most fossils are found in sedimentary rocks
Answer:
Sedimentary rock.
Explanation:
Help! How do you find the Eccentricity??
Explanation:
The formula to determine the eccentricity of an ellipse is the distance between foci divided by the length of the major axis
If a car has a mass of 200 kilograms and produces a force of 500 N, how fast will the car accelerate?
Answer:
2.5m/s²
Explanation:
Given parameters:
Mass of car = 200kg
Force on car = 500N
Unknown:
Acceleration of the car = ?
Solution:
According to Newton's second law of motion:
Force = mass x acceleration
Insert the given parameters and find the acceleration;
500 = 200 x acceleration
acceleration = 2.5m/s²
Explanation:
F = ma
500N = 200 × a
200a. = 500N
a. =. 2.5m/s²
PLEASE GIVE BRAINLIEST.
calculate the displacement and velocity of a ball 0.50 seconds after it is thrown straight up with an initial velocity of 15.0 m/s. take the point of release to be an initial height of zero.
Answer:
The ball will have a displacement of 0.5*15.0=7.5m after 0.5 seconds. The velocity of the ball will be 15.0 m/s, since it is not acted on by any forces except gravity (which acts in the direction opposite of the velocity).
Explanation:
We know this is the answer because, according to the kinematic equation:
v^2=u^2+2*a*d
0=15.0^2+2*(-9.8)*d
d=-7.5m
An airfoil is deflected upward as the airflow is deflected downward. Which of Newton's laws does this example best illustrate?
If a bicycle has an average acceleration of -0.44 m/s^2, and its initial forward velocity is 8.2 m/s, how long will it take the cyclist to bring the bicycle to a complete stop
Answer:
The value is [tex]t = 18.6 s[/tex]
Explanation:
From the question we are told that
The average acceleration of the bicycle is [tex]v = -0.44 \ m/s^2[/tex]
The initial forward velocity is [tex]u = 8.2 \ m/s[/tex]
Generally from kinematic equations we have that
[tex]v = u + at[/tex]
Here v is the final velocity of the bicycle and the value is v = 0 m/s
So
[tex]0 = 8.2 + (-0.44)t[/tex]
=> t = 18.6 s
Two carts connected by a 0.25 m spring hit a wall, compressing the spring to 0.1 m. The spring constant k is 100 N m . What is the elastic potential energy stored from the spring's compression?
Given that,
Initial position of the spring, x₁ = 0.25 m
Final position of the spring, x₂ = 0.1 m
The spring constant of the spring, k = 100 N/m
To find,
The elastic potential energy stored from the spring's compression.
Solution,
The work done in moving a spring from on position to another is stored in the form of elastic potential energy. It can be given as follows :
[tex]E=\dfrac{1}{2}k(x_2^2-x_1^2)\\\\=\dfrac{1}{2}\times 100\times (0.1^2-0.25^2)\\\\=2.62\ J[/tex]
So, the required energy is 2.62 J.
Answer:
1.125 J
Explanation:
The correct answer is 1.125 J
What unite do scientists use to measure force
A) Newton
B) grams
C) meters
D) meters per second per second
a ball is thrown upward at 25 m/s from the ground. what is the average velocity and average speed of the ball after 5 seconds?
what are two conditions of equilibrium? write them in word
Newton's first law of motion: Objects in motion will stay in motion and objects at rest will stay at rest, unless acted on by
a. friction
b. acceleration
c. unbalanced force
d. contact force
Newton's first law states that every object will remain at rest or in uniform motion in a straight line unless compelled to change its state by the action of an external force. This is normally taken as the definition of inertia
the density of aluminum is 2.70 g/cm3. express this value in units of kilogram per cubic meter and pounds per cubic foot.
The density of aluminum in units of kilogram per cubic meter is 2700kg/m³
The density of aluminum in units of pounds per cubic foot is 1.686lb/ft³
unit conversion - conversion of one unit to another unit of measurement of same quantity by using multiplication/division.
the density of aluminum is 2.70 g/cm3.(given)
1 kg = 1000g
1m = 100cm
density of aluminum in kg/m³ is :
2.7×10⁻³kg/10⁻⁶m³
2700kg/m³
density of aluminum in lb/ft³ (ponds per cubic foot) is :
1g = 0.2204lb
1cm = 0.328ft
= 2.7×0.02204/(0.328)³
1.686lb/ft³
The density of aluminum in units of kilogram per cubic meter is 2700kg/m³
The density of aluminum in units of pounds per cubic foot is 1.686lb/ft³
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An object of known mass that can be used to establish uncertainty in measurements made with a balance is best described as a.
According to the graphic, the weighing balance has a hundredth-place level of uncertainty.
What is a balance?The characteristic of matter that gauges its resistance to acceleration in physics. An object's mass can be thought of as a rough count of its atoms.
Any tool that measures an object's mass or weight is referred to as a balance. Every laboratory needs balance as an essential tool.
In the hundredth position, there is uncertainty. There are always three significant figures for a mass that is between 1 gram and 9 grams when it is measured on this balance.
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A green laser pointer emits light with a wavelength of 532 nm. What is the frequency of this radiation, in hz?.
The frequency of electromagnetic waves is 5.64 x 10¹⁴ Hz.
We need to know about electromagnetic waves to solve this problem. Electromagnetic waves can propagate without media. The speed of electromagnetic in vacuum media is equal to the speed of light. Hence, the wavelength and frequency can be determined as
c = λ . f
where c is the speed of light (3 x 10⁸ m/s), λ is wavelength and f is frequency.
From the question above, we know that
λ = 532 x 10¯⁹ m
By substituting the given parameter, we can calculate the frequency of green laser pointer
c = λ . f
f = c / λ
f = 3 x 10⁸ / 532x10¯⁹
f = 5.64 x 10¹⁴ Hz
Hence, the frequency is 5.64 x 10¹⁴ Hz.
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A sound wave has a velocity of 350 meters/second and a frequency of 430 hertz. what is its wavelength? a. 0.01 meters b. 0.60 meters c. 0.81 meters d. 0.08 meters
The wavelength of a sound wave with a velocity of 350 meters/second and a frequency of 430 Hz is 0.81 meters.
The relation between velocity(v), frequency(f) and wavelength(lambda) of a sound wave is given by the following formula,
V = (f)(λ) equation1
We are given that , v = 350 meters/second
f = 430 hertz
By putting the above values in the equation1 , we will get
350 = 430 x (λ)
350/430 = λ
λ = 0.81 meters
Thus, the wavelength of a sound wave with a velocity of 350 meters/second and a frequency of 430 Hz is 0.81 meters.
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broglie wavelength of a 231 gg baseball with a speed of 34.0 m/sm/s ? express your answer in meters.
The broglie wavelength is 9.27 x 10¯³⁵ meter.
We need to know about de Broglie's wavelength to solve this problem. Broglie's wave equation is the following :
λ = h / (m.v)
where λ is the wavelength, h is Max Planck constant 6.62x10⁻³⁴ J.s, m is the mass and v is velocity.
From the question above, we know that:
m = 231 gram = 0.231 kg
v = 34 m/s
By substituting the parameter, we get :
λ = h / (m.v)
λ = 6.62x10⁻³⁴ / (0.21 x 34)
λ = 9.27 x 10¯³⁵ m
Hence, the broglie wavelength is 9.27 x 10¯³⁵ meter.
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please help me will mark u brainiest
Answer:
Answer is A :)))))))))
You are playing catch in the front yard and your sister throws a football at you, then your neighbor throws a baseball at
you at the same speed.
Which ball has the greater momentum?
estimate how long it would take one person to mow a football field using an ordinary home lawn mower. suppose that the mower moves with a 1- km/h speed, has a 0.5- m width, and a field is 360 ft long and 160 ft wide. 1 m
The calculated time taken is 10.7 hours
Given that our speed is 1 km/h and our width is 0.5 m, we can mow a path that is 0.5 m wide and 1000 m long in an hour, covering a total area of 1000 m * 0.5 m = 500 m2/hr.
Let's now determine the size of that football field.
5350.692864 m2 is equal to 360 ft / 3.281 ft/m plus 160 ft / 3.281 ft/m.
To determine how many hours it will take, divide that area by the 500 m2 that was previously determined.
500 m2/hour / 5350.692864 m2
= 10.70138573 hr
In other words, moving the football field would take around 10.7 hours.
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If the radius of an atom is 60 pm and the radius of the Earth is 6000 km, by how many orders of
magnitude is the radius of the Earth larger than an atom?
Answer:
1 x 10¹⁷
Explanation:
Given data:
Radius of the earth = 6000km
Radius of an atom = 60pm
Now, how many orders is the radius of the earth larger than an atom
Solution:
To solve this problem, let us express both quantity as the same unit;
1000m = 1km
6000km = 6000 x 10³m = 6 x 10⁶m
60pm;
1 x 10⁻¹²m = 1pm
60pm = 60 x 1 x 10⁻¹²m = 6 x 10⁻¹¹m
Now;
The order: [tex]\frac{6 x 10^{6} }{6 x 10^{-11} }[/tex] = 1 x 10¹⁷
A bicyclist pedaling up a hill is this a form of kinetic energy or potential energy?
Answer:
Kinetic
Explanation:
Its a moving action
When a bicyclist is pedaling up a hill, it is a form of potential energy. The correct option is option potential energy.
An object's position or configuration in relation to other things might provide it potential energy. The potential energy in this situation is gravitational potential energy.
Because they are being lifted against gravity as they ascend the hill, the cyclist gains gravitational potential energy. The potential energy of the cyclist increases as they ascend.
The potential energy will be transformed into kinetic energy once the cyclist begins pedaling or moving downward.
As a result of their increased height above the ground, cyclists are building up potential energy as they bike up a hill. They gain speed as they cycle downhill, transforming that potential energy into kinetic energy.
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Two Forces 20N and 50N act at a point and at an angle of 120 to each. Draw a force diagram for the system
the resultant force is F=F1-F2.
F1 = 20 N, and F2 = 50 N
In this instance, two different resultant forces are feasible.
when the two are at an angle of A with one another.
See the outcome in case 1 of the image if both are facing the same way. if they are both facing the opposite directions. when both are at a zero-degree angle from one another If they are parallel to one another and moving in the same direction, the resultant force is F=F1+F2. If they are parallel but moving in the opposite direction, the resultant force is F=F1-F2.
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What is a physical change ?
A. Burning wood
B. Rusting metal
C. Cooking a egg
D. Freezing water
Answer : Freezing water !
Scientists study how the continents move. Why might scientists use a model
to show this movement?
O A. It is too slow to observe directly.
O B. It is too fast to observe directly.
O C. It is too dangerous to observe directly.
O D. It is too complex to observe directly.
Answer: A
Explanation: continents move very slowly, about one inch per year
Answer:
A
Explanation:
it takes thousands of years to see the continents progress in it's movement. by the time we see progress of how they are moving you'd have been dead for 50000 years XD
A nonconducting ring of radius R is uniformly charged with a total positive charge q. The ring rotates at a constant angular speed \omega about an axis through its center, perpendicular to the plane of the ring. What is the magnitude of the magnetic field on the axis of the ring a distance 1/2 R from its center?
The magnitude of the magnetic field on the axis of the ring (1/2)R from its center is [tex]\frac{\mu_{0} \omega qR^{2}}{2.5(\sqrt{5} )\pi R }[/tex].
The magnetic influence on moving electric currents, electric charges, and magnetic materials is described by a magnetic field, which is a vector field. A force acting on a charge while it travels through a magnetic field is perpendicular to both the charge's motion and the magnetic field.
The radius of the nonconducting ring is R.
The ring is uniformly charged q.
The ring rotates at a speed of ω.
The distance between the ring and its center is x = (1/2)R.
The magnetic field on a current loop's axis is given as follows:
[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi (x^{2}+R^{2})^{\frac{3}{2}} }[/tex]
Now, [tex]I=\frac{q}{2 \pi /\omega}[/tex]
The magnetic field's strength at x = R/2 is:
[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi (x^{2}+R^{2})^{\frac{3}{2}} }[/tex]
[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi ((\frac{R}{2} )^{2}+R^{2})^{\frac{3}{2}} }[/tex]
[tex]B = \frac{\mu_{0} IR^{2}}{4 \pi ((\frac{5}{4} )R^{2})^{\frac{3}{2}} }[/tex]
[tex]B = \frac{\mu_{0} \omega qR^{2}}{2.5(\sqrt{5} )\pi R}[/tex]
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which statement correctly line graph
a. the x-axis is on the left side of the graph
b. the responding variable is on the y-axis
c. the line graph has 3 axes
d. the manipulated variable is not shown
Answer:
A.
Explanation:
The X-Axis is always on the left side.
1. What coefficients would balance the following equation?
_Al + _02 →_Al2O3
2A1 + 302 +1A1,03
2A1+ 302 → 2A1203
3A1 + 302 + 2A1003
4A1 + 302 → 2A1203
Answer:
D. 4Al + 3O2 → 2Al2O3
Explanation:
Chemical reactions involves the chemical combination of two or more substances called REACTANTS to yield other substances called PRODUCTS. However, in accordance with the LAW OF CONSERVATION OF MASS, the amount of reactants must be equal to that of the products.
To accomplish this, the reaction must be BALANCED. A balanced equation is an equation in which the number of atoms of each element in the reactant side equals the number of atoms in the product side. In this reaction involving Aluminum and Oxygen to give Aluminum oxide as follows:
Al + 02 → Al2O3
A coefficient is used to balance the number of atoms on both sides of the equation as follows:
4Al + 3O2 → 2Al2O3
Answer:
here for points
3u3784y297y4ui3t7
Explanation:
Ou
A truck starts from rest and accelerates uniformly over a time of 5.5 seconds for a
distance of 130 m. Determine the acceleration (in m/s^2) of the truck.
Please submit your answer with 2 decimal places!
Answer:
8.6m/s²
Explanation:
Given parameters:
Initial velocity = 0m/s
Time = 5.5s
Distance = 130m
Unknown:
Acceleration = ?
Solution:
To solve this problem, we use one of the appropriate motion equations:
S = Ut + [tex]\frac{1}{2}[/tex] at²
S is the distance
U is the initial velocity
t is the time taken
a is the unknown acceleration
t is time taken
Since U = 0m/s
S = [tex]\frac{1}{2}[/tex] at²
130 = [tex]\frac{1}{2}[/tex] x a x 5.5²
130 = 15.13a
a = 8.6m/s²
The effect of gravity on a falling object can be modeled by a ball dropped
from different heights. What is a limitation of this model?
O A. Not all objects bounce, even though balls do.
B. Friction with air also affects the fall of the object.
C. Some balls float in water, while others sink.
O
D. The ball can be dropped from varying heights.
Answer:
B. Friction with air also affects the fall of the object.
Explanation:
The limitation of this experimental design is that friction with air also affects the fall of the object.
Therefore, it is difficult to measure effect of gravity on falling objects. Air resistance cause friction in the movement of an object falling. Frictional force resists the motion of an object subject to free fall.Therefore, the experiment will be biased due to the influence of the frictional force.
100 POINTS PHYSICS PLEASE HELP
1: Let’s say you drop a 100 kg ball from the top of the stairs and by the
time it reaches the ground it has a velocity of 40 m/s. How much kinetic
energy would it have?
2: If a 63.5 kg person climbs a hill that is 1500 m and stands at the top
looking over the edge, what is their potential energy at that point?
3: If that 63.5 kg person went parachuting, jumped out of an airplane, and
reached a velocity of 80 m/s before opening their parachute, how much
kinetic energy would they have?
4: Look at the formula for potential energy. Why would that 63.5 kg person
have more energy if they walked up a 1500 m hill than if they walked 1500
m on a flat surface?
Answer:
1: The Ball Has 80,000 J
2: Their Potential Energy Is 934,083 J At That Point
3: They Would Have 203,200 Kinetic Energy
4: The Person Would Have More Potential Energy GoingUp A 1500 M Hill Rather Than Walking 1500 M On A Flat Surface Because When You Walk Up Something You Have More Potential Energy Then When You Walk On Flat Ground
Reason:
1: 100kg x 40 m/s = 80,000
2: 63.5 x 1500 M = 934,083
3: 63.5 x 80 M/s = 203,200
What is the answer please help me!
Answer:
The greatest force of gravity on the ball will occur at the point when the ball is near to hit the ground
Explanation:
We know that the earth's center attracts everything towards its center with an acceleration of 9.8 m/s² so it simply means that the change in velocity must occur to produce acceleration. When the ball comes towards the earth, its speed continuously increases and it is at maximum level when it is about to hit the ground so this is the point where gravitational force is maximum.
I hope this helps ^_^