Answer:
Tack coat is a sprayed application of an asphalt binder upon an existing asphalt or Portland cement concrete pavement prior to an overlay, or between layers of new asphalt concrete.
Explanation:
A cylindrical bar of metal having a diameter of 19.9 mm and a length of 186 mm is deformed elastically in tension with a force of 42600 N. Given that the elastic modulus and Poisson's ratio of the metal are 67.1 GPa and 0.34, respectively, determine the following: (a) The amount by which this specimen will elongate (in mm) in the direction of the applied stress. (b) The change in diameter of the specimen (in mm). Indicate an increase in diameter with a positive number and a decrease with a negative number.
Answer:
a) 0.347 mm
b) - 0.0126 mm
Explanation:
Diameter of metal bar = 19.9 mm
length = 186 mm = 0.186 m
Tension force = 42600 N
elastic modulus = 67.1 GPa
Poisson's ratio = 0.34
a) calculate the amount by which the specimen will elongate
first calculate the area of metal bar
Area = πd^2 / 4 = π/4 ( 19.9 )^2 = 3.11 * 10^-4 m^2
Elongation ( E ) = б / e = P/A * L / ΔL
and ΔL = PL / AE
hence the elongation ( ΔL) = [ (42600 * 0.186 ) / ( 3.4*10^-4 * 67.1 * 10^9 ) ]
= 3.47 * 10^-4 m ≈ 0.347 mm
b) Calculate the change in diameter of specimen
μ = -( Δd / d) / ( ΔL/L )
0.34 = - (Δd / 19.9 ) / ( 0.347 / 186 )
∴ Δd = 0.34 * 0.00186 * 19.9 = - 0.0126 mm
A thick steel slab ( 7800 kg/m3 , c 480 J/kg K, k 50 W/m K) is initially at 300 C and is cooled by water jets impinging on one of its surfaces. The temperature of the water is 25 C, and the jets maintain an extremely large, approximately uniform convection coefficient at the surface. Assuming that the surface is maintained at the temperature of the water throughout the cooling, how long will it take for the temperature to reach 50 C at a distance of 25 mm from the surface
Answer:
1791 secs ≈ 29.85 minutes
Explanation:
( Initial temperature of slab ) T1 = 300° C
temperature of water ( Ts ) = 25°C
T2 ( final temp of slab ) = 50°C
distance between slab and water jet = 25 mm
Determine how long it will take to reach T2
First calculate the thermal diffusivity
∝ = 50 / ( 7800 * 480 ) = 1.34 * 10^-5 m^2/s
next express Temp as a function of time
T( 25 mm , t ) = 50°C
next calculate the time required for the slab to reach 50°C at a distance of 25mm
attached below is the remaining part of the detailed solution
As part of a heat treatment process, cylindrical, 304 stainless steel rods of 100-mm diameter are cooled from an initial temperature of 500 C by suspending them in an oil bath at 30 C. If a convection coefficient of 500 W/m2 K is maintained by circulation of the oil, how long does it take for the centerline of a rod to reach a temperature of 50 C, at which point it is withdrawn from the bath
Answer:
Explanation:
Given that:
diameter = 100 mm
initial temperature = 500 ° C
Conventional coefficient = 500 W/m^2 K
length = 1 m
We obtain the following data from the tables A-1;
For the stainless steel of the rod [tex]\overline T = 548 \ K[/tex]
[tex]\rho = 7900 \ kg/m^3[/tex]
[tex]K = 19.0 \ W/mk \\ \\ C_p = 545 \ J/kg.K[/tex]
[tex]\alpha = 4.40 \times 10^{-6} \ m^2/s \\ \\ B_i = \dfrac{h(\rho/4)}{K} \\ \\ =0.657[/tex]
Here, we can't apply the lumped capacitance method, since Bi > 0.1
[tex]\theta_o = \dfrac{T_o-T_{\infty}}{T_i -T_\infty}} \\ \\ \theta_o = \dfrac{50-30}{500 -30}} \\ \\ \theta_o = 0.0426\\[/tex]
[tex]0.0426 = c_1 \ exp (- E^2_1 F_o_)\\ \\ \\ 0.0426 = 1.1382 \ exp (-10.9287)^2 \ f_o \\ \\ = f_o = \dfrac{In(0.0374)}{0.863} \\ \\ f_o = 3.81[/tex]
[tex]t_f = \dfrac{f_o r^2}{\alpha} \\ \\ t_f = \dfrac{3.81 \times (0.05)^2}{4.40 \times 10^{-6}} \\ \\ t_f= 2162.5 \\ \\ t_f = 36 mins[/tex]
However, on a single rod, the energy extracted is:
[tex]\theta = pcv (T_i - T_{\infty} )(1 - \dfrac{2 \theta}{c} J_1 (\zeta) ) \\ \\ = 7900 \\times 546 \times 0.007854 \times (500 -300) (1 - \dfrac{2 \times 0.0426}{1.3643}) \\ \\ \theta = 1.54 \times 10^7 \ J[/tex]
Hence, for centerline temperature at 50 °C;
The surface temperature is:
[tex]T(r_o,t) = T_{\infty} +(T_1 -T_{\infty}) \theta_o \ J_o(\zeta_1) \\ \\ = 30 + (500-30) \times 0.0426 \times 0.5386 \\ \\ \mathbf{T(r_o,t) = 41.69 ^0 \ C}[/tex]
A cylindrical metal specimen having an original diameter of 10.33 mm and gauge length of 52.8 mm is pulled in tension until fracture occurs. The diameter at the point of fracture is 6.38 mm, and the fractured gauge length is 73.9 mm. Calculate the ductility in terms of (a) percent reduction in area (percent RA), and (b) percent elongation (percent EL).
Answer
a) 62 percent
b) 40 percent
Explanation:
Original diameter ( d[tex]_{i}[/tex] ) = 10.33 mm
Original Gauge length ( L[tex]_{i}[/tex] ) = 52.8 mm
diameter at point of fracture ( d[tex]_{f}[/tex] ) = 6.38 mm
New gauge length ( L[tex]_{f}[/tex] ) = 73.9 mm
Calculate ductility in terms of
a) percent reduction in area
percentage reduction = [ (A[tex]_{i}[/tex] - A[tex]_{f}[/tex] ) / A[tex]_{i}[/tex] ] * 100
A[tex]_{i}[/tex] ( initial area ) = π /4 di^2
= π /4 * ( 10.33 )^2 = 83.81 mm^2
A[tex]_{f}[/tex] ( final area ) = π /4 df^2
= π /4 ( 6.38)^2 = 31.97 mm^2
hence : %reduction = ( 83.81 - 31.97 ) / 83.81
= 0.62 = 62 percent
b ) percent elongation
percentage elongation = ( L[tex]_{f}[/tex] - L[tex]_{i}[/tex] ) / L[tex]_{i}[/tex]
= ( 73.9 - 52.8 ) / 52.8 = 0.40 = 40 percent
Tungsten is being used at half its melting point (Tm≈3,400◦C) and astress level of 160 MPa. An engineer suggests increasing the grain size by afactor of 4 as an effective means of reducing the creep rate.(a)Do you agree with the engineer? Why? What if the stress level were equalto 1.6 MPa?(b)What is the predicted increase in length of the specimen after 10,000hours if the initial length is 10 cm?
Answer:
Explanation:
The missing diagram is attached in the image below which shows the deformation map of the Tungsten.
Given that:
Stress level [tex]\sigma = 160 MPa[/tex]
T = 0.5 Tm
[tex]\implies \dfrac{T}{Tm} = 0.5[/tex]
G = 160 GPa
[tex]\implies \dfrac{\sigma}{G} = 10^{-3}[/tex]
a)
The regulating creep mechanism is dislocation driven, as we can see from the deformation mechanism.
The engineer's recommendation would not be approved because increasing grain size results in a decrease in the grain-boundary count, preferring dislocation motion. The existence of grain borders is a hindrance to dislocation motion, as the dislocation principle explicitly states. To stop the motion, we'll need a substance with finer grains, which would result in more grain borders, or a material with higher pressure. In the case of Nabarro creep, which is diffusion-driven, an engineer's recommendation would be useful.
b)
If stress level reduced to [tex]\sigma = 1.6 MPa[/tex]
[tex]\implies \dfrac{\sigma }{G} = 10^{-5}[/tex]
Cable creep is now the controlling creep mode, which entails tension-driven atom diffusion along grain borders to elongate grain along the stress axis, a process known as grain-boundary diffusion. Cable creep is more common in fine-grained materials. As a result, the engineer's advice would succeed in this case. The affinity for cable creep is reduced when the grain size is increased.
c)
From the map of creep mechanism for [tex]\dfrac{\sigma}{G} = 10^{-3} \ and \ \dfrac{T}{Tm} = 0.5[/tex]
We read strain rate [tex](e) = 10^{-6}/sec[/tex]
Therefore,
[tex]Strain (E) = e * \Delta t[/tex]
[tex]= 10^{-6} \times 10000 \times 3600[/tex]
= 36
Therefore, [tex]\Delta L = E \times Li[/tex]
= [tex]36 * 10 cm[/tex]
= 360 cm
Thus, the increase in length = 360 cm
a tensile specimen with a 12mm initial diameter and 50mm gage length reaches maximum load at 90KN and fractures at 70KN
the minimum diameter at fracture is 10mm
determine the engineering stress at maximum load and the true fracture stress.
