!Please help!
When representing a frequency distribution with a bar chart, which of these bars will be the shortest?
A. A bar representing a frequency of 24
B. A bar representing a frequency of 48
C. A bar representing a frequency of 36
D. A bar representing a frequency of 12

Answers

Answer 1

Answer:

D

Step-by-step explanation:

12 is lowest.

Answer 2

A bar chart is one of the most commonly used representations or visually translate groups of data.

We have given that,

When representing a frequency distribution with a bar chart.

What is the frequency distribution?

frequency distribution, a graph or data set organized to show the frequency of occurrence of each possible outcome of a repeatable event observed many times.

It is drawn in such a way that the x-axis of the graph would represent the items and the y-axis will be for the frequency.

Out of the choices given, the shortest among the bars will be that would frequency is only 36.

Hence, the answer to this item is the letter C.

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Related Questions

how do you add 9 in 1 6 + 2 1/12​

Answers

Step-by-step explanation:

9 + 1/6 + 2 1/12

9 + 2.25

11.25

the sum of the three numbers in 2003,two of the numbers are 814 and 519 what is the third number​

Answers

Answer:

670

Step-by-step explanation:

2003-814=1189

1189-519=670

Answer: The third number is 670.

Step-by-step explanation:

The sum means three numbers being added up is equal to 2003 so give two of those numbers you have to add them up and subtract it from 2003 to find the third number.

814 + 519 + x = 2003   where x is the third number

1333 + x = 2003

-1333          -1333  

  x = 670   So the third number is 670

Check:  

 814 + 670 + 519 = 2003

     2003 = 2003   so yes again 670 is the third number.

There are nine saxophone players in the band. The number of saxophone players is one less than twice the number of tuba players. Find the number of tuba players.

Answers

Answer:

[tex]5[/tex]

Step-by-step explanation:

Let [tex]x[/tex] be the number of tuba players.

We are given that the number of saxophone players is one less than twice the number of tuba players.

There are 9 saxophone players.

[tex]9 = 2 x-1[/tex]

[tex]9+1=2x[/tex]

[tex]10=2x[/tex]

[tex]10 \div 2=x[/tex]

[tex]5=x[/tex]

22,056 people went to the baseball game on Sunday. Half as many people came on money. How many people were at the baseball game on Sunday and Monday altogether?

Answers

Answer:33084

Step-by-step explanation:

22056 divided by 2 = Monday

Monday= 11028

11028+22056=33084

Answer:

33084 People were at the baseball game on Sunday and ~Money~ Monday all together.

Step-by-step explanation:

Sunday - 22056

Monday -  "Half as many" 22056 Divided by 2

                  = 11028

Altogether - Sunday + Monday = 33084

As a shortcut on your calculator, you could do:

22056 + (22056 divided by 2)

= 33084

$17,500,000 is what percent of $70,000,000?

Answers

Answer: 1/4 of 70,000,000

Step-by-step explanation: 17,500,000 / 70,000,000 = 0.25

Answer:

[tex]25\%[/tex]

Step-by-step explanation:

[tex]\frac{17,500,000}{70,000,000}[/tex]

[tex]\frac{1}{4}=0.25=25/100=25\%[/tex]

An amusement park had 56,437 visitors the first year and 48, 319 visitors the second year it was open . What was the total number of visitors for both year

Answers

Answer:

the total number is 104756

Step-by-step explanation:

You need to add 56437 with 48319 which equals 104756

Awnser is 104,756 if you add the 2 numbers

1/4+3/8+1/2+5/8+7/8

Answers

Answer: 1/4+3/8+1/2+5/8+7/8

= 21/8

Hope this helps :)))

Answer:

21/8

Step-by-step explanation:

Simplify
6x^-2. .... ​

Answers

Answer:

6/x^2

Step-by-step explanation:

6x^-2

6*x^-2

6*(1/x^2)

6/x^2

write down the exact value of

a. cos 30 degrees

b. sin45 degrees

c. tan 30 degrees

Answers

Answer:

.86602 a

.707106 b

.577355 c

Step-by-step explanation:

entered itno calculator

x^2 + 5x - 24 = 0 How do I solve by factoring

Answers

Answer:

x = -8 or x = 3

Step-by-step explanation:

To factor ax² + bx + c, use AC method.

a times c is 1 × -24 = -24.

Factors of ac (-24) that add up to b (5) are 8 and -3.

Divide by a and reduce: 8/1 and -3/1.

Therefore, the factors are x + 8 and x − 3.

x² + 5x − 24 = 0

(x + 8) (x − 3) = 0

x = -8 or 3

Steve drove for 812 hours at 72 miles per hour. How much distance did he travel

Answers

Answer:

[tex]58,464 \: \: miles[/tex]

Step-by-step explanation:

[tex]speed = \frac{distantce}{time} \\ [/tex]

[tex]distance = speed \times time \\ x = 72 \times 812 \\ x = 58,464 \: \: miles[/tex]

hope this helps

brainliest appreciated

good luck! have a nice day!

From a sample with nequals24​, the mean number of televisions per household is 4 with a standard deviation of 1 television. Using​ Chebychev's Theorem, determine at least how many of the households have between 2 and 6 televisions. At least nothing of the households have between 2 and 6 televisions.

Answers

Answer:

At least 18 of the households have between 2 and 6 televisions.

Step-by-step explanation:

Chebyshev Theorem

The Chebyshev Theorem can also be applied to non-normal distribution. It states that:

At least 75% of the measures are within 2 standard deviations of the mean.

At least 89% of the measures are within 3 standard deviations of the mean.

An in general terms, the percentage of measures within k standard deviations of the mean is given by [tex]100(1 - \frac{1}{k^{2}})[/tex].

In this question:

Mean = 4

Standard deviation = 1

Percentage of households that have between 2 and 6 televisions.

2 = 4 - 2*1

So 2 is two standard deviations below the mean

6 = 4 + 2*1

So 6 is two standard deviations above the mean

By Chebyshev's Theorem, at least 75% of the measures are within 2 standard deviations of the mean.

Out of 24

0.75*24 = 18

At least 18 of the households have between 2 and 6 televisions.

What is the main issue with plugging values into a function and then graphing it?

Too hard to calculate.
Takes too much time.
Never sure of exact data points.
Does not provide accurate results.

Answers

the answer is all of the above!


Answer:

B: It takes too much time

Step-by-step explanation:

Once the points have been calculated and then graphed, the solutions to y = 0 can be found. Look for y = 0 and the solutions are -5 and -1. But that takes a lot of time. There must be an easier way, and fortunately, there is.

If you have changed the tires on your car, the original diameter is 24.5 inches. to a new diameter of 26 inches, how fast are you actually going if your speedometer is reading 53 mph? A. 50.5 mph B. 53 mph C. 56.2 mph D. 62.8 mph

Answers

Answer:  c) 56.2

Step-by-step explanation:

Compare the original rate to the the new rate:

[tex]\dfrac{diameter}{mph}:\dfrac{24.5\ in}{53\ mph}=\dfrac{26\ in}{x}\\\\\\24.5x=53(26)\\\\\\x=\dfrac{53(26)}{24.5}\\\\\\x=\large\boxed{56.2\ mph}[/tex]

A researcher wants to test the claim that convicted burglars spend an average of 18.7 months in jail. She takes a random sample of 11 such cases from court files and finds x=20.6 months and s=8 months. Test the claim that u=18.7 months at the 0.05 significance level.

