Reuben will rent a car for the weekend. he can choose one of two plans. the first has no initial fee but costs $0.90 per mile driven. The second plan has an initial fee of $65 and costs an additional $0.70 per mile driven. How many miles would Reuben need to drive for the two plans to cost the same? ​

Answers

Answer 1

Answer:

80 miles for the .9 one.

Step-by-step explanation:


Related Questions

PLEASE HELP ASAP!!! URGENT

Verify the identity. Sinx/1-cosx = cscx+cotx

Please use the answers shown in the image !! Thank you !!

Answers

Answer:

1) [tex]\frac{\sin x}{1-\cos x} = \csc x + \cot x[/tex]

2) [tex]\frac{\sin x}{1-\cos x} = \frac{1}{\sin x} + \frac{\cos x}{\sin x}[/tex]

3) [tex]\frac{\sin x}{1-\cos x} = \frac{1+\cos x}{\sin x}[/tex]

4) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x \cdot (1+\cos x)}{\sin^{2}x}[/tex]

5) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{1-\cos^{2}x}[/tex]

6) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{(1+\cos x)\cdot (1-\cos x)}[/tex]

7) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x}{1-\cos x}[/tex]

Step-by-step explanation:

Now we proceed to show all steps needed to demonstrate the trigonometric identity:

1) [tex]\frac{\sin x}{1-\cos x} = \csc x + \cot x[/tex] Given.

2) [tex]\frac{\sin x}{1-\cos x} = \frac{1}{\sin x} + \frac{\cos x}{\sin x}[/tex] Identities for cosecant and cotangent functions.

3) [tex]\frac{\sin x}{1-\cos x} = \frac{1+\cos x}{\sin x}[/tex]             [tex]\frac{a}{b}+\frac{c}{b} = \frac{a+c}{b}[/tex]

4) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x \cdot (1+\cos x)}{\sin^{2}x}[/tex] Existence of additive inverse/Modulative property.

5) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{1-\cos^{2}x}[/tex]    Fundamental trigonometric identity.

6) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x\cdot (1+\cos x)}{(1+\cos x)\cdot (1-\cos x)}[/tex]   Factorization.

7) [tex]\frac{\sin x}{1-\cos x} = \frac{\sin x}{1-\cos x}[/tex] Existence of additive inverse/Modulative property/Result.

xsquare-8x+15 please help me answer it thank you​

Answers

Step-by-step explanation:

[tex] {x}^{2} - 8x + 15 = 0 \\ (x - 3)(x - 5) = 0 \\ x = 3 \: or \: x = 5[/tex]

The difference between the squares of two numbers is 35. Twice the square of
the first number increased by the square of the second number is 73. Find the
numbers.

Answers

Answer:

Los números son

7 y 8

Explicación paso a paso:

Si el número menor es "x"  , el mayor es "x + 1"

entonces

( x + 1 )² - x² = 15

x² + 2x + 1 -x² = 15

2x + 1 = 15

2x = 15 - 1

2x = 14

x = 14/2

x = 7  (  número menor )

x + 1  = 7 + 1

x + 1 = 8 ( número mayor )

Please help!!
Imaginary Numbers

Answers

Answer:

A. 1

Step-by-step explanation:

its A

QUICK PLEASE I NEED HELP ON THIS

Answers

Answer:

Some

Step-by-step explanation:

the mean absolute deviation would intersect and would there for be some but at far enough apart to not be a lot

POSSIBLE POINTS: 6
Solve each equation and match the solution.



e+8=31
t−25=54
32=y −21
14=b−12
x+8.95=21.95
n +21 =32

Answers

Answers,

1. 23

2. 79

3. 53

4. 26

5. 13

6. 11

How I did this,

What I did was subtract 8 from 31 to get ( e ) by itself.

This subject will get harder so I reccomend you focus on school and learn how to do this.

(see picture) Find the measures of the numbered angles in each isosceles trapezoid.

Answers

1,365


I hope it’s correct please mark me :)

help aced and expert giving 20 points

Answers

The correct answer is 0.0625 square meters.