Answer:
i) 796.18 N/mm^2
ii) 1111.11 N/mm^2
Explanation:
Initial diameter ( D ) = 12 mm
Gage Length = 50 mm
maximum load ( P ) = 90 KN
Fractures at = 70 KN
minimum diameter at fracture = 10mm
Calculate the engineering stress at Maximum load and the True fracture stress
i) Engineering stress at maximum load = P/ A
= P / [tex]\pi \frac{D^2}{4}[/tex] = 90 * 10^3 / ( 3.14 * 12^2 ) / 4
= 90,000 / 113.04 = 796.18 N/mm^2
ii) True Fracture stress = P/A
= 90 * 10^3 / ( 3.24 * 10^2) / 4
= 90000 / 81 = 1111.11 N/mm^2
An ideal gas is contained in a closed assembly with an initial pressure and temperature of
250kN/m² and 115°C respectively. If the final volume of the system is increased 1.5 times and
the temperature drops to 35°C, identify the final pressure of the gas.
Answer:
Two identical containers each of volume V 0 are joined by a small pipe. The containers contain identical gases at temperature T 0 and pressure P 0 .One container is heated to temperature 2T 0 while maintaining the other at the same temperature. The common pressure of the gas is P and n is the number of moles of gas in container at temperature 2T 0
Explanation:
Which color is used to indicate that a wire will be energized when power is brought to the circuit
A. Yellow
B. Black
C. Blue
D. White
Answer:
I think the answer is B. Black
Which option identifies the specialized field of engineering that would best suit Erik in the following scenario?
Erik is an accounting major, but he fears that working with numbers all day may be a bit constrictive for him. His roommate is an engineering
major and is planning to specialize in chemical engineering, Erik is not interested in chemistry, but he does find engineering fascinating.
O structural engineering
O materials engineering
industrial engineering
O aerospace engineering
Answer:
industrial engineering
Explanation:
i gave 15 min to finish this java program
Answer:
class TriangleNumbers
{
public static void main (String[] args)
{
for (int number = 1; number <= 10; ++number) {
int sum = 1;
System.out.print("1");
for (int summed = 2; summed <= number; ++summed) {
sum += summed;
System.out.print(" + " + Integer.toString(summed));
}
System.out.print(" = " + Integer.toString(sum) + '\n');
}
}
}
Explanation:
We need to run the code for each of the 10 lines. Each time we sum numbers from 1 to n. We start with 1, then add numbers from 2 to n (and print the operation). At the end, we always print the equals sign, the sum and a newline character.
Assume that the flowrate. Q, of a gas from a smokestack is a function of the density of the ambient air,rhoarho a , the density of the gas,rhogrho g , within the stack, the acceleration of gravity, g, and the height and diameter of the stack, h and d, respectively. Use rhocrho c , d, and g as repeating variables to develop a set of pi terms that could be used to describe this problem.
Answer:
hello your question poorly written attached below is the well written question
answer : ∅[tex]( \frac{Pg}{Pa} , \frac{h}{d})[/tex][tex]( \frac{p_{g} }{p_{a} } , \frac{h}{d} )[/tex]
Explanation:
Develop a set of pi terms that could be used to describe the problem
attached below is the required solution
Consider a mild steel specimen with yield strength of 43.5 ksi and Young's modulus of 29,000 ksi. It is stretched up to a point where the strain in the specimen is 0.2% (or 0.002). If the specimen is unloaded (i.e. load reduces to zero), the residual strain (or permanent set) is: 0.05% 0.1% 0% 0.2%
Answer:
0.05%
Explanation:
From the question, we have;
The yield strength of the mild steel, [tex]\sigma _c[/tex] = 43.5 ksi
Young's modulus of elasticity, ∈ = 29,000 ksi
The total strain, [tex]\epsilon _c[/tex] = 0.2% = 0.002
The inelatic strain [tex]\epsilon_c^{in}[/tex] is given as follows;
[tex]\epsilon_c^{in}[/tex] = [tex]\epsilon _c[/tex] - [tex]\sigma _c[/tex]/∈
Therefore, we have;
[tex]\epsilon_c^{in}[/tex] = 0.002 - 43.5/(29,000) = 0.0005
Therefore, the inelastic strain, [tex]\epsilon_c^{in}[/tex] = 0.0005 = 0.05%
Taking the inelastic strain as the residual strain, we have;
The residual strain = 0.05%
three ways to advertise for AVID
Answer:
newspaper, radio, televison
Explanation:
had avid in 7th :)
Answer:
1. will help for colcollares.
