Show that the force of gravity is 3.5 * 1022 N between Earth and the Sun
(Sun’s mass = 2.0 x 1030 kg; average Earth–Sun distance = 1.5 x 1011 m).

Answers

Answer 1

The force of gravity between the sun and the earth is determined as 3.54 x 10²² N.

What is force of gravity?

This is the force of gravity is the force exerted between two objects in the universe.

According to Newton's law of universal gravitation, two bodies in space pull on each other with a force proportional to the product of their masses and the inversely proportional to the square of the distance between them.

F = Gm1m2/r²

where;

m1 is mass of the sunm2 is mass of the earthr is the distance between the two bodies

F = (6.67 x 10⁻¹¹ x 2 x 10³⁰ x 5.97 x 10²⁴) / (1.5 x 10¹¹)²

F = 3.54 x 10²² N

Thus, the force of gravity between the sun and the earth is determined as 3.54 x 10²² N.

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Related Questions

19 "Made mostly of ice", fits best under which heading in the table below?
Asteroid
Meteor
Comet
Planet
Description
A Asteroid
B Meteor
C Comet
D Planet

Answers

Answer is comet

Comets are frozen leftovers from the formation of the solar system composed of dust, rock and ices. They range from a few miles to tens of miles wide, but as they orbit closer to the sun, they heat up and spew gases and dust into a glowing head that can be larger than a planet.

Two train whistles have identical frequencies of 220 Hz. When one train is at rest in the station sounding its whistle, a beat frequency of 10.0 Hz is heard from the other train that is approaching the station. What is the speed of the approaching train? Assume that the speed of sound is 340 m/s.

Answers

Answer:

Speed of the approaching train = 15.45 m/s

Explanation:

Given:

Frequency F0 = 220 Hz

Beat frequency F1 = 10.0 Hz

Find:

Speed of the approaching train

Computation:

Approaching frequency F2 = 220 + 10.0 Hz

Approaching frequency F2 = 230 Hz

Doppler shift;

F = [(v+v0)/(v-vS)]F0

230 = [(340+v0)/(340-0)]220

V0 = 15.45 m/s

Speed of the approaching train = 15.45 m/s

A man fires a silver bullet of mass 2g with a velocity of200m/sec into wall. What is the temperature changeof the bullet? Note: Csilver = 234J/kg.°CL

Answers

F=nmv

where;

n=no. of bullets = 1

m=mass of bullets=2g *10^-3

V=velocity of bullets200m/sec

F=1

loss in Kinetic energy=gain in heat energy

1/2MV^2=MS∆t

let M council M

=1/2V^2=S∆t

M=2g

K.E=MV^2/2

=(2*10^-3)(200)^2/2

2 councils 2

2*10^-3*4*10/2

K.E=40Js

H=mv∆t

(40/4.2)

40Js=40/4.2=mc∆t

40/4.2=2*0.03*∆t

=158.73°C

The object has a speed of 15 m/s. It took the object 5 second to travel, how far did the object go?

Answers

Answer:

Seventy-Five Metres

Explanation:

You can solve this simply by multiplying 15 m/s by 5 seconds

[tex]15 \frac{m}{s} * 5s\\=75\frac{ms}{s}\\= 75m[/tex]

A marble is fired from a spring-loaded gun at an angle of 30◦

above the ground and reaches a

maximum height 500m.
a. What is the velocity of the marble at it’s maximum height?
b. What is the acceleration of the marble at it’s maximum height?
c. What was the marbles initial velocity?
d. How long did it take for the marble to reach it’s maximum height?

Answers

Answer:

jrirnr tn

Explanation:

and then we was just wondering what we should be talking to about to see how you are

0
Northeast
North Central
South
Region of the United States
West

8 Claims Evidence Reasoning Which
region of the country has the coldest
January temperatures? Use the data in the
graph to support your claim, and explain

Answers

North is the coldest

A 1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail

Answers

Answer:

132 N

Explanation:

Given that a  1.1 kg hammer strikes a nail. Before the impact, the hammer is moving at 4.5 m/s; after the impact it is moving at 1.5 m/s in the opposite direction. If the hammer is in contact with the nail for 0.025 s, what is the magnitude of the average force exerted by the hammer on the nail

From Newton 2nd law of motion,

Change in momentum = impulse.

Change in momentum = m( V - U )

Substitute all the parameters into the formula

Change in momentum = 1.1 ( 4.5 - 1.5 )

Change in momentum = 1.1 × 3

Change in momentum = 3.3 kgm/s

Impulse = Ft

That is,

Ft = 3.3

Substitute time t into the formula above

F × 0.025 = 3.3

F = 3.3 / 0.025

F = 132 N

Therefore, the magnitude of the average force exerted by the hammer on the nail is 132 N.

Carlos is riding her bicycle. His velocity is 5 m/s to the right. His acceleration is 1.2 m/s2 to the left. He is doing what?

- moving at a constant speed
- slowing down
- speeding up

Answers

Answer:

Slowing down

Explanation:

Carlos is travelling to the right as indicated by his velocity, so his velocity is +5m/s. He is also accelerating to the left which is the opposite direction to his velocity so his acceleration is -1.2m/s2 to the right.

Since his acceleration is negative relative to his velocity and direction of motion, his speed is decreasing and he is slowing down.

Hope this helped!

Can someone please help me with some physics​

Answers

Answer:

sure I will helpy you iru

1. A boy is standing on top of a roof that is 4.5 m high. If he throws a 1.4 kg water balloon down with a velocity of 2m/s,
what velocity will the water balloon strike the ground with? (ignore air resistance)

Answers

Answer:

The magnitude of the final velocity of the water balloon is 84.3 m/s.

Explanation:

To calculate the velocity of the water balloon when it strikes the ground we need to use the next equation:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh [/tex]

Where:

[tex]v_{f}[/tex]: is the final velocity =?

[tex]v_{0}[/tex]: is the initial velocity = 2 m/s

g: is the gravity = 9.81 m/s²

h: is the height = 4.5 m

By entering the above values into equation (1) we have:

[tex] v_{f}^{2} = v_{0}^{2} - 2gh = (2 m/s)^{2} - 2*9.81 m/s^{2}*4.5 m = -84.3 m/s [/tex]

The minus sign is because the direction of the velocity vector is in the negative vertical axis.  

         

Therefore, the magnitude of the final velocity of the water balloon is 84.3 m/s.

I hope it helps you!

A 125 g pendulum bob hung on a string of length 35 cm has the same period as when the bob is hung from a spring and caused to oscillate. What is the spring’s elastic constant?a) 3.5 N/mb) 5.2 N/mc) 1.9 N/md) 27 N/m

Answers

Answer:

k = 3.5 N/m

Explanation:

It is given that the time period the bob in pendulum is the same as its time period in spring mass system:

[tex]Time\ Period\ of\ Pendulum = Time\ Period\ of\ Spring-Mass\ System\\2\pi \sqrt{\frac{l}{g}} = 2\pi \sqrt{\frac{m}{k}[/tex]

[tex]\frac{l}{g} = \frac{m}{k}\\\\ k = g\frac{m}{l}[/tex]

where,

k = spring constant = ?

g = acceleration due to gravity = 9.81 m/s²

m = mass of bob = 125 g = 0.125 kg

l = length of pendulum = 35 cm = 0.35 m

Therefore,

[tex]k = (9.81\ m/s^2)(\frac{0.125\ kg}{0.35\ m})\\\\[/tex]

k = 3.5 N/m

Answer5 ms 3. A football player has a mass of 95 kg, and he is running with a velocity of 15 m/s. What is his momentum? Answer:​

Answers

Answer:

1425kgm/s

Explanation:

Given parameters:

Mass  = 95kg

Velocity  = 15m/s

Unknown:

Momentum  = ?

Solution:

The momentum of a body is the amount of motion it posses;

  Momentum  = mass x velocity

Insert the parameters and solve;

 Momentum  = 95 x 15  = 1425kgm/s

In a tug of war, team A pulls the rope with a force of 50 N to the right and team B pulls it with a force of 110 N to the left. What is the resultant force on the rope and which direction does the rope move? (N represents newton, the unit of force)

Answers

Given that,

Force in right side = 50 N

Force in left side = 110 N

To find,

The resultant and direction of force.

Solution,

Let the net force F is acting on the rope. Also, we can assume that right side is positive and left side is negative.

F = 50+(-110)

= -60 N

So, the magnitude of the resultant force acting on the rope is 60 N and it acts in left side.

How does cyanoacrylate compare to the elements
that make it up?

HELPPPPP NOWWWWW

Answers

Explanation:

It exists in the tube as single molecules in liquid form. But when they come into contact with water, the molecules react with hydroxide ions to form long polymer chains that set into a hard solid. As there is a thin layer of moisture covering most surfaces, cyanoacrylate can bond them together very effectively.

Energy stored because of an object's height above the Earth's surface is_____energy.

nuclear

gravitational

electrical or chemical​

Answers

gravitational potential energy

A ball is tied to the end of a cable of negligible mass. The ball is spun in a circle with a radius 7.1 m making 3.9 revolutions every 9.4 second. What is the centripetal acceleration of the ball?

Answers

Answer:

48,2 m/s²

Explanation:

We're gonna use the Centripetal Acceleration formula: v² / r but before that, we got to know the velocity, that is not shown clearly to us, so....

To know the velocity let's calculate the distance that the ball traveled

The circumference of a circle formula is:

2piR

2 . 3,14 . 7,1 | That is equal to 44,588 m

We know that the ball traveled this distance 3,9 times, so...

44,588 . 3,9 = 173,8932 m

Ok, now we have the distance, just need to know the time, that is 9.4 seconds.

Velocity = Distance / Time

V = 173,8932 / 9,4

V = 18,5 (approximate)

So...

We are back to the first formula:

Ca = v² / r

Ca = 18,5² / 7.1

Ca = 48,2 m/s² (approximate)

I hope it is correct, hahaha.

Max observes a spaceship traveling toward him at 0.75c. He measures its length and finds that the spaceship is 250 m long. The ship brakes hard and skids to a stop on a nearby airstrip. Max remeasures the spaceship. What length does he find

Answers

Answer:

380m

Explanation:

We have the speed of the spaceship v = 0.75c

Max measures contracted length L of the spaceship as it travels

We have been given L = 250m

As this ship stops he is going to get exact length of the ship = Lol

We solve using this formula

L = Lo√ 1-v²/c²

From the formula above we make Lo subject of the formula

When we input values

Lo = 250/√1-(0.75c/c)²

= 250/√1-(0.75)²

= 250/√0.4375

= 250/0.6614

= 377.98

This is approximately 380

If the lead bar was heated to a temperature of 120 degrees Celsius, what would happen to its volume, mass and density?

Answers

On heating a lead bar, its volume increases, density decreases and its mass remains constant.

According to Ideal gas equation,

pV = nRT

ρ = m / V

V = Volume

T = Temperature

ρ = Density

m = Mass

Based on Ideal gas equation, Volume is directly proportional to Temperature. As temperature increases, volume also increases. Based on density formula, Volume is indirectly proportional to Density. As Volume increases density decreases.  

In any reaction, the mass is always conserved. Because, mass is the amount of matter present in a substance. During a reaction, atoms are neither created nor destroyed, just rearranged. So the mass always remains constant.  

Therefore, if a lead bar was heated to 120°C, its volume increases, density decreases and its mass remains constant.

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g volume of 0.025 m3. If the temperature of the gas is 290 K, what is the rms speed of the gas atoms

Answers

This question is incomplete, the complete question is;

Argon gas (a monatomic gas) is sometimes used to insulate a double-pane window for purposes of insulation. In a particular window, the space in between two glass sheets has a volume of 0.025 m³.

If the temperature of the gas is 290 K . what is the rms speed of the gas atoms ?

The atomic mass of Argon is 39.9 u.

(1 u = 1.66 x 10⁻²⁷ kg) Enter your answer in m/s.

Enter your Answer in m/s

Answer: the rms speed of the gas atoms is 425.754 m/s

Explanation:

Given that;

mass of Argon = 39.9 u

and 1 u = 1.66 x 10⁻²⁷ kg

so 39.9 × 1.66 x 10⁻²⁷ kg = 6.6234 x 10⁻²⁶

Temperature T = 290 K

Now

V_rms = √( 3KT / M)

where Boltzmann's constant K = 1.38 × 10⁻²³ m²kg s⁻² K⁻¹

so we substitute

V_rms = √( 3 × 1.38 × 10⁻²³ × 290 / 6.6234 x 10⁻²⁶)

V_rms = √( 181266.419)

V_rms = 425.754 m/s

Therefore the rms speed of the gas atoms is 425.754 m/s

A crate of oranges on a horizontal floor has a mass of 30 kg. The coefficient of static friction is 0.62. The coefficient of kinetic friction is 0.52. The worker pulls the crate with a force of 200 N.
How do you know if the crate is moving or not? Explain it by comparing the magnitude of the friction with the magnitude of the applied force.