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each division expression with the correct quotient. (These are the answers)
18x^(2)+39x+15 over 3x+5 -----> 6x+3
35x^(2)-5x-30 over 5x-5 -------> 7x+6
15x^(2)-44x+21 over 5x-3 ------> 3x-7

Answers

can you answer the question that it’s in blue please

Answer:

18x^(2)+39x+15 over 3x+5 -----> 6x+3

35x^(2)-5x-30 over 5x-5 -------> 7x+6

15x^(2)-44x+21 over 5x-3 ------> 3x-7

Step-by-step explanation:

Plato Gang

find the least common multiple of 16,30,36 no links or file​

Answers

9514 1404 393

Answer:

  720

Step-by-step explanation:

The LCM of these numbers will have every factor that is part of these numbers.

  16 = 2^4

  30 = 2 × 3 × 5

  36 = 2^2 × 3^2

So, the LCM will have factors of 2^4, 3^2, and 5:

  LCM(16, 30, 36) = 2^4 × 3^2 × 5 = 720

720 = 16×45 = 30×24 = 36×20

The least common multiple is 720.

twice the difference of v and z

Answers

Answer:

me

Step-by-step explanation:

becaus im the bes guy

The length of a rectangle is 3 inches more than three times it's width. Write an equation relating the length, “, of the rectangle to its width, w.

Answers

An equation relating the length of the rectangle to its width would be, “l+3=w”. The length plus 3 inches would be equal to the width.

Find the value of x.
(a)
(10.7)" = 2
3x92x1 = 27*
(b)​

Answers

Step-by-step explanation:

where is x in the question

What is the image of the point (4,1) after a rotation of 270° counterclockwise about
the origin?
Will give brainliest

Answers

Answer:

1,-4

Step-by-step explanation:

formula for rotation of 270 is (x,y) to (y,-x)

Help what is 3 1/2 divided by 8

Answers

Answer I got was 2.28

Question 20 A retired couple invested $6000 in bonds. At the end of one year, they received an interest payment of $402. What was the simple interest rate of the bonds? ​

Answers

Answer: interest rate was 6.7 %

Step-by-step explanation: 402/6000 = 0.067 = 6.7%

An introductory psychology class has 9 freshman males, 15 freshman females, 8 sophomore males, and 12 sophomore females. A random sample of n = 2 students is selected from the class. If the first student in the sample is a male, what is the probability that the second student will also be a male?

Answers

Answer

16/43

Step-by-step explanation:

17 Male + 27 female = 44 students

now n= 2 so first student was male so one male student was taken out of the equation so 16 male left. now left male students by remaining students  so now total left students = 43

so, prob = remaining males/remaining students=16/43

Write each expression as an algebraic​ (nontrigonometric) expression in​ u, u > 0.
sin(2sec^-1 u/10)

Answers

Answer:

[tex]\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0[/tex]

Step-by-step explanation:

We want to write the trignometric expression:

[tex]\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)\text{ where } u>0[/tex]

As an algebraic equation.

First, we can focus on the inner expression. Let θ equal the expression:

[tex]\displaystyle \theta=\sec^{-1}\left(\frac{u}{10}\right)[/tex]

Take the secant of both sides:

[tex]\displaystyle \sec(\theta)=\frac{u}{10}[/tex]

Since secant is the ratio of the hypotenuse side to the adjacent side, this means that the opposite side is:

[tex]\displaystyle o=\sqrt{u^2-10^2}=\sqrt{u^2-100}[/tex]

By substitutition:

[tex]\displaystyle= \sin(2\theta)[/tex]

Using an double-angle identity:

[tex]=2\sin(\theta)\cos(\theta)[/tex]

We know that the opposite side is √(u² -100), the adjacent side is 10, and the hypotenuse is u. Therefore:

[tex]\displaystyle =2\left(\frac{\sqrt{u^2-100}}{u}\right)\left(\frac{10}{u}\right)[/tex]

Simplify. Therefore:

[tex]\displaystyle \sin\left(2\sec^{-1}\left(\frac{u}{10}\right)\right)=\frac{20\sqrt{u^2-100}}{u^2}\text{ where } u>0[/tex]

A racing car driver is investigating whether the type of fuel he uses in his car affects his overall speed. He uses three different types of fuel. The driver runs an experiment where he fills his car with each type of fuel 20 times, and each time records the time taken to drive one lap of a track. A one-way ANOVA test is conducted to test the null hypothesis that type of fuel is not a significant factor in determining speed. The result of the test is that the null hypothesis is not rejected.