2. gives you money for studies
3. helps you choose the perfect collage
1)Saturated steam at 1.20bar (absolute)is condensed on the outside ofahorizontal steel pipe with an inside and outside diameter of 0.620 inches and 0.750 inches, respectively. Cooling water enters the tubes at 60.0°F and leaves at 75.0°F at a velocity of 6.00ft/s. (HINT: You may assume laminar condensate flow.You many also assume that the mean bulk temperature of the cooling water is equal to the wall temperature on the outside of the pipe, T".You may also neglect the viscosity correction in your calculations.)a)What are the inside
Answer:
hi = 7026.8 W/m^2.k
Explanation:
Given data :
pressure of saturated steam = 1.2 bar
Horizontal steel pipe : inside diameter = 0.620 , outside diameter = 0.750 inches
temperature of water at entry = 60°F
temperature of water at exit = 75°F
velocity of water = 6 ft/s
Calculate the Inside convective heat transfer coefficient ( hi )
mean temperature ( Tm ) = 60 + 75 / 2 = 67.5°F ≈ 292.877 K ≈ 19.727°C
next : find the properties of water at this temperature ( 19.727°C )
thermal conductivity = 0.598 w/m.k
density = 1000 kg/m^3
specific heat ( Cp ) = 4.18 KJ/kg.k
viscosity = 0.001 pa.s
velocity of water = 6 ft/s ≈ 1.8288 m/s
∴ Re ( Reynolds number ) = 28712.16
and Prandtl number ( Pr ) = (4180 * 0.001) / 0.598 = 6.989
finally to determine the inside convective heat transfer coefficient we will apply the Dittos - Bolter equation
hi = 7026.8 w/m^2.k
attached below is the remaining solution
The standard procedure for dimensioning the location of a house on a site is to dimension ____ of the house from adjacent lot lines. A one side b two sides c two corners d one corner
Answer:
One corner ( D )
Explanation:
when dimensioning the location of a house on site the standard and the acceptable procedure is to ; Dimension One corner of the house
Adjacent lots is a term used to describe parcels of the site that meet each other along their boundary lines. and they also include parcels that may be separated by streets
How should backing plates, struts, levers, and other metal brake parts be cleaned?
Answer: Cleaning of mechanical parts is necessary to remove contaminants, and to avoid clogging of wastes which could restrict the functioning of the machine.
Explanation:
There are different agents used for cleaning different machine instruments to prevent their corrosion and experience proper cleaning.
Backing plates must be dry cleaned using a cotton cloth to remove the dirt, dust or any other dry contaminant.
Struts can be wet cleaned by applying alcoholic solvent.
Levers can be cleaned using a mineral spirit.
Metallic plates can be cleaned using water based solution or water.
When an arbitrary substance undergoes an ideal throttling process through a valve at steady state, (SELECT ALL THAT APPLY) inlet and outlet mass flowrates will be equal. inlet and outlet specific enthalpies will be equal. inlet and outlet pressures will be equal. inlet and outlet mass flowrates will be equal. inlet and outlet specific enthalpies will be equal. inlet and outlet temperatures will be equal.
Answer:
15x
Explanation:
What Modern-Day Railroad Runs From Chicago to Seattle?
Answer:
The empire builder
Explanation:
4.54 Saturated liquid nitrogen at 600 kPa enters a boiler at a rate of 0.008 kg/s and exits as saturated vapor (see Fig. P4.54). It then flows into a superheater also at 600 kPa, where it exits at 600 kPa, 280 K. Find the rate of heat transfer in the boiler and the superheater.
Answer:
hello the figure attached to your question is missing attached below is the missing diagram
answer :
i) 1.347 kW
ii) 1.6192 kW
Explanation:
Attached below is the detailed solution to the problem above
First step : Calculate for Enthalpy
h1 - hf = -3909.9 kJ/kg ( For saturated liquid nitrogen at 600 kPa )
h2- hg = -222.5 kJ/kg ( For saturated vapor nitrogen at 600 kPa )
second step : Calculate the rate of heat transfer in boiler
Q1-2 = m( h2 - h1 ) = 0.008( -222.5 -(-390.9) = 1.347 kW
step 3 : find the enthalpy of superheated Nitrogen at 600 Kpa and 280 K
from the super heated Nitrogen table
h3 = -20.1 kJ/kg
step 4 : calculate the rate of heat transfer in the super heater
Q2-3 = m ( h3 - h2 )
= 0.008 ( -20.1 -(-222.5 ) = 1.6192 kW
Wattage is:
Select one:
a.
A measure of the total electrical work being performed per unit of time.
b.
Expressed as P = R × A.
c.
Both A and B.
d.
Neither A nor B.
Answer:
c.Both A and B.
Explanation:
the wattage is c and d
Using a small cube as a representative volume of material, illustrate graphically all the six independent components of strains that determine the state of strain in the volume of material that is enclosed by the cube. Indicate in your schematics, the change in shape produced by each of the normal strain and shear strain components.
Answer:
Attached below
Explanation:
Attached below is the schematic diagram of a small cube representing volume of material and all the six independent components of strains that will determine the state of strain
Note : Attached below is a free hand diagram of the cube indicating the six independent components of strains and a screen shot of the change in shape produced by each of the normal strain and shear strain components
( drawn with online tools )
What regulates the car engines temperature
Answer:
car’s thermostat is used to regulate the temperature of the engine to help the engine stay cool.
Explanation:
Answer:
Coolant
Explanation:
For maximum safety, an electrician should learn
A. all OSHA standards and requirements by heart.
B. to perform most tasks with one hand.
c. to perform tasks in low light situations.
D. every NEC code by heart.
Answer:A
Explanation:The minimum level of education required to become an electrician is a high school diploma or equivalency degree, like the General Education Diploma (GED). This educational step is important on the journey to becoming an electrician because the high school curriculum covers the basic principles used on the job.
Which two technologies were combined to create product life cycle management (PLM) software?
CAD and a database
spreadsheets and graphics
a database and spreadsheets
CAD and spreadsheets
Answer:
CAD and a database
Explanation:
The correct answer is CAD and a database. When American Motors Corportation introduced the Jeep Cherokee, it implemented CAD to increase engineering productivity and combined that with a new communications system.
5. The pin support at A allows _______. Select the one that applies. (a) displacement in the x direction (b) rotation about its central axis (c) displacement in the y direction (d) none of the above 6. The support at B does not allow _______. Select the one that applies. (a) displacement in the x direction (b) rotation about its central axis (c) displacement in the y direction
Answer: Diagram associated with your question is attached below
5) B
6) C
Explanation:
5) The pin support at A allows ; Rotation about its central axis
This is because pin supports does not allow the translation of its structural member in any direction i.e. y or x but only rotation about its axis
6) The support at B does not allow displacement in y direction
This is because roller support allows displacement only in the direction that they are situated and in this case it is the x - direction
What is the difference between ""Errors due to the Curvature"" and ""Errors due to Refraction"". Support your answer with sketches
Answer:
In " errors due to the curvature " the points appears to be lower than they are in reality while
In " errors due to Refraction " The points appears to be higher than they are in reality .
Explanation:
The difference between both errors
In " errors due to the curvature " the points appears to be lower than they are in reality while
In " errors due to Refraction " The points appears to be higher than they are in reality .
when the effects of both Errors are combined the points will appear lower and this is because the effect of "error due to the curvature" is greater
attached below are the sketches
Assume, X Company Limited (XCL) is one of the leading 4th generation Life Insurance
Companies in Bangladesh. The Company is fully customer focused. This Life insurance company are
experimenting with analysis of consumer profiles (to determine whether a person eats healthy food,
exercises, smokes or drinks too much, has high-risk hobbies, and so on) to estimate life expectancy.
Companies might use the analysis to find populations to market policies to. From the perspective of
privacy, what are some of the key ethical or social issues raised? Evaluate some of them.
Answer:
The issues related to the privacy are:
1. Informational privacy
2. Discrimination factors
3. Biased grouping on the basis of Data mining
4. Lack of consent
5. Morally wrong
6. Illegal distribution of information risks
7. Possibility of threat to life
Let's look at some major concerns:
1. Informational privacy : The concept of privacy of the personal information is totally nullified when the information is being used for a purpose other than the intended one for which it was given. This unethical use of information even for general purposes is not correct and is a matter of concern. It is more like using the sensitive data of others for personal benefit which is purely objectionable and raises security issues. Sometimes the data is also shared with the potential employers which might have certain impacts we are unaware of.
2. Data mining issues : The process of using a certain information to arrive and understand the trend and outcomes is called data mining. In this case, the consumer's data undergoes grouping and might get placed in the wrong group rather than the actual one. Also, there can be a case of biasing towards the groups which are not be focused on, or are not a part of the intended audience. This leads to the discrimination factors if we see it from a social point of view.
3. Lack of consent : Use of information without the consent or awareness of the consumers raises concern over the business ethics followed by the company. No one deserves the right to misuse information for his personal benefits without any of its information to the consumer. It is morally wrong and againt the work ethics. Moreover, it raises trust issues between the two involved, and hence is socially unacceptable.Explanation:
The volume of a right circular cone of radius r and height h is V = 1 3 πr 2h (a) (i) Find a formula for the instantaneous rate of change of V with respect to r if r changes and h remain constant. (ii) Suppose that h = 2 is fixed but r varies. Find the rate of change of V w. R. To r at the point where r = 4.
Answer:
(i) [tex]\frac{2}{3}[/tex][tex]\pi[/tex]rh
(ii) [tex]\frac{16}{3}[/tex][tex]\pi[/tex]
Explanation:
Given:
V = [tex]\frac{1}{3}[/tex][tex]\pi[/tex]r²h
Where;
V = volume of a right circular cone.
r = radius of the cone
h = height of the cone.
(i) The rate of change of V with respect to r if r changes and h remains constant is [tex]\frac{dV}{dr}[/tex], and is given by finding the differentiation of V with respect to r as follow:
[tex]\frac{dV}{dr}[/tex] = [tex]\frac{d}{dr}[/tex][[tex]\frac{1}{3}[/tex][tex]\pi[/tex]r²h]
[tex]\frac{dV}{dr}[/tex] = [tex]\frac{2}{3}[/tex][tex]\pi[/tex]rh --------------------(i)
(ii)
Given;
h = 2
r = 4
Substitute these values into equation (i) as follows;
[tex]\frac{dV}{dr}[/tex] = [tex]\frac{2}{3}[/tex][tex]\pi[/tex](4 x 2)
[tex]\frac{dV}{dr}[/tex] = [tex]\frac{2}{3}[/tex][tex]\pi[/tex](8)
[tex]\frac{dV}{dr}[/tex] = [tex]\frac{16}{3}[/tex][tex]\pi[/tex]
[tex]\frac{dV}{dr}[/tex] = [tex]\frac{16}{3}[/tex][tex]\pi[/tex]
A right circular cone is one where the axis of cones is the line connecting the vertex to circular base's midway, the volume of right circular cone as follows:
Volume calculation:Formula:
[tex]V = \frac{1}{3} \pi r^2h[/tex]
Where;
V = right circular cone volume
r = Cone radius.
h = Cone height.
The calculation for part 1:
[tex]\frac{dV}{dr}[/tex] is indeed the rate of change of V with reference to r when r changes but h remains constant, and it is calculated via calculating the differentiation of V with respect to r as follows:
[tex]\to \frac{dV}{dr} =\frac{d}{d}r [ \frac{1}{3} \pi r^2h] =\frac{2}{3} \pi r h[/tex]
The calculation for part 2:
When h = 2 and r = 4 then substituting the value into the part 1 equation then:
[tex]\to \frac{dV}{dr} = \frac{2}{3} \pi (4 \times 2) = \frac{2}{3} \pi (8) = \frac{16}{3} \pi[/tex]
Find out more about the volume here:
brainly.com/question/24086520
Which of the following identifies three advantages of PLM software?
reduced cost, faster marketing, and process transparency
faster marketing, process transparency, and outsourcing
process transparency, outsourcing, and reduced cost
outsourcing, reduced cost, and faster marketing
Answer:
reduced cost, faster marketing, and process transparency
Explanation:
The correct answer is reduced cost, faster marketing, and process transparency. PLM software helps coordinate tasks during implementation.
if the output of a signal is 36% on and 64% off and repeats itself is it considered periodic
helppppp
Answer:
No, it is not a periodic Signal
Explanation:
No, it is not a periodic Signal
This signal is repeating itself with the fixed on and off values but the major point to note here is that is this signal repeating after a fixed length of time every time. No, such information is provided in the question and hence, this signal cannot be termed as periodic.