Answers

Answer:

Explanation:

The Net Force

The net force is defined as the sum of all the forces acting on a body at a certain moment.

Recall some basic concepts and equations to solve the problem.

If no external forces are applied in the vertical direction, the weight of the object and the normal force have the same magnitude and point to opposite directions.

The friction force is defined as:

[tex]Fr_k=\mu_k N[/tex]

[tex]Fr_s=\mu_s N[/tex]

Where the subindices k and s are referred as to the kinetic and static friction forces respectively.

The condition for the object to move is that the applied force is greater than the friction force.

The crate of oranges has a mass of 30 Kg, thus its weight is:

W = m.g = 30 * 9.8 = 294 N

The normal force is:

N = W = 294 N

The kinetic friction is calculated as:

[tex]Fr_k=0.52* 294[/tex]

[tex]Fr_k=152.88\ N[/tex]

The static friction is calculated as:

[tex]Fr_s=0.62* 294[/tex]

[tex]Fr_s=182.28\ N[/tex]

The applied force is 200 N and it's greater than both the kinetic and the static friction forces, thus the crate is definitely moving at a certain positive acceleration.

A 100 A current circulates around a 2.00-mm-diameter superconducting ring.
A. What is the ring's magnetic dipole moment?
B. What is the on-axis magnetic field strength 4.70 cm from the ring?

Answers

Answer:

0.000314 Am²

6.049*10^-7 T

Explanation:

A

From the definitions of magnetic dipole moment, we can establish that

= , where

= the magnetic dipole moment in itself

= Current, 100 A

= Area, πr² (r = diameter divided by 2). Converting to m², we have 0.000001 m²

On solving, we have

= ,

= 100 * 3.14 * 0.000001

= 0.000314 Am²

B

= (0)/4 * 2 / ³, where

(0) = constant of permeability = 1.256*10^-6

z = 4.7 cm = 0.047 m

B = 1.256*10^-6 / 4*3.142 * [2 * 0.000314/0.047³]

B = 1*10^-7 * 0.000628/1.038*10^-4

B = 1*10^-7 * 6.049

B = 6.049*10^-7 T

Help Me Please
8th grade science, one question ​

Answers

You can make a laser go through someone’s skin in some circumstances you can’t do that with other light sources

An ice skater applies a horizontal force to a 150 N block on frictionless, level ice, causing the block to accelerate uniformly at to the right. After the skater
stops pushing the block, it slides onto a region of ice that is covered with a thin layer of sand. The coefficient of kinetic friction between the block and the
sand-covered ice is 0.36.
Calculate the magnitude of the force of friction acting on the block as it slides over the sand-covered ice




















Answers

Answer:

The friction force has a magnitude of 54 N and points to the left

Explanation:

Friction Force

When an object is moving and encounters friction in the air or rough surfaces, it loses acceleration because the friction force opposes motion.

The friction force when an object is moving on a horizontal surface is calculated by:

[tex]Fr=\mu N[/tex]

Where \mu is the coefficient of static or kinetics friction and N is the normal force.

If no forces other then the weight and the normal are acting upon the y-direction, then the weight and the normal are equal in magnitude:

N = W

Thus, the friction force is:

[tex]Fr=\mu W[/tex]

The ice skater accelerates a block to the right on frictionless horizontal ice and then stops pushing it. The block continues to move at a constant speed when it finds a sand-covered surface with a kinetic coefficient of friction of 0.36.

The friction force is:

Fr=0.36*150

Fr = 54 N

The friction force has a magnitude of 54 N and points to the left

If a ball leaves the ground with a velocity of 4.67 m/s,
how high does the ball travel?

Answers

Answer:

[tex]Vf^2=Vo^2+2aS\\(0m/s)^2=(4.67m/s)^2+(2*-10m/s^2)S\\-(4.67)^2 m^2/s^2=-20m/s^2*S\\S=(21.8089/20) m\\S=1.090445 m\\[/tex]

A bullet is fired horizontally at a height of 2 meters at a velocity of 930 m/s. Assume no air resistance. How far did the bullet travel horizontally when it hit the ground?
595.2 m
478.4 m
364.0 m
247.2 m

Answers

Answer:

im pretty sure its a

Explanation:

It’s most likely A , i’m not so sure though

Two forces of 50 N and 30N respectively, are acting on an object. Find the net force (in N) on the object if

Answers

A) the forces are acting in the same direction.. B) Together, forces are acting in opposite directions

Answer:

A) 80 N

B) 20 N

Explanation:

A) If the forces acting are in the same direction, then the net force will be a sum of both so many faces..

Thus;

ΣF = 50 + 30

ΣF = 80 N

B) If the forces are acting in the in opposite directions with the larger force pointing in the positive y-axis then, the net force is;

ΣF = 50 - 30

ΣF = 20 N

why the efficiency of the single movable pully system is not 100%​

Answers

Answer:

This is because part of the energy input is used to overcome gravity, inertia and friction

The efficiency of a single movable pulley system is not 100% this is because (i)The friction of the pulley bearing is not zero , (ii)The weight of the pulley and string is not zero. b) The efficiency of a movable pulley is always less than 100%. ... (a) In a single fixed pulley, some effort is wasted in overcoming friction between the strings and the grooves of the pulley; so the effort needed is greater than the load and hence the mechanical advantage is less than the velocity ratio. When you pull either up or down on the rope, the wheel will turn. This makes moving the object easier, because pulling a rope downward, for instance, is easier than lifting a heavy object upward. Of course, a single pulley will not affect the amount of work necessary to move an object very much.


Runner A is initially 8.0 mi west of a flagpole and is running with a constant velocity of 7.0 mi/h due east. Runner B is initially 8.0 mi east of the flagpole and is running with a constant velocity of 6.0 mi/h due
west. How far are the runners from the flagpole when they meet?

Answers

The runners meet at 0.615mi away from the flagpole due to constant velocity.

Velocity informs us of the rate of change of your position, or how quickly your location is altering in relation to time. The difference between your end and beginning positions is referred to as displacement in physics, and velocity is defined as displacement divided by time. Additionally, an object is considered to be moving with constant velocity if it covers the same distance every second.

A vector is a speed that is constant. For a quantity to be fully described, it needs both a magnitude and a direction. Distance per time units is defined as constant velocity. The velocity tells you how quickly your distance is changing per unit of time or how quickly your location is changing.

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Two particles, each of mass 7.0 kg, are a distance 3.0 m apart. To bring a third particle, with mass 21 kg, from far away to a resting point midway between the two particles, an external agent must do work equal to

Answers

Answer: the external agent must do work equal to -1.3 × 10⁻⁸ J

Explanation:

Given that;

Mass M1 = 7.0 kg

r = 3.0/2 m = 1.5 m

Mass M2 = 21 kg

we know that G = 6.67 × 10⁻¹¹ N.m²/kg²

work done by an external agent W = -2GM2M1 / r

so we substitute

W = (-2 × 6.67 × 10⁻¹¹ × 21 × 7) / 1.5

W = -1.96098 × 10⁻⁸ / 1.5

W = -1.3 × 10⁻⁸ J

Therefore the external agent must do work equal to -1.3 × 10⁻⁸ J

(2)
(Total 6 marks)
6
Karen wants to pump up her car tyre.
Her pump has a piston with an area of 7 cm^2
175 N
area = 7 cm^2
Karen pushes the handle down with a force of 175 N.
(a)
What pressure does she exert on the air in the pump?

Answers

Answer:

250000Pa

Explanation:

Given parameters:

Force applied = 175N

Area = 7cm²

Unknown:

Pressure exerted by the air in the pump = ?

Solution:

Pressure is the force per unit area acting on a body;

        Pressure  = [tex]\frac{force }{area}[/tex]

Area  = 7cm²  ;

           10000cm²   = 1m²

        7cm² is 7 x 10⁻⁴m²

Pressure  = [tex]\frac{175}{0.0007}[/tex] = 250000Pa

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