be given as the collection of flora and fauna in the region. The latitude affects the biome, with the short summers in the north and hot weather at the equator.

The latitude can be given as the horizontal lines imaginary drawn on the earth. The equator is the center of latitude passing from the middle of the earth.

The sun's rays fall directly towards the equator, while the poles in the north and the south experiences the transverse rays of the sun.

The direct rays falling at the equator termed the area closer to the equator warmer, while the falling rays to the north resulted in the short summers and cold for trees. Thus, options A and C are correct.

Learn more about biome, here:

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Answer:

Explanation:

At the highest point of the first and tallest slope, your potential energy is at its most elevated it will at any point be on this ride. As you plunge, your potential energy diminishes until it's totally gone at the lower part of the slope." The more limited the slope the exciting ride climbs, the more prominent its active energy.

Another way of saying is that

A roller ride works utilizing gravity. the underlying slope must be sufficiently high that gravity can create sufficient force to finish the course.

Brainliest?

Answer:

bar graph

Explanation: