PLEASEEE HELPPPP ASAPPPPP

Answer:

=29

Step-by-step explanation:

2f(b)=28

divide by 2

f(b)=14

f(b)=3b-1

3b-1=14

add 1 on both sides

3b=15

divide by 3

b=5

f(5)=14

let's plug that in

f(2×5)=3(2×5)-1

f(10)=30-1

f(10)=29

The value of f(2b) is 29 if f(x) = 3x - 1 and 2f(b) = 28 the answer is 29.

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

f(x) = 3x - 1 and 2f(b) = 28

Plug x = b

f(b) = 3b - 1

2f(b) =2(3b - 1)

2f(b) = 28

28 = 2(3b - 1)

b = 5

f(2b) = f(2(5)) = f(10)

f(10) = 3(10) - 1

f(10) = 30 - 1 = 29

Thus, the value of f(2b) is 29 if f(x) = 3x - 1 and 2f(b) = 28 the answer is 29.

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Answer:

m=1.5 b=4

Step-by-step explanation:

Answer:

B. and D.

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Here are the correct sums:

A. –2.0 + (–0.5) = -2.5

B. –4.5 + 6.5 = 2.0

C. 3.0 + (–0.5) = 2.5

D. 5.5 + (–2.5) = 3.0

Only D is correct.

Answer: D

Answer:

-r ^3

Step-by-step explanation:

Answer:

40in^2

Step-by-step explanation:

Answer:

Answer:

9.46 = y

Step-by-step explanation:

=================================================================

You have to use the cosine function equation.

cos(38) =  

Multiply 12 on both sides.

12cos(38) = y

Solve.

9.46 = y

How to know which one to use:

Sin, Cos, Tan, Sec, Cosec, and Cot

Sin function is to do opposite number side length over the hypotenuse number side

Cos function is to do adjacent (side length that is next to angle) over the hypotenuse

Tan function is to do Opposite over Adjacent,

These are the inverse of each one

Sec is hypotenuse over opposite (inverse of Sin)

Cosec is hypotenuse over adjacent (Inverse of Cos)

Cot is Adjacent over Opposite (Inverse of Tan)

=================================================================

Answer:

B. |-6| < |-8|

Step-by-step explanation:

The absolute value will always make the number positive. B is the only option in which (once absolute value is used) will make a true statement.

|-6| < |-8| = 6 < 8

( 6 is less than 8 )

Answer:

Step-by-step explanation:

what is average speed:

"The average speed of an object is defined as the distance traveled divided by the time elapsed. Velocity is a vector quantity, and average velocity can be defined as the displacement divided by the time."

step one:

given data

Distances   Time

4km             32min

2km              22min

 1km              16min

the total distance covered is

4+2+1= 7km

the total time taken = 32+22+16=70min

the average speed= distance/time

average speed= 7/70= 0.1km per min

Answer:

It's 1 kilometer

Step-by-step explanation:

Answer:

2.49 or 2.50

Step-by-step explanation:

Answer:

= 52.4475 rounded to nearest cent = 52.44

Step-by-step explanation:

Plz mark brainliest!!!

Step-by-step explanation:

jm sorry, I've never done anything like this in math.

Answer:

Step-by-step explanation:

its 9

Answer:-3

Step-by-step explanation:

The minimum value of a function can be obtained from its derivative

The point on the x-axis that makes [tex]\overline{AC}[/tex] + [tex]\overline{BC}[/tex] minimum is the point [tex]\underline{(9, \, 0)}[/tex]

Reason:

Let (d, 0) represent the coordinate of the point, on the x-axis, we have;

[tex]\overline{AC}[/tex]² = (4 - d)² + (-5)²

[tex]\overline{AC}[/tex] = √((4 - d)² + (-5)²)

[tex]\overline{BC}[/tex]² = (12 - d)² + 3²

[tex]\overline{BC}[/tex] = √((12 - d)² + 3²)

[tex]\overline{AC}[/tex]² + [tex]\overline{BC}[/tex]² = L =  4² + (-5 - d)² + 12² + (3 - d)²

When [tex]\overline{AC}[/tex] + [tex]\overline{BC}[/tex] is minimum, we have;

[tex]\lim_{n \to \infty} a_n \dfrac{d}{dd} (\overline{AC} + \overline{BC}) = \dfrac{d}{dd} \left(\sqrt{ (4 - d)^2 + (-5)^2)} + \sqrt{ (12 - d)^2 + 3 ^2)} \right) = 0[/tex]

Which gives;

[tex]\dfrac{d}{dd} \left(\sqrt{ (4 - d)^2 + (-5)^2)} + \sqrt{ (12 - d)^2 + 3 ^2)} \right) = \dfrac{2 \cdot d - 24}{2 \cdot \sqrt{d^2-24 \cdot d + 153} } + \dfrac{2 \cdot d - 8}{2 \cdot \sqrt{d^2 - 8\cdot d + 41} }[/tex]

Therefore;

[tex]\dfrac{2 \cdot d - 24}{2 \cdot \sqrt{d^2-24 \cdot d + 153} } + \dfrac{2 \cdot d - 8}{2 \cdot \sqrt{d^2 - 8 \cdot d + 41} } = 0[/tex]

[tex]\dfrac{2 \cdot d - 24}{2 \cdot \sqrt{d^2-24 \cdot d + 153} } =- \dfrac{2 \cdot d - 8}{2 \cdot \sqrt{d^2 - 8 \cdot d + 41} }[/tex]

Squaring both sides and cross multiplying gives;

16·d² - 528·d + 3456 = 0

Which gives;

16·(d - 24)·(d - 9) = 0

Therefore, d = 24, and d = 9

The point (9, 0), is closer to the given points than the point (24, 0), therefore;

The point on the x-axis that makes [tex]\overline{AC}[/tex] + [tex]\overline{BC}[/tex] minimum is the point [tex]\underline{(9, \, 0)}[/tex]

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Answer:

it should be b but if i'm wrong im really sorry :(

Step-by-step explanation:

Answer:

Assuming it is a constant function.

[tex]f(x)=0x-2[/tex]

Step-by-step explanation:

(5,-2)

(-6,-2)

(3,-2)

(4,-2)

From the points, we can see that for any value of [tex]x[/tex], the function will give -2. The graph of this function will be a horizontal line, parallel to the [tex]x[/tex]-line passing the y-intersect point -2.

So the function might be

[tex]f(x)=0x-2[/tex]

If it is a constant function.

I'm considering that there are no discontinuities.

Answer:

Domain: x>=-6

Range: y=-2

Step-by-step explanation:

I think this is the one but I’m not entirely sure

Answer:

The graph of a quadratic function is a curve called a parabola which makes a quadratic function unique.

Step-by-step explanation:

Parabolas may open upward or downward and vary in "width" or "steepness", but they all have the same basic "U" shape which makes it easy to identify.

Hope it helps.

Answer:

Step-by-step explanation:

Maybe that can be solve in so

-maybe diferent ways like graphicly, quadratic equation, factoring, form a perfect square...

-maybe because it has real, imaginary roots, or equal roots

Answer:

2:8

Step-by-step explanation:

Answer: 2:8

but yeah its 2:8

Answer:

There's two answers.

-5, -4, and -3

3, 4, 5

Step-by-step explanation:

[tex]x^{2} +(x+1)^{2} +(x+2)^{2} =50\\x^{2} +x^{2} +2x+1+x^{2} +4x+4=50\\3x^{2} +6x+5=50\\3x^{2} +6x-45=0\\3(x^{2} +2x-15)=0\\(x+5)(x-3)=0\\x = -5\\x = 3\\[/tex]

Answer:

iba nalang

Step-by-step explanation:

just tell someting wag yan

1. -

2. ×

3.÷

i guess these r the answers

Answer:

50

Step-by-step explanation:

5 times 5 =25

25 times 2 =50

Answer:

it the first one cause you adding so it 8b plus 2

Answer:

300 students

Step-by-step explanation:

divide 60 by 3 to find how many students there are per teacher: 60/3 = 20

multiply 20 by 15 to find how many students there are for 15 teachers:

20 x 15 = 300

Answer:

angel F

Step-by-step explanation:

116=$0.05

hope this helps

The total cost of chocolate sprinkles is $800

This is an implementation of the numeral system that shows the value of each digit in a number using their positions

Given that, Chocolate sprinkles cost as much per pound as sugar.

From the complete question, we have the following parameters:

Unit rate = $8.00

Total pounds = 100

Total cost of chocolate sprinkles

So, the total cost of chocolate sprinkles is calculated using the following formula;

Unit = Total / Pounds

This gives

$8.00 = Total / 100

Total = $800

Hence, the total cost of chocolate sprinkles is $800

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