Answers

Answer:

[tex]t=\frac{20.6-18.7}{\frac{8}{\sqrt{11}}}=0.788[/tex]  

The degrees of freedom are given by;

[tex] df =n-1= 11-1=10[/tex]

And the p value would be:

[tex]p_v =2*P(t_{10}>0.788)=0.449[/tex]  

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different than 18.7

Step-by-step explanation:

Information given

[tex]\bar X=20.6[/tex] represent the sample mean

[tex]s=8[/tex] represent the sample standard deviation

[tex]n=11[/tex] sample size  

[tex]\mu_o =18.7[/tex] represent the value to test

[tex]\alpha=0.05[/tex] represent the significance level

t would represent the statistic  

[tex]p_v[/tex] represent the p value

Hypotesis to test

We want to verify if the true mean is equal to 18.7, the system of hypothesis would be:  

Null hypothesis:[tex]\mu =18.7[/tex]  

Alternative hypothesis:[tex]\mu \neq 18.7[/tex]  

The statistic is given by:

[tex]t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}[/tex] (1)  

Replacing the info we got:

[tex]t=\frac{20.6-18.7}{\frac{8}{\sqrt{11}}}=0.788[/tex]  

The degrees of freedom are given by;

[tex] df =n-1= 11-1=10[/tex]

And the p value would be:

[tex]p_v =2*P(t_{10}>0.788)=0.449[/tex]  

Since the p value is higher than the significance level we have enough evidence to FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly different than 18.7

In this diagram, BAC – EDF. If the
area of BAC = 24 in2, what is the
area of EDF?
Help please

Answers

The triangles are congruent. So.

Triangle ABC is 24 inch^2 and BC is 4 inches.
The area of a triangle is 0.5 x base x height. The will be 12 because 12 x 4 x 0.5 which equals 24.

Triangle DEF is half the size of ABC because bc is 4 and EF is 2 showing it’s half. This then means the height will be half which then mean it will be 6.

This then means we can use the equation to work it out. So. 6 x 0.5 x 2 = 6in^2

The answer is 6inches^2

If the area of ΔBAC = 24 in², the area of ΔEDF is 6 in².

What are similar triangles?

If two triangles' angles are congruent and their corresponding sides are proportionate, they are considered similar. To put it another way, similar triangles are the same in shape but not necessarily in size. If ΔPQR and ΔMNO are two similar triangles, then we can write it as ΔPQR ∼ ΔMNO.

Statement:

The square of the ratio of any pair of their respective sides is equal to the ratio of the areas of two similar triangles.

How to solve this problem?

Since ΔBAC ∼ ΔEDF, we can use the above statement to find the area of ΔEDF. Let the area of ΔEDF be x in². Given that length of EF and BC is 2 in and 4 in respectively.

So, we have to solve this equation,

24/x = 4²/2²

Now, 24/x = 16/4

i.e. 24/x = 4

i.e. 4x = 24

i.e. x = 24/4 = 6

Therefore the area of ΔEDF is 6 in².

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A recent national survey found that parents read an average (mean) of 10 books per month to their children under five years old. The population standard deviation is 5. The distribution of books read per month follows the normal distribution. A random sample of 25 households revealed that the mean number of books read last month was 12. At the .01 significance level, can we conclude that parents read more than the average number of books to their children

Answers

Answer:

Step-by-step explanation:

Null hypothesis: u = 10

Alternative hypothesis: u =/ 10

Using the formula: t = (x - u) / (s /√n)

Where x = 12, u = 10, s = 5 and n = 25

t= (12-10) / (5/√25)

t = (2)/(5/5)

t = 2/1= 2

t = 2.0

At a 0.01 level of significance with a degree of freedom of 24, the p-value is 0.0569, which is greater than 0.01 we will fail to reject the null and conclude that parents do not read more than the average number of books to their children

WILL GIVE BRAINLIEST! HURRY

Answers

Answer:

4

Step-by-step explanation:

2(6x+4)-6+2x=3(4x+3)+1

=14x+2=12x+10

=14x+2-2=12x+10-2

=14x=12x+8

=14x-12x=12x+8-12x

=2x=8

=2x/2=8/2

x=4

Given f(xl=x-7 and g(x)=x^2 find g(f(4))

Answers

Answer:

So we first need to solve for f(4) because thats what's inside g(_)

It should be 4-7 because I think its f(x)=x-7 you weren't very clear on it.

so that means that we need to solve for g(-3)

-3^2 = 9 because -3*-3 = 9

9 is answer

round 3, 942,588 to the nearest thousand

Answers

Answer:

3, 943,000

Step-by-step explanation:

3, 942,588

The 2 is in the thousands place

We look at the hundreds place

There is a 5, that means we round up

2 becomes a 3

3, 943,000

ABDC is a rhombus with side length 10cm
angle ADC=40degrees
DAC is a sector of a circle with center D
BAC is a sector of a circle with center B
CALCULATE THE SHADED AREA (in cm2)

Answers

Cm2 equation equals the equivelens


What’s the correct answer for this question?

Answers

Answer:

B

Step-by-step explanation:

In the attached file

Please answer this correctly

Answers

Answer:

629

Step-by-step explanation:

l x w

25x14

4x7

12x18

5x7

629

At Ajax Spring Water, a half-liter bottle of soft drink is supposed to contain a mean of 519 ml. The filling process follows a normal distribution with a known process standard deviation of 6 ml.
1) The normal distribution should be used for the sample mean because:_____.
a) the sample population has a large mean.
b) the population distribution is known to be normal.
c) the population standard deviation is known.
d) the standard deviation is very small.
2) Set up hypotheses and a two-tailed decision rule for the correct mean using the 5 percent level of significance. The hypothesis for a two-tailed decision is:_______.
A. H0: mu not equal to 519, H1: mu = 519, reject if z < -1.96 or z > 1.96.
B. H0: mu not equal to 519, H1: mu = 519, reject if z > 1.96 or z < -1.96.
C. H0: mu = 519, mu not equal to 519, reject if z> 1.96 or z< -1.96.
D. H0: mu = 519, H_1: mu not equal to 519, reject if z > -1.96 or z< 1.96.
a. a.
b. b.
c. c.
d. d.
3) If a sample of 16 bottles shows a mean fill of 522 ml, does this contradict the hypothesis that the true mean is 519 ml?
A) Yes.
B) No

Answers

Answer:

1) The normal distribution should be used for the sample mean because the population distribution is known to be normal (answer b).

2) C. H0: mu = 519, H_1: mu not equal to 519, reject if z> 1.96 or z< -1.96.

3) Yes. There is enough evidence to support the claim that the true mean is not 519 ml.

Step-by-step explanation:

1) When the population follows a normal distribution, it is correct to assume a normal distribution for the sample mean.

2) As it is a two-tailed decision rule, we are interested in detecting a significant difference below and above the mean. This is why we use the unequal sign in the alternative hypothesis.

The null hypothesis state that there is not significant difference from 519.

The critical value for a significance level of 5% is z=1.96.

[tex]H_0: \mu=519\\\\H_a:\mu\neq 519[/tex]

3) The claim is that the true mean is not 519 ml.

Then, the null and alternative hypothesis are:

[tex]H_0: \mu=519\\\\H_a:\mu\neq 519[/tex]

The significance level is 0.05.

The sample has a size n=16.

The sample mean is M=522.

The standard deviation of the population is known and has a value of σ=6.

We can calculate the standard error as:

[tex]\sigma_M=\dfrac{\sigma}{\sqrt{n}}=\dfrac{6}{\sqrt{16}}=1.5[/tex]

Then, we can calculate the z-statistic as:

[tex]z=\dfrac{M-\mu}{\sigma_M}=\dfrac{522-519}{1.5}=\dfrac{3}{1.5}=2[/tex]

This test is a two-tailed test, so the P-value for this test is calculated as:

[tex]\text{P-value}=2\cdot P(z>2)=0.046[/tex]

As the P-value (0.046) is smaller than the significance level (0.05), the effect is significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that the true mean is not 519 ml.

What is the slope intercept form.

Answers

Answer:

y = 1/4x + 2

Step-by-step explanation:

Since they gave you point slope form already, all you need to do is convert that into slope-intercept form. Just distribute the parenthesis and move the 4 over. Once you do so, you should get C/3rd option as your answer.

please help image attached!