The conclusion that follows from this test is that: __________

a. it has been proven that the type of fuel is a significant factor in determining speed
b. it cannot be ruled out that the type of fuel is an insignificant factor in determining speed
c. it has been proven that the type of fuel is an insignificant factor in determining speed
d. it has been proven that the type of fuel can sometimes be a significant factor in determining speed

Answers

Answer:

b. it cannot be ruled out that the type of fuel is an insignificant factor in determining speed.

Step-by-step explanation:

From the question :

Let the speed of each fuel be represented as ;

u1, u2, u3

The null hypothesis, H0 ;

H0 : u1 = u2 = u3

H0 is of the notion that fuel type is not a significant factor in determining speed

The alternative hypothesis, H1;

H1 : u1 ≠ u2 ≠ u3

The alternative is the opposite of the null, fuel type is a significant factor in determining speed

If after conducting the statistical test, the null hypothesis cannot be rejected ;

Then the conclusion will be ;

There is no significant evidence to conclude that the fuel type is a significant factor in determining speed ;

Hence, fuel fuel type remains an insignificant factor in determining speed.

Solve the system of equations.
2.5y+ 3x = 27
5x-2.5y = 5
What equation is the result of adding the two equations?
What is the solution to the system?​

Answers

Answer:

The asnwer to the system of equation

x=4 y=6

Step-by-step explanation:

Answer:  1) 8x=32       2) (4,6)

Step-by-step explanation:

Hope this helps!

Mark me brainliest!

Pls and ty!

Help please question in picture

Answers

Answer:

220

Step-by-step explanation:

Area of square=8*20=160

Area of triangle=(6*20)/2=60

160+60

Answer:

220 units²

I'm sure this is the answer!

I just need help finding out the missing sides

Answers

DON'T OPEN IT, IT'S A VIRUS!!

Only 3 more questions to go

Answers

90° angle on a straight lines gotta be 180°

There were 816 cars parked in the parking lot on Monday morning. At lunchtime 91 cars left the lot. After lunch, 135 cars came back to the parking lot. How many parking spots were left on Monday morning ?

Answers

Answer:

467

Step-by-step explanation:

There were a total 1327 parking lots.

Out of these 816 were taken in the morning, 91 cars left in the afternoon, while 135 came back after lunch.

So there are,

[tex]Cars left = 1327 - (816 - 91 + 135) \\\\ = 1327 - 860\\ = 467[/tex]

Thus, there are 467 parking spots left on Monday afternoon.  

Find cos(B) in the triangle.
Choose 1 answer:

Answers

Cosine: adjacent/hypothenuse
Adjacent = 3, hypothenuse = 5

Solution: 3/5

What probability statement would you add to ​P(blue) = 1 10 to make a complete probability model for the event choosing a foam ball at random from the​ box?

Answers

Answer:

The chances of landing on blue are 1 in 4, or one fourth. The chances of landing on red are 1 in 4, or one fourth. This problem asked us to find some probabilities involving a spinner.

Which fraction is equivalent to 2/-6

Answers

Answer:

-1/3

Step-by-step explanation:

A stationery store wants to estimate the mean retail value of greeting cards that it has in its inventory. A random sample of 15 greeting cards indicates an average value of $3.00 and a s of $0.40. The critical value for a 99% confidence interval is

Answers

Answer:

The critical value for a 99% confidence interval is T = 2.9768

Step-by-step explanation:

We have the standard deviation of the sample, which means that the t-distribution is used to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 15 - 1 = 14

Critical value

Now, we have to find a value of T, which is found looking at the t table, with 14 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.99}{2} = 0.995[/tex]. So we have T = 2.9768

The critical value for a 99% confidence interval is T = 2.9768

The function f is defined by f(x) = 57. What is the value of f(3)?
O 15
O 25
O 53
O 125

Answers

Answer:

53

Step-by-step explanation:

Because

how do i solve for the inequality, p=3.4?​

Answers

Answer:

Step-by-step explanation:

This is already solved, and this would not be considered a inequality since it has only a equal sign.

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