Answers

Answer:

The unit circle centered at the origin in the Euclidean plane is defined by the equation:

[tex]x^2+y^2=1\\[/tex]

Given an angle , there is a unique point P on the unit circle at an angle θ from the x-axis, and the x- and y-coordinates of P are:

[tex]x=cos \theta \\y = sin \theta[/tex]

Consequently, from the equation for the unit circle:

[tex]cos^2\theta+sin^2\theta=1[/tex]  

the Pythagorean identity.

Choose the slope and y-intercept that
correspond with the graph.

Answers

Answer:

slope = -3, y intercept = 3

Step-by-step explanation:

The y intercept is where it crosses the y axis

y intercept is 3

The slope is found by taking two points (0,3) and (1,0) and using the slope formula

m = (y2-y1)/(x2-x1)

   = (0-3)/(1-0)

   -3/1

  =-3

Can someone plz help me solved this problem I need help ASAP plz help me! Will mark you as brainiest!

Answers

Answer:

8

Step-by-step explanation:

y²+by+16= (y+4)²

y²+by+16= y²+2*4*y+4²

y²+by+16= y²+8y+16

by=8y

b=8

At the beginning of an experiment, a scientist has 300 grams of radioactive goo. After 150 minutes, her sample has decayed to 37.5 grams.




What is the half-life of the goo in minutes?


________



Find a formula for


G(t),


the amount of goo remaining at time T.


G= _________



How many grams of goo will remain after 32 minutes?

Answers

Answer:

Half-life of the goo is 49.5 minutes

[tex]G(t)= 300e^{-0.014t}[/tex]

191.7 grams of goo will remain after 32 minutes

Step-by-step explanation:

Let [tex]M_0\,,\,M_f[/tex] denotes initial and final mass.

[tex]M_0=300\,\,grams\,,\,M_f=37.5\,\,grams[/tex]

According to exponential decay,

[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt[/tex]

Here, t denotes time and k denotes decay constant.

[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt\\\ln \left ( \frac{37.5}{300} \right )=-k(150)\\-2.079=-k(150)\\k=\frac{2.079}{150}=0.014[/tex]

So, half-life of the goo in minutes is calculated as follows:

[tex]\ln \left ( \frac{50}{100} \right )=-kt\\\ln \left ( \frac{50}{100} \right )=-(0.014)t\\t=\frac{-0.693}{-0.014}=49.5\,\,minutes[/tex]

Half-life of the goo is 49.5 minutes

[tex]\ln \left ( \frac{M_f}{M_0} \right )=-kt\Rightarrow M_f=M_0e^{-kt}[/tex]

So,

[tex]G(t)= M_f=M_0e^{-kt}[/tex]

Put [tex]M_0=300\,\,grams\,,\,k=0.014[/tex]

[tex]G(t)= 300e^{-0.014t}[/tex]

Put t = 32 minutes

[tex]G(32)= 300e^{-0.014(32)}=300e^{-0.448}=191.7\,\,grams[/tex]

Find all zeros of f(x)=x^3−17x^2+49x−833

Answers

Answer:

x = 17 or x = ±7i

Step-by-step explanation:

x³ − 17x² + 49x − 833 = 0

x² (x − 17) + 49 (x − 17) = 0

(x² + 49) (x − 17) = 0

x = 17 or ±7i

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What is the answer to this, I need an explanation please ASAP The Importance of Competition A competition is a great way to engage students to be more interested in school activities because it adds a "fun" element to the learning process. Competitions are also known to motivate some students. But are competitions always healthy? Is being part of competitions the only way to prove capability? Students' families should not force students to participate in competitions. The idea of winning a competition may be so demanding that a student may concentrate all of his or her efforts on preparing for the competition over other things. This may create an imbalance in the student's life. Students might also neglect their studies because they are intent at being successful in only one thing. This fear of losing may also make students overwork, which can have a negative effect